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quartic MCQ Questions for Class 10

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14 questions tagged with quartic.

Question 1/14 Expert Mathematics Polynomials Polynomials in one variable Class 10 Level 48

यदि (p(x)=x-4-16), तो \(x^2+4\) के कारण वास्तविक शून्यकों पर क्या प्रभाव पड़ता है?

For (p(x)=x-4-16), what effect does \(x^2+4\) have on real zeroes?

Explanation opens after your attempt
Correct Answer

A. यह कोई वास्तविक शून्यक नहीं देताIt gives no real zero

Step 1

Concept

(x-4-16=\(x^2-4\)\(x^2+4\)). The factor \(x^2+4\) is never (0) for real (x).

Step 2

Why this answer is correct

The correct answer is A. यह कोई वास्तविक शून्यक नहीं देता / It gives no real zero. (x-4-16=\(x^2-4\)\(x^2+4\)). The factor \(x^2+4\) is never (0) for real (x).

Step 3

Exam Tip

(x-4-16=\(x^2-4\)\(x^2+4\)) है। \(x^2+4\) वास्तविक (x) के लिए कभी (0) नहीं होता।

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Question 2/14 Expert Mathematics Polynomials Polynomials in one variable Class 10 Level 48

यदि (p(x)=x-4-5x-2+4), तो इसके वास्तविक शून्यक कौन-से हैं?

If (p(x)=x-4-5x-2+4), what are its real zeroes?

Explanation opens after your attempt
Correct Answer

A. -(2,-1,1,2)

Step 1

Concept

(x-4-5x-2+4=\(x^2-1\)\(x^2-4\)). Therefore the real zeroes are (-2,-1,1,2).

Step 2

Why this answer is correct

The correct answer is A. -(2,-1,1,2). (x-4-5x-2+4=\(x^2-1\)\(x^2-4\)). Therefore the real zeroes are (-2,-1,1,2).

Step 3

Exam Tip

(x-4-5x-2+4=\(x^2-1\)\(x^2-4\)) है। इसलिए वास्तविक शून्यक (-2,-1,1,2) हैं।

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Question 3/14 Expert Mathematics Polynomials Polynomials in one variable Class 10 Level 47

(p(x)=x-4-x-3+x-2-x+1) के लिए (p(1)) क्या है?

What is (p(1)) for (p(x)=x-4-x-3+x-2-x+1)?

Explanation opens after your attempt
Correct Answer

B. (1)

Step 1

Concept

(p(1)=1-1+1-1+1=1). Add alternating signs in order.

Step 2

Why this answer is correct

The correct answer is B. (1). (p(1)=1-1+1-1+1=1). Add alternating signs in order.

Step 3

Exam Tip

(p(1)=1-1+1-1+1=1)। वैकल्पिक संकेतों को क्रम से जोड़ें।

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Question 4/14 Expert Mathematics Polynomials Polynomials in one variable Class 10 Level 47

किस मान के लिए (p(x)=x-4-3x-3+mx-5) में (p(1)=0) होगा?

For what value of (m) will (p(1)=0) in (p(x)=x-4-3x-3+mx-5)?

Explanation opens after your attempt
Correct Answer

C. (7)

Step 1

Concept

(p(1)=1-3+m-5=m-7), so (m=7). Substitute the given value and form a simple equation.

Step 2

Why this answer is correct

The correct answer is C. (7). (p(1)=1-3+m-5=m-7), so (m=7). Substitute the given value and form a simple equation.

Step 3

Exam Tip

(p(1)=1-3+m-5=m-7), इसलिए (m=7)। दिए गए मान को रखकर सरल समीकरण बनाएं।

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Question 5/14 Hard Mathematics Polynomials Polynomials in one variable Class 10 Level 48

यदि (p(x)=x-4+mx-2+16) को (\(x^2-4\)2) के रूप में लिखा जा सकता है, तो (m) क्या है?

If (p(x)=x-4+mx-2+16) can be written as (\(x^2-4\)2), what is (m)?

Explanation opens after your attempt
Correct Answer

A. (-8)

Step 1

Concept

(\(x^2-4\)2=x-4-8x-2+16), so (m=-8). In a square identity, find the middle term (2ab) carefully.

Step 2

Why this answer is correct

The correct answer is A. (-8). (\(x^2-4\)2=x-4-8x-2+16), so (m=-8). In a square identity, find the middle term (2ab) carefully.

Step 3

Exam Tip

(\(x^2-4\)2=x-4-8x-2+16), इसलिए (m=-8)। वर्ग पहचान में मध्य पद (2ab) को ध्यान से निकालें।

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Question 6/14 Expert Mathematics Polynomials Polynomials in one variable Class 10 Level 46

यदि (p(x)=x-4-1), तो (x=1) और (x=-1) के अलावा वास्तविक शून्यकों की संख्या क्या है?

