Search: angle-interval

Question Expert Mathematics Pair of Linear Equations in Two Variables Algebraic methods: Substitution method and Elimination method. Class 10 Level 57

दो पूरक कोणों में एक कोण दूसरे से $28^\circ$ अधिक है। बड़ा कोण क्या है?

Two complementary angles have one angle $28^\circ$ more than the other. What is the larger angle?

Explanation opens after your attempt

Correct Answer

C. $59^\circ$

Step 1

Concept

Let the angles be (x) and (y), so $x+y=90^\circ$ and $x-y=28^\circ$. Adding gives $2x=118^\circ$, so the larger angle is $59^\circ$.

Step 2

Why this answer is correct

The correct answer is C. $59^\circ$. Let the angles be (x) and (y), so $x+y=90^\circ$ and $x-y=28^\circ$. Adding gives $2x=118^\circ$, so the larger angle is $59^\circ$.

Step 3

Exam Tip

यदि कोण (x) और (y) हों तो $x+y=90^\circ$ और $x-y=28^\circ$। जोड़ने पर $2x=118^\circ$, इसलिए बड़ा कोण $59^\circ$ है।

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Question Expert Mathematics Polynomials Representing real numbers on the number line Class 10 Level 51

यदि संख्या रेखा पर $u=-\sqrt{27}-3$, तो (u) किस अंतराल में है?

If $u=-\sqrt{27}-3$ on the number line, in which interval does (u) lie?

Explanation opens after your attempt

Correct Answer

B. ( -8 ) और ( -7 ) के बीचBetween ( -8 ) and ( -7 )

Step 1

Concept

$ -\sqrt{27}\approx-5.196 $, so $ -\sqrt{27}-3\approx-8.196 $. Therefore it lies between (-9) and (-8).

Step 2

Why this answer is correct

The correct answer is B. ( -8 ) और ( -7 ) के बीच / Between ( -8 ) and ( -7 ). $ -\sqrt{27}\approx-5.196 $, so $ -\sqrt{27}-3\approx-8.196 $. Therefore it lies between (-9) and (-8).

Step 3

Exam Tip

$ -\sqrt{27}-3\approx-8.196 $ नहीं, बल्कि $ -\sqrt{27}\approx-5.196 $ होने से योग लगभग (-8.196) है। इसलिए यह (-9) और (-8) के बीच है।

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Question Expert Mathematics Polynomials Representing real numbers on the number line Class 10 Level 51

संख्या रेखा पर $6-\sqrt{39}$ का सही स्थान किस अंतराल में है?

In which interval is $6-\sqrt{39}$ correctly located on the number line?

Explanation opens after your attempt

Correct Answer

A. ( -1 ) और (0) के बीचBetween ( -1 ) and (0)

Step 1

Concept

$ \sqrt{39}\approx6.245 $, so $6-\sqrt{39}\approx-0.245$. Always check the sign in root subtraction.

Step 2

Why this answer is correct

The correct answer is A. ( -1 ) और (0) के बीच / Between ( -1 ) and (0). $ \sqrt{39}\approx6.245 $, so $6-\sqrt{39}\approx-0.245$. Always check the sign in root subtraction.

Step 3

Exam Tip

$ \sqrt{39}\approx6.245 $, इसलिए $6-\sqrt{39}\approx-0.245$ है। घटाव वाले मूल में चिह्न जरूर जाँचें।

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Question Expert Mathematics Polynomials Representing real numbers on the number line Class 10 Level 50

यदि संख्या रेखा पर $u=-\sqrt{18}-2$, तो (u) किस अंतराल में है?

If $u=-\sqrt{18}-2$ on the number line, in which interval does (u) lie?

Explanation opens after your attempt

Correct Answer

C. ( -7 ) और ( -6 ) के बीचBetween ( -7 ) and ( -6 )

Step 1

Concept

$ -\sqrt{18}-2\approx-6.243 $, so it lies between (-7) and (-6). Estimate negative sums carefully.

Step 2

Why this answer is correct

The correct answer is C. ( -7 ) और ( -6 ) के बीच / Between ( -7 ) and ( -6 ). $ -\sqrt{18}-2\approx-6.243 $, so it lies between (-7) and (-6). Estimate negative sums carefully.

Step 3

Exam Tip

$ -\sqrt{18}-2\approx-6.243 $, इसलिए यह (-7) और (-6) के बीच है। ऋणात्मक योगों में अनुमान सावधानी से करें।

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Question Expert Mathematics Polynomials Representing real numbers on the number line Class 10 Level 50

संख्या रेखा पर $5-\sqrt{31}$ का सही स्थान किस अंतराल में है?

In which interval is $5-\sqrt{31}$ correctly located on the number line?

Explanation opens after your attempt

Correct Answer

B. ( -1 ) और (0) के बीचBetween ( -1 ) and (0)

Step 1

Concept

$ \sqrt{31}\approx5.568 $, so $5-\sqrt{31}\approx-0.568$. Always check the sign in root subtraction.

Step 2

Why this answer is correct

The correct answer is B. ( -1 ) और (0) के बीच / Between ( -1 ) and (0). $ \sqrt{31}\approx5.568 $, so $5-\sqrt{31}\approx-0.568$. Always check the sign in root subtraction.

Step 3

Exam Tip

$ \sqrt{31}\approx5.568 $, इसलिए $5-\sqrt{31}\approx-0.568$ है। घटाव वाले मूलों में चिह्न अवश्य जाँचें।

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Question Hard Mathematics Polynomials Representing real numbers on the number line Class 10 Level 51

यदि संख्या रेखा पर $u=-2-\sqrt{7}$, तो (u) किस अंतराल में स्थित है?

If $u=-2-\sqrt{7}$, in which interval is (u) located on the number line?

Explanation opens after your attempt

Correct Answer

C. ( -5 ) और ( -4 ) के बीचBetween ( -5 ) and ( -4 )

Step 1

Concept

$ \sqrt{7}\approx2.646 $, so $u\approx-4.646$. Therefore it lies between (-5) and (-4).

Step 2

Why this answer is correct

The correct answer is C. ( -5 ) और ( -4 ) के बीच / Between ( -5 ) and ( -4 ). $ \sqrt{7}\approx2.646 $, so $u\approx-4.646$. Therefore it lies between (-5) and (-4).

Step 3

Exam Tip

$ \sqrt{7}\approx2.646 $, इसलिए $u\approx-4.646$ है। अतः यह (-5) और (-4) के बीच होगा।

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Question Hard Mathematics Polynomials Representing real numbers on the number line Class 10 Level 51

यदि $x=-5+\sqrt{22}$, तो संख्या रेखा पर (x) किस अंतराल में है?

If $x=-5+\sqrt{22}$, in which interval is (x) on the number line?

Explanation opens after your attempt

Correct Answer

C. ( -1 ) और (0) के बीचBetween ( -1 ) and (0)

Step 1

Concept

Since $4<\sqrt{22}<5$, $-1<-5+\sqrt{22}<0$. Add bounds carefully in mixed expressions.

Step 2

Why this answer is correct

The correct answer is C. ( -1 ) और (0) के बीच / Between ( -1 ) and (0). Since $4<\sqrt{22}<5$, $-1<-5+\sqrt{22}<0$. Add bounds carefully in mixed expressions.

Step 3

Exam Tip

$4<\sqrt{22}<5$, इसलिए $-1<-5+\sqrt{22}<0$। मिश्रित अभिव्यक्ति में सीमा जोड़ें।

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Question Hard Mathematics Polynomials Representing real numbers on the number line Class 10 Level 51

यदि संख्या रेखा पर $x=-\sqrt{29}$, तो (x) किस अंतराल में होगा?

If $x=-\sqrt{29}$ on the number line, in which interval will (x) lie?

Explanation opens after your attempt

Correct Answer

B. ( -6 ) और ( -5 ) के बीचBetween ( -6 ) and ( -5 )

Step 1

Concept

Since $5<\sqrt{29}<6$, $-6<-\sqrt{29}<-5$. For negative roots, write the reversed interval carefully.

Step 2

Why this answer is correct

The correct answer is B. ( -6 ) और ( -5 ) के बीच / Between ( -6 ) and ( -5 ). Since $5<\sqrt{29}<6$, $-6<-\sqrt{29}<-5$. For negative roots, write the reversed interval carefully.

Step 3

Exam Tip

क्योंकि $5<\sqrt{29}<6$, इसलिए $-6<-\sqrt{29}<-5$। ऋणात्मक मूलों में क्रम उलटकर लिखें।

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Question Expert Mathematics Polynomials Representing real numbers on the number line Class 10 Level 49

यदि संख्या रेखा पर $u=-\sqrt{2}-1$, तो (u) किस अंतराल में है?

If $u=-\sqrt{2}-1$ on the number line, in which interval does (u) lie?

Explanation opens after your attempt

Correct Answer

A. ( -3 ) और ( -2 ) के बीचBetween ( -3 ) and ( -2 )

Step 1

Concept

$ -\sqrt{2}-1\approx-2.414 $, so it lies between (-3) and (-2). Estimate negative sums carefully.

Step 2

Why this answer is correct

The correct answer is A. ( -3 ) और ( -2 ) के बीच / Between ( -3 ) and ( -2 ). $ -\sqrt{2}-1\approx-2.414 $, so it lies between (-3) and (-2). Estimate negative sums carefully.

Step 3

Exam Tip

$ -\sqrt{2}-1\approx-2.414 $, इसलिए यह (-3) और (-2) के बीच है। ऋणात्मक योगों में अनुमान सावधानी से करें।

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Question Expert Mathematics Polynomials Representing real numbers on the number line Class 10 Level 49

संख्या रेखा पर $2-\sqrt{10}$ का सही स्थान किस अंतराल में है?

In which interval is $2-\sqrt{10}$ correctly located on the number line?

Explanation opens after your attempt

Correct Answer

A. (-2) और (-1) के बीचBetween (-2) and (-1)

Step 1

Concept

$ \sqrt{10}\approx3.162 $, so $2-\sqrt{10}\approx-1.162$. Estimation is important in root subtraction.

Step 2

Why this answer is correct

The correct answer is A. (-2) और (-1) के बीच / Between (-2) and (-1). $ \sqrt{10}\approx3.162 $, so $2-\sqrt{10}\approx-1.162$. Estimation is important in root subtraction.

Step 3

Exam Tip

$ \sqrt{10}\approx3.162 $ इसलिए $2-\sqrt{10}\approx-1.162$ है। घटाव वाले मूल में अनुमान जरूरी है।

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Question Hard Mathematics Polynomials Representing real numbers on the number line Class 10 Level 50

संख्या रेखा पर (x) का स्थान ( -4 ) से $ \sqrt{13} $ इकाई दाईं ओर है। (x) किस अंतराल में है?

The point (x) is $ \sqrt{13} $ units to the right of (-4) on the number line. In which interval does (x) lie?

Explanation opens after your attempt

Correct Answer

A. (-1) और (0) के बीचBetween (-1) and (0)

Step 1

Concept

$x=-4+\sqrt{13}$, and $3<\sqrt{13}<4$, so (-1<x<0). Add bounds in combined expressions.

Step 2

Why this answer is correct

The correct answer is A. (-1) और (0) के बीच / Between (-1) and (0). $x=-4+\sqrt{13}$, and $3<\sqrt{13}<4$, so (-1<x<0). Add bounds in combined expressions.

Step 3

Exam Tip

$x=-4+\sqrt{13}$ और $3<\sqrt{13}<4$, इसलिए (-1<x<0)। संयुक्त अभिव्यक्ति में सीमा जोड़ें।

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Question Hard Mathematics Polynomials Representing real numbers on the number line Class 10 Level 49

संख्या रेखा पर $\sqrt{5}-\sqrt{2}$ किस अंतराल में स्थित होगा?

On the number line, in which interval will $\sqrt{5}-\sqrt{2}$ lie?

Explanation opens after your attempt

Correct Answer

A. ((0,1))

Step 1

Concept

$\sqrt{5}\approx2.236$ and $\sqrt{2}\approx1.414$, so the difference is about (0.822). Use short approximations to locate differences of irrationals.

Step 2

Why this answer is correct

The correct answer is A. ((0,1)). $\sqrt{5}\approx2.236$ and $\sqrt{2}\approx1.414$, so the difference is about (0.822). Use short approximations to locate differences of irrationals.

Step 3

Exam Tip

$\sqrt{5}\approx2.236$ और $\sqrt{2}\approx1.414$, इसलिए अंतर लगभग (0.822) है। अपरिमेयों के अंतर का स्थान निकालने के लिए छोटे अनुमान उपयोग करें।

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Question Hard Mathematics Polynomials Representing real numbers on the number line Class 10 Level 49

किस विकल्प में संख्या रेखा पर $-\sqrt{12}$ का सही सरल अंतराल है?

Which option gives the correct simple interval for $-\sqrt{12}$ on the number line?

Explanation opens after your attempt

Correct Answer

A. ((-4,-3))

Step 1

Concept

Since $3<\sqrt{12}<4$, $-4<-\sqrt{12}<-3$. Multiplying by a negative reverses the inequality.

