Class 9 Mathematics - Introduction to Polynomials - Definition of polynomial Expert Quiz

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यदि (p(x)=(a-5)x-6+4x-2-9) को ठीक द्विघात बहुपद बनाना हो, तो (a) का मान क्या होगा?

If (p(x)=(a-5)x-6+4x-2-9) is to be exactly a quadratic polynomial, what is the value of (a)?

Explanation opens after your attempt
Correct Answer

A. (5)

Step 1

Concept

For exactly quadratic, the coefficient of \(x^6\) must be zero and the coefficient of \(x^2\) is non-zero. From (a-5=0), (a=5).

Step 2

Why this answer is correct

The correct answer is A. (5). For exactly quadratic, the coefficient of \(x^6\) must be zero and the coefficient of \(x^2\) is non-zero. From (a-5=0), (a=5).

Step 3

Exam Tip

ठीक द्विघात के लिए \(x^6\) का गुणांक शून्य होना चाहिए और \(x^2\) का गुणांक अशून्य है। (a-5=0) से (a=5) मिलता है।

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कौन-सा व्यंजक (x) में बहुपद नहीं है, हालांकि उसमें \(x^4\) पद है?

Which expression is not a polynomial in (x), even though it has an \(x^4\) term?

Explanation opens after your attempt
Correct Answer

B. \(x^4+\frac{2}{x}-1\)

Step 1

Concept

\(\frac{2}{x}=2x^{-1}\), where the variable has a negative power. One invalid term prevents the whole expression from being a polynomial.

Step 2

Why this answer is correct

The correct answer is B. \(x^4+\frac{2}{x}-1\). \(\frac{2}{x}=2x^{-1}\), where the variable has a negative power. One invalid term prevents the whole expression from being a polynomial.

Step 3

Exam Tip

\(\frac{2}{x}=2x^{-1}\) है, जिसमें चर की घात ऋणात्मक है। एक अमान्य पद पूरे व्यंजक को बहुपद नहीं रहने देता।

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यदि (p(x)=0x-8-6x-5+2x-3-1), तो (p(x)) की घात क्या है?

If (p(x)=0x-8-6x-5+2x-3-1), what is the degree of (p(x))?

Explanation opens after your attempt
Correct Answer

C. (5)

Step 1

Concept

\(0x^8\) is a zero term and does not determine the degree. The highest non-zero power is (5).

Step 2

Why this answer is correct

The correct answer is C. (5). \(0x^8\) is a zero term and does not determine the degree. The highest non-zero power is (5).

Step 3

Exam Tip

\(0x^8\) शून्य पद है और घात तय नहीं करता। सबसे बड़ी अशून्य घात (5) है।

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किस (k) पर ((k-1)x-4+(k+2)x-3+7x-4) की घात (3) होगी?

For which (k) will ((k-1)x-4+(k+2)x-3+7x-4) have degree (3)?

Explanation opens after your attempt
Correct Answer

A. (k=1)

Step 1

Concept

For degree (3), the \(x^4\) coefficient must be zero and the \(x^3\) coefficient must be non-zero. At (k=1), (k+2=3) is also non-zero.

Step 2

Why this answer is correct

The correct answer is A. (k=1). For degree (3), the \(x^4\) coefficient must be zero and the \(x^3\) coefficient must be non-zero. At (k=1), (k+2=3) is also non-zero.

Step 3

Exam Tip

घात (3) के लिए \(x^4\) का गुणांक शून्य और \(x^3\) का गुणांक अशून्य होना चाहिए। (k=1) पर (k+2=3) भी अशून्य है।

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\(\frac{x^4-3x^2}{x^2}\) को \(x\neq0\) पर सरल करने के बाद कौन-सा रूप मिलेगा?

After simplifying \(\frac{x^4-3x^2}{x^2}\) for \(x\neq0\), which form is obtained?

Explanation opens after your attempt
Correct Answer

A. \(x^2-3\)

Step 1

Concept

Dividing by common \(x^2\) gives \(x^2-3\). It is a polynomial of degree (2).

Step 2

Why this answer is correct

The correct answer is A. \(x^2-3\). Dividing by common \(x^2\) gives \(x^2-3\). It is a polynomial of degree (2).

Step 3

Exam Tip

साझा \(x^2\) से भाग देने पर \(x^2-3\) मिलता है। यह घात (2) का बहुपद है।

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कौन-सा व्यंजक (x) में बहुपद नहीं है क्योंकि चर की घात \(\frac{7}{3}\) है?

Which expression is not a polynomial in (x) because the variable has power \(\frac{7}{3}\)?

Explanation opens after your attempt
Correct Answer

B. (x^{73}+2x-5)

Step 1

Concept

In a polynomial, powers of the variable must be non-negative integers. \(\frac{7}{3}\) is not an integer.

Step 2

Why this answer is correct

The correct answer is B. \(x^{7 / 3}+2x-5\). In a polynomial, powers of the variable must be non-negative integers. \(\frac{7}{3}\) is not an integer.

Step 3

Exam Tip

बहुपद में चर की घातें शून्य या धनात्मक पूर्णांक होनी चाहिए। \(\frac{7}{3}\) पूर्णांक नहीं है।

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यदि (p(x)=\lambda x-4-2x-2+3) की घात (4) है, तो \(\lambda\) के लिए कौन-सी शर्त सही है?

