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If (x^2+2px+2p+9=0) has real roots, which condition on (p) is correct?यदि (x^2+2px+2p+9=0) के मूल वास्तविक हैं, तो (p) पर सही शर्त कौन सी है?
Answer and explanationउत्तर और व्याख्या
Correct answer:सही उत्तर: (p\le -2) or (p\ge \frac{9}{2})(p\le -2) या (p\ge \frac{9}{2})
For real roots, (D\ge0) is required. Here (D=4(p+2)(2p-9)), so (p\le -2) or (p\ge \frac{9}{2}).वास्तविक मूलों के लिए (D\ge0) चाहिए। यहाँ (D=4(p+2)(2p-9)), इसलिए (p\le -2) या (p\ge \frac{9}{2})।
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