Step 2

Why this answer is correct

The correct answer is A. ((-4,-3)). Since $3<\sqrt{12}<4$, $-4<-\sqrt{12}<-3$. Multiplying by a negative reverses the inequality.

Step 3

Exam Tip

क्योंकि $3<\sqrt{12}<4$, इसलिए $-4<-\sqrt{12}<-3$। ऋणात्मक करने पर असमानता की दिशा बदलती है।

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Question Hard Mathematics Polynomials Representing real numbers on the number line Class 10 Level 49

संख्या रेखा पर $\sqrt{2}+\sqrt{3}$ किस अंतराल में होगा?

On the number line, in which interval will $\sqrt{2}+\sqrt{3}$ lie?

Explanation opens after your attempt

Correct Answer

A. ((3,4))

Step 1

Concept

$\sqrt{2}\approx1.414$ and $\sqrt{3}\approx1.732$, so the sum is about (3.146). Add approximate values for sums.

Step 2

Why this answer is correct

The correct answer is A. ((3,4)). $\sqrt{2}\approx1.414$ and $\sqrt{3}\approx1.732$, so the sum is about (3.146). Add approximate values for sums.

Step 3

Exam Tip

$\sqrt{2}\approx1.414$ और $\sqrt{3}\approx1.732$, इसलिए योग लगभग (3.146) है। योग के लिए अनुमानित मान जोड़ें।

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Question Hard Mathematics Polynomials Representing real numbers on the number line Class 10 Level 49

किस विकल्प में संख्या रेखा पर $-1+\sqrt{5}$ का सही अंतराल है?

Which option gives the correct interval of $-1+\sqrt{5}$ on the number line?

Explanation opens after your attempt

Correct Answer

A. ((1,2))

Step 1

Concept

Since $2<\sqrt{5}<3$, $1<-1+\sqrt{5}<2$. When adding or subtracting a constant, adjust the whole inequality.

Step 2

Why this answer is correct

The correct answer is A. ((1,2)). Since $2<\sqrt{5}<3$, $1<-1+\sqrt{5}<2$. When adding or subtracting a constant, adjust the whole inequality.

Step 3

Exam Tip

क्योंकि $2<\sqrt{5}<3$, इसलिए $1<-1+\sqrt{5}<2$। स्थिर संख्या जोड़ने या घटाने पर पूरी असमानता बदलें।

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Question Hard Mathematics Polynomials Representing real numbers on the number line Class 10 Level 49

संख्या रेखा पर $2-\sqrt{3}$ किस अंतराल में स्थित होगा?

On the number line, in which interval will $2-\sqrt{3}$ lie?

Explanation opens after your attempt

Correct Answer

A. ((0,1))

Step 1

Concept

Since $1<\sqrt{3}<2$, $0<2-\sqrt{3}<1$. Be careful with inequalities when subtracting.

Step 2

Why this answer is correct

The correct answer is A. ((0,1)). Since $1<\sqrt{3}<2$, $0<2-\sqrt{3}<1$. Be careful with inequalities when subtracting.

Step 3

Exam Tip

क्योंकि $1<\sqrt{3}<2$, इसलिए $0<2-\sqrt{3}<1$। घटाव में असमानता की दिशा सावधानी से देखें।

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Question Hard Mathematics Polynomials Representing real numbers on the number line Class 10 Level 49

किस विकल्प में $\sqrt{20}$ का संख्या रेखा पर सही अंतराल दिया गया है?

Which option gives the correct interval for $\sqrt{20}$ on the number line?

Explanation opens after your attempt

Correct Answer

A. ((4,5))

Step 1

Concept

Because $4^2=16$ and $5^2=25$, $4<\sqrt{20}<5$. Perfect-square bounds quickly give the interval.

Step 2

Why this answer is correct

The correct answer is A. ((4,5)). Because $4^2=16$ and $5^2=25$, $4<\sqrt{20}<5$. Perfect-square bounds quickly give the interval.

Step 3

Exam Tip

क्योंकि $4^2=16$ और $5^2=25$, इसलिए $4<\sqrt{20}<5$। पूर्ण वर्गों की सीमा तुरंत अंतराल देती है।

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Question Hard Mathematics Polynomials Representing real numbers on the number line Class 10 Level 49

संख्या रेखा पर $-\sqrt{5}$ की स्थिति किस अंतराल में होगी?

On the number line, in which interval will $-\sqrt{5}$ lie?

Explanation opens after your attempt

Correct Answer

A. ((-3,-2))

Step 1

Concept

Since $2^2<5<3^2$, $\sqrt{5}$ lies between (2) and (3), so $-\sqrt{5}$ lies between (-3) and (-2). On the negative side, order reverses.

Step 2

Why this answer is correct

The correct answer is A. ((-3,-2)). Since $2^2<5<3^2$, $\sqrt{5}$ lies between (2) and (3), so $-\sqrt{5}$ lies between (-3) and (-2). On the negative side, order reverses.

Step 3

Exam Tip

क्योंकि $2^2<5<3^2$, इसलिए $\sqrt{5}$ (2) और (3) के बीच है और ऋणात्मक मान (-3) और (-2) के बीच होगा। ऋणात्मक दिशा में क्रम उलट जाता है।

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Question Expert Mathematics Quadratic Equations Nature of Roots Class 10 Level 39

समीकरण (x^-2-2(4t+1)x+$7t^2+2t+5$=0) के कोई वास्तविक मूल नहीं हैं। (t) के लिए सही अंतराल क्या है?

The equation (x^-2-2(4t+1)x+$7t^2+2t+5$=0) has no real roots. What is the correct interval for (t)?

Explanation opens after your attempt

Correct Answer

A. $-1<t<\frac{2}{9}$

Step 1

Concept

Here (D=4(4t+1)²-4$7t^2+2t+5$=36t^-2+24t-16). From (D<0), $-1<t<\frac{2}{9}$.

Step 2

Why this answer is correct

The correct answer is A. $-1<t<\frac{2}{9}$. Here (D=4(4t+1)²-4$7t^2+2t+5$=36t^-2+24t-16). From (D<0), $-1<t<\frac{2}{9}$.

Step 3

Exam Tip

यहाँ (D=4(4t+1)²-4$7t^2+2t+5$=36t^-2+24t-16) है। (D<0) से $-1<t<\frac{2}{9}$ मिलता है।

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Question Expert Mathematics Quadratic Equations Nature of Roots Class 10 Level 39

यदि (x^-2+2(v+2)x+(4v+11)=0) के कोई वास्तविक मूल नहीं हों, तो (v) किस अंतराल में होगा?

If (x^-2+2(v+2)x+(4v+11)=0) has no real roots, in which interval will (v) lie?

Explanation opens after your attempt

Correct Answer

A. (-3<v<1)

Step 1

Concept

Here (D=4(v+2)²-4(4v+11)) must be expanded carefully. Always verify the middle term before solving the interval.

Step 2

Why this answer is correct

The correct answer is A. (-3<v<1). Here (D=4(v+2)²-4(4v+11)) must be expanded carefully. Always verify the middle term before solving the interval.

Step 3

Exam Tip

यहाँ (D=4(v+2)²-4(4v+11)=4$v^2-7$) नहीं, सही रूप (4$v^2-7$) नहीं है। परीक्षा में विस्तार सावधानी से करें।

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Question Expert Mathematics Quadratic Equations Nature of Roots Class 10 Level 38

समीकरण (x^-2-2(3t+1)x+$5t^2+2t+4$=0) के कोई वास्तविक मूल नहीं हैं। (t) के लिए सही अंतराल क्या है?

The equation (x^-2-2(3t+1)x+$5t^2+2t+4$=0) has no real roots. What is the correct interval for (t)?

Explanation opens after your attempt

Correct Answer

A. (-2<t<1)

Step 1

Concept

Here (D=4(3t+1)²-4$5t^2+2t+4$=16(t-1)(t+2)). From (D<0), (-2<t<1).

Step 2

Why this answer is correct

The correct answer is A. (-2<t<1). Here (D=4(3t+1)²-4$5t^2+2t+4$=16(t-1)(t+2)). From (D<0), (-2<t<1).

Step 3

Exam Tip

यहाँ (D=4(3t+1)²-4$5t^2+2t+4$=16(t-1)(t+2)) है। (D<0) से (-2<t<1)।

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Question Expert Mathematics Quadratic Equations Nature of Roots Class 10 Level 38

यदि (x^-2+2(t+1)x+(3t+7)=0) के कोई वास्तविक मूल नहीं हों, तो (t) किस अंतराल में होगा?

If (x^-2+2(t+1)x+(3t+7)=0) has no real roots, in which interval will (t) lie?

Explanation opens after your attempt

Correct Answer

A. (-4<t<1)

Step 1

Concept

Here (D=4(t+1)²-4(3t+7)=4$t^2-t-6$). For (D<0), factor again carefully before selecting the interval.

Step 2

Why this answer is correct

The correct answer is A. (-4<t<1). Here (D=4(t+1)²-4(3t+7)=4$t^2-t-6$). For (D<0), factor again carefully before selecting the interval.

Step 3

Exam Tip

यहाँ (D=4(t+1)²-4(3t+7)=4$t^2-t-6$) है। (D<0) से (-2<t<3) नहीं, गुणनखंड फिर से जाँचें।

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Question Expert Mathematics Quadratic Equations Nature of Roots Class 10 Level 37

समीकरण (x^-2-2(2t-1)x+$t^2+2$=0) के कोई वास्तविक मूल नहीं हैं। (t) के लिए सही अंतराल चुनिए।

The equation (x^-2-2(2t-1)x+$t^2+2$=0) has no real roots. Choose the correct interval for (t).

Explanation opens after your attempt

Correct Answer

A. $\frac{4-2\sqrt{6}}{3}<t<\frac{4+2\sqrt{6}}{3}$

Step 1

Concept

Here (D=4(2t-1)²-4$t^2+2$=4$3t^2-4t-1$). From (D<0), the interval between the two boundary roots is obtained.

Step 2

Why this answer is correct

The correct answer is A. $\frac{4-2\sqrt{6}}{3}<t<\frac{4+2\sqrt{6}}{3}$. Here (D=4(2t-1)²-4$t^2+2$=4$3t^2-4t-1$). From (D<0), the interval between the two boundary roots is obtained.

Step 3

Exam Tip

यहाँ (D=4(2t-1)²-4$t^2+2$=4$3t^2-4t-1$) है। (D<0) से दिए गए दोनों मूलों के बीच का अंतराल मिलता है।

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Question Expert Mathematics Quadratic Equations Nature of Roots Class 10 Level 37

यदि (x^-2+2(k-1)x+(k+5)=0) के कोई वास्तविक मूल नहीं हैं, तो (k) किस अंतराल में होगा?

If (x^-2+2(k-1)x+(k+5)=0) has no real roots, in which interval will (k) lie?

Explanation opens after your attempt

Correct Answer

A. (0<k<3)

Step 1

Concept

Here (D=4(k-1)²-4(k+5)=4$k^2-3k-4$). Use (D<0) and factor carefully before choosing the interval.

Step 2

Why this answer is correct

The correct answer is A. (0<k<3). Here (D=4(k-1)²-4(k+5)=4$k^2-3k-4$). Use (D<0) and factor carefully before choosing the interval.

Step 3

Exam Tip

यहाँ (D=4(k-1)²-4(k+5)=4$k^2-3k-4$) नहीं, सही सरल रूप (4$k^2-3k-4$) है। (D<0) से (0<k<3) नहीं मिलता, इसलिए गुणनखंड जाँचें।

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Question Medium Mathematics Quadratic Equations Nature of Roots Class 10 Level 39

समीकरण (x^-2+(k+2)x+9=0) में कोई वास्तविक मूल न होने के लिए (k) का अंतराल क्या है?

What is the interval of (k) for no real roots in (x^-2+(k+2)x+9=0)?

Explanation opens after your attempt

Correct Answer

A. (-8<k<4)

Step 1

Concept

Here (D=(k+2)²-36). From (D<0), we get (-8<k<4).

Step 2

Why this answer is correct

The correct answer is A. (-8<k<4). Here (D=(k+2)²-36). From (D<0), we get (-8<k<4).

Step 3

Exam Tip

यहाँ (D=(k+2)²-36) है। (D<0) से (-8<k<4) मिलता है।

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Question Hard Mathematics Quadratic Equations Nature of Roots Class 10 Level 38

समीकरण (3x^-2-2(2a+1)x+$a^2+a+1$=0) के वास्तविक मूल न होने का अंतराल कौन सा है?

Which interval gives no real roots for (3x^-2-2(2a+1)x+$a^2+a+1$=0)?

Explanation opens after your attempt

Correct Answer

A. (-2<a<1)

Step 1

Concept

For no real roots, (D<0) is required. From $a^2+a-2<0$, we get (-2<a<1).

Step 2

Why this answer is correct

The correct answer is A. (-2<a<1). For no real roots, (D<0) is required. From $a^2+a-2<0$, we get (-2<a<1).