If (p(x)=\lambda x-4-2x-2+3) has degree (4), which condition is correct for \(\lambda\)?

Explanation opens after your attempt
Correct Answer

B. \(\lambda\neq0\)

Step 1

Concept

The degree is (4) only when the coefficient of \(x^4\) is not zero. Therefore, \(\lambda\neq0\) is required.

Step 2

Why this answer is correct

The correct answer is B. \(\lambda\neq0\). The degree is (4) only when the coefficient of \(x^4\) is not zero. Therefore, \(\lambda\neq0\) is required.

Step 3

Exam Tip

घात (4) तभी होगी जब \(x^4\) का गुणांक शून्य न हो। इसलिए \(\lambda\neq0\) आवश्यक है।

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यदि (p(x)=(r-3)x-3+(r+1)x-2+9) स्थिर बहुपद हो, तो (r) के बारे में सही निष्कर्ष क्या है?

If (p(x)=(r-3)x-3+(r+1)x-2+9) is a constant polynomial, what is the correct conclusion about (r)?

Explanation opens after your attempt
Correct Answer

C. ऐसा कोई (r) नहीं हैNo such (r) exists

Step 1

Concept

For a constant polynomial, both (r-3=0) and (r+1=0) are needed. One value of (r) cannot satisfy both conditions.

Step 2

Why this answer is correct

The correct answer is C. ऐसा कोई (r) नहीं है / No such (r) exists. For a constant polynomial, both (r-3=0) and (r+1=0) are needed. One value of (r) cannot satisfy both conditions.

Step 3

Exam Tip

स्थिर बहुपद के लिए (r-3=0) और (r+1=0) दोनों चाहिए। एक ही (r) दोनों शर्तें पूरी नहीं कर सकता।

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शून्य बहुपद (p(x)=0) की घात के बारे में कौन-सा कथन सही है?

Which statement about the degree of the zero polynomial (p(x)=0) is correct?

Explanation opens after your attempt
Correct Answer

C. घात परिभाषित नहीं हैDegree is not defined

Step 1

Concept

The degree of the zero polynomial is not defined. Keep it separate from a non-zero constant polynomial.

Step 2

Why this answer is correct

The correct answer is C. घात परिभाषित नहीं है / Degree is not defined. The degree of the zero polynomial is not defined. Keep it separate from a non-zero constant polynomial.

Step 3

Exam Tip

शून्य बहुपद की घात परिभाषित नहीं होती। इसे शून्य से अलग स्थिर बहुपद से अलग समझें।

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यदि (q(x)=(m+4)x-5+(m-1)x-4+x-2) की घात (4) हो, तो (m) क्या होगा?

If (q(x)=(m+4)x-5+(m-1)x-4+x-2) has degree (4), what is (m)?

Explanation opens after your attempt
Correct Answer

B. (-4)

Step 1

Concept

For degree (4), the \(x^5\) coefficient must be zero and the \(x^4\) coefficient must be non-zero. At (m=-4), (m-1=-5) is non-zero.

Step 2

Why this answer is correct

The correct answer is B. (-4). For degree (4), the \(x^5\) coefficient must be zero and the \(x^4\) coefficient must be non-zero. At (m=-4), (m-1=-5) is non-zero.

Step 3

Exam Tip

घात (4) के लिए \(x^5\) का गुणांक शून्य और \(x^4\) का गुणांक अशून्य चाहिए। (m=-4) पर (m-1=-5) अशून्य है।

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\(x^2+\sqrt{x^2+4}\) के बारे में सही कथन कौन-सा है?

Which statement is correct about \(x^2+\sqrt{x^2+4}\)?

Explanation opens after your attempt
Correct Answer

B. यह बहुपद नहीं है क्योंकि चर मूल के अंदर हैIt is not a polynomial because the variable is inside a root

Step 1

Concept

\(\sqrt{x^2+4}\) has the variable inside a root. In the class (9) definition, such a term is not treated as a polynomial term.

Step 2

Why this answer is correct

The correct answer is B. यह बहुपद नहीं है क्योंकि चर मूल के अंदर है / It is not a polynomial because the variable is inside a root. \(\sqrt{x^2+4}\) has the variable inside a root. In the class (9) definition, such a term is not treated as a polynomial term.

Step 3

Exam Tip

\(\sqrt{x^2+4}\) में चर मूल के अंदर है। कक्षा (9) की परिभाषा में ऐसा पद बहुपद पद नहीं माना जाता।

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कौन-सा व्यंजक घात (6) का चार-पदी बहुपद है?

Which expression is a four-term polynomial of degree (6)?

Explanation opens after your attempt
Correct Answer

A. \(x^6-2x^4+x-3\)

Step 1

Concept

The first option has four terms and the highest power is (6). All powers are valid for a polynomial.

Step 2

Why this answer is correct

The correct answer is A. \(x^6-2x^4+x-3\). The first option has four terms and the highest power is (6). All powers are valid for a polynomial.

Step 3

Exam Tip

पहले विकल्प में चार पद हैं और सबसे बड़ी घात (6) है। सभी घातें बहुपद के लिए मान्य हैं।

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यदि (p(x)=\(a^2-16\)x-3+5x-2) रैखिक बहुपद हो, तो (a) के संभव मान कौन-से हैं?

