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3 results found for "number-162" in Class 10.
Question
Medium Mathematics
Chapter 1: Real Numbers 3: Prime factorisation Class 10 Level 9
संख्या 1620 का सही अभाज्य गुणनखंडन क्या है?
What is the correct prime factorisation of 1620?
#prime-factorisation
#number-1620
#medium
A \(2^2\times3^4\times5\)
B \(2\times3^4\times5\)
C \(162\times10\)
D \(4\times405\)
Explanation opens after your attempt
Correct Answer
A. \(2^2\times3^4\times5\)
Step 1
Concept
Write \(1620=162\times10\).
Step 2
Why this answer is correct
\(162=2\times3^4\) and \(10=2\times5\), so \(1620=2^2\times3^4\times5\).
Step 3
Exam Tip
Count the total power of 2 correctly. चरण 1: \(1620=162\times10\) लिखें। चरण 2: \(162=2\times3^4\) और \(10=2\times5\), इसलिए \(1620=2^2\times3^4\times5\)। चरण 3: 2 की कुल घात सही गिनें।
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Question
Easy Mathematics
Chapter 1: Real Numbers 3: Prime factorisation Class 10 Level 9
किस संख्या का अभाज्य गुणनखंडन \(2\times3^4\) है?
Which number has prime factorisation \(2\times3^4\)?
#evaluate-factorisation
#number-162
#easy
A 162
B 81
C 324
D 486
Explanation opens after your attempt
Step 1
Concept
Calculate \(3^4=81\).
Step 2
Why this answer is correct
\(2\times81=162\).
Step 3
Exam Tip
Simplify the factor with a power first. चरण 1: \(3^4=81\) निकालें। चरण 2: \(2\times81=162\)। चरण 3: घात वाले गुणनखंड को पहले सरल करें।
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Question
Easy Mathematics
Chapter 1: Real Numbers 3: Prime factorisation Class 10 Level 8
संख्या 162 का सही अभाज्य गुणनखंडन क्या है?
What is the correct prime factorisation of 162?
#prime-factorisation
#number-162
#easy
A \(2\times3^4\)
B \(2^2\times3^3\)
C \(18\times9\)
D \(6\times27\)
Explanation opens after your attempt
Correct Answer
A. \(2\times3^4\)
Step 1
Concept
Write \(162=2\times81\).
Step 2
Why this answer is correct
Since \(81=3^4\), \(162=2\times3^4\).
Step 3
Exam Tip
Do not leave 81 in the final form; write \(3^4\). चरण 1: \(162=2\times81\) लिखें। चरण 2: \(81=3^4\), इसलिए \(162=2\times3^4\)। चरण 3: 81 को अंतिम रूप में न छोड़कर \(3^4\) लिखें।
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