Step 3

Exam Tip

वास्तविक मूल न होने के लिए (D<0) चाहिए। $a^2+a-2<0$ से (-2<a<1) मिलता है।

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Question Hard Mathematics Quadratic Equations Nature of Roots Class 10 Level 38

यदि विविक्तकर (D=(z+1)²-9) है, तो वास्तविक मूल न होने के लिए (z) किस अंतराल में होगा?

If the discriminant is (D=(z+1)²-9), in which interval will (z) lie for no real roots?

Explanation opens after your attempt

Correct Answer

A. (-4<z<2)

Step 1

Concept

For no real roots, (D<0) is needed. From ((z+1)²<9), we get (-4<z<2).

Step 2

Why this answer is correct

The correct answer is A. (-4<z<2). For no real roots, (D<0) is needed. From ((z+1)²<9), we get (-4<z<2).

Step 3

Exam Tip

वास्तविक मूल न होने के लिए (D<0) चाहिए। ((z+1)²<9) से (-4<z<2) मिलता है।

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Question Medium Mathematics Quadratic Equations Nature of Roots Class 10 Level 38

समीकरण (x^-2+(k-3)x+4=0) में कोई वास्तविक मूल न होने के लिए (k) का अंतराल क्या है?

What is the interval of (k) for no real roots in (x^-2+(k-3)x+4=0)?

Explanation opens after your attempt

Correct Answer

A. (-1<k<7)

Step 1

Concept

Here (D=(k-3)²-16). From (D<0), we get (-1<k<7).

Step 2

Why this answer is correct

The correct answer is A. (-1<k<7). Here (D=(k-3)²-16). From (D<0), we get (-1<k<7).

Step 3

Exam Tip

यहाँ (D=(k-3)²-16) है। (D<0) से (-1<k<7) मिलता है।

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Question Hard Mathematics Quadratic Equations Nature of Roots Class 10 Level 37

समीकरण (x^-2+2(a-2)x+2a+5=0) के वास्तविक मूल न होने के लिए (a) किस अंतराल में होगा?

In which interval will (a) lie for (x^-2+2(a-2)x+2a+5=0) to have no real roots?

Explanation opens after your attempt

Correct Answer

A. $3-\sqrt{10}<a<3+\sqrt{10}$

Step 1

Concept

For no real roots, (D<0) is required. Here (D=4$a^2-6a-1$), so $3-\sqrt{10}<a<3+\sqrt{10}$.

Step 2

Why this answer is correct

The correct answer is A. $3-\sqrt{10}<a<3+\sqrt{10}$. For no real roots, (D<0) is required. Here (D=4$a^2-6a-1$), so $3-\sqrt{10}<a<3+\sqrt{10}$.

Step 3

Exam Tip

वास्तविक मूल न होने के लिए (D<0) चाहिए। यहाँ (D=4$a^2-6a-1$), इसलिए $3-\sqrt{10}<a<3+\sqrt{10}$।

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Question Hard Mathematics Quadratic Equations Nature of Roots Class 10 Level 37

समीकरण $x^2-2mx+3m=0$ के वास्तविक मूल न होने के लिए सही अंतराल कौन सा है?

Which interval is correct for $x^2-2mx+3m=0$ to have no real roots?

Explanation opens after your attempt

Correct Answer

A. (0<m<3)

Step 1

Concept

For no real roots, (D<0) is needed. From (D=4m(m^-3)<0), we get (0<m<3).

Step 2

Why this answer is correct

The correct answer is A. (0<m<3). For no real roots, (D<0) is needed. From (D=4m(m^-3)<0), we get (0<m<3).

Step 3

Exam Tip

वास्तविक मूल न होने के लिए (D<0) चाहिए। (D=4m(m^-3)<0) से (0<m<3) मिलता है।

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Question Hard Mathematics Quadratic Equations Nature of Roots Class 10 Level 37

समीकरण $x^2+2tx+t+4=0$ के वास्तविक मूल न होने के लिए (t) किस अंतराल में होगा?

In which interval will (t) lie for $x^2+2tx+t+4=0$ to have no real roots?

Explanation opens after your attempt

Correct Answer

A. $-\frac{3}{2}<t<2$

Step 1

Concept

For no real roots, (D<0) is required. Here (D=4(t-2)(2t+3)), so $-\frac{3}{2}<t<2$.

Step 2

Why this answer is correct

The correct answer is A. $-\frac{3}{2}<t<2$. For no real roots, (D<0) is required. Here (D=4(t-2)(2t+3)), so $-\frac{3}{2}<t<2$.

Step 3

Exam Tip

वास्तविक मूल न होने के लिए (D<0) चाहिए। यहाँ (D=4(t-2)(2t+3)), इसलिए $-\frac{3}{2}<t<2$।

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Question Medium Mathematics Quadratic Equations Nature of Roots Class 10 Level 37

समीकरण (x^-2-(k+1)x+4=0) में वास्तविक मूल न होने के लिए (k) किस अंतराल में होगा?

For (x^-2-(k+1)x+4=0), in which interval will (k) lie for no real roots?

Explanation opens after your attempt

Correct Answer

A. (-5<k<3)

Step 1

Concept

Here (D=(k+1)²-16), and no real roots need (D<0). This gives (-5<k<3).

Step 2

Why this answer is correct

The correct answer is A. (-5<k<3). Here (D=(k+1)²-16), and no real roots need (D<0). This gives (-5<k<3).

Step 3

Exam Tip

यहाँ (D=(k+1)²-16) है और वास्तविक मूल न होने के लिए (D<0) चाहिए। इससे (-5<k<3) मिलता है।

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Question Expert Mathematics Polynomials Representing real numbers on the number line Class 10 Level 51

यदि $p=-\sqrt{99}+4$, तो (p) संख्या रेखा पर किस अंतराल में होगा?

If $p=-\sqrt{99}+4$, in which interval will (p) lie on the number line?

Explanation opens after your attempt

Correct Answer

B. ( -6 ) और ( -5 ) के बीचBetween ( -6 ) and ( -5 )

Step 1

Concept

$ \sqrt{99}\approx9.95 $, so $p\approx-5.95$. Hence it lies between (-6) and (-5).

Step 2

Why this answer is correct

The correct answer is B. ( -6 ) और ( -5 ) के बीच / Between ( -6 ) and ( -5 ). $ \sqrt{99}\approx9.95 $, so $p\approx-5.95$. Hence it lies between (-6) and (-5).

Step 3

Exam Tip

$ \sqrt{99}\approx9.95 $, इसलिए $p\approx-5.95$ है। अतः यह (-6) और (-5) के बीच होगा।

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Question Expert Mathematics Polynomials Representing real numbers on the number line Class 10 Level 50

यदि $p=-\sqrt{68}+3$, तो (p) संख्या रेखा पर किस अंतराल में होगा?

If $p=-\sqrt{68}+3$, in which interval will (p) lie on the number line?

Explanation opens after your attempt

Correct Answer

A. ( -6 ) और ( -5 ) के बीचBetween ( -6 ) and ( -5 )

Step 1

Concept

$ \sqrt{68}\approx8.246 $, so $p\approx-5.246$. Hence it lies between (-6) and (-5).

Step 2

Why this answer is correct

The correct answer is A. ( -6 ) और ( -5 ) के बीच / Between ( -6 ) and ( -5 ). $ \sqrt{68}\approx8.246 $, so $p\approx-5.246$. Hence it lies between (-6) and (-5).

Step 3

Exam Tip

$ \sqrt{68}\approx8.246 $, इसलिए $p\approx-5.246$ है। इसलिए यह (-6) और (-5) के बीच है।

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Question Expert Mathematics Polynomials Representing real numbers on the number line Class 10 Level 49

यदि $p=-\sqrt{45}+2$, तो (p) संख्या रेखा पर किस अंतराल में होगा?

If $p=-\sqrt{45}+2$, in which interval will (p) lie on the number line?

Explanation opens after your attempt

Correct Answer

A. ( -5 ) और ( -4 ) के बीचBetween ( -5 ) and ( -4 )

Step 1

Concept

$ \sqrt{45}\approx6.708 $, so $p\approx-4.708$. Hence it lies between (-5) and (-4).

Step 2

Why this answer is correct

The correct answer is A. ( -5 ) और ( -4 ) के बीच / Between ( -5 ) and ( -4 ). $ \sqrt{45}\approx6.708 $, so $p\approx-4.708$. Hence it lies between (-5) and (-4).

Step 3

Exam Tip

$ \sqrt{45}\approx6.708 $, इसलिए $p\approx-4.708$ है। इसलिए यह (-5) और (-4) के बीच है।

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Question Hard Mathematics Polynomials Representing real numbers on the number line Class 10 Level 49

संख्या रेखा पर $\frac{7}{4}$ को चिह्नित करने के लिए (0) और (2) के बीच कितने बराबर भाग करना सबसे सीधा तरीका है?

To mark $\frac{7}{4}$ on the number line, dividing the interval from (0) to (2) into how many equal parts is the most direct method?

Explanation opens after your attempt

Correct Answer

A. (8) भाग(8) parts

Step 1

Concept

Since $2=\frac{8}{4}$, the interval from (0) to (2) has (8) fourth-parts and $\frac{7}{4}$ is at the seventh part. Use the denominator to make equal units.

Step 2

Why this answer is correct

The correct answer is A. (8) भाग / (8) parts. Since $2=\frac{8}{4}$, the interval from (0) to (2) has (8) fourth-parts and $\frac{7}{4}$ is at the seventh part. Use the denominator to make equal units.

Step 3

Exam Tip

क्योंकि $2=\frac{8}{4}$, इसलिए (0) से (2) तक (8) चौथाई भाग बनेंगे और $\frac{7}{4}$ सातवें भाग पर होगा। हर को समान इकाई बनाने में प्रयोग करें।

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Question Medium Mathematics Polynomials Representing real numbers on the number line Class 10 Level 50

संख्या रेखा पर (r(x)=4x+6) का शून्यक किस अंतराल में होगा?

In which interval will the zero of (r(x)=4x+6) lie on the number line?

Explanation opens after your attempt

Correct Answer

A. (-2) और (-1)(-2) and (-1)

Step 1

Concept

From (4x+6=0), $x=-\frac{3}{2}$, which lies between (-2) and (-1). In exams, identify the interval of a negative fraction carefully.

Step 2

Why this answer is correct

The correct answer is A. (-2) और (-1) / (-2) and (-1). From (4x+6=0), $x=-\frac{3}{2}$, which lies between (-2) and (-1). In exams, identify the interval of a negative fraction carefully.

Step 3

Exam Tip

(4x+6=0) से $x=-\frac{3}{2}$, जो (-2) और (-1) के बीच है। परीक्षा में ऋणात्मक भिन्न का अंतराल सावधानी से पहचानें।

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Question Easy Mathematics Polynomials Representing real numbers on the number line Class 10 Level 51

संख्या रेखा पर $-\frac{3}{4}$ किस अंतराल में स्थित होगा?

In which interval will $-\frac{3}{4}$ lie on the number line?

Explanation opens after your attempt

Correct Answer

B. (-1) और (0) के बीचBetween (-1) and (0)

Step 1

Concept

$-\frac{3}{4}$ is negative and greater than (-1). In exams, show such fractions between (-1) and (0).

Step 2

Why this answer is correct

The correct answer is B. (-1) और (0) के बीच / Between (-1) and (0). $-\frac{3}{4}$ is negative and greater than (-1). In exams, show such fractions between (-1) and (0).

Step 3

Exam Tip

$-\frac{3}{4}$ ऋणात्मक है और (-1) से बड़ा है। परीक्षा में ऐसे भिन्न को (-1) और (0) के बीच दिखाएं।

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Question Easy Mathematics Polynomials Representing real numbers on the number line Class 10 Level 50

संख्या रेखा पर $-\frac{1}{4}$ किस अंतराल में होगा?

In which interval will $-\frac{1}{4}$ lie on the number line?

Explanation opens after your attempt

Correct Answer

A. (-1) और (0) के बीचbetween (-1) and (0)

Step 1

Concept

$-\frac{1}{4}=-0.25$, so it lies between (-1) and (0). Small negative fractions are close to (0) on the left.

Step 2

Why this answer is correct

The correct answer is A. (-1) और (0) के बीच / between (-1) and (0). $-\frac{1}{4}=-0.25$, so it lies between (-1) and (0). Small negative fractions are close to (0) on the left.

Step 3

Exam Tip

$-\frac{1}{4}=-0.25$, इसलिए यह (-1) और (0) के बीच है। छोटे ऋणात्मक भिन्न (0) के बाईं ओर पास होते हैं।

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Question Expert Mathematics Quadratic Equations Nature of Roots Class 10 Level 39

यदि किसी द्विघात समीकरण का विविक्तकर (D=(r-2)²-9) है, तो कोई वास्तविक मूल न होने के लिए (r) का अंतराल कौन सा है?

If a quadratic equation has discriminant (D=(r-2)²-9), which interval of (r) gives no real roots?