If (p(x)=\(a^2-16\)x-3+5x-2) is a linear polynomial, what are the possible values of (a)?

Explanation opens after your attempt
Correct Answer

A. (a=4) या (a=-4)(a=4) or (a=-4)

Step 1

Concept

For it to be linear, the \(x^3\) coefficient must be zero. From \(a^2-16=0\), \(a=\pm4\).

Step 2

Why this answer is correct

The correct answer is A. (a=4) या (a=-4) / (a=4) or (a=-4). For it to be linear, the \(x^3\) coefficient must be zero. From \(a^2-16=0\), \(a=\pm4\).

Step 3

Exam Tip

रैखिक होने के लिए \(x^3\) का गुणांक शून्य होना चाहिए। \(a^2-16=0\) से \(a=\pm4\) मिलता है।

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कौन-सा कथन \(x^0+x^{-2}+3\) के लिए सही है?

Which statement is correct for \(x^0+x^{-2}+3\)?

Explanation opens after your attempt
Correct Answer

B. यह बहुपद नहीं है क्योंकि \(x^{-2}\) हैIt is not a polynomial because it has \(x^{-2}\)

Step 1

Concept

\(x^0\) is valid, but \(x^{-2}\) is invalid. Negative powers are not allowed in a polynomial.

Step 2

Why this answer is correct

The correct answer is B. यह बहुपद नहीं है क्योंकि \(x^{-2}\) है / It is not a polynomial because it has \(x^{-2}\). \(x^0\) is valid, but \(x^{-2}\) is invalid. Negative powers are not allowed in a polynomial.

Step 3

Exam Tip

\(x^0\) मान्य है, लेकिन \(x^{-2}\) अमान्य है। बहुपद में ऋणात्मक घात स्वीकार्य नहीं होती।

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किस व्यंजक को \(x\neq0\) पर सरल करने के बाद भी बहुपद नहीं मिलेगा?

Which expression will still not become a polynomial after simplification for \(x\neq0\)?

Explanation opens after your attempt
Correct Answer

C. \(\frac{x^3+1}{x}\)

Step 1

Concept

\(\frac{x^3+1}{x}=x^2+\frac{1}{x}\). Since \(\frac{1}{x}\) has a negative power, it is not a polynomial.

Step 2

Why this answer is correct

The correct answer is C. \(\frac{x^3+1}{x}\). \(\frac{x^3+1}{x}=x^2+\frac{1}{x}\). Since \(\frac{1}{x}\) has a negative power, it is not a polynomial.

Step 3

Exam Tip

\(\frac{x^3+1}{x}=x^2+\frac{1}{x}\) है। \(\frac{1}{x}\) में ऋणात्मक घात है, इसलिए यह बहुपद नहीं है।

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यदि (p(x)=2x-4+(b-3)x-2+7), तो (p(x)) की घात क्या होगी?

If (p(x)=2x-4+(b-3)x-2+7), what will be the degree of (p(x))?

Explanation opens after your attempt
Correct Answer

A. हमेशा (4)Always (4)

Step 1

Concept

The coefficient of \(x^4\) is (2), which is non-zero. Therefore, the degree remains (4) for any (b).

Step 2

Why this answer is correct

The correct answer is A. हमेशा (4) / Always (4). The coefficient of \(x^4\) is (2), which is non-zero. Therefore, the degree remains (4) for any (b).

Step 3

Exam Tip

\(x^4\) का गुणांक (2) है जो शून्य नहीं है। इसलिए किसी भी (b) पर घात (4) रहेगी।

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कौन-सा व्यंजक (x) में बहुपद है लेकिन केवल विषम घातें और स्थिर पद रखता है?

Which expression is a polynomial in (x) with only odd powers and a constant term?

Explanation opens after your attempt
Correct Answer

A. \(x^7-4x^5+2x-6\)

Step 1

Concept

In the first option, the powers are (7), (5), (1), and (0). All are valid for a polynomial.

Step 2

Why this answer is correct

The correct answer is A. \(x^7-4x^5+2x-6\). In the first option, the powers are (7), (5), (1), and (0). All are valid for a polynomial.

Step 3

Exam Tip

पहले विकल्प में घातें (7), (5), (1) और (0) हैं। ये सभी बहुपद के लिए मान्य हैं।

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यदि (p(x)=0x-4+0x-2+9), तो यह किस प्रकार का बहुपद है?

If (p(x)=0x-4+0x-2+9), what type of polynomial is it?

Explanation opens after your attempt
Correct Answer

C. स्थिर बहुपदConstant polynomial

Step 1

Concept

The zero-coefficient terms disappear and (p(x)=9) remains. It is a non-zero constant polynomial.

Step 2

Why this answer is correct

The correct answer is C. स्थिर बहुपद / Constant polynomial. The zero-coefficient terms disappear and (p(x)=9) remains. It is a non-zero constant polynomial.

Step 3

Exam Tip

शून्य गुणांक वाले पद हट जाते हैं और (p(x)=9) बचता है। यह शून्य से अलग स्थिर बहुपद है।

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यदि (p(x)=kx-3+(k-2)x-2+1) की घात (2) हो, तो (k) क्या होगा?

If (p(x)=kx-3+(k-2)x-2+1) has degree (2), what is (k)?