If (p(x)=x-4-1), how many real zeroes are there besides (x=1) and (x=-1)?

Explanation opens after your attempt
Correct Answer

A. (0)

Step 1

Concept

(x-4-1=\(x^2-1\)\(x^2+1\)). Since \(x^2+1\) has no real zeroes, there are (0) extra real zeroes.

Step 2

Why this answer is correct

The correct answer is A. (0). (x-4-1=\(x^2-1\)\(x^2+1\)). Since \(x^2+1\) has no real zeroes, there are (0) extra real zeroes.

Step 3

Exam Tip

(x-4-1=\(x^2-1\)\(x^2+1\)) है। \(x^2+1\) के वास्तविक शून्यक नहीं हैं, इसलिए अतिरिक्त वास्तविक शून्यक (0) हैं।

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Question 7/14 Hard Mathematics Polynomials Polynomials in one variable Class 10 Level 46

यदि (p(x)=x-4-5x-2+4), तो कौन सा मान (p(x)) का शून्यक नहीं है?

If (p(x)=x-4-5x-2+4), which value is not a zero of (p(x))?

Explanation opens after your attempt
Correct Answer

D. (3)

Step 1

Concept

(p(3)=81-45+4=40), so (3) is not a zero. The values (1), (-1), and (2) make the polynomial (0).

Step 2

Why this answer is correct

The correct answer is D. (3). (p(3)=81-45+4=40), so (3) is not a zero. The values (1), (-1), and (2) make the polynomial (0).

Step 3

Exam Tip

(p(3)=81-45+4=40) है, इसलिए (3) शून्यक नहीं है। शेष (1), (-1) और (2) पर मान (0) मिलता है।

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Question 8/14 Medium Mathematics Polynomials Polynomials in one variable Class 10 Level 48

(p(x)=7x-4-2x-2+9) में \(x^3\) का गुणांक क्या है?

What is the coefficient of \(x^3\) in (p(x)=7x-4-2x-2+9)?

Explanation opens after your attempt
Correct Answer

C. (0)

Step 1

Concept

There is no \(x^3\)-term, so its coefficient is (0). Treat the missing term as \(0x^3\).

Step 2

Why this answer is correct

The correct answer is C. (0). There is no \(x^3\)-term, so its coefficient is (0). Treat the missing term as \(0x^3\).

Step 3

Exam Tip

\(x^3\) का पद उपस्थित नहीं है इसलिए उसका गुणांक (0) है। अनुपस्थित पद को \(0x^3\) समझें।

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Question 9/14 Expert Mathematics Polynomials Geometrical meaning of the zeroes of a polynomial. Class 10 Level 23

यदि (p(x)=x-4-1296) है, तो वास्तविक (x)-अक्ष कटान कौन से हैं?

If (p(x)=x-4-1296), what are the real (x)-axis intersections?

Explanation opens after your attempt
Correct Answer

A. ((-6,0)) और ((6,0))((-6,0)) and ((6,0))

Step 1

Concept

(x-4-1296=\(x^2-36\)\(x^2+36\)), and the real zeroes are only \(\pm6\). Tip: \(x^2+36\) gives no real zero.

Step 2

Why this answer is correct

The correct answer is A. ((-6,0)) और ((6,0)) / ((-6,0)) and ((6,0)). (x-4-1296=\(x^2-36\)\(x^2+36\)), and the real zeroes are only \(\pm6\). Tip: \(x^2+36\) gives no real zero.

Step 3

Exam Tip

(x-4-1296=\(x^2-36\)\(x^2+36\)) है और वास्तविक शून्यक केवल \(\pm6\) हैं। टिप: \(x^2+36\) वास्तविक शून्यक नहीं देता।

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Question 10/14 Expert Mathematics Polynomials Geometrical meaning of the zeroes of a polynomial. Class 10 Level 22

यदि (p(x)=x-4-625) है, तो वास्तविक (x)-अक्ष कटान कौन से हैं?

If (p(x)=x-4-625), what are the real (x)-axis intersections?

Explanation opens after your attempt
Correct Answer

A. ((-5,0)) और ((5,0))((-5,0)) and ((5,0))

Step 1

Concept

(x-4-625=\(x^2-25\)\(x^2+25\)), and the real zeroes are only \(\pm5\). Tip: \(x^2+25\) gives no real zero.

Step 2

Why this answer is correct

The correct answer is A. ((-5,0)) और ((5,0)) / ((-5,0)) and ((5,0)). (x-4-625=\(x^2-25\)\(x^2+25\)), and the real zeroes are only \(\pm5\). Tip: \(x^2+25\) gives no real zero.

