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The square of a positive number is 120 more than twice the number. What is the number?

Answer and explanation

Correct answer: 12

The governing concept is converting a verbal comparison into a quadratic equation and then selecting the solution allowed by the condition. Let the positive number be x. Its square is 120 more than twice the number, so x² = 2x + 120. Rearranging gives x² − 2x − 120 = 0. Factoring, (x − 12)(x + 10) = 0, so x = 12 or x = −10. The problem specifies a positive number, hence x = 12 is the only admissible solution. Verification gives 12² = 144 and 2(12) + 120 = 144. Thus option C is correct; −10 is rejected because it is not positive, and the other choices do not satisfy the equation.

Related tags

Quadratic-EquationsNumber-ProblemWord-ApplicationWord Problems And ApplicationsQuadratic EquationsMathematicsClass 10 Mcq

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