Explanation opens after your attempt
Correct Answer

A. (0)

Step 1

Concept

For degree (2), the \(x^3\) coefficient must be zero and the \(x^2\) coefficient must be non-zero. At (k=0), (k-2=-2) is non-zero.

Step 2

Why this answer is correct

The correct answer is A. (0). For degree (2), the \(x^3\) coefficient must be zero and the \(x^2\) coefficient must be non-zero. At (k=0), (k-2=-2) is non-zero.

Step 3

Exam Tip

घात (2) के लिए \(x^3\) का गुणांक शून्य चाहिए और \(x^2\) का गुणांक अशून्य चाहिए। (k=0) पर (k-2=-2) अशून्य है।

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कौन-सा व्यंजक (x) में बहुपद नहीं है क्योंकि सभी घातें पूर्णांक होने पर भी एक घात ऋणात्मक है?

Which expression is not a polynomial in (x) because although all powers are integers, one power is negative?

Explanation opens after your attempt
Correct Answer

B. \(x^{-3}+2x^2-1\)

Step 1

Concept

(-3) is an integer but it is negative. In a polynomial, powers must be zero or positive integers.

Step 2

Why this answer is correct

The correct answer is B. \(x^{-3}+2x^2-1\). (-3) is an integer but it is negative. In a polynomial, powers must be zero or positive integers.

Step 3

Exam Tip

(-3) पूर्णांक है लेकिन ऋणात्मक है। बहुपद में घातें शून्य या धनात्मक पूर्णांक होनी चाहिए।

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यदि (f(x)=x-2-1) और (g(x)=x-3+f(x)), तो (g(x)) की घात क्या है?

If (f(x)=x-2-1) and (g(x)=x-3+f(x)), what is the degree of (g(x))?

Explanation opens after your attempt
Correct Answer

C. (3)

Step 1

Concept

(g(x)=x-3+x-2-1). The highest power is (3).

Step 2

Why this answer is correct

The correct answer is C. (3). (g(x)=x-3+x-2-1). The highest power is (3).

Step 3

Exam Tip

(g(x)=x-3+x-2-1) है। सबसे बड़ी घात (3) है।

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कौन-सा व्यंजक वास्तविक गुणांक वाला बहुपद है और अपरिमेय गुणांक रखता है?

Which expression is a polynomial with real coefficients and an irrational coefficient?

Explanation opens after your attempt
Correct Answer

B. \(\sqrt{7}x^4-3x+2\)

Step 1

Concept

\(\sqrt{7}\) is a real coefficient and is allowed. All powers of the variable are non-negative integers.

Step 2

Why this answer is correct

The correct answer is B. \(\sqrt{7}x^4-3x+2\). \(\sqrt{7}\) is a real coefficient and is allowed. All powers of the variable are non-negative integers.

Step 3

Exam Tip

\(\sqrt{7}\) एक वास्तविक गुणांक है और मान्य है। चर की सभी घातें शून्य या धनात्मक पूर्णांक हैं।

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यदि (p(x)=(a+1)x-2+(a-2)x+5) को स्थिर बहुपद बनाना हो, तो क्या संभव है?

If (p(x)=(a+1)x-2+(a-2)x+5) is to be made a constant polynomial, what is possible?

Explanation opens after your attempt
Correct Answer

C. ऐसा कोई (a) नहीं हैNo such (a) exists

Step 1

Concept

For a constant polynomial, both (a+1=0) and (a-2=0) are required. These cannot hold together.

Step 2

Why this answer is correct

The correct answer is C. ऐसा कोई (a) नहीं है / No such (a) exists. For a constant polynomial, both (a+1=0) and (a-2=0) are required. These cannot hold together.

Step 3

Exam Tip

स्थिर बहुपद के लिए (a+1=0) और (a-2=0) दोनों चाहिए। ये दोनों एक साथ संभव नहीं हैं।

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कौन-सा व्यंजक बहुपद नहीं है क्योंकि (x) की घात किसी चर (n) पर निर्भर करती है?

Which expression is not a polynomial because the power of (x) depends on a variable (n)?

Explanation opens after your attempt
Correct Answer

A. \(x^n+2\), जहाँ (n) बदलता है\(x^n+2\), where (n) varies

Step 1

Concept

In a polynomial, powers are fixed non-negative integers. A power depending on a varying variable is not valid in the definition.

Step 2

Why this answer is correct

The correct answer is A. \(x^n+2\), जहाँ (n) बदलता है / \(x^n+2\), where (n) varies. In a polynomial, powers are fixed non-negative integers. A power depending on a varying variable is not valid in the definition.

Step 3

Exam Tip

बहुपद में घातें निश्चित शून्य या धनात्मक पूर्णांक होती हैं। बदलते चर पर निर्भर घात परिभाषा में मान्य नहीं है।

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यदि \(a\neq0\) और (p(x)=ax-7+bx-2+c), तो (p(x)) की घात क्या होगी?

If \(a\neq0\) and (p(x)=ax-7+bx-2+c), what is the degree of (p(x))?

Explanation opens after your attempt
Correct Answer

B. (7)

Step 1

Concept

Since \(a\neq0\), the \(x^7\) term remains present. Therefore, the highest power is (7).

Step 2

Why this answer is correct

The correct answer is B. (7). Since \(a\neq0\), the \(x^7\) term remains present. Therefore, the highest power is (7).

