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If (x^2+2(v+2)x+(4v+11)=0) has no real roots, in which interval will (v) lie?यदि (x^2+2(v+2)x+(4v+11)=0) के कोई वास्तविक मूल नहीं हों, तो (v) किस अंतराल में होगा?
Answer and explanationउत्तर और व्याख्या
Correct answer:सही उत्तर: (-3<v<1)(-3<v<1)
Here (D=4(v+2)^2-4(4v+11)) must be expanded carefully. Always verify the middle term before solving the interval.यहाँ (D=4(v+2)^2-4(4v+11)=4(v^2-7)) नहीं, सही रूप (4(v^2-7)) नहीं है। परीक्षा में विस्तार सावधानी से करें।
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