After simplifying \(\frac{x^4-3x^2}{x^2}\) for \(x\neq0\), which form is obtained?

Correct answer: \(x^2-3\)

Divide both terms of the numerator by \(x^2\): \(\frac{x^4}{x^2}-\frac{3x^2}{x^2}=x^{4-2}-3x^{2-2}=x^2-3\). Therefore, \(x^2-3\) is the correct answer. Option B incorrectly divides the second term, since \(\frac{3x^2}{x^2}=3\), not \(\frac{3}{x^2}\). The simplification is valid only for \(x\neq0\), as the original expression is undefined at \(x=0\). Exam tip: when dividing powers with the same base, subtract the exponents.