Step 3

Exam Tip

\(a\neq0\) होने से \(x^7\) पद मौजूद रहता है। इसलिए सबसे बड़ी घात (7) है।

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कौन-सा व्यंजक द्विघात बहुपद है लेकिन त्रिपदी नहीं है?

Which expression is a quadratic polynomial but not a trinomial?

Explanation opens after your attempt
Correct Answer

C. \(7x^2+5\)

Step 1

Concept

\(7x^2+5\) has degree (2) and two terms. So it is a quadratic binomial.

Step 2

Why this answer is correct

The correct answer is C. \(7x^2+5\). \(7x^2+5\) has degree (2) and two terms. So it is a quadratic binomial.

Step 3

Exam Tip

\(7x^2+5\) की घात (2) है और इसमें दो पद हैं। इसलिए यह द्विघात द्विपदी है।

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कौन-सा व्यंजक (x) में बहुपद है लेकिन बीच की कई घातें अनुपस्थित हैं?

Which expression is a polynomial in (x) but has several middle powers missing?

Explanation opens after your attempt
Correct Answer

A. \(x^8+3x^3-2\)

Step 1

Concept

A polynomial need not contain all middle powers. In \(x^8+3x^3-2\), the present powers are valid.

Step 2

Why this answer is correct

The correct answer is A. \(x^8+3x^3-2\). A polynomial need not contain all middle powers. In \(x^8+3x^3-2\), the present powers are valid.

Step 3

Exam Tip

बहुपद में सभी बीच की घातों का होना जरूरी नहीं है। \(x^8+3x^3-2\) में उपस्थित घातें मान्य हैं।

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यदि (p(x)=2x-3+(h-5)x+4) की घात (3) है, तो (h) के बारे में क्या सही है?

If (p(x)=2x-3+(h-5)x+4) has degree (3), what is correct about (h)?

Explanation opens after your attempt
Correct Answer

B. कोई भी वास्तविक (h)Any real (h)

Step 1

Concept

The coefficient of \(x^3\) is always non-zero. Therefore, the degree remains (3) for every (h).

Step 2

Why this answer is correct

The correct answer is B. कोई भी वास्तविक (h) / Any real (h). The coefficient of \(x^3\) is always non-zero. Therefore, the degree remains (3) for every (h).

Step 3

Exam Tip

\(x^3\) का गुणांक (2) हमेशा अशून्य है। इसलिए घात (3) हर (h) के लिए रहेगी।

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\(\frac{x^5+x^2}{x^2}\) को सरल करने पर किस कारण बहुपद नहीं मिलेगा?

Why will \(\frac{x^5+x^2}{x^2}\) give a polynomial after simplification or not?

Explanation opens after your attempt
Correct Answer

A. यह \(x^3+1\) बनता है, इसलिए बहुपद हैIt becomes \(x^3+1\), so it is a polynomial

Step 1

Concept

\(\frac{x^5+x^2}{x^2}=x^3+1\). Its powers are (3) and (0), so it is a polynomial.

Step 2

Why this answer is correct

The correct answer is A. यह \(x^3+1\) बनता है, इसलिए बहुपद है / It becomes \(x^3+1\), so it is a polynomial. \(\frac{x^5+x^2}{x^2}=x^3+1\). Its powers are (3) and (0), so it is a polynomial.

Step 3

Exam Tip

\(\frac{x^5+x^2}{x^2}=x^3+1\) है। इसमें घातें (3) और (0) हैं, इसलिए यह बहुपद है।

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कौन-सा कथन \(x^2+\sin x\) के बारे में सही है?

Which statement is correct about \(x^2+\sin x\)?

Explanation opens after your attempt
Correct Answer

B. यह बहुपद नहीं है क्योंकि \(\sin x\) बहुपद पद नहीं हैIt is not a polynomial because \(\sin x\) is not a polynomial term

Step 1

Concept

In a polynomial, terms are powers of the variable with non-negative integer exponents. \(\sin x\) is not such a term.

Step 2

Why this answer is correct

The correct answer is B. यह बहुपद नहीं है क्योंकि \(\sin x\) बहुपद पद नहीं है / It is not a polynomial because \(\sin x\) is not a polynomial term. In a polynomial, terms are powers of the variable with non-negative integer exponents. \(\sin x\) is not such a term.

Step 3

Exam Tip

बहुपद में पद चर की शून्य या धनात्मक पूर्णांक घातों के रूप में होते हैं। \(\sin x\) ऐसा पद नहीं है।

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यदि (p(x)=x-2+ax+a), तो इसकी घात (2) कब होगी?

If (p(x)=x-2+ax+a), when will its degree be (2)?

Explanation opens after your attempt
Correct Answer

C. सभी वास्तविक (a) के लिएFor all real (a)

Step 1

Concept

The coefficient of \(x^2\) is (1), which is non-zero. Therefore, the degree is (2) for every (a).

Step 2

Why this answer is correct

The correct answer is C. सभी वास्तविक (a) के लिए / For all real (a). The coefficient of \(x^2\) is (1), which is non-zero. Therefore, the degree is (2) for every (a).

Step 3

Exam Tip

\(x^2\) का गुणांक (1) है, जो शून्य नहीं है। इसलिए घात हर (a) के लिए (2) है।

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कौन-सा व्यंजक बहुपद नहीं है क्योंकि उसमें \(\frac{1}{x^5}\) है?