Explanation opens after your attempt

Correct Answer

A. (-1<r<5)

Step 1

Concept

For no real roots (D<0) is needed. From ((r-2)²<9), we get (-1<r<5).

Step 2

Why this answer is correct

The correct answer is A. (-1<r<5). For no real roots (D<0) is needed. From ((r-2)²<9), we get (-1<r<5).

Step 3

Exam Tip

कोई वास्तविक मूल न होने के लिए (D<0) चाहिए। ((r-2)²<9) से (-1<r<5) मिलता है।

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Question Expert Mathematics Quadratic Equations Nature of Roots Class 10 Level 39

यदि (D=(z-9)(z+1)) है, तो कोई वास्तविक मूल न होने के लिए (z) का अंतराल कौन सा है?

If (D=(z-9)(z+1)), which interval of (z) gives no real roots?

Explanation opens after your attempt

Correct Answer

A. (-1<z<9)

Step 1

Concept

For no real roots (D<0) is needed. ((z-9)(z+1)<0) gives (-1<z<9).

Step 2

Why this answer is correct

The correct answer is A. (-1<z<9). For no real roots (D<0) is needed. ((z-9)(z+1)<0) gives (-1<z<9).

Step 3

Exam Tip

कोई वास्तविक मूल न होने के लिए (D<0) चाहिए। ((z-9)(z+1)<0) से (-1<z<9) मिलता है।

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Question Expert Mathematics Quadratic Equations Nature of Roots Class 10 Level 38

यदि (D=(z-4)(z+6)) है, तो कोई वास्तविक मूल न होने के लिए (z) का अंतराल कौन सा है?

If (D=(z-4)(z+6)), which interval of (z) gives no real roots?

Explanation opens after your attempt

Correct Answer

A. (-6<z<4)

Step 1

Concept

For no real roots (D<0) is needed. ((z-4)(z+6)<0) gives (-6<z<4).

Step 2

Why this answer is correct

The correct answer is A. (-6<z<4). For no real roots (D<0) is needed. ((z-4)(z+6)<0) gives (-6<z<4).

Step 3

Exam Tip

कोई वास्तविक मूल न होने के लिए (D<0) चाहिए। ((z-4)(z+6)<0) से (-6<z<4) मिलता है।

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Question Expert Mathematics Quadratic Equations Nature of Roots Class 10 Level 37

यदि (D=(u+1)(u-5)) है, तो कोई वास्तविक मूल न होने के लिए (u) का अंतराल कौन सा है?

If (D=(u+1)(u-5)), which interval of (u) gives no real roots?

Explanation opens after your attempt

Correct Answer

A. (-1<u<5)

Step 1

Concept

For no real roots (D<0) is needed. ((u+1)(u-5)<0) gives (-1<u<5).

Step 2

Why this answer is correct

The correct answer is A. (-1<u<5). For no real roots (D<0) is needed. ((u+1)(u-5)<0) gives (-1<u<5).

Step 3

Exam Tip

कोई वास्तविक मूल न होने के लिए (D<0) चाहिए। ((u+1)(u-5)<0) से (-1<u<5) मिलता है।

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Question Easy Art Education Fundamentals of Visual Arts Line Class 10 Level 11

जिगजैग रेखा में कैसा बदलाव होता है?

What kind of change occurs in a zigzag line?

Explanation opens after your attempt

Correct Answer

B. एकदम तेज कोणीय मोड़Sharp angular turns

Step 1

Concept

A zigzag line turns through sharp angles. Exam tip: identify zigzag by sharp turns.

Step 2

Why this answer is correct

The correct answer is B. एकदम तेज कोणीय मोड़ / Sharp angular turns. A zigzag line turns through sharp angles. Exam tip: identify zigzag by sharp turns.

Step 3

Exam Tip

जिगजैग रेखा तेज कोणों में मुड़ती है। परीक्षा में zigzag को sharp turns से पहचानें।

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Question Medium Art Education Fundamentals of Visual Arts Elements of Art Class 10 Level 8

पड़ी छाया की लंबाई किस बात से प्रभावित हो सकती है?

The length of cast shadow can be affected by what?

Explanation opens after your attempt

Correct Answer

D. प्रकाश के कोण सेBy angle of light

Step 1

Concept

Angle of light changes direction and length of cast shadow. Exam tip: connect cast shadow with light angle.

Step 2

Why this answer is correct

The correct answer is D. प्रकाश के कोण से / By angle of light. Angle of light changes direction and length of cast shadow. Exam tip: connect cast shadow with light angle.

Step 3

Exam Tip

प्रकाश का कोण पड़ी छाया की दिशा और लंबाई बदलता है। परीक्षा में cast shadow को light angle से जोड़ें।

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Question Hard Mathematics Arithmetic Progressions (AP) Finding the sum of the first $n$ terms of an AP Class 10 Level 67

(50) से (250) तक (7) से विभाज्य सभी संख्याओं का योग ज्ञात कीजिए।

Find the sum of all numbers divisible by (7) from (50) to (250).

Explanation opens after your attempt

Correct Answer

C. (4214)

Step 1

Concept

The AP is $56,63,\ldots,245$ with (28) terms, and the sum is (4214). Choose the first and last multiples within the limits correctly.

Step 2

Why this answer is correct

The correct answer is C. (4214). The AP is $56,63,\ldots,245$ with (28) terms, and the sum is (4214). Choose the first and last multiples within the limits correctly.

Step 3

Exam Tip

श्रेढ़ी $56,63,\ldots,245$ है जिसमें (28) पद हैं और योग (4214) है। सीमा के अंदर पहला और अंतिम गुणज सही चुनें।

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Question Expert Mathematics Polynomials Representing real numbers on the number line Class 10 Level 51

कौन सा मान ( -5 ) और $ -\sqrt{23} $ के बीच संख्या रेखा पर स्थित है?

Which value lies between (-5) and $ -\sqrt{23} $ on the number line?

Explanation opens after your attempt

Correct Answer

B. ( -4.90 )

Step 1

Concept

$ -\sqrt{23}\approx-4.796 $, so (-4.90) lies between (-5) and (-4.796). Read negative intervals in order.

Step 2

Why this answer is correct

The correct answer is B. ( -4.90 ). $ -\sqrt{23}\approx-4.796 $, so (-4.90) lies between (-5) and (-4.796). Read negative intervals in order.

Step 3

Exam Tip

$ -\sqrt{23}\approx-4.796 $, इसलिए (-4.90) (-5) और (-4.796) के बीच है। ऋणात्मक अंतराल को क्रम से पढ़ें।

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Question Expert Mathematics Polynomials Representing real numbers on the number line Class 10 Level 51

यदि (x) संख्या रेखा पर (-5) और (-1) के बीच है तथा (x) की (-5) से दूरी $ \frac{13}{6} $ है, तो (x) क्या है?

If (x) lies between (-5) and (-1) and its distance from (-5) is $ \frac{13}{6} $, what is (x)?

Explanation opens after your attempt

Correct Answer

A. $ -\frac{17}{6} $

Step 1

Concept

Moving $ \frac{13}{6} $ to the right of (-5) gives $ -5+\frac{13}{6}=-\frac{17}{6} $. Use the given interval to choose direction.

Step 2

Why this answer is correct

The correct answer is A. $ -\frac{17}{6} $. Moving $ \frac{13}{6} $ to the right of (-5) gives $ -5+\frac{13}{6}=-\frac{17}{6} $. Use the given interval to choose direction.

Step 3

Exam Tip

(-5) से दाईं ओर $ \frac{13}{6} $ जाने पर $ -5+\frac{13}{6}=-\frac{17}{6} $ मिलता है। दिए गए अंतराल से दिशा चुनें।

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Question Expert Mathematics Polynomials Representing real numbers on the number line Class 10 Level 51

संख्या रेखा पर $ -\frac{43}{11} $ किस दो पूर्णांकों के बीच स्थित है?

Between which two integers is $ -\frac{43}{11} $ located on the number line?

Explanation opens after your attempt

Correct Answer

C. ( -4 ) और ( -3 )( -4 ) and ( -3 )

Step 1

Concept

$ -\frac{43}{11}\approx-3.909 $, so it lies between (-4) and (-3). Convert negative fractions to decimals.

Step 2

Why this answer is correct

The correct answer is C. ( -4 ) और ( -3 ) / ( -4 ) and ( -3 ). $ -\frac{43}{11}\approx-3.909 $, so it lies between (-4) and (-3). Convert negative fractions to decimals.

Step 3

Exam Tip

$ -\frac{43}{11}\approx-3.909 $, इसलिए यह (-4) और (-3) के बीच है। ऋणात्मक भिन्नों को दशमलव में बदलें।

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Question Expert Mathematics Polynomials Representing real numbers on the number line Class 10 Level 51

कौन सा मान संख्या रेखा पर $ -\sqrt{12} $ और $ -\frac{17}{5} $ के बीच है?

Which value lies between $ -\sqrt{12} $ and $ -\frac{17}{5} $ on the number line?

Explanation opens after your attempt

Correct Answer

B. ( -3.43 )

Step 1

Concept

$ -\sqrt{12}\approx-3.464 $ and $ -\frac{17}{5}=-3.4 $. Therefore (-3.43) lies between them.

Step 2

Why this answer is correct

The correct answer is B. ( -3.43 ). $ -\sqrt{12}\approx-3.464 $ and $ -\frac{17}{5}=-3.4 $. Therefore (-3.43) lies between them.

Step 3

Exam Tip

$ -\sqrt{12}\approx-3.464 $ और $ -\frac{17}{5}=-3.4 $ है। इसलिए (-3.43) इनके बीच स्थित है।

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Question Expert Mathematics Polynomials Representing real numbers on the number line Class 10 Level 50

कौन सा मान ( -4 ) और $ -\sqrt{15} $ के बीच संख्या रेखा पर स्थित है?

Which value lies between (-4) and $ -\sqrt{15} $ on the number line?

Explanation opens after your attempt

Correct Answer

B. ( -3.95 )

Step 1

Concept

$ -\sqrt{15}\approx-3.873 $, so (-3.95) lies between (-4) and (-3.873). Read negative intervals in order.

Step 2

Why this answer is correct

The correct answer is B. ( -3.95 ). $ -\sqrt{15}\approx-3.873 $, so (-3.95) lies between (-4) and (-3.873). Read negative intervals in order.

Step 3

Exam Tip

$ -\sqrt{15}\approx-3.873 $, इसलिए (-3.95) (-4) और (-3.873) के बीच है। ऋणात्मक अंतराल को क्रम से पढ़ें।

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Question Expert Mathematics Polynomials Representing real numbers on the number line Class 10 Level 50

यदि (x) संख्या रेखा पर (-3) और (0) के बीच है तथा (x) की (-3) से दूरी $ \frac{7}{5} $ है, तो (x) क्या है?

If (x) lies between (-3) and (0) and its distance from (-3) is $ \frac{7}{5} $, what is (x)?

Explanation opens after your attempt

Correct Answer

A. $ -\frac{8}{5} $

Step 1

Concept

Moving $ \frac{7}{5} $ to the right of (-3) gives $ -3+\frac{7}{5}=-\frac{8}{5} $. Use the given interval to choose direction.

Step 2

Why this answer is correct

The correct answer is A. $ -\frac{8}{5} $. Moving $ \frac{7}{5} $ to the right of (-3) gives $ -3+\frac{7}{5}=-\frac{8}{5} $. Use the given interval to choose direction.

Step 3

Exam Tip

(-3) से दाईं ओर $ \frac{7}{5} $ जाने पर $ -3+\frac{7}{5}=-\frac{8}{5} $ मिलता है। दिए गए अंतराल से दिशा चुनें।

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Question Expert Mathematics Polynomials Representing real numbers on the number line Class 10 Level 50

संख्या रेखा पर $ -\frac{31}{9} $ किस दो पूर्णांकों के बीच स्थित है?

Between which two integers is $ -\frac{31}{9} $ located on the number line?

Explanation opens after your attempt

Correct Answer

C. ( -4 ) और ( -3 )( -4 ) and ( -3 )

Step 1

Concept

$ -\frac{31}{9}\approx-3.444 $, so it lies between (-4) and (-3). Convert negative fractions to decimals.

Step 2

Why this answer is correct

The correct answer is C. ( -4 ) और ( -3 ) / ( -4 ) and ( -3 ). $ -\frac{31}{9}\approx-3.444 $, so it lies between (-4) and (-3). Convert negative fractions to decimals.

Step 3

Exam Tip

$ -\frac{31}{9}\approx-3.444 $, इसलिए यह (-4) और (-3) के बीच है। ऋणात्मक भिन्नों को दशमलव में बदलें।

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Question Expert Mathematics Polynomials Representing real numbers on the number line Class 10 Level 50

कौन सा मान संख्या रेखा पर $ -\sqrt{10} $ और $ -\frac{19}{6} $ के बीच है?

Which value lies between $ -\sqrt{10} $ and $ -\frac{19}{6} $ on the number line?

