15 results found for "quartic" in Class 10.
यदि (p(x)=x-4 -16), तो \(x^2+4\) के कारण वास्तविक शून्यकों पर क्या प्रभाव पड़ता है?
For (p(x)=x-4 -16), what effect does \(x^2+4\) have on real zeroes?
#quartic
#real-zeroes
#factor
A यह कोई वास्तविक शून्यक नहीं देता / It gives no real zero
B यह शून्यक (2) देता है / It gives zero (2)
C यह शून्यक (-2) देता है / It gives zero (-2)
D यह दो वास्तविक शून्यक देता है / It gives two real zeroes
Explanation opens after your attempt
Correct Answer
A. यह कोई वास्तविक शून्यक नहीं देता / It gives no real zero
Step 1
Concept
(x-4 -16=\(x^2-4\)\(x^2+4\)). The factor \(x^2+4\) is never (0) for real (x).
Step 2
Why this answer is correct
The correct answer is A. यह कोई वास्तविक शून्यक नहीं देता / It gives no real zero. (x-4 -16=\(x^2-4\)\(x^2+4\)). The factor \(x^2+4\) is never (0) for real (x).
Step 3
Exam Tip
(x-4 -16=\(x^2-4\)\(x^2+4\)) है। \(x^2+4\) वास्तविक (x) के लिए कभी (0) नहीं होता।
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यदि (p(x)=x-4 -5x-2 +4), तो इसके वास्तविक शून्यक कौन-से हैं?
If (p(x)=x-4 -5x-2 +4), what are its real zeroes?
#quartic
#biquadratic
#zeroes
A -(2,-1,1,2)
B -(4,-1,1,4)
C -(2,0,1,2)
D -(1,1)
Explanation opens after your attempt
Correct Answer
A. -(2,-1,1,2)
Step 1
Concept
(x-4 -5x-2 +4=\(x^2-1\)\(x^2-4\)). Therefore the real zeroes are (-2,-1,1,2).
Step 2
Why this answer is correct
The correct answer is A. -(2,-1,1,2). (x-4 -5x-2 +4=\(x^2-1\)\(x^2-4\)). Therefore the real zeroes are (-2,-1,1,2).
Step 3
Exam Tip
(x-4 -5x-2 +4=\(x^2-1\)\(x^2-4\)) है। इसलिए वास्तविक शून्यक (-2,-1,1,2) हैं।
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(p(x)=x-4 -x-3 +x-2 -x+1) के लिए (p(1)) क्या है?
What is (p(1)) for (p(x)=x-4 -x-3 +x-2 -x+1)?
#evaluation
#quartic
#substitution
A (0)
B (1)
C (2)
D (5)
Explanation opens after your attempt
Step 1
Concept
(p(1)=1-1+1-1+1=1). Add alternating signs in order.
Step 2
Why this answer is correct
The correct answer is B. (1). (p(1)=1-1+1-1+1=1). Add alternating signs in order.
Step 3
Exam Tip
(p(1)=1-1+1-1+1=1)। वैकल्पिक संकेतों को क्रम से जोड़ें।
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किस मान के लिए (p(x)=x-4 -3x-3 +mx-5) में (p(1)=0) होगा?
For what value of (m) will (p(1)=0) in (p(x)=x-4 -3x-3 +mx-5)?
#parameter
#evaluation
#quartic
A (5)
B (6)
C (7)
D (8)
Explanation opens after your attempt
Step 1
Concept
(p(1)=1-3+m-5 =m-7 ), so (m=7). Substitute the given value and form a simple equation.
Step 2
Why this answer is correct
The correct answer is C. (7). (p(1)=1-3+m-5 =m-7 ), so (m=7). Substitute the given value and form a simple equation.
Step 3
Exam Tip
(p(1)=1-3+m-5 =m-7 ), इसलिए (m=7)। दिए गए मान को रखकर सरल समीकरण बनाएं।
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यदि (p(x)=x-4 +mx-2 +16) को (\(x^2-4\)2 ) के रूप में लिखा जा सकता है, तो (m) क्या है?