Which expression is not a polynomial because it contains \(\frac{1}{x^5}\)?

Explanation opens after your attempt
Correct Answer

B. \(4+\frac{1}{x^5}\)

Step 1

Concept

\(\frac{1}{x^5}=x^{-5}\). Due to the negative power, it is not a polynomial.

Step 2

Why this answer is correct

The correct answer is B. \(4+\frac{1}{x^5}\). \(\frac{1}{x^5}=x^{-5}\). Due to the negative power, it is not a polynomial.

Step 3

Exam Tip

\(\frac{1}{x^5}=x^{-5}\) है। ऋणात्मक घात के कारण यह बहुपद नहीं है।

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(p(x)=x-6-2x-4+x-2-1) में कितने पद हैं और घात क्या है?

How many terms and what degree does (p(x)=x-6-2x-4+x-2-1) have?

Explanation opens after your attempt
Correct Answer

A. (4) पद, घात (6)(4) terms, degree (6)

Step 1

Concept

It has four terms and the highest power is (6). Count terms with their signs.

Step 2

Why this answer is correct

The correct answer is A. (4) पद, घात (6) / (4) terms, degree (6). It has four terms and the highest power is (6). Count terms with their signs.

Step 3

Exam Tip

इसमें चार पद हैं और सबसे बड़ी घात (6) है। पदों को चिन्ह सहित गिनें।

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कौन-सा व्यंजक (x) में बहुपद है, जबकि (z) गुणांक की तरह काम करता है?

Which expression is a polynomial in (x), while (z) acts like a coefficient?

Explanation opens after your attempt
Correct Answer

B. \(z^2x^4+3zx^2-8\)

Step 1

Concept

With respect to (x), \(z^2\) and (3z) are coefficients. The powers of (x) are (4), (2), and (0).

Step 2

Why this answer is correct

The correct answer is B. \(z^2x^4+3zx^2-8\). With respect to (x), \(z^2\) and (3z) are coefficients. The powers of (x) are (4), (2), and (0).

Step 3

Exam Tip

(x) के संदर्भ में \(z^2\) और (3z) गुणांक हैं। (x) की घातें (4), (2) और (0) हैं।

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यदि (p(x)=(a-2)x-2+(a-2)x+7) की घात (0) हो, तो (a) क्या होगा?

If (p(x)=(a-2)x-2+(a-2)x+7) has degree (0), what is (a)?

Explanation opens after your attempt
Correct Answer

A. (2)

Step 1

Concept

For degree (0), the coefficients of both \(x^2\) and (x) must be zero. From (a-2=0), (a=2), and (7) remains.

Step 2

Why this answer is correct

The correct answer is A. (2). For degree (0), the coefficients of both \(x^2\) and (x) must be zero. From (a-2=0), (a=2), and (7) remains.

Step 3

Exam Tip

घात (0) के लिए \(x^2\) और (x) दोनों के गुणांक शून्य होने चाहिए। (a-2=0) से (a=2) है और (7) बचता है।

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कौन-सा व्यंजक (x) में बहुपद नहीं है क्योंकि उसमें \(\log x\) है?

Which expression is not a polynomial in (x) because it contains \(\log x\)?

Explanation opens after your attempt
Correct Answer

A. \(x^2+\log x\)

Step 1

Concept

\(\log x\) is not a term with a non-negative integer power of the variable. Therefore, it is not a polynomial.

Step 2

Why this answer is correct

The correct answer is A. \(x^2+\log x\). \(\log x\) is not a term with a non-negative integer power of the variable. Therefore, it is not a polynomial.

Step 3

Exam Tip

\(\log x\) चर की शून्य या धनात्मक पूर्णांक घात वाला पद नहीं है। इसलिए यह बहुपद नहीं है।

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यदि (p(x)=0x-9+0x-4+0), तो (p(x)) के बारे में सही कथन कौन-सा है?

If (p(x)=0x-9+0x-4+0), which statement is correct about (p(x))?

Explanation opens after your attempt
Correct Answer

C. यह शून्य बहुपद है जिसकी घात परिभाषित नहीं हैIt is the zero polynomial whose degree is not defined

Step 1

Concept

All terms have zero coefficients, so it is the zero polynomial. The degree of the zero polynomial is not defined.

Step 2

Why this answer is correct

The correct answer is C. यह शून्य बहुपद है जिसकी घात परिभाषित नहीं है / It is the zero polynomial whose degree is not defined. All terms have zero coefficients, so it is the zero polynomial. The degree of the zero polynomial is not defined.

Step 3

Exam Tip

सभी पदों के गुणांक शून्य हैं, इसलिए यह शून्य बहुपद है। शून्य बहुपद की घात परिभाषित नहीं होती।

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किस विकल्प में बहुपद की परिभाषा सबसे सटीक है?

Which option gives the most accurate definition of a polynomial?

Explanation opens after your attempt
Correct Answer

A. चर की घातें निश्चित शून्य या धनात्मक पूर्णांक होंVariable powers are fixed zero or positive integers

Step 1

Concept

A polynomial is identified mainly by the powers of the variable. The powers must be fixed non-negative integers.

