किस व्यंजक को \(x\neq0\) पर सरल करने के बाद भी बहुपद नहीं मिलेगा?
Which expression will still not become a polynomial after simplification for \(x\neq0\)?
Explanation opens after your attempt
Correct Answer
C. \(\frac{x^3+1}{x}\)
Concept
\(\frac{x^3+1}{x}=x^2+\frac{1}{x}\). Since \(\frac{1}{x}\) has a negative power, it is not a polynomial.
Why this answer is correct
The correct answer is C. \(\frac{x^3+1}{x}\). \(\frac{x^3+1}{x}=x^2+\frac{1}{x}\). Since \(\frac{1}{x}\) has a negative power, it is not a polynomial.
Exam Tip
\(\frac{x^3+1}{x}=x^2+\frac{1}{x}\) है। \(\frac{1}{x}\) में ऋणात्मक घात है, इसलिए यह बहुपद नहीं है।
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