If the HCF of (162), (270), and (378) is found, what will be the power of (3) in it?
Answer and explanation
Correct answer: (3)
Step 1: Compare the powers of (3). Step 2: (162=2\times3^4), (270=2\times3^3\times5), and (378=2\times3^3\times7), so the smallest power is (3). Step 3: HCF uses the smallest power.
Frequently asked questions
What is the correct answer to this question?
(3)
Why is this the correct answer?
Step 1: Compare the powers of (3). Step 2: (162=2\times3^4), (270=2\times3^3\times5), and (378=2\times3^3\times7), so the smallest power is (3). Step 3: HCF uses the smallest power.
Which subject and chapter does this question cover?
This is a Class 10 Mathematics question. Chapter: Real Numbers. Topic: HCF and LCM using prime factorisation.
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