Explanation opens after your attempt

Correct Answer

A. ( -3.20 )

Step 1

Concept

$ -\sqrt{10}\approx-3.162 $ and $ -\frac{19}{6}\approx-3.167 $. (-3.20) is not between them, so recheck direction for close negative values.

Step 2

Why this answer is correct

The correct answer is A. ( -3.20 ). $ -\sqrt{10}\approx-3.162 $ and $ -\frac{19}{6}\approx-3.167 $. (-3.20) is not between them, so recheck direction for close negative values.

Step 3

Exam Tip

$ -\sqrt{10}\approx-3.162 $ और $ -\frac{19}{6}\approx-3.167 $ है। (-3.20) इनके बीच नहीं है, इसलिए निकट ऋणात्मक मानों में दिशा दोबारा जाँचें।

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Question Hard Mathematics Polynomials Representing real numbers on the number line Class 10 Level 51

किस विकल्प में $4-\sqrt{18}$ की संख्या रेखा पर स्थिति सही है?

Which option correctly gives the position of $4-\sqrt{18}$ on the number line?

Explanation opens after your attempt

Correct Answer

A. ( -1 ) और (0) के बीचBetween ( -1 ) and (0)

Step 1

Concept

$ \sqrt{18}\approx4.243 $, so $4-\sqrt{18}\approx-0.243$. The sign can change when subtracting a root.

Step 2

Why this answer is correct

The correct answer is A. ( -1 ) और (0) के बीच / Between ( -1 ) and (0). $ \sqrt{18}\approx4.243 $, so $4-\sqrt{18}\approx-0.243$. The sign can change when subtracting a root.

Step 3

Exam Tip

$ \sqrt{18}\approx4.243 $, इसलिए $4-\sqrt{18}\approx-0.243$। मूल घटाने पर चिह्न बदल सकता है।

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Question Hard Mathematics Polynomials Representing real numbers on the number line Class 10 Level 51

कौन सा मान $ -\sqrt{6} $ और ( -2.4 ) के बीच स्थित है?

Which value lies between $ -\sqrt{6} $ and (-2.4)?

Explanation opens after your attempt

Correct Answer

C. ( -2.43 )

Step 1

Concept

$ -\sqrt{6}\approx-2.449 $, so (-2.43) lies between it and (-2.4). Read negative intervals carefully.

Step 2

Why this answer is correct

The correct answer is C. ( -2.43 ). $ -\sqrt{6}\approx-2.449 $, so (-2.43) lies between it and (-2.4). Read negative intervals carefully.

Step 3

Exam Tip

$ -\sqrt{6}\approx-2.449 $, इसलिए (-2.43) इसके और (-2.4) के बीच है। ऋणात्मक अंतराल को ध्यान से पढ़ें।

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Question Hard Mathematics Polynomials Representing real numbers on the number line Class 10 Level 51

संख्या रेखा पर $ \frac{11}{12} $ को (0) और (1) के बीच कैसे समझना सही है?

How should $ \frac{11}{12} $ be correctly understood between (0) and (1) on the number line?

Explanation opens after your attempt

Correct Answer

B. (0) से (1) तक (12) बराबर भागों में (11)वाँ बिंदुThe (11)th point among (12) equal parts from (0) to (1)

Step 1

Concept

$ \frac{11}{12} $ means (11) parts out of (12) equal parts. The denominator gives the number of equal parts.

Step 2

Why this answer is correct

The correct answer is B. (0) से (1) तक (12) बराबर भागों में (11)वाँ बिंदु / The (11)th point among (12) equal parts from (0) to (1). $ \frac{11}{12} $ means (11) parts out of (12) equal parts. The denominator gives the number of equal parts.

Step 3

Exam Tip

$ \frac{11}{12} $ का अर्थ (12) बराबर भागों में (11) भाग है। हर बराबर भागों की संख्या बताता है।

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Question Hard Mathematics Polynomials Representing real numbers on the number line Class 10 Level 51

संख्या रेखा पर $ -\frac{19}{6} $ का सही वर्णन कौन सा है?

Which is the correct description of $ -\frac{19}{6} $ on the number line?

Explanation opens after your attempt

Correct Answer

C. यह (-4) और (-3) के बीच हैIt lies between (-4) and (-3)

Step 1

Concept

$ -\frac{19}{6}\approx-3.167 $, so it lies between (-4) and (-3). Converting a negative fraction to decimal is useful.

Step 2

Why this answer is correct

The correct answer is C. यह (-4) और (-3) के बीच है / It lies between (-4) and (-3). $ -\frac{19}{6}\approx-3.167 $, so it lies between (-4) and (-3). Converting a negative fraction to decimal is useful.

Step 3

Exam Tip

$ -\frac{19}{6}\approx-3.167 $, इसलिए यह (-4) और (-3) के बीच है। ऋणात्मक भिन्न को दशमलव में बदलना उपयोगी है।

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Question Expert Mathematics Polynomials Representing real numbers on the number line Class 10 Level 49

कौन सा मान ( -2 ) और $ -\sqrt{3} $ के बीच संख्या रेखा पर स्थित है?

Which value lies between (-2) and $ -\sqrt{3} $ on the number line?

Explanation opens after your attempt

Correct Answer

A. ( -1.8 )

Step 1

Concept

$ -\sqrt{3}\approx-1.732 $, and (-1.8) lies between it and (-2). Check left-to-right order in negative intervals.

Step 2

Why this answer is correct

The correct answer is A. ( -1.8 ). $ -\sqrt{3}\approx-1.732 $, and (-1.8) lies between it and (-2). Check left-to-right order in negative intervals.

Step 3

Exam Tip

$ -\sqrt{3}\approx-1.732 $ है और (-1.8) इसके तथा (-2) के बीच है। ऋणात्मक अंतराल में बाएँ से दाएँ क्रम देखें।

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Question Expert Mathematics Polynomials Representing real numbers on the number line Class 10 Level 49

यदि (x) संख्या रेखा पर ( -2 ) और (1) के बीच है तथा (x) की ( -2 ) से दूरी $ \frac{5}{4} $ है, तो (x) क्या है?

If (x) lies between (-2) and (1) and its distance from (-2) is $ \frac{5}{4} $, what is (x)?

Explanation opens after your attempt

Correct Answer

A. $ -\frac{3}{4} $

Step 1

Concept

Moving $ \frac{5}{4} $ to the right of (-2) gives $ -2+\frac{5}{4}=-\frac{3}{4} $. Use the given interval to choose the direction.

Step 2

Why this answer is correct

The correct answer is A. $ -\frac{3}{4} $. Moving $ \frac{5}{4} $ to the right of (-2) gives $ -2+\frac{5}{4}=-\frac{3}{4} $. Use the given interval to choose the direction.

Step 3

Exam Tip

(-2) से दाईं ओर $ \frac{5}{4} $ जाने पर $ -2+\frac{5}{4}=-\frac{3}{4} $ मिलता है। दिए गए अंतराल से सही दिशा चुनें।

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Question Expert Mathematics Polynomials Representing real numbers on the number line Class 10 Level 49

संख्या रेखा पर $ -\frac{17}{5} $ किस दो पूर्णांकों के बीच स्थित है?

Between which two integers is $ -\frac{17}{5} $ located on the number line?

Explanation opens after your attempt

Correct Answer

A. ( -4 ) और ( -3 )( -4 ) and ( -3 )

Step 1

Concept

$ -\frac{17}{5}=-3.4 $. It lies between (-4) and (-3).

Step 2

Why this answer is correct

The correct answer is A. ( -4 ) और ( -3 ) / ( -4 ) and ( -3 ). $ -\frac{17}{5}=-3.4 $. It lies between (-4) and (-3).

Step 3

Exam Tip

$ -\frac{17}{5}=-3.4 $ है। यह (-4) और (-3) के बीच आता है।

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Question Expert Mathematics Polynomials Representing real numbers on the number line Class 10 Level 49

कौन सा मान संख्या रेखा पर $ -\sqrt{3} $ और $ -\frac{5}{3} $ के बीच है?

Which value lies between $ -\sqrt{3} $ and $ -\frac{5}{3} $ on the number line?

Explanation opens after your attempt

Correct Answer

A. ( -1.70 )

Step 1

Concept

$ -\sqrt{3}\approx-1.732 $ and $ -\frac{5}{3}\approx-1.667 $. Therefore (-1.70) lies between them.

Step 2

Why this answer is correct

The correct answer is A. ( -1.70 ). $ -\sqrt{3}\approx-1.732 $ and $ -\frac{5}{3}\approx-1.667 $. Therefore (-1.70) lies between them.

Step 3

Exam Tip

$ -\sqrt{3}\approx-1.732 $ और $ -\frac{5}{3}\approx-1.667 $ है। इसलिए (-1.70) इनके बीच है।

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Question Hard Mathematics Polynomials Representing real numbers on the number line Class 10 Level 50

किस विकल्प में $2-\sqrt{5}$ की संख्या रेखा पर स्थिति सही है?

Which option correctly gives the position of $2-\sqrt{5}$ on the number line?

Explanation opens after your attempt

Correct Answer

A. (-1) और (0) के बीचBetween (-1) and (0)

Step 1

Concept

$ \sqrt{5}\approx2.236$, so $2-\sqrt{5}\approx-0.236$. Estimation is fastest for subtraction with roots.

Step 2

Why this answer is correct

The correct answer is A. (-1) और (0) के बीच / Between (-1) and (0). $ \sqrt{5}\approx2.236$, so $2-\sqrt{5}\approx-0.236$. Estimation is fastest for subtraction with roots.

Step 3

Exam Tip

$ \sqrt{5}\approx2.236$, इसलिए $2-\sqrt{5}\approx-0.236$। घटाव वाले मूलों में अनुमान सबसे तेज होता है।

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Question Hard Mathematics Polynomials Representing real numbers on the number line Class 10 Level 50

यदि संख्या रेखा पर (P) का निर्देशांक $ -\sqrt{48} $ है, तो (P) किस दो लगातार पूर्णांकों के बीच है?

If point (P) has coordinate $ -\sqrt{48} $ on the number line, between which two consecutive integers does (P) lie?

Explanation opens after your attempt

Correct Answer

A. (-7) और (-6)(-7) and (-6)

Step 1

Concept

Since $6<\sqrt{48}<7$, $-7<-\sqrt{48}<-6$. Write the interval carefully for negative square roots.

Step 2

Why this answer is correct

The correct answer is A. (-7) और (-6) / (-7) and (-6). Since $6<\sqrt{48}<7$, $-7<-\sqrt{48}<-6$. Write the interval carefully for negative square roots.

Step 3

Exam Tip

$6<\sqrt{48}<7$, इसलिए $-7<-\sqrt{48}<-6$। ऋणात्मक वर्गमूल में अंतराल उल्टा लिखें।

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Question Hard Mathematics Polynomials Representing real numbers on the number line Class 10 Level 50

संख्या रेखा पर कौन सा मान $ -\sqrt{2} $ और ( -1.3 ) के बीच है?

Which value lies between $ -\sqrt{2} $ and ( -1.3 ) on the number line?

Explanation opens after your attempt

Correct Answer

A. ( -1.35)

Step 1

Concept

$ -\sqrt{2}\approx-1.414$, so (-1.35) lies between it and (-1.3). Read order carefully in negative intervals.

Step 2

Why this answer is correct

The correct answer is A. ( -1.35). $ -\sqrt{2}\approx-1.414$, so (-1.35) lies between it and (-1.3). Read order carefully in negative intervals.

Step 3

Exam Tip

$ -\sqrt{2}\approx-1.414$, इसलिए (-1.35) उसके और (-1.3) के बीच है। ऋणात्मक अंतराल में क्रम सावधानी से पढ़ें।

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Question Hard Mathematics Polynomials Representing real numbers on the number line Class 10 Level 50

संख्या रेखा पर $ \frac{7}{8} $ को (0) और (1) के बीच किस प्रकार समझना सही है?

How should $ \frac{7}{8} $ be correctly understood between (0) and (1) on the number line?

Explanation opens after your attempt

Correct Answer

A. यह (0) से (1) तक के आठ बराबर भागों में सातवें भाग पर हैIt is at the seventh of eight equal parts from (0) to (1)

Step 1

Concept

$ \frac{7}{8}$ means (7) parts out of (8) equal parts from (0) to (1). The denominator gives the number of equal parts.

Step 2

Why this answer is correct

The correct answer is A. यह (0) से (1) तक के आठ बराबर भागों में सातवें भाग पर है / It is at the seventh of eight equal parts from (0) to (1). $ \frac{7}{8}$ means (7) parts out of (8) equal parts from (0) to (1). The denominator gives the number of equal parts.

Step 3

Exam Tip

$ \frac{7}{8}$ का अर्थ (0) से (1) तक (8) बराबर भागों में (7) भाग है। हर बराबर भागों की संख्या बताता है।

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Question Hard Mathematics Polynomials Representing real numbers on the number line Class 10 Level 49

यदि $\sqrt{10}$ को संख्या रेखा पर रखा जाए, तो वह किन दो पूर्णांकों के बीच होगा?

