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Class 10MathematicsQuadratic EquationsMethods of Solving Quadratic EquationsExpert
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Which root is common to (10x^2-41x+40=0) and (15x^2-47x+30=0)?

Answer and explanation

Correct answer: (x=\frac{5}{2})

The first equation has roots (\frac{5}{2},\frac{8}{5}), and the second has roots (\frac{5}{2},\frac{4}{5}). In exams, solve both equations separately for the common root.

Related tags

QuadraticCommon-RootFactorisationMethods Of Solving Quadratic EquationsQuadratic EquationsMathematicsClass 10 Mcq
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10 more MCQs
  1. 1Using factorisation method, what are the roots of (x^2-5x+6=0)?
  2. 2In factorisation method, how will (x^2+7x+12=0) be written?
  3. 3Which is the simplest method to solve (x^2-9=0)?
  4. 4If (x^2=16), what is the value of (x) by square root method?
  5. 5Using the zero-product rule, what are the solutions of x(x−4)=0?
  6. 6In completing square method for \(x^2+6x+5=0\), which number is added and subtracted?
  7. 7Which is the correct formula to find roots of (ax^2+bx+c=0) by quadratic formula?
  8. 8What do we get first after simplifying (2x^2-8=0)?
  9. 9What are the correct factors for (x^2-2x-8=0)?
  10. 10In which form can (x^2+4x+4=0) be written?
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