Concept-wise Practice

biquadratic MCQ Questions for Class 10

biquadratic se related questions ko ek jagah revise karein. Har question me bilingual content, answer feedback aur explanation available hai.

Practice Questions

7 questions tagged with biquadratic.

यदि (p(x)=x-4-5x-2+4), तो इसके वास्तविक शून्यक कौन-से हैं?

If (p(x)=x-4-5x-2+4), what are its real zeroes?

Explanation opens after your attempt
Correct Answer

A. -(2,-1,1,2)

Step 1

Concept

(x-4-5x-2+4=\(x^2-1\)\(x^2-4\)). Therefore the real zeroes are (-2,-1,1,2).

Step 2

Why this answer is correct

The correct answer is A. -(2,-1,1,2). (x-4-5x-2+4=\(x^2-1\)\(x^2-4\)). Therefore the real zeroes are (-2,-1,1,2).

Step 3

Exam Tip

(x-4-5x-2+4=\(x^2-1\)\(x^2-4\)) है। इसलिए वास्तविक शून्यक (-2,-1,1,2) हैं।

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\(x^4-25x^2+144=0\) में \(y=x^2\) रखने पर कौनसा समीकरण मिलेगा?

If \(y=x^2\) is put in \(x^4-25x^2+144=0\), which equation is obtained?

Explanation opens after your attempt
Correct Answer

A. \(y^2-25y+144=0\)

Step 1

Concept

Since (x-4=\(x^2\)2=y-2), the new equation is \(y^2-25y+144=0\). In exams, use substitution to form a quadratic.

Step 2

Why this answer is correct

The correct answer is A. \(y^2-25y+144=0\). Since (x-4=\(x^2\)2=y-2), the new equation is \(y^2-25y+144=0\). In exams, use substitution to form a quadratic.

Step 3

Exam Tip

क्योंकि (x-4=\(x^2\)2=y-2), इसलिए नया समीकरण \(y^2-25y+144=0\) है। परीक्षा में प्रतिस्थापन से द्विघात रूप बनाएं।

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\(x^4-20x^2+64=0\) में \(y=x^2\) रखने पर कौनसा समीकरण मिलेगा?

If \(y=x^2\) is put in \(x^4-20x^2+64=0\), which equation is obtained?

Explanation opens after your attempt
Correct Answer

A. \(y^2-20y+64=0\)

Step 1

Concept

Since (x-4=\(x^2\)2=y-2), the new equation is \(y^2-20y+64=0\). In exams, use substitution to form a quadratic.

Step 2

Why this answer is correct

The correct answer is A. \(y^2-20y+64=0\). Since (x-4=\(x^2\)2=y-2), the new equation is \(y^2-20y+64=0\). In exams, use substitution to form a quadratic.

Step 3

Exam Tip

क्योंकि (x-4=\(x^2\)2=y-2), इसलिए नया समीकरण \(y^2-20y+64=0\) है। परीक्षा में प्रतिस्थापन से द्विघात रूप बनाएं।

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\(x^4-17x^2+16=0\) में \(y=x^2\) रखने पर कौनसा समीकरण मिलेगा?

If \(y=x^2\) is put in \(x^4-17x^2+16=0\), which equation is obtained?

Explanation opens after your attempt
Correct Answer

A. \(y^2-17y+16=0\)

Step 1

Concept

Since (x-4=\(x^2\)2=y-2), the new equation is \(y^2-17y+16=0\). In exams, use substitution to form a quadratic.

Step 2

Why this answer is correct

The correct answer is A. \(y^2-17y+16=0\). Since (x-4=\(x^2\)2=y-2), the new equation is \(y^2-17y+16=0\). In exams, use substitution to form a quadratic.

Step 3

Exam Tip

क्योंकि (x-4=\(x^2\)2=y-2), इसलिए नया समीकरण \(y^2-17y+16=0\) है। परीक्षा में प्रतिस्थापन से द्विघात रूप बनाएं।

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\(x^4-13x^2+36=0\) में \(y=x^2\) रखने पर कौनसा समीकरण मिलेगा?

If \(y=x^2\) is put in \(x^4-13x^2+36=0\), which equation is obtained?

Explanation opens after your attempt
Correct Answer

A. \(y^2-13y+36=0\)

Step 1

Concept

Since (x-4=\(x^2\)2=y-2), the new equation is \(y^2-13y+36=0\). In exams, substitution simplifies a difficult form.

Step 2

Why this answer is correct

The correct answer is A. \(y^2-13y+36=0\). Since (x-4=\(x^2\)2=y-2), the new equation is \(y^2-13y+36=0\). In exams, substitution simplifies a difficult form.

Step 3

Exam Tip

क्योंकि (x-4=\(x^2\)2=y-2), इसलिए नया समीकरण \(y^2-13y+36=0\) है। परीक्षा में प्रतिस्थापन कठिन रूप को सरल बनाता है।

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\(x^4-10x^2+9=0\) में \(y=x^2\) रखने पर कौनसा समीकरण मिलेगा?

If \(y=x^2\) is put in \(x^4-10x^2+9=0\), which equation is obtained?

Explanation opens after your attempt
Correct Answer

A. \(y^2-10y+9=0\)

Step 1

Concept

Since (x-4=\(x^2\)2=y-2), the new equation is \(y^2-10y+9=0\). In exams, substitution can simplify a difficult form.

Step 2

Why this answer is correct

The correct answer is A. \(y^2-10y+9=0\). Since (x-4=\(x^2\)2=y-2), the new equation is \(y^2-10y+9=0\). In exams, substitution can simplify a difficult form.

Step 3

Exam Tip

क्योंकि (x-4=\(x^2\)2=y-2), इसलिए नया समीकरण \(y^2-10y+9=0\) है। परीक्षा में प्रतिस्थापन कठिन रूप को सरल बना सकता है।

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\(x^4-5x^2+4=0\) में \(y=x^2\) रखने पर कौनसा समीकरण मिलेगा?

If \(y=x^2\) is put in \(x^4-5x^2+4=0\), which equation is obtained?

Explanation opens after your attempt
Correct Answer

A. \(y^2-5y+4=0\)

Step 1

Concept

Since (x-4=\(x^2\)2=y-2), the new equation is \(y^2-5y+4=0\). In exams, substitution can simplify difficult forms.

Step 2

Why this answer is correct

The correct answer is A. \(y^2-5y+4=0\). Since (x-4=\(x^2\)2=y-2), the new equation is \(y^2-5y+4=0\). In exams, substitution can simplify difficult forms.

Step 3

Exam Tip

क्योंकि (x-4=\(x^2\)2=y-2), इसलिए नया समीकरण \(y^2-5y+4=0\) है। परीक्षा में प्रतिस्थापन से कठिन रूप सरल हो सकता है।

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