If (p(x)=x-4 +mx-2 +16) can be written as (\(x^2-4\)2 ), what is (m)?
#perfect square
#quartic
#identity
A (-8)
B (-4)
C (4)
D (8)
Explanation opens after your attempt
Step 1
Concept
(\(x^2-4\)2 =x-4 -8x-2 +16), so (m=-8). In a square identity, find the middle term (2ab) carefully.
Step 2
Why this answer is correct
The correct answer is A. (-8). (\(x^2-4\)2 =x-4 -8x-2 +16), so (m=-8). In a square identity, find the middle term (2ab) carefully.
Step 3
Exam Tip
(\(x^2-4\)2 =x-4 -8x-2 +16), इसलिए (m=-8)। वर्ग पहचान में मध्य पद (2ab) को ध्यान से निकालें।
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यदि (p(x)=x-4 -1), तो (x=1) और (x=-1) के अलावा वास्तविक शून्यकों की संख्या क्या है?
If (p(x)=x-4 -1), how many real zeroes are there besides (x=1) and (x=-1)?
#quartic
#real-zeroes
#factorisation
A (0)
B (1)
C (2)
D (4)
Explanation opens after your attempt
Step 1
Concept
(x-4 -1=\(x^2-1\)\(x^2+1\)). Since \(x^2+1\) has no real zeroes, there are (0) extra real zeroes.
Step 2
Why this answer is correct
The correct answer is A. (0). (x-4 -1=\(x^2-1\)\(x^2+1\)). Since \(x^2+1\) has no real zeroes, there are (0) extra real zeroes.
Step 3
Exam Tip
(x-4 -1=\(x^2-1\)\(x^2+1\)) है। \(x^2+1\) के वास्तविक शून्यक नहीं हैं, इसलिए अतिरिक्त वास्तविक शून्यक (0) हैं।
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यदि (p(x)=x-4 -5x-2 +4), तो कौन सा मान (p(x)) का शून्यक नहीं है?
If (p(x)=x-4 -5x-2 +4), which value is not a zero of (p(x))?
#polynomials
#quartic
#zero_check
#hard
A (1)
B (-1)
C (2)
D (3)
Explanation opens after your attempt
Step 1
Concept
(p(3)=81-45+4=40), so (3) is not a zero. The values (1), (-1), and (2) make the polynomial (0).
Step 2
Why this answer is correct
The correct answer is D. (3). (p(3)=81-45+4=40), so (3) is not a zero. The values (1), (-1), and (2) make the polynomial (0).
Step 3
Exam Tip
(p(3)=81-45+4=40) है, इसलिए (3) शून्यक नहीं है। शेष (1), (-1) और (2) पर मान (0) मिलता है।
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(p(x)=7x-4 -2x-2 +9) में \(x^3\) का गुणांक क्या है?
What is the coefficient of \(x^3\) in (p(x)=7x-4 -2x-2 +9)?
#coefficient
#missing term
#quartic
A (7)
B (-2)
C (0)
D (9)
Explanation opens after your attempt
Step 1
Concept
There is no \(x^3\)-term, so its coefficient is (0). Treat the missing term as \(0x^3\).
Step 2
Why this answer is correct
The correct answer is C. (0). There is no \(x^3\)-term, so its coefficient is (0). Treat the missing term as \(0x^3\).
Step 3
Exam Tip
\(x^3\) का पद उपस्थित नहीं है इसलिए उसका गुणांक (0) है। अनुपस्थित पद को \(0x^3\) समझें।
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(p(x)=8x-4 -5x-3 +2x-6) में \(x^4\) के पद का गुणांक क्या है?
What is the coefficient of the \(x^4\)-term in (p(x)=8x-4 -5x-3 +2x-6)?
#coefficient
#quartic term
#polynomial
A (8)
B (-5)
C (2)
D (-6)
Explanation opens after your attempt
Step 1
Concept
The coefficient of the \(x^4\)-term \(8x^4\) is (8). Identify the power and coefficient separately.