If $\sqrt{10}$ is placed on the number line, between which two integers will it lie?

Explanation opens after your attempt

Correct Answer

A. (3) और (4)(3) and (4)

Step 1

Concept

Because $3^2=9$ and $4^2=16$, $3<\sqrt{10}<4$. First find the nearest perfect squares.

Step 2

Why this answer is correct

The correct answer is A. (3) और (4) / (3) and (4). Because $3^2=9$ and $4^2=16$, $3<\sqrt{10}<4$. First find the nearest perfect squares.

Step 3

Exam Tip

क्योंकि $3^2=9$ और $4^2=16$, इसलिए $3<\sqrt{10}<4$। पहले निकटतम पूर्ण वर्ग खोजें।

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Question Medium Mathematics Polynomials Representing real numbers on the number line Class 10 Level 51

संख्या रेखा पर $\sqrt{37}-6$ किस दो पूर्णांकों के बीच होगा?

Between which two integers will $\sqrt{37}-6$ lie on the number line?

Explanation opens after your attempt

Correct Answer

A. (0) और (1)(0) and (1)

Step 1

Concept

Since $6^2<37<7^2$, $6<\sqrt{37}<7$ and $0<\sqrt{37}-6<1$. Subtract the same number from a root interval to locate the value.

Step 2

Why this answer is correct

The correct answer is A. (0) और (1) / (0) and (1). Since $6^2<37<7^2$, $6<\sqrt{37}<7$ and $0<\sqrt{37}-6<1$. Subtract the same number from a root interval to locate the value.

Step 3

Exam Tip

क्योंकि $6^2<37<7^2$, इसलिए $6<\sqrt{37}<7$ और $0<\sqrt{37}-6<1$ है। वर्गमूल वाले अंतराल में समान संख्या घटाकर स्थिति पाएं।

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Question Medium Mathematics Polynomials Representing real numbers on the number line Class 10 Level 51

संख्या रेखा पर $-\sqrt{11}$ किस दो पूर्णांकों के बीच होगा?

Between which two integers will $-\sqrt{11}$ lie on the number line?

Explanation opens after your attempt

Correct Answer

C. (-4) और (-3)(-4) and (-3)

Step 1

Concept

$\sqrt{11}$ lies between (3) and (4), so $-\sqrt{11}$ lies between (-4) and (-3). The negative sign changes the side.

Step 2

Why this answer is correct

The correct answer is C. (-4) और (-3) / (-4) and (-3). $\sqrt{11}$ lies between (3) and (4), so $-\sqrt{11}$ lies between (-4) and (-3). The negative sign changes the side.

Step 3

Exam Tip

$\sqrt{11}$ (3) और (4) के बीच है इसलिए $-\sqrt{11}$ (-4) और (-3) के बीच होगा। ऋणात्मक चिन्ह दिशा बदल देता है।

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Question Medium Mathematics Polynomials Representing real numbers on the number line Class 10 Level 51

संख्या रेखा पर $\sqrt{50}$ किस दो पूर्णांकों के बीच स्थित होगा?

Between which two integers will $\sqrt{50}$ be located on the number line?

Explanation opens after your attempt

Correct Answer

C. (7) और (8)(7) and (8)

Step 1

Concept

Since $7^2<50<8^2$, $\sqrt{50}$ lies between (7) and (8). Use perfect squares to decide the interval.

Step 2

Why this answer is correct

The correct answer is C. (7) और (8) / (7) and (8). Since $7^2<50<8^2$, $\sqrt{50}$ lies between (7) and (8). Use perfect squares to decide the interval.

Step 3

Exam Tip

क्योंकि $7^2<50<8^2$, इसलिए $\sqrt{50}$ (7) और (8) के बीच है। पूर्ण वर्गों से अंतराल तय करें।

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Question Medium Mathematics Polynomials Representing real numbers on the number line Class 10 Level 50

संख्या रेखा पर कौन सा बिंदु (-2) और (-1) के बीच स्थित है?

Which point lies between (-2) and (-1) on the number line?

Explanation opens after your attempt

Correct Answer

B. $-\frac{3}{2}$

Step 1

Concept

$-\frac{3}{2}=-1.5$, so it lies between (-2) and (-1). In exams, the decimal form of a negative fraction helps.

Step 2

Why this answer is correct

The correct answer is B. $-\frac{3}{2}$. $-\frac{3}{2}=-1.5$, so it lies between (-2) and (-1). In exams, the decimal form of a negative fraction helps.

Step 3

Exam Tip

$-\frac{3}{2}=-1.5$, इसलिए यह (-2) और (-1) के बीच है। परीक्षा में ऋणात्मक भिन्न का दशमलव रूप मदद करता है।

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Question Medium Mathematics Polynomials Representing real numbers on the number line Class 10 Level 50

कौन सी संख्या संख्या रेखा पर (-1) और (0) के बीच नहीं है?

Which number is not between (-1) and (0) on the number line?

Explanation opens after your attempt

Correct Answer

C. $-\frac{5}{4}$

Step 1

Concept

$-\frac{5}{4}=-1.25$, which is to the left of (-1). In exams, convert negative fractions into decimals to check.

Step 2

Why this answer is correct

The correct answer is C. $-\frac{5}{4}$. $-\frac{5}{4}=-1.25$, which is to the left of (-1). In exams, convert negative fractions into decimals to check.

Step 3

Exam Tip

$-\frac{5}{4}=-1.25$, जो (-1) से बाईं ओर है। परीक्षा में ऋणात्मक भिन्न को दशमलव में बदलकर जांच सकते हैं।

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Question Medium Mathematics Polynomials Representing real numbers on the number line Class 10 Level 50

संख्या रेखा पर $-\sqrt{30}$ किस दो पूर्णांकों के बीच होगा?

Between which two integers will $-\sqrt{30}$ lie on the number line?

Explanation opens after your attempt

Correct Answer

B. (-6) और (-5)(-6) and (-5)

Step 1

Concept

Since $\sqrt{30}$ lies between (5) and (6), $-\sqrt{30}$ lies between (-6) and (-5). In exams, keep the negative direction in mind.

Step 2

Why this answer is correct

The correct answer is B. (-6) और (-5) / (-6) and (-5). Since $\sqrt{30}$ lies between (5) and (6), $-\sqrt{30}$ lies between (-6) and (-5). In exams, keep the negative direction in mind.

Step 3

Exam Tip

क्योंकि $\sqrt{30}$ (5) और (6) के बीच है, इसलिए $-\sqrt{30}$ (-6) और (-5) के बीच होगा। परीक्षा में ऋणात्मक दिशा को ध्यान रखें।

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Question Medium Mathematics Polynomials Representing real numbers on the number line Class 10 Level 50

संख्या रेखा पर $\sqrt{27}$ किस दो पूर्णांकों के बीच स्थित होगा?

Between which two integers will $\sqrt{27}$ lie on the number line?

Explanation opens after your attempt

Correct Answer

C. (5) और (6)(5) and (6)

Step 1

Concept

Since $5^2=25$ and $6^2=36$, $\sqrt{27}$ lies between (5) and (6). In exams, remember nearby perfect squares.

Step 2

Why this answer is correct

The correct answer is C. (5) और (6) / (5) and (6). Since $5^2=25$ and $6^2=36$, $\sqrt{27}$ lies between (5) and (6). In exams, remember nearby perfect squares.

Step 3

Exam Tip

क्योंकि $5^2=25$ और $6^2=36$, इसलिए $\sqrt{27}$ (5) और (6) के बीच है। परीक्षा में निकट पूर्ण वर्गों को याद रखें।

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Question Medium Mathematics Polynomials Representing real numbers on the number line Class 10 Level 49

संख्या रेखा पर $\frac{-13}{6}$ की स्थिति किस विकल्प से सही बतती है?

Which option correctly describes the position of $\frac{-13}{6}$ on the number line?

Explanation opens after your attempt

Correct Answer

A. यह (-2) और (-3) के बीच हैIt is between (-2) and (-3)

Step 1

Concept

$\frac{-13}{6}\approx -2.17$, so it lies between (-3) and (-2). Intervals with negative numbers can be tricky.

Step 2

Why this answer is correct

The correct answer is A. यह (-2) और (-3) के बीच है / It is between (-2) and (-3). $\frac{-13}{6}\approx -2.17$, so it lies between (-3) and (-2). Intervals with negative numbers can be tricky.

Step 3

Exam Tip

$\frac{-13}{6}\approx -2.17$, इसलिए यह (-3) और (-2) के बीच है। ऋणात्मक संख्या में पूर्णांक अंतराल उलझा सकता है।

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Question Easy Mathematics Polynomials Representing real numbers on the number line Class 10 Level 50

संख्या रेखा पर $\frac{1}{3}$ दिखाने के लिए (0) और (1) के बीच कौन-सा निशान लेना चाहिए?

To show $\frac{1}{3}$ on the number line, which mark between (0) and (1) should be taken?

Explanation opens after your attempt

Correct Answer

A. तीन बराबर भागों में पहला निशानfirst mark among three equal parts

Step 1

Concept

For $\frac{1}{3}$, divide (0) to (1) into (3) equal parts and take the first mark. The denominator tells the number of parts.

Step 2

Why this answer is correct

The correct answer is A. तीन बराबर भागों में पहला निशान / first mark among three equal parts. For $\frac{1}{3}$, divide (0) to (1) into (3) equal parts and take the first mark. The denominator tells the number of parts.

Step 3

Exam Tip

$\frac{1}{3}$ के लिए (0) से (1) तक (3) बराबर भाग करें और पहला निशान लें। हर भागों की संख्या बताता है।

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Question Easy Mathematics Polynomials Representing real numbers on the number line Class 10 Level 49

संख्या रेखा पर (0.75) किस बिंदु के बराबर है?

Which point is equal to (0.75) on the number line?

Explanation opens after your attempt

Correct Answer

A. $\frac{3}{4}$

Step 1

Concept

$0.75=\frac{75}{100}=\frac{3}{4}$. It is three-fourths of the distance from (0) to (1).

Step 2

Why this answer is correct

The correct answer is A. $\frac{3}{4}$. $0.75=\frac{75}{100}=\frac{3}{4}$. It is three-fourths of the distance from (0) to (1).

Step 3

Exam Tip

$0.75=\frac{75}{100}=\frac{3}{4}$। (0) से (1) के बीच यह तीन-चौथाई दूरी पर है।

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Question Easy Mathematics Polynomials Representing real numbers on the number line Class 10 Level 49

संख्या रेखा पर $\frac{3}{4}$ को दिखाने के लिए (0) और (1) के बीच भागों की संख्या कितनी करनी चाहिए?

To represent $\frac{3}{4}$ on the number line, into how many equal parts should the segment from (0) to (1) be divided?

Explanation opens after your attempt

Correct Answer

A. (4) भाग(4) parts

Step 1

Concept

The denominator of $\frac{3}{4}$ is (4), so divide (0) to (1) into (4) equal parts. Then move (3) parts to the right.

Step 2

Why this answer is correct

The correct answer is A. (4) भाग / (4) parts. The denominator of $\frac{3}{4}$ is (4), so divide (0) to (1) into (4) equal parts. Then move (3) parts to the right.

Step 3

Exam Tip

$\frac{3}{4}$ में हर (4) है, इसलिए (0) से (1) को (4) बराबर भागों में बाँटते हैं। फिर (3) भाग दाईं ओर जाते हैं।

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Question Expert Mathematics Quadratic Equations Nature of Roots Class 10 Level 39

समीकरण (x^-2+2(v+2)x+(4v+11)=0) के कोई वास्तविक मूल नहीं होने की सही शर्त क्या है?

What is the correct condition for (x^-2+2(v+2)x+(4v+11)=0) to have no real roots?

Explanation opens after your attempt

Correct Answer

A. $-\sqrt{7}<v<\sqrt{7}$

Step 1

Concept

Here (D=4(v+2)²-4(4v+11)=4$v^2-7$). From (D<0), $-\sqrt{7}<v<\sqrt{7}$.

Step 2

Why this answer is correct

The correct answer is A. $-\sqrt{7}<v<\sqrt{7}$. Here (D=4(v+2)²-4(4v+11)=4$v^2-7$). From (D<0), $-\sqrt{7}<v<\sqrt{7}$.

Step 3

Exam Tip

यहाँ (D=4(v+2)²-4(4v+11)=4$v^2-7$) है। (D<0) से $-\sqrt{7}<v<\sqrt{7}$।

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Question Expert Mathematics Quadratic Equations Nature of Roots Class 10 Level 38

समीकरण (x^-2+2(t+1)x+(3t+7)=0) के कोई वास्तविक मूल नहीं होने की सही शर्त क्या है?

What is the correct condition for (x^-2+2(t+1)x+(3t+7)=0) to have no real roots?

Explanation opens after your attempt

Correct Answer

A. (-2<t<3)

Step 1

Concept

Here (D=4$t^2-t-6$=4(t-3)(t+2)). From (D<0), we get (-2<t<3).

