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Subjects
Class 10MathematicsPolynomialsRepresenting real numbers on the number lineExpertLevel 51
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In which interval is (6-\sqrt{39}) correctly located on the number line?

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Answer and explanation

Correct answer: Between ( -1 ) and (0)

( \sqrt{39}\approx6.245 ), so (6-\sqrt{39}\approx-0.245). Always check the sign in root subtraction.

Related tags

Number-LineRoot-ExpressionInterval

Frequently asked questions

What is the correct answer to this question?

Between ( -1 ) and (0)

Why is this the correct answer?

( \sqrt{39}\approx6.245 ), so (6-\sqrt{39}\approx-0.245). Always check the sign in root subtraction.

Which subject and chapter does this question cover?

This is a Class 10 Mathematics question. Chapter: Polynomials. Topic: Representing real numbers on the number line.

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10 more MCQs
  1. 1Which number lies to the right of (0) on the number line?
  2. 2Which number lies to the left of 0 on the number line?
  3. 3Which number lies between 2 and 3 on the number line?
  4. 4Between which two integers does (\frac{1}{2}) lie on the number line?
  5. 5What is the distance between 4 and 6 on the number line?
  6. 6Which of the following numbers is irrational and can be represented by a unique point on the number line?
  7. 7Which number is to the right on the number line between (-5) and (-2)?
  8. 8Which of the following fractions is equal to \\(1.25\\) on the number line?
  9. 9To represent (\frac{3}{4}) on the number line, into how many equal parts should the segment from (0) to (1) be divided?
  10. 10Between which two integers does (\frac{7}{4}) lie on the number line?
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