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If (p(x)=(k^2-1)x^5+2x^4+3), when will the degree of (p(x)) be (4)?यदि (p(x)=(k^2-1)x^5+2x^4+3), तो (p(x)) की घात (4) कब होगी?
Answer and explanationउत्तर और व्याख्या
Correct answer:सही उत्तर: (k=1) or (k=-1)(k=1) या (k=-1)
For degree (4), the coefficient of (x^5) must be zero. From (k^2-1=0), (k=\pm1), and (2x^4) remains non-zero.घात (4) के लिए (x^5) का गुणांक शून्य होना चाहिए। (k^2-1=0) से (k=\pm1) और (2x^4) अशून्य रहता है।
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