Step 2

Why this answer is correct

The correct answer is A. (-2<t<3). Here (D=4$t^2-t-6$=4(t-3)(t+2)). From (D<0), we get (-2<t<3).

Step 3

Exam Tip

यहाँ (D=4$t^2-t-6$=4(t-3)(t+2)) है। (D<0) से (-2<t<3) मिलता है।

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Question Expert Mathematics Quadratic Equations Nature of Roots Class 10 Level 37

समीकरण (3x^-2-2(2k+1)x+(k+1)²=0) के दो असमान वास्तविक मूलों के लिए कौन सी शर्त सही है?

Which condition is correct for two distinct real roots of (3x^-2-2(2k+1)x+(k+1)²=0)?

Explanation opens after your attempt

Correct Answer

A. (k<-2) या (k>1)(k<-2) or (k>1)

Step 1

Concept

Here (D=4(k-1)(k+2)). From (D>0), we get (k<-2) or (k>1).

Step 2

Why this answer is correct

The correct answer is A. (k<-2) या (k>1) / (k<-2) or (k>1). Here (D=4(k-1)(k+2)). From (D>0), we get (k<-2) or (k>1).

Step 3

Exam Tip

यहाँ (D=4(k-1)(k+2)) है। (D>0) से (k<-2) या (k>1) मिलता है।

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Question Expert Mathematics Quadratic Equations Nature of Roots Class 10 Level 37

समीकरण (x^-2+2(k-1)x+(k+5)=0) के कोई वास्तविक मूल नहीं होने की सही शर्त क्या है?

What is the correct condition for (x^-2+2(k-1)x+(k+5)=0) to have no real roots?

Explanation opens after your attempt

Correct Answer

A. (-1<k<4)

Step 1

Concept

Here (D=4((k-1)²-(k+5))=4$k^2-3k-4$). From (D<0), ((k-4)(k+1)<0), so (-1<k<4).

Step 2

Why this answer is correct

The correct answer is A. (-1<k<4). Here (D=4((k-1)²-(k+5))=4$k^2-3k-4$). From (D<0), ((k-4)(k+1)<0), so (-1<k<4).

Step 3

Exam Tip

यहाँ (D=4((k-1)²-(k+5))=4$k^2-3k-4$) है। (D<0) से ((k-4)(k+1)<0), इसलिए (-1<k<4)।

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Question Medium Mathematics Quadratic Equations Nature of Roots Class 10 Level 39

यदि (3x^-2+(k-2)x+4=0) के दो असमान वास्तविक मूल हों, तो (k) पर कौन सी शर्त सही है?

If (3x^-2+(k-2)x+4=0) has two distinct real roots, which condition on (k) is correct?

Explanation opens after your attempt

Correct Answer

A. $k<2-4\sqrt{3}$ या $k>2+4\sqrt{3}$$k<2-4\sqrt{3}$ or $k>2+4\sqrt{3}$

Step 1

Concept

Here (D=(k-2)²-48). For distinct real roots (D>0), so ((k-2)²>48).

Step 2

Why this answer is correct

The correct answer is A. $k<2-4\sqrt{3}$ या $k>2+4\sqrt{3}$ / $k<2-4\sqrt{3}$ or $k>2+4\sqrt{3}$. Here (D=(k-2)²-48). For distinct real roots (D>0), so ((k-2)²>48).

Step 3

Exam Tip

यहाँ (D=(k-2)²-48) है। असमान वास्तविक मूलों के लिए (D>0), इसलिए ((k-2)²>48)।

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Question Hard Mathematics Quadratic Equations Nature of Roots Class 10 Level 38

समीकरण (3x^-2-2(2a+1)x+$a^2+a+1$=0) के वास्तविक और भिन्न मूल कब होंगे?

When will (3x^-2-2(2a+1)x+$a^2+a+1$=0) have real and distinct roots?

Explanation opens after your attempt

Correct Answer

A. (a<-2) या (a>1)(a<-2) or (a>1)

Step 1

Concept

For real and distinct roots, (D>0) is needed. From $a^2+a-2>0$, we get (a<-2) or (a>1).

Step 2

Why this answer is correct

The correct answer is A. (a<-2) या (a>1) / (a<-2) or (a>1). For real and distinct roots, (D>0) is needed. From $a^2+a-2>0$, we get (a<-2) or (a>1).

Step 3

Exam Tip

वास्तविक और भिन्न मूलों के लिए (D>0) चाहिए। $a^2+a-2>0$ से (a<-2) या (a>1) मिलता है।

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Question Hard Mathematics Quadratic Equations Nature of Roots Class 10 Level 38

यदि (D=(s^-2)(s+5)) है, तो मूल वास्तविक और भिन्न कब होंगे?

If (D=(s^-2)(s+5)), when will the roots be real and distinct?

Explanation opens after your attempt

Correct Answer

A. (s<-5) या (s>2)(s<-5) or (s>2)

Step 1

Concept

For real and distinct roots, (D>0) is required. From ((s^-2)(s+5)>0), we get (s<-5) or (s>2).

Step 2

Why this answer is correct

The correct answer is A. (s<-5) या (s>2) / (s<-5) or (s>2). For real and distinct roots, (D>0) is required. From ((s^-2)(s+5)>0), we get (s<-5) or (s>2).

Step 3

Exam Tip

वास्तविक और भिन्न मूलों के लिए (D>0) चाहिए। ((s^-2)(s+5)>0) से (s<-5) या (s>2) मिलता है।

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Question Hard Mathematics Quadratic Equations Nature of Roots Class 10 Level 38

यदि $x^2+2px+2p+9=0$ के मूल वास्तविक हैं, तो (p) पर सही शर्त कौन सी है?

If $x^2+2px+2p+9=0$ has real roots, which condition on (p) is correct?

Explanation opens after your attempt

Correct Answer

A. $p\le -2$ या $p\ge \frac{9}{2}$$p\le -2$ or $p\ge \frac{9}{2}$

Step 1

Concept

For real roots, $D\ge0$ is required. Here (D=4(p+2)(2p-9)), so $p\le -2$ or $p\ge \frac{9}{2}$.

Step 2

Why this answer is correct

The correct answer is A. $p\le -2$ या $p\ge \frac{9}{2}$ / $p\le -2$ or $p\ge \frac{9}{2}$. For real roots, $D\ge0$ is required. Here (D=4(p+2)(2p-9)), so $p\le -2$ or $p\ge \frac{9}{2}$.

Step 3

Exam Tip

वास्तविक मूलों के लिए $D\ge0$ चाहिए। यहाँ (D=4(p+2)(2p-9)), इसलिए $p\le -2$ या $p\ge \frac{9}{2}$।

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Question Medium Mathematics Quadratic Equations Nature of Roots Class 10 Level 38

यदि (2x^-2+(k+1)x+3=0) के दो असमान वास्तविक मूल हों, तो (k) पर कौन सी शर्त सही है?

If (2x^-2+(k+1)x+3=0) has two distinct real roots, which condition on (k) is correct?

Explanation opens after your attempt

Correct Answer

A. $k<-1-2\sqrt{6}$ या $k>-1+2\sqrt{6}$$k<-1-2\sqrt{6}$ or $k>-1+2\sqrt{6}$

Step 1

Concept

Here (D=(k+1)²-24). For distinct real roots (D>0), so ((k+1)²>24).

Step 2

Why this answer is correct

The correct answer is A. $k<-1-2\sqrt{6}$ या $k>-1+2\sqrt{6}$ / $k<-1-2\sqrt{6}$ or $k>-1+2\sqrt{6}$. Here (D=(k+1)²-24). For distinct real roots (D>0), so ((k+1)²>24).

Step 3

Exam Tip

यहाँ (D=(k+1)²-24) है। असमान वास्तविक मूलों के लिए (D>0), इसलिए ((k+1)²>24)।

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Question Hard Mathematics Quadratic Equations Nature of Roots Class 10 Level 37

समीकरण $x^2-2mx+3m=0$ के वास्तविक और भिन्न मूलों के लिए (m) पर क्या शर्त है?

What condition on (m) gives real and distinct roots for $x^2-2mx+3m=0$?

Explanation opens after your attempt

Correct Answer

A. (m<0) या (m>3)(m<0) or (m>3)

Step 1

Concept

Here (D=4m(m^-3)). From (D>0), (m<0) or (m>3).

Step 2

Why this answer is correct

The correct answer is A. (m<0) या (m>3) / (m<0) or (m>3). Here (D=4m(m^-3)). From (D>0), (m<0) or (m>3).

Step 3

Exam Tip

यहाँ (D=4m(m^-3)) है। (D>0) से (m<0) या (m>3) मिलता है।

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Question Hard Mathematics Quadratic Equations Nature of Roots Class 10 Level 37

किस शर्त पर $x^2-2sx+s+2=0$ के मूल वास्तविक और भिन्न होंगे?

Under which condition will $x^2-2sx+s+2=0$ have real and distinct roots?

Explanation opens after your attempt

Correct Answer

A. (s<-1) या (s>2)(s<-1) or (s>2)

Step 1

Concept

Here (D=4s^-2-4(s+2)=4(s^-2)(s+1)). From (D>0), (s<-1) or (s>2).

Step 2

Why this answer is correct

The correct answer is A. (s<-1) या (s>2) / (s<-1) or (s>2). Here (D=4s^-2-4(s+2)=4(s^-2)(s+1)). From (D>0), (s<-1) or (s>2).

Step 3

Exam Tip

यहाँ (D=4s^-2-4(s+2)=4(s^-2)(s+1)) है। (D>0) से (s<-1) या (s>2) मिलता है।

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Question Medium Mathematics Quadratic Equations Nature of Roots Class 10 Level 37

समीकरण (x^-2+(m^-2)x+1=0) में वास्तविक मूल न होने के लिए (m) पर कौन सी शर्त सही है?

Which condition on (m) gives no real roots in (x^-2+(m^-2)x+1=0)?

Explanation opens after your attempt

Correct Answer

A. (0<m<4)

Step 1

Concept

Here (D=(m^-2)²-4), and we need (D<0). This gives (0<m<4).

Step 2

Why this answer is correct

The correct answer is A. (0<m<4). Here (D=(m^-2)²-4), and we need (D<0). This gives (0<m<4).

Step 3

Exam Tip

यहाँ (D=(m^-2)²-4) है और (D<0) चाहिए। इससे (0<m<4) मिलता है।

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Question Expert Mathematics Polynomials Geometrical meaning of the zeroes of a polynomial. Class 10 Level 23

यदि (p(x)=(x+9)(x-5)(x-12)) है, तो (5<x<12) में (p(x)) का चिह्न क्या होगा?

If (p(x)=(x+9)(x-5)(x-12)), what will be the sign of (p(x)) for (5<x<12)?

Explanation opens after your attempt

Correct Answer

B. ऋणात्मकNegative

Step 1

Concept

In this interval the first two factors are positive and the third is negative, so the product is negative. Tip: check the sign of each factor separately.

Step 2

Why this answer is correct

The correct answer is B. ऋणात्मक / Negative. In this interval the first two factors are positive and the third is negative, so the product is negative. Tip: check the sign of each factor separately.

Step 3

Exam Tip

इस अंतराल में पहले दो कारक धनात्मक और तीसरा ऋणात्मक है, इसलिए गुणनफल ऋणात्मक है। टिप: प्रत्येक कारक का चिह्न अलग जांचें।

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Question Expert Mathematics Polynomials Geometrical meaning of the zeroes of a polynomial. Class 10 Level 23

यदि (p(x)=-(x+8)(x-2)(x-6)) है, तो (2<x<6) में ग्राफ (x)-अक्ष के किस ओर होगा?

If (p(x)=-(x+8)(x-2)(x-6)), on which side of the (x)-axis will the graph lie for (2<x<6)?

Explanation opens after your attempt

Correct Answer

A. ऊपरAbove

Step 1

Concept

In this interval the factor signs are (+), (+), (-), and the outside negative makes the value positive. Tip: apply the outside sign at the end.

Step 2

Why this answer is correct

The correct answer is A. ऊपर / Above. In this interval the factor signs are (+), (+), (-), and the outside negative makes the value positive. Tip: apply the outside sign at the end.

Step 3

Exam Tip

इस अंतराल में कारकों के चिह्न (+), (+), (-) हैं और बाहर का ऋण चिन्ह मान को धनात्मक बनाता है। टिप: बाहरी चिन्ह को अंत में लगाएं।

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Question Expert Mathematics Polynomials Geometrical meaning of the zeroes of a polynomial. Class 10 Level 22

यदि (p(x)=(x+6)(x-4)(x-10)) है, तो (4<x<10) में (p(x)) का चिह्न क्या होगा?

If (p(x)=(x+6)(x-4)(x-10)), what will be the sign of (p(x)) for (4<x<10)?

Explanation opens after your attempt

Correct Answer

B. ऋणात्मकNegative

Step 1

Concept

In this interval the first two factors are positive and the third is negative, so the product is negative. Tip: check the sign of each factor separately.