Step 2

Why this answer is correct

The correct answer is A. चर की घातें निश्चित शून्य या धनात्मक पूर्णांक हों / Variable powers are fixed zero or positive integers. A polynomial is identified mainly by the powers of the variable. The powers must be fixed non-negative integers.

Step 3

Exam Tip

बहुपद की पहचान मुख्य रूप से चर की घातों से होती है। घातें निश्चित शून्य या धनात्मक पूर्णांक होनी चाहिए।

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कौन-सा व्यंजक (x) में बहुपद है और केवल सम घातें रखता है?

Which expression is a polynomial in (x) and has only even powers?

Explanation opens after your attempt
Correct Answer

A. \(x^8-5x^6+2x^2+4\)

Step 1

Concept

In the first option, the powers are (8), (6), (2), and (0). All are even and valid.

Step 2

Why this answer is correct

The correct answer is A. \(x^8-5x^6+2x^2+4\). In the first option, the powers are (8), (6), (2), and (0). All are even and valid.

Step 3

Exam Tip

पहले विकल्प में घातें (8), (6), (2) और (0) हैं। ये सभी सम और मान्य हैं।

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यदि (p(x)=\(k^2-1\)x-5+2x-4+3), तो (p(x)) की घात (4) कब होगी?

If (p(x)=\(k^2-1\)x-5+2x-4+3), when will the degree of (p(x)) be (4)?

Explanation opens after your attempt
Correct Answer

A. (k=1) या (k=-1)(k=1) or (k=-1)

Step 1

Concept

For degree (4), the coefficient of \(x^5\) must be zero. From \(k^2-1=0\), \(k=\pm1\), and \(2x^4\) remains non-zero.

Step 2

Why this answer is correct

The correct answer is A. (k=1) या (k=-1) / (k=1) or (k=-1). For degree (4), the coefficient of \(x^5\) must be zero. From \(k^2-1=0\), \(k=\pm1\), and \(2x^4\) remains non-zero.

Step 3

Exam Tip

घात (4) के लिए \(x^5\) का गुणांक शून्य होना चाहिए। \(k^2-1=0\) से \(k=\pm1\) और \(2x^4\) अशून्य रहता है।

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कौन-सा व्यंजक द्विघात त्रिपदी बहुपद है?

Which expression is a quadratic trinomial polynomial?

Explanation opens after your attempt
Correct Answer

A. \(x^2-5x+6\)

Step 1

Concept

\(x^2-5x+6\) has degree (2) and three terms. Therefore, it is a quadratic trinomial.

Step 2

Why this answer is correct

The correct answer is A. \(x^2-5x+6\). \(x^2-5x+6\) has degree (2) and three terms. Therefore, it is a quadratic trinomial.

Step 3

Exam Tip

\(x^2-5x+6\) की घात (2) है और इसमें तीन पद हैं। इसलिए यह द्विघात त्रिपदी है।

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कौन-सा व्यंजक बहुपद नहीं है क्योंकि उसमें (x) हर में छिपा हुआ है?

Which expression is not a polynomial because (x) is hidden in the denominator?

Explanation opens after your attempt
Correct Answer

B. \(\frac{x^2+4}{x^2}\)

Step 1

Concept

\(\frac{x^2+4}{x^2}=1+\frac{4}{x^2}\). Since \(\frac{4}{x^2}=4x^{-2}\), it is not a polynomial.

Step 2

Why this answer is correct

The correct answer is B. \(\frac{x^2+4}{x^2}\). \(\frac{x^2+4}{x^2}=1+\frac{4}{x^2}\). Since \(\frac{4}{x^2}=4x^{-2}\), it is not a polynomial.

Step 3

Exam Tip

\(\frac{x^2+4}{x^2}=1+\frac{4}{x^2}\) है। \(\frac{4}{x^2}=4x^{-2}\), इसलिए यह बहुपद नहीं है।

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यदि (p(x)=x-4+cx-3+dx-2+e), तो किस स्थिति में इसकी घात निश्चित रूप से (4) है?

If (p(x)=x-4+cx-3+dx-2+e), under what condition is its degree definitely (4)?

Explanation opens after your attempt
Correct Answer

A. किसी भी (c), (d), (e) के लिएFor any (c), (d), (e)

Step 1

Concept

The coefficient of \(x^4\) is (1), which is never zero. Therefore, the degree is always (4).

Step 2

Why this answer is correct

The correct answer is A. किसी भी (c), (d), (e) के लिए / For any (c), (d), (e). The coefficient of \(x^4\) is (1), which is never zero. Therefore, the degree is always (4).

Step 3

Exam Tip

\(x^4\) का गुणांक (1) है, जो कभी शून्य नहीं होता। इसलिए घात हमेशा (4) रहेगी।

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कौन-सा व्यंजक (x) में बहुपद है लेकिन (x) में रैखिक बहुपद नहीं है?

Which expression is a polynomial in (x) but not a linear polynomial in (x)?

Explanation opens after your attempt
Correct Answer

B. \(x^3+1\)

Step 1

Concept

\(x^3+1\) is a polynomial, but its degree is (3). A linear polynomial has degree (1).

Step 2

Why this answer is correct

The correct answer is B. \(x^3+1\). \(x^3+1\) is a polynomial, but its degree is (3). A linear polynomial has degree (1).

