Between which two consecutive integers does \(\sqrt{2}\) lie on the number line?
Answer and explanation
Correct answer: 1 and 2
Since \(1^2=1<2<4=2^2\), taking positive square roots gives \(1<\sqrt{2}<2\). Therefore, \(\sqrt{2}\) lies between 1 and 2 on the number line. Exam tip: locate a square root by comparing the number with consecutive perfect squares; hence 0 and 1 is not correct.
Frequently asked questions
What is the correct answer to this question?
1 and 2
Why is this the correct answer?
Since \(1^2=1<2<4=2^2\), taking positive square roots gives \(1<\sqrt{2}<2\). Therefore, \(\sqrt{2}\) lies between 1 and 2 on the number line. Exam tip: locate a square root by comparing the number with consecutive perfect squares; hence 0 and 1 is not correct.
Which subject and chapter does this question cover?
This is a Class 10 Mathematics question. Chapter: Polynomials. Topic: Representing real numbers on the number line.
Student feedback
Was this question useful?
👍 0 Helpful 👎 0 Not helpful
Yes 0% No 0%
0 responsesStudent Reviews
No published reviews yet.