Step 2

Why this answer is correct

The correct answer is B. ऋणात्मक / Negative. In this interval the first two factors are positive and the third is negative, so the product is negative. Tip: check the sign of each factor separately.

Step 3

Exam Tip

इस अंतराल में पहले दो कारक धनात्मक और तीसरा ऋणात्मक है, इसलिए गुणनफल ऋणात्मक है। टिप: प्रत्येक कारक का चिह्न अलग जांचें।

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Question Expert Mathematics Polynomials Geometrical meaning of the zeroes of a polynomial. Class 10 Level 22

यदि (p(x)=-(x-3)(x+7)(x-1)) है, तो (1<x<3) में ग्राफ (x)-अक्ष के किस ओर होगा?

If (p(x)=-(x-3)(x+7)(x-1)), on which side of the (x)-axis will the graph lie for (1<x<3)?

Explanation opens after your attempt

Correct Answer

A. ऊपरAbove

Step 1

Concept

In this interval the factor signs are (-), (+), (+), and the outside negative makes the value positive. Tip: apply the outside sign at the end.

Step 2

Why this answer is correct

The correct answer is A. ऊपर / Above. In this interval the factor signs are (-), (+), (+), and the outside negative makes the value positive. Tip: apply the outside sign at the end.

Step 3

Exam Tip

इस अंतराल में कारकों के चिह्न (-), (+), (+) हैं और बाहर का ऋण चिन्ह मान को धनात्मक बनाता है। टिप: बाहरी चिन्ह को अंत में लगाएं।

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Question Hard Mathematics Polynomials Geometrical meaning of the zeroes of a polynomial. Class 10 Level 24

यदि (p(x)=(x+5)(x-3)(x-9)) है तो (3<x<9) में (p(x)) का चिह्न क्या होगा?

If (p(x)=(x+5)(x-3)(x-9)), what will be the sign of (p(x)) for (3<x<9)?

Explanation opens after your attempt

Correct Answer

B. ऋणात्मकNegative

Step 1

Concept

In this interval the first two factors are positive and the third is negative, so the product is negative. Tip: check factor signs separately.

Step 2

Why this answer is correct

The correct answer is B. ऋणात्मक / Negative. In this interval the first two factors are positive and the third is negative, so the product is negative. Tip: check factor signs separately.

Step 3

Exam Tip

इस अंतराल में पहले दो कारक धनात्मक और तीसरा ऋणात्मक है इसलिए गुणनफल ऋणात्मक है। टिप: कारकों के चिह्न अलग-अलग जांचें।

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Question Hard Mathematics Polynomials Geometrical meaning of the zeroes of a polynomial. Class 10 Level 23

यदि (p(x)=(x+4)(x-2)(x-7)) है, तो (2<x<7) में (p(x)) का चिह्न क्या होगा?

If (p(x)=(x+4)(x-2)(x-7)), what will be the sign of (p(x)) for (2<x<7)?

Explanation opens after your attempt

Correct Answer

B. ऋणात्मकNegative

Step 1

Concept

In this interval the first two factors are positive and the third is negative, so the product is negative. Tip: check factor signs separately.

Step 2

Why this answer is correct

The correct answer is B. ऋणात्मक / Negative. In this interval the first two factors are positive and the third is negative, so the product is negative. Tip: check factor signs separately.

Step 3

Exam Tip

इस अंतराल में पहले दो कारक धनात्मक और तीसरा ऋणात्मक है, इसलिए गुणनफल ऋणात्मक है। टिप: कारकों के चिह्न अलग-अलग जाँचें।

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Question Hard Mathematics Polynomials Geometrical meaning of the zeroes of a polynomial. Class 10 Level 22

यदि (p(x)=(x+2)(x-1)(x-6)) है, तो (1<x<6) में (p(x)) का चिह्न क्या होगा?

If (p(x)=(x+2)(x-1)(x-6)), what will be the sign of (p(x)) for (1<x<6)?

Explanation opens after your attempt

Correct Answer

B. ऋणात्मकNegative

Step 1

Concept

In this interval the first two factors are positive and the third is negative, so the product is negative. Tip: check the sign of each factor separately.

Step 2

Why this answer is correct

The correct answer is B. ऋणात्मक / Negative. In this interval the first two factors are positive and the third is negative, so the product is negative. Tip: check the sign of each factor separately.

Step 3

Exam Tip

इस अंतराल में पहले दो कारक धनात्मक और तीसरा ऋणात्मक है, इसलिए गुणनफल ऋणात्मक है। टिप: प्रत्येक कारक का चिह्न अलग जांचें।

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Question Expert Mathematics Real Numbers HCF and LCM using prime factorisation Class 10 Level 12

चार यंत्र क्रमशः (28), (36), (63) और (84) सेकंड के अंतराल पर संकेत देते हैं। वे अभी साथ संकेत देते हैं। वे फिर कितने सेकंड बाद साथ संकेत देंगे?

Four devices give signals at intervals of (28), (36), (63), and (84) seconds respectively. They signal together now. After how many seconds will they signal together again?

Explanation opens after your attempt

Correct Answer

B. (252)

Step 1

Concept

The next common signal time is the LCM of all intervals.

Step 2

Why this answer is correct

$28=2^2\times7$, $36=2^2\times3^2$, $63=3^2\times7$, and $84=2^2\times3\times7$, so the LCM is (252).

Step 3

Exam Tip

Use LCM for repeated-time questions. चरण 1: साथ में दोबारा संकेत देने का समय सभी अंतरालों का लघुत्तम समापवर्त्य होता है। चरण 2: $28=2^2\times7$, $36=2^2\times3^2$, $63=3^2\times7$, $84=2^2\times3\times7$, इसलिए लघुत्तम समापवर्त्य (252) है। चरण 3: दोहराव वाले समय प्रश्नों में लघुत्तम समापवर्त्य लें।

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Question Expert Mathematics Real Numbers HCF and LCM using prime factorisation Class 10 Level 11

चार स्वचालित संकेत क्रमशः (18), (27), (45) और (60) सेकंड के अंतराल पर बजते हैं। वे अभी साथ बजे हैं। वे फिर कितने सेकंड बाद साथ बजेंगे?

Four automatic signals ring at intervals of (18), (27), (45), and (60) seconds respectively. They ring together now. After how many seconds will they ring together again?

Explanation opens after your attempt

Correct Answer

A. (540)

Step 1

Concept

The next common ringing time is the LCM of the intervals.

Step 2

Why this answer is correct

$18=2\times3^2$, $27=3^3$, $45=3^2\times5$, and $60=2^2\times3\times5$, so LCM $=2^2\times3^3\times5=540$.

Step 3

Exam Tip

For repeated-time questions, use LCM. चरण 1: साथ में दोबारा बजने का समय अंतरालों का लघुत्तम समापवर्त्य होता है। चरण 2: $18=2\times3^2$, $27=3^3$, $45=3^2\times5$, $60=2^2\times3\times5$, इसलिए लघुत्तम समापवर्त्य $2^2\times3^3\times5=540$ है। चरण 3: दोहराव वाले समय प्रश्नों में लघुत्तम समापवर्त्य लें।

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Question Expert Mathematics Real Numbers HCF and LCM using prime factorisation Class 10 Level 10

तीन घंटियाँ क्रमशः (45), (60) और (84) सेकंड के अंतराल पर बजती हैं। यदि वे अभी साथ बजी हैं, तो वे फिर कितने सेकंड बाद साथ बजेंगी?

Three bells ring at intervals of (45), (60), and (84) seconds respectively. If they ring together now, after how many seconds will they ring together again?

Explanation opens after your attempt

Correct Answer

A. (1260)

Step 1

Concept

The next common ringing time is the LCM of the intervals.

Step 2

Why this answer is correct

$45=3^2\times5$, $60=2^2\times3\times5$, and $84=2^2\times3\times7$, so LCM $=2^2\times3^2\times5\times7=1260$.

Step 3

Exam Tip

Use LCM for repeated-time questions. चरण 1: साथ में दोबारा बजने का समय अंतरालों का लघुत्तम समापवर्त्य होता है। चरण 2: $45=3^2\times5$, $60=2^2\times3\times5$, $84=2^2\times3\times7$, इसलिए लघुत्तम समापवर्त्य $2^2\times3^2\times5\times7=1260$ है। चरण 3: समय के दोहराव वाले प्रश्नों में लघुत्तम समापवर्त्य उपयोग करें।

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दो पूरक कोणों में एक कोण दूसरे से \(28^\circ\) अधिक है। बड़ा कोण क्या है?

Concept

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Exam Tip

यदि संख्या रेखा पर \(u=-\sqrt{27}-3\), तो (u) किस अंतराल में है?

Concept

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Exam Tip

संख्या रेखा पर \(6-\sqrt{39}\) का सही स्थान किस अंतराल में है?

Concept

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Exam Tip

यदि संख्या रेखा पर \(u=-\sqrt{18}-2\), तो (u) किस अंतराल में है?

Concept

Why this answer is correct

Exam Tip

संख्या रेखा पर \(5-\sqrt{31}\) का सही स्थान किस अंतराल में है?

Concept

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Exam Tip

यदि संख्या रेखा पर \(u=-2-\sqrt{7}\), तो (u) किस अंतराल में स्थित है?

Concept

Why this answer is correct

Exam Tip

यदि \(x=-5+\sqrt{22}\), तो संख्या रेखा पर (x) किस अंतराल में है?

Concept

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Exam Tip

यदि संख्या रेखा पर \(x=-\sqrt{29}\), तो (x) किस अंतराल में होगा?

Concept

Why this answer is correct

Exam Tip

यदि संख्या रेखा पर \(u=-\sqrt{2}-1\), तो (u) किस अंतराल में है?

Concept

Why this answer is correct

Exam Tip

संख्या रेखा पर \(2-\sqrt{10}\) का सही स्थान किस अंतराल में है?

Concept

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Exam Tip

संख्या रेखा पर (x) का स्थान ( -4 ) से \( \sqrt{13} \) इकाई दाईं ओर है। (x) किस अंतराल में है?

Concept

Why this answer is correct

Exam Tip

संख्या रेखा पर \(\sqrt{5}-\sqrt{2}\) किस अंतराल में स्थित होगा?

Concept

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Exam Tip

किस विकल्प में संख्या रेखा पर \(-\sqrt{12}\) का सही सरल अंतराल है?

Concept

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Exam Tip

संख्या रेखा पर \(\sqrt{2}+\sqrt{3}\) किस अंतराल में होगा?

Concept

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Exam Tip

किस विकल्प में संख्या रेखा पर \(-1+\sqrt{5}\) का सही अंतराल है?

Concept

Why this answer is correct

Exam Tip

संख्या रेखा पर \(2-\sqrt{3}\) किस अंतराल में स्थित होगा?

Concept

Why this answer is correct

Exam Tip

किस विकल्प में \(\sqrt{20}\) का संख्या रेखा पर सही अंतराल दिया गया है?

Concept

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Exam Tip

संख्या रेखा पर \(-\sqrt{5}\) की स्थिति किस अंतराल में होगी?

Concept

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Exam Tip

समीकरण (x-2-2(4t+1)x+\(7t^2+2t+5\)=0) के कोई वास्तविक मूल नहीं हैं। (t) के लिए सही अंतराल क्या है?

Concept

Why this answer is correct

Exam Tip

यदि (x-2+2(v+2)x+(4v+11)=0) के कोई वास्तविक मूल नहीं हों, तो (v) किस अंतराल में होगा?

Concept

Why this answer is correct

समीकरण (x^-2-2(4t+1)x+\(7t^2+2t+5\)=0) के कोई वास्तविक मूल नहीं हैं। (t) के लिए सही अंतराल क्या है?

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समीकरण (x^-2-2(3t+1)x+\(5t^2+2t+4\)=0) के कोई वास्तविक मूल नहीं हैं। (t) के लिए सही अंतराल क्या है?

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समीकरण (x^-2-2(2t-1)x+\(t^2+2\)=0) के कोई वास्तविक मूल नहीं हैं। (t) के लिए सही अंतराल चुनिए।

यदि (x^-2+2(k-1)x+(k+5)=0) के कोई वास्तविक मूल नहीं हैं, तो (k) किस अंतराल में होगा?

समीकरण (x^-2+(k+2)x+9=0) में कोई वास्तविक मूल न होने के लिए (k) का अंतराल क्या है?

समीकरण (3x^-2-2(2a+1)x+\(a^2+a+1\)=0) के वास्तविक मूल न होने का अंतराल कौन सा है?

यदि विविक्तकर (D=(z+1)²-9) है, तो वास्तविक मूल न होने के लिए (z) किस अंतराल में होगा?

समीकरण (x^-2+(k-3)x+4=0) में कोई वास्तविक मूल न होने के लिए (k) का अंतराल क्या है?

समीकरण (x^-2+2(a-2)x+2a+5=0) के वास्तविक मूल न होने के लिए (a) किस अंतराल में होगा?

समीकरण (x^-2-(k+1)x+4=0) में वास्तविक मूल न होने के लिए (k) किस अंतराल में होगा?