Step 3

Exam Tip

(x-4-625=\(x^2-25\)\(x^2+25\)) है और वास्तविक शून्यक केवल \(\pm5\) हैं। टिप: \(x^2+25\) वास्तविक शून्यक नहीं देता।

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Question 11/14 Hard Mathematics Polynomials Geometrical meaning of the zeroes of a polynomial. Class 10 Level 24

यदि (p(x)=x-4-81) है तो वास्तविक (x)-अक्ष कटान कौन से हैं?

If (p(x)=x-4-81), what are the real (x)-axis intersections?

Explanation opens after your attempt
Correct Answer

A. ((-3,0)) और ((3,0))((-3,0)) and ((3,0))

Step 1

Concept

(x-4-81=\(x^2-9\)\(x^2+9\)), and the real zeroes are only \(\pm3\). Tip: \(x^2+9\) gives no real zero.

Step 2

Why this answer is correct

The correct answer is A. ((-3,0)) और ((3,0)) / ((-3,0)) and ((3,0)). (x-4-81=\(x^2-9\)\(x^2+9\)), and the real zeroes are only \(\pm3\). Tip: \(x^2+9\) gives no real zero.

Step 3

Exam Tip

(x-4-81=\(x^2-9\)\(x^2+9\)) है और वास्तविक शून्यक केवल \(\pm3\) हैं। टिप: \(x^2+9\) वास्तविक शून्यक नहीं देता।

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Question 12/14 Hard Mathematics Polynomials Geometrical meaning of the zeroes of a polynomial. Class 10 Level 23

यदि (p(x)=x-4-16) है, तो वास्तविक (x)-अक्ष कटान कौन से हैं?

If (p(x)=x-4-16), what are the real (x)-axis intersections?

Explanation opens after your attempt
Correct Answer

A. ((-2,0)) और ((2,0))((-2,0)) and ((2,0))

Step 1

Concept

(x-4-16=\(x^2-4\)\(x^2+4\)), and the real zeroes are only \(\pm2\). Tip: \(x^2+4\) gives no real zero.

Step 2

Why this answer is correct

The correct answer is A. ((-2,0)) और ((2,0)) / ((-2,0)) and ((2,0)). (x-4-16=\(x^2-4\)\(x^2+4\)), and the real zeroes are only \(\pm2\). Tip: \(x^2+4\) gives no real zero.

Step 3

Exam Tip

(x-4-16=\(x^2-4\)\(x^2+4\)) है और वास्तविक शून्यक केवल \(\pm2\) हैं। टिप: \(x^2+4\) वास्तविक शून्यक नहीं देता।

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Question 13/14 Hard Mathematics Polynomials Geometrical meaning of the zeroes of a polynomial. Class 10 Level 22

यदि (p(x)=x-4+1), तो उसके ग्राफ के वास्तविक शून्यकों की संख्या क्या है?

If (p(x)=x-4+1), what is the number of real zeroes of its graph?

Explanation opens after your attempt
Correct Answer

A. शून्यZero

Step 1

Concept

For real (x), \(x^4\geq0\), so \(x^4+1>0\). Tip: an always positive polynomial does not cut the (x)-axis.

Step 2

Why this answer is correct

The correct answer is A. शून्य / Zero. For real (x), \(x^4\geq0\), so \(x^4+1>0\). Tip: an always positive polynomial does not cut the (x)-axis.

Step 3

Exam Tip

वास्तविक (x) के लिए \(x^4\geq0\), इसलिए \(x^4+1>0\) है। टिप: हमेशा धनात्मक बहुपद (x)-अक्ष को नहीं काटता।

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Question 14/14 Hard Mathematics Polynomials Geometrical meaning of the zeroes of a polynomial. Class 10 Level 22

यदि (p(x)=x-4-1) है, तो ग्राफ के वास्तविक (x)-अक्ष कटान कौन से हैं?

If (p(x)=x-4-1), what are the real (x)-axis intersections of the graph?

Explanation opens after your attempt
Correct Answer

A. ((-1,0)) और ((1,0))((-1,0)) and ((1,0))

Step 1

Concept

(x-4-1=\(x^2-1\)\(x^2+1\)), and the real zeroes are only \(\pm1\). Tip: \(x^2+1\) gives no real zero.

Step 2

Why this answer is correct

The correct answer is A. ((-1,0)) और ((1,0)) / ((-1,0)) and ((1,0)). (x-4-1=\(x^2-1\)\(x^2+1\)), and the real zeroes are only \(\pm1\). Tip: \(x^2+1\) gives no real zero.

Step 3

Exam Tip

(x-4-1=\(x^2-1\)\(x^2+1\)) है और वास्तविक शून्यक केवल \(\pm1\) हैं। टिप: \(x^2+1\) वास्तविक शून्यक नहीं देता।

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