7 results found for "leading coefficient" in Class 10.
Question
Medium Mathematics
Quadratic Equations Roots of a Quadratic Equation Class 10 Level 33
यदि किसी द्विघात समीकरण के मूल (c) और (-c) हैं तो अचर पद और अग्र गुणांक के अनुपात \(\frac{d}{a}\) का मान क्या होगा?
If the roots of a quadratic equation are (c) and (-c), what is the value of the ratio \(\frac{d}{a}\) of constant term to leading coefficient?
#roots
#opposite_roots
#product
A \(-c^2\)
B \(c^2\)
C (0)
D (2c)
Explanation opens after your attempt
Correct Answer
A. \(-c^2\)
Step 1
Concept
\(\frac{d}{a}\) is the product of roots. Here (c(-c)=-c-2 ).
Step 2
Why this answer is correct
The correct answer is A. \(-c^2\). \(\frac{d}{a}\) is the product of roots. Here (c(-c)=-c-2 ).
Step 3
Exam Tip
\(\frac{d}{a}\) मूलों का गुणनफल होता है। यहां (c(-c)=-c-2 ) है।
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Question
Medium Mathematics
Quadratic Equations Roots of a Quadratic Equation Class 10 Level 32
यदि किसी द्विघात समीकरण के मूल (b) और (-b) हैं तो अचर पद और अग्र गुणांक के अनुपात \(\frac{c}{a}\) का मान क्या होगा?
If the roots of a quadratic equation are (b) and (-b), what is the value of the ratio \(\frac{c}{a}\) of constant term to leading coefficient?
#roots
#opposite_roots
#product
A \(-b^2\)
B \(b^2\)
C (0)
D (2b)
Explanation opens after your attempt
Correct Answer
A. \(-b^2\)
Step 1
Concept
\(\frac{c}{a}\) is the product of roots. Here (b(-b)=-b-2 ).
Step 2
Why this answer is correct
The correct answer is A. \(-b^2\). \(\frac{c}{a}\) is the product of roots. Here (b(-b)=-b-2 ).
Step 3
Exam Tip
\(\frac{c}{a}\) मूलों का गुणनफल होता है। यहां (b(-b)=-b-2 ) है।
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Question
Medium Mathematics
Quadratic Equations Roots of a Quadratic Equation Class 10 Level 31
यदि किसी द्विघात समीकरण के मूल (a) और (-a) हैं तो अचर पद और अग्र गुणांक के अनुपात \(\frac{c}{a_1}\) का मान क्या होगा?
If the roots of a quadratic equation are (a) and (-a), what is the value of the ratio \(\frac{c}{a_1}\) of constant term to leading coefficient?
#roots
#opposite_roots
#product
A \(-a^2\)
B \(a^2\)
C (0)
D (2a)
Explanation opens after your attempt
Correct Answer
A. \(-a^2\)
Step 1
Concept
\(\frac{c}{a_1}\) is the product of roots. Here (a(-a)=-a-2 ).
Step 2
Why this answer is correct
The correct answer is A. \(-a^2\). \(\frac{c}{a_1}\) is the product of roots. Here (a(-a)=-a-2 ).
Step 3
Exam Tip
\(\frac{c}{a_1}\) मूलों का गुणनफल होता है। यहां (a(-a)=-a-2 ) है।
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Question
Hard Mathematics
Polynomials Irrational numbers and real numbers Class 10 Level 26
यदि शून्यक \(2\sqrt{2}\) और \(3\sqrt{2}\) हैं, तो बहुपद का स्थिर पद क्या होगा यदि अग्र गुणांक (1) है?
If the zeroes are \(2\sqrt{2}\) and \(3\sqrt{2}\), what is the constant term if the leading coefficient is (1)?
#constant-term
#product
#irrational-zeroes
A (12)
B \(5\sqrt{2}\)
C \(6\sqrt{2}\)
D (10)
Explanation opens after your attempt
Step 1
Concept
The constant term equals the product of the zeroes. (\(2\sqrt{2}\)\(3\sqrt{2}\)=12).
Step 2
Why this answer is correct
The correct answer is A. (12). The constant term equals the product of the zeroes. (\(2\sqrt{2}\)\(3\sqrt{2}\)=12).
Step 3
Exam Tip
स्थिर पद शून्यकों के गुणनफल के बराबर है। (\(2\sqrt{2}\)\(3\sqrt{2}\)=12) है।
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Question
Medium Mathematics
Quadratic Equations Roots of a Quadratic Equation Class 10 Level 32
यदि किसी द्विघात समीकरण (p(x)=0) में (x=a) रखने पर (p(a)=0) हो जाता है तो (a) क्या कहलाता है?
If substituting (x=a) in a quadratic equation (p(x)=0) gives (p(a)=0), what is (a) called?
#roots
#definition
#substitution
A मूल / Root
B अचर पद / Constant term
C मध्य पद / Middle term
D अग्र गुणांक / Leading coefficient
Explanation opens after your attempt
Correct Answer
A. मूल / Root
Step 1
Concept
Since the equation becomes true after substituting (x=a), (a) is a root. In exams check a root by direct substitution.
Step 2
Why this answer is correct
The correct answer is A. मूल / Root. Since the equation becomes true after substituting (x=a), (a) is a root. In exams check a root by direct substitution.
Step 3
Exam Tip
क्योंकि (x=a) रखने पर समीकरण सत्य हो जाता है इसलिए (a) मूल है। परीक्षा में मूल की जांच सीधे प्रतिस्थापन से करें।
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Question
Easy Mathematics
Quadratic Equations Introduction to Quadratic Equations Class 10 Level 29
समीकरण ((k-1)x-2 +3x+2=0) द्विघात रहे इसके लिए कौन सी शर्त सही है?
Which condition is correct for ((k-1)x-2 +3x+2=0) to remain quadratic?
#quadratic equations
#parameter
#leading coefficient
A (k=1)
B \(k\neq1\)
C (k=0)
D (k=-1)
Explanation opens after your attempt
Correct Answer
B. \(k\neq1\)
Step 1
Concept
The coefficient of the quadratic term is ((k-1)), which must not be (0). Hence \(k\neq1\) is necessary.
Step 2
Why this answer is correct
The correct answer is B. \(k\neq1\). The coefficient of the quadratic term is ((k-1)), which must not be (0). Hence \(k\neq1\) is necessary.
Step 3
Exam Tip
द्विघात पद का गुणांक ((k-1)) है जो (0) नहीं होना चाहिए। इसलिए \(k\neq1\) होना जरूरी है।
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Question
Easy Mathematics
Quadratic Equations Introduction to Quadratic Equations Class 10 Level 29
किस शर्त पर \(px^2+qx+r=0\) द्विघात समीकरण होगा?
Under which condition will \(px^2+qx+r=0\) be a quadratic equation?
#quadratic equations
#condition
#leading coefficient
A (p=0)
B \(p\neq0\)
C (q=0)
D (r=0)
Explanation opens after your attempt
Correct Answer
B. \(p\neq0\)
Step 1
Concept
The quadratic term \(px^2\) must remain, so \(p\neq0\). If (p=0), degree (2) will not remain.
Step 2
Why this answer is correct
The correct answer is B. \(p\neq0\). The quadratic term \(px^2\) must remain, so \(p\neq0\). If (p=0), degree (2) will not remain.
Step 3
Exam Tip
द्विघात पद \(px^2\) बना रहे इसलिए \(p\neq0\) होना चाहिए। यदि (p=0) हो तो घात (2) नहीं रहेगी।
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