If one root of (x^2+ax+12=0) is (3) more than the other root, what are the possible values of (a)?

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Answer and explanation

Correct answer: (\sqrt{57}) and (-\sqrt{57})

Let the roots be (r) and (r+3). Then (r(r+3)=12), giving the sum as (\pm\sqrt{57}), so (a=\mp\sqrt{57}).

What is the correct answer to this question?

(\sqrt{57}) and (-\sqrt{57})

Why is this the correct answer?

Let the roots be (r) and (r+3). Then (r(r+3)=12), giving the sum as (\pm\sqrt{57}), so (a=\mp\sqrt{57}).

Which subject and chapter does this question cover?

This is a Class 10 Mathematics question. Chapter: Quadratic Equations. Topic: Roots of a Quadratic Equation.

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