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equal-root-value MCQ Questions for Class 10

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5 questions tagged with equal-root-value.

Question 1/5 Medium Mathematics Quadratic Equations Nature of Roots Class 10 Level 39

समीकरण \(16x^2+24x+9=0\) के लिए सही कथन चुनिए।

Choose the correct statement for \(16x^2+24x+9=0\).

Explanation opens after your attempt
Correct Answer

A. मूल समान हैं और \(x=-\frac{3}{4}\)Roots are equal and \(x=-\frac{3}{4}\)

Step 1

Concept

Here (16x-2+24x+9=(4x+3)2). Hence the equal root is \(x=-\frac{3}{4}\).

Step 2

Why this answer is correct

The correct answer is A. मूल समान हैं और \(x=-\frac{3}{4}\) / Roots are equal and \(x=-\frac{3}{4}\). Here (16x-2+24x+9=(4x+3)2). Hence the equal root is \(x=-\frac{3}{4}\).

Step 3

Exam Tip

यहाँ (16x-2+24x+9=(4x+3)2) है। अतः समान मूल \(x=-\frac{3}{4}\) है।

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Question 2/5 Medium Mathematics Quadratic Equations Nature of Roots Class 10 Level 39

समीकरण \(9x^2-6x+1=0\) में समान मूल का मान क्या है?

What is the equal root in \(9x^2-6x+1=0\)?

Explanation opens after your attempt
Correct Answer

A. \(x=\frac{1}{3}\)

Step 1

Concept

Here (9x-2-6x+1=(3x-1)2). Therefore the equal root is \(x=\frac{1}{3}\).

Step 2

Why this answer is correct

The correct answer is A. \(x=\frac{1}{3}\). Here (9x-2-6x+1=(3x-1)2). Therefore the equal root is \(x=\frac{1}{3}\).

Step 3

Exam Tip

यहाँ (9x-2-6x+1=(3x-1)2) है। इसलिए समान मूल \(x=\frac{1}{3}\) है।

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Question 3/5 Medium Mathematics Quadratic Equations Nature of Roots Class 10 Level 38

समीकरण \(4x^2-20x+25=0\) में समान मूल का मान क्या है?

What is the equal root in \(4x^2-20x+25=0\)?

Explanation opens after your attempt
Correct Answer

A. \(x=\frac{5}{2}\)

Step 1

Concept

Here (D=(-20)2-4(4)(25)=0), and ((2x-5)2=0). So the equal root is \(x=\frac{5}{2}\).

Step 2

Why this answer is correct

The correct answer is A. \(x=\frac{5}{2}\). Here (D=(-20)2-4(4)(25)=0), and ((2x-5)2=0). So the equal root is \(x=\frac{5}{2}\).

Step 3

Exam Tip

यहाँ (D=(-20)2-4(4)(25)=0) और ((2x-5)2=0) है। इसलिए समान मूल \(x=\frac{5}{2}\) है।

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Question 4/5 Medium Mathematics Quadratic Equations Nature of Roots Class 10 Level 37

समीकरण \(4x^2-4x+1=0\) के लिए सही कथन कौन सा है?

Which statement is correct for \(4x^2-4x+1=0\)?

Explanation opens after your attempt
Correct Answer

A. मूल समान हैं और \(x=\frac{1}{2}\)Roots are equal and \(x=\frac{1}{2}\)

Step 1

Concept

Here (D=(-4)2-4(4)(1)=0), and the equation is ((2x-1)2=0). So the equal root is \(x=\frac{1}{2}\).

Step 2

Why this answer is correct

The correct answer is A. मूल समान हैं और \(x=\frac{1}{2}\) / Roots are equal and \(x=\frac{1}{2}\). Here (D=(-4)2-4(4)(1)=0), and the equation is ((2x-1)2=0). So the equal root is \(x=\frac{1}{2}\).

Step 3

Exam Tip

यहाँ (D=(-4)2-4(4)(1)=0) और समीकरण ((2x-1)2=0) है। इसलिए समान मूल \(x=\frac{1}{2}\) है।

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Question 5/5 Medium Mathematics Quadratic Equations Nature of Roots Class 10 Level 37

समीकरण \(x^2-8x+16=0\) में समान मूल का मान क्या है?

What is the equal root of \(x^2-8x+16=0\)?

Explanation opens after your attempt
Correct Answer

A. (4)

Step 1

Concept

The equation becomes ((x-4)2=0). The equal root is (x=4).

Step 2

Why this answer is correct

The correct answer is A. (4). The equation becomes ((x-4)2=0). The equal root is (x=4).

Step 3

Exam Tip

समीकरण ((x-4)2=0) बनता है। समान मूल सीधे (x=4) है।

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