Step 2
Why this answer is correct
The correct answer is A. (8). The coefficient of the \(x^4\)-term \(8x^4\) is (8). Identify the power and coefficient separately.
Step 3
Exam Tip
\(x^4\) वाले पद \(8x^4\) का गुणांक (8) है। घात और गुणांक को अलग पहचानें।
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यदि (p(x)=x-4 -1296) है, तो वास्तविक (x)-अक्ष कटान कौन से हैं?
If (p(x)=x-4 -1296), what are the real (x)-axis intersections?
#quartic
#real zeroes
#graph
A ((-6,0)) और ((6,0)) / ((-6,0)) and ((6,0))
B ((-36,0)) और ((36,0)) / ((-36,0)) and ((36,0))
C ((0,0)), ((-6,0)), ((6,0))
D कोई नहीं / None
Explanation opens after your attempt
Correct Answer
A. ((-6,0)) और ((6,0)) / ((-6,0)) and ((6,0))
Step 1
Concept
(x-4 -1296=\(x^2-36\)\(x^2+36\)), and the real zeroes are only \(\pm6\). Tip: \(x^2+36\) gives no real zero.
Step 2
Why this answer is correct
The correct answer is A. ((-6,0)) और ((6,0)) / ((-6,0)) and ((6,0)). (x-4 -1296=\(x^2-36\)\(x^2+36\)), and the real zeroes are only \(\pm6\). Tip: \(x^2+36\) gives no real zero.
Step 3
Exam Tip
(x-4 -1296=\(x^2-36\)\(x^2+36\)) है और वास्तविक शून्यक केवल \(\pm6\) हैं। टिप: \(x^2+36\) वास्तविक शून्यक नहीं देता।
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यदि (p(x)=x-4 -625) है, तो वास्तविक (x)-अक्ष कटान कौन से हैं?
If (p(x)=x-4 -625), what are the real (x)-axis intersections?
#quartic
#real zeroes
#graph
A ((-5,0)) और ((5,0)) / ((-5,0)) and ((5,0))
B ((-25,0)) और ((25,0)) / ((-25,0)) and ((25,0))
C ((0,0)), ((-5,0)), ((5,0))
D कोई नहीं / None
Explanation opens after your attempt
Correct Answer
A. ((-5,0)) और ((5,0)) / ((-5,0)) and ((5,0))
Step 1
Concept
(x-4 -625=\(x^2-25\)\(x^2+25\)), and the real zeroes are only \(\pm5\). Tip: \(x^2+25\) gives no real zero.
Step 2
Why this answer is correct
The correct answer is A. ((-5,0)) और ((5,0)) / ((-5,0)) and ((5,0)). (x-4 -625=\(x^2-25\)\(x^2+25\)), and the real zeroes are only \(\pm5\). Tip: \(x^2+25\) gives no real zero.
Step 3
Exam Tip
(x-4 -625=\(x^2-25\)\(x^2+25\)) है और वास्तविक शून्यक केवल \(\pm5\) हैं। टिप: \(x^2+25\) वास्तविक शून्यक नहीं देता।
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यदि (p(x)=x-4 -81) है तो वास्तविक (x)-अक्ष कटान कौन से हैं?
If (p(x)=x-4 -81), what are the real (x)-axis intersections?
#quartic
#real zeroes
#graph
A ((-3,0)) और ((3,0)) / ((-3,0)) and ((3,0))
B ((-9,0)) और ((9,0)) / ((-9,0)) and ((9,0))
C ((0,0)), ((3,0)), ((-3,0))
D कोई नहीं / None
Explanation opens after your attempt
Correct Answer
A. ((-3,0)) और ((3,0)) / ((-3,0)) and ((3,0))
Step 1
Concept
(x-4 -81=\(x^2-9\)\(x^2+9\)), and the real zeroes are only \(\pm3\). Tip: \(x^2+9\) gives no real zero.
Step 2
Why this answer is correct
The correct answer is A. ((-3,0)) और ((3,0)) / ((-3,0)) and ((3,0)). (x-4 -81=\(x^2-9\)\(x^2+9\)), and the real zeroes are only \(\pm3\). Tip: \(x^2+9\) gives no real zero.