Step 3

Exam Tip

\(x^3+1\) बहुपद है, पर इसकी घात (3) है। रैखिक बहुपद की घात (1) होती है।

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यदि (p(x)=(a-1)x-3+(a-1)x-2+(a-1)x+5) स्थिर बहुपद हो, तो (a) क्या होगा?

If (p(x)=(a-1)x-3+(a-1)x-2+(a-1)x+5) is a constant polynomial, what is (a)?

Explanation opens after your attempt
Correct Answer

A. (1)

Step 1

Concept

For a constant polynomial, all variable-term coefficients must be zero. From (a-1=0), (a=1), and (5) remains.

Step 2

Why this answer is correct

The correct answer is A. (1). For a constant polynomial, all variable-term coefficients must be zero. From (a-1=0), (a=1), and (5) remains.

Step 3

Exam Tip

स्थिर बहुपद के लिए सभी चर पदों के गुणांक शून्य होने चाहिए। (a-1=0) से (a=1) मिलता है और (5) बचता है।

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यदि (q(x)=(a+2)x-6+(a-4)x-5+3) की घात ठीक (5) हो, तो (a) का मान क्या होगा?

If (q(x)=(a+2)x-6+(a-4)x-5+3) has degree exactly (5), what is the value of (a)?

Explanation opens after your attempt
Correct Answer

B. (-2)

Step 1

Concept

For degree (5), the \(x^6\) coefficient must be zero and the \(x^5\) coefficient must be non-zero. At (a=-2), (a-4=-6) remains non-zero.

Step 2

Why this answer is correct

The correct answer is B. (-2). For degree (5), the \(x^6\) coefficient must be zero and the \(x^5\) coefficient must be non-zero. At (a=-2), (a-4=-6) remains non-zero.

Step 3

Exam Tip

घात (5) के लिए \(x^6\) का गुणांक शून्य और \(x^5\) का गुणांक अशून्य होना चाहिए। (a=-2) पर (a-4=-6) अशून्य रहता है।

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\(\frac{x^4+x^2+x}{x}\) को \(x\neq0\) पर सरल करने के बाद कौन-सा बहुपद मिलेगा?

After simplifying \(\frac{x^4+x^2+x}{x}\) for \(x\neq0\), which polynomial is obtained?

Explanation opens after your attempt
Correct Answer

A. \(x^3+x+1\)

Step 1

Concept

Dividing each term by (x) gives \(x^3+x+1\). All its powers are non-negative integers.

Step 2

Why this answer is correct

The correct answer is A. \(x^3+x+1\). Dividing each term by (x) gives \(x^3+x+1\). All its powers are non-negative integers.

Step 3

Exam Tip

हर पद को (x) से भाग देने पर \(x^3+x+1\) मिलता है। इसमें सभी घातें शून्य या धनात्मक पूर्णांक हैं।

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कौन-सा व्यंजक (x) में बहुपद नहीं है क्योंकि उसमें \(\cos x\) जैसा पद है?

Which expression is not a polynomial in (x) because it contains a term like \(\cos x\)?

Explanation opens after your attempt
Correct Answer

B. \(3x^2+\cos x\)

Step 1

Concept

Polynomial terms use fixed non-negative integer powers of the variable. \(\cos x\) is not such a term.

Step 2

Why this answer is correct

The correct answer is B. \(3x^2+\cos x\). Polynomial terms use fixed non-negative integer powers of the variable. \(\cos x\) is not such a term.

Step 3

Exam Tip

बहुपद के पद चर की निश्चित शून्य या धनात्मक पूर्णांक घातों में होते हैं। \(\cos x\) ऐसा पद नहीं है।

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यदि (p(x)=(k-3)x-2+(2k-6)x+11) की घात (0) हो, तो (k) क्या होगा?

If (p(x)=(k-3)x-2+(2k-6)x+11) has degree (0), what is (k)?

Explanation opens after your attempt
Correct Answer

C. (3)

Step 1

Concept

For degree (0), both variable-term coefficients must be zero. Both (k-3=0) and (2k-6=0) give (k=3).

Step 2

Why this answer is correct

The correct answer is C. (3). For degree (0), both variable-term coefficients must be zero. Both (k-3=0) and (2k-6=0) give (k=3).

Step 3

Exam Tip

घात (0) के लिए चर वाले दोनों गुणांक शून्य होने चाहिए। (k-3=0) और (2k-6=0) दोनों से (k=3) मिलता है।

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यदि (p(x)=\(a^2-4\)x-4+(a+2)x-3+5x+1) की घात ठीक (3) हो, तो (a) का मान क्या होगा?

If (p(x)=\(a^2-4\)x-4+(a+2)x-3+5x+1) has degree exactly (3), what is the value of (a)?

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Correct Answer

B. (2)

Step 1

Concept

For degree (3), the \(x^4\) coefficient must be zero and the \(x^3\) coefficient must be non-zero. At (a=2), \(a^2-4=0\) and (a+2=4).

Step 2

Why this answer is correct

The correct answer is B. (2). For degree (3), the \(x^4\) coefficient must be zero and the \(x^3\) coefficient must be non-zero. At (a=2), \(a^2-4=0\) and (a+2=4).

Step 3

Exam Tip

घात (3) के लिए \(x^4\) का गुणांक शून्य और \(x^3\) का गुणांक अशून्य होना चाहिए। (a=2) पर \(a^2-4=0\) और (a+2=4) है।

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