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If the coefficient of \(x^2\) in the polynomial \(p(x)=2x^3+mx^2-x+4\) is \(-5\), what is the value of \(m\)?

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Answer and explanation

Correct answer: -5

In the polynomial \(2x^3+mx^2-x+4\), the coefficient of \(x^2\) is directly \(m\). Since this coefficient is given as \(-5\), we get \(m=-5\). Exam tip: identify the coefficient attached to the required power of the variable.

Related tags

CoefficientParameterPolynomial

Frequently asked questions

What is the correct answer to this question?

-5

Why is this the correct answer?

In the polynomial \(2x^3+mx^2-x+4\), the coefficient of \(x^2\) is directly \(m\). Since this coefficient is given as \(-5\), we get \(m=-5\). Exam tip: identify the coefficient attached to the required power of the variable.

Which subject and chapter does this question cover?

This is a Class 10 Mathematics question. Chapter: Polynomials. Topic: Polynomials in one variable.

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