Step 3
Exam Tip
(x-4 -81=\(x^2-9\)\(x^2+9\)) है और वास्तविक शून्यक केवल \(\pm3\) हैं। टिप: \(x^2+9\) वास्तविक शून्यक नहीं देता।
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यदि (p(x)=x-4 -16) है, तो वास्तविक (x)-अक्ष कटान कौन से हैं?
If (p(x)=x-4 -16), what are the real (x)-axis intersections?
#quartic
#real zeroes
#graph
A ((-2,0)) और ((2,0)) / ((-2,0)) and ((2,0))
B ((-4,0)) और ((4,0)) / ((-4,0)) and ((4,0))
C ((0,0)), ((2,0)), ((-2,0))
D कोई नहीं / None
Explanation opens after your attempt
Correct Answer
A. ((-2,0)) और ((2,0)) / ((-2,0)) and ((2,0))
Step 1
Concept
(x-4 -16=\(x^2-4\)\(x^2+4\)), and the real zeroes are only \(\pm2\). Tip: \(x^2+4\) gives no real zero.
Step 2
Why this answer is correct
The correct answer is A. ((-2,0)) और ((2,0)) / ((-2,0)) and ((2,0)). (x-4 -16=\(x^2-4\)\(x^2+4\)), and the real zeroes are only \(\pm2\). Tip: \(x^2+4\) gives no real zero.
Step 3
Exam Tip
(x-4 -16=\(x^2-4\)\(x^2+4\)) है और वास्तविक शून्यक केवल \(\pm2\) हैं। टिप: \(x^2+4\) वास्तविक शून्यक नहीं देता।
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यदि (p(x)=x-4 +1), तो उसके ग्राफ के वास्तविक शून्यकों की संख्या क्या है?
If (p(x)=x-4 +1), what is the number of real zeroes of its graph?
#quartic
#no real zero
#graph
A शून्य / Zero
B एक / One
C दो / Two
D चार / Four
Explanation opens after your attempt
Correct Answer
A. शून्य / Zero
Step 1
Concept
For real (x), \(x^4\geq0\), so \(x^4+1>0\). Tip: an always positive polynomial does not cut the (x)-axis.
Step 2
Why this answer is correct
The correct answer is A. शून्य / Zero. For real (x), \(x^4\geq0\), so \(x^4+1>0\). Tip: an always positive polynomial does not cut the (x)-axis.
Step 3
Exam Tip
वास्तविक (x) के लिए \(x^4\geq0\), इसलिए \(x^4+1>0\) है। टिप: हमेशा धनात्मक बहुपद (x)-अक्ष को नहीं काटता।
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यदि (p(x)=x-4 -1) है, तो ग्राफ के वास्तविक (x)-अक्ष कटान कौन से हैं?
If (p(x)=x-4 -1), what are the real (x)-axis intersections of the graph?
#quartic
#real zeroes
#graph
A ((-1,0)) और ((1,0)) / ((-1,0)) and ((1,0))
B ((-1,0)), ((0,0)), ((1,0))
C ((1,0)) और ((4,0)) / ((1,0)) and ((4,0))
D कोई नहीं / None
Explanation opens after your attempt
Correct Answer
A. ((-1,0)) और ((1,0)) / ((-1,0)) and ((1,0))
Step 1
Concept
(x-4 -1=\(x^2-1\)\(x^2+1\)), and the real zeroes are only \(\pm1\). Tip: \(x^2+1\) gives no real zero.
Step 2
Why this answer is correct
The correct answer is A. ((-1,0)) और ((1,0)) / ((-1,0)) and ((1,0)). (x-4 -1=\(x^2-1\)\(x^2+1\)), and the real zeroes are only \(\pm1\). Tip: \(x^2+1\) gives no real zero.
Step 3
Exam Tip
(x-4 -1=\(x^2-1\)\(x^2+1\)) है और वास्तविक शून्यक केवल \(\pm1\) हैं। टिप: \(x^2+1\) वास्तविक शून्यक नहीं देता।
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