\(\sqrt{9+16}=5\) while \(\sqrt{9}+\sqrt{16}=7\). In exams do not split addition inside a radical.
Step 2
Why this answer is correct
The correct answer is A. (a=9) और (b=16) / (a=9) and (b=16). \(\sqrt{9+16}=5\) while \(\sqrt{9}+\sqrt{16}=7\). In exams do not split addition inside a radical.
Step 3
Exam Tip
\(\sqrt{9+16}=5\) है जबकि \(\sqrt{9}+\sqrt{16}=7\) है। परीक्षा में मूल के अंदर के योग को अलग-अलग न तोड़ें।
A. \(\sqrt{a+b}=\sqrt{a}+\sqrt{b}\) हमेशा/\(\sqrt{a+b}=\sqrt{a}+\sqrt{b}\) always
Step 1
Concept
\(\sqrt{a+b}=\sqrt{a}+\sqrt{b}\) is generally false, for example \(\sqrt{9+16}\ne3+4\). In exams do not split addition inside a radical.
Step 2
Why this answer is correct
The correct answer is A. \(\sqrt{a+b}=\sqrt{a}+\sqrt{b}\) हमेशा / \(\sqrt{a+b}=\sqrt{a}+\sqrt{b}\) always. \(\sqrt{a+b}=\sqrt{a}+\sqrt{b}\) is generally false, for example \(\sqrt{9+16}\ne3+4\). In exams do not split addition inside a radical.
Step 3
Exam Tip
\(\sqrt{a+b}=\sqrt{a}+\sqrt{b}\) सामान्यतः गलत है, जैसे \(\sqrt{9+16}\ne3+4\)। परीक्षा में मूल के अंदर योग को अलग-अलग न तोड़ें।
