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quartic MCQ Questions for Class 10

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6 questions tagged with quartic.

Question 1/6 Expert Mathematics Chapter 2: Polynomials Geometrical meaning of the zeroes of a polynomial. Class 10 Level 23

यदि (p(x)=x-4-1296) है, तो वास्तविक (x)-अक्ष कटान कौन से हैं?

If (p(x)=x-4-1296), what are the real (x)-axis intersections?

Explanation opens after your attempt
Correct Answer

A. ((-6,0)) और ((6,0))((-6,0)) and ((6,0))

Step 1

Concept

(x-4-1296=\(x^2-36\)\(x^2+36\)), and the real zeroes are only \(\pm6\). Tip: \(x^2+36\) gives no real zero.

Step 2

Why this answer is correct

The correct answer is A. ((-6,0)) और ((6,0)) / ((-6,0)) and ((6,0)). (x-4-1296=\(x^2-36\)\(x^2+36\)), and the real zeroes are only \(\pm6\). Tip: \(x^2+36\) gives no real zero.

Step 3

Exam Tip

(x-4-1296=\(x^2-36\)\(x^2+36\)) है और वास्तविक शून्यक केवल \(\pm6\) हैं। टिप: \(x^2+36\) वास्तविक शून्यक नहीं देता।

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Question 2/6 Expert Mathematics Chapter 2: Polynomials Geometrical meaning of the zeroes of a polynomial. Class 10 Level 22

यदि (p(x)=x-4-625) है, तो वास्तविक (x)-अक्ष कटान कौन से हैं?

If (p(x)=x-4-625), what are the real (x)-axis intersections?

Explanation opens after your attempt
Correct Answer

A. ((-5,0)) और ((5,0))((-5,0)) and ((5,0))

Step 1

Concept

(x-4-625=\(x^2-25\)\(x^2+25\)), and the real zeroes are only \(\pm5\). Tip: \(x^2+25\) gives no real zero.

Step 2

Why this answer is correct

The correct answer is A. ((-5,0)) और ((5,0)) / ((-5,0)) and ((5,0)). (x-4-625=\(x^2-25\)\(x^2+25\)), and the real zeroes are only \(\pm5\). Tip: \(x^2+25\) gives no real zero.

Step 3

Exam Tip

(x-4-625=\(x^2-25\)\(x^2+25\)) है और वास्तविक शून्यक केवल \(\pm5\) हैं। टिप: \(x^2+25\) वास्तविक शून्यक नहीं देता।

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Question 3/6 Hard Mathematics Chapter 2: Polynomials Geometrical meaning of the zeroes of a polynomial. Class 10 Level 24

यदि (p(x)=x-4-81) है तो वास्तविक (x)-अक्ष कटान कौन से हैं?

If (p(x)=x-4-81), what are the real (x)-axis intersections?

Explanation opens after your attempt
Correct Answer

A. ((-3,0)) और ((3,0))((-3,0)) and ((3,0))

Step 1

Concept

(x-4-81=\(x^2-9\)\(x^2+9\)), and the real zeroes are only \(\pm3\). Tip: \(x^2+9\) gives no real zero.

Step 2

Why this answer is correct

The correct answer is A. ((-3,0)) और ((3,0)) / ((-3,0)) and ((3,0)). (x-4-81=\(x^2-9\)\(x^2+9\)), and the real zeroes are only \(\pm3\). Tip: \(x^2+9\) gives no real zero.

Step 3

Exam Tip

(x-4-81=\(x^2-9\)\(x^2+9\)) है और वास्तविक शून्यक केवल \(\pm3\) हैं। टिप: \(x^2+9\) वास्तविक शून्यक नहीं देता।

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Question 4/6 Hard Mathematics Chapter 2: Polynomials Geometrical meaning of the zeroes of a polynomial. Class 10 Level 23

यदि (p(x)=x-4-16) है, तो वास्तविक (x)-अक्ष कटान कौन से हैं?

If (p(x)=x-4-16), what are the real (x)-axis intersections?

Explanation opens after your attempt
Correct Answer

A. ((-2,0)) और ((2,0))((-2,0)) and ((2,0))

Step 1

Concept

(x-4-16=\(x^2-4\)\(x^2+4\)), and the real zeroes are only \(\pm2\). Tip: \(x^2+4\) gives no real zero.

Step 2

Why this answer is correct

The correct answer is A. ((-2,0)) और ((2,0)) / ((-2,0)) and ((2,0)). (x-4-16=\(x^2-4\)\(x^2+4\)), and the real zeroes are only \(\pm2\). Tip: \(x^2+4\) gives no real zero.

Step 3

Exam Tip

(x-4-16=\(x^2-4\)\(x^2+4\)) है और वास्तविक शून्यक केवल \(\pm2\) हैं। टिप: \(x^2+4\) वास्तविक शून्यक नहीं देता।

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Question 5/6 Hard Mathematics Chapter 2: Polynomials Geometrical meaning of the zeroes of a polynomial. Class 10 Level 22

यदि (p(x)=x-4+1), तो उसके ग्राफ के वास्तविक शून्यकों की संख्या क्या है?

If (p(x)=x-4+1), what is the number of real zeroes of its graph?

Explanation opens after your attempt
Correct Answer

A. शून्यZero

Step 1

Concept

For real (x), \(x^4\geq0\), so \(x^4+1>0\). Tip: an always positive polynomial does not cut the (x)-axis.

Step 2

Why this answer is correct

The correct answer is A. शून्य / Zero. For real (x), \(x^4\geq0\), so \(x^4+1>0\). Tip: an always positive polynomial does not cut the (x)-axis.

Step 3

Exam Tip

वास्तविक (x) के लिए \(x^4\geq0\), इसलिए \(x^4+1>0\) है। टिप: हमेशा धनात्मक बहुपद (x)-अक्ष को नहीं काटता।

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Question 6/6 Hard Mathematics Chapter 2: Polynomials Geometrical meaning of the zeroes of a polynomial. Class 10 Level 22

यदि (p(x)=x-4-1) है, तो ग्राफ के वास्तविक (x)-अक्ष कटान कौन से हैं?

If (p(x)=x-4-1), what are the real (x)-axis intersections of the graph?

Explanation opens after your attempt
Correct Answer

A. ((-1,0)) और ((1,0))((-1,0)) and ((1,0))

Step 1

Concept

(x-4-1=\(x^2-1\)\(x^2+1\)), and the real zeroes are only \(\pm1\). Tip: \(x^2+1\) gives no real zero.

Step 2

Why this answer is correct

The correct answer is A. ((-1,0)) और ((1,0)) / ((-1,0)) and ((1,0)). (x-4-1=\(x^2-1\)\(x^2+1\)), and the real zeroes are only \(\pm1\). Tip: \(x^2+1\) gives no real zero.

Step 3

Exam Tip

(x-4-1=\(x^2-1\)\(x^2+1\)) है और वास्तविक शून्यक केवल \(\pm1\) हैं। टिप: \(x^2+1\) वास्तविक शून्यक नहीं देता।

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