यदि (p(x)=\(k^2-1\)x-5+2x-4+3), तो (p(x)) की घात (4) कब होगी?
If (p(x)=\(k^2-1\)x-5+2x-4+3), when will the degree of (p(x)) be (4)?
Explanation opens after your attempt
A. (k=1) या (k=-1)(k=1) or (k=-1)
Concept
For degree (4), the coefficient of \(x^5\) must be zero. From \(k^2-1=0\), \(k=\pm1\), and \(2x^4\) remains non-zero.
Why this answer is correct
The correct answer is A. (k=1) या (k=-1) / (k=1) or (k=-1). For degree (4), the coefficient of \(x^5\) must be zero. From \(k^2-1=0\), \(k=\pm1\), and \(2x^4\) remains non-zero.
Exam Tip
घात (4) के लिए \(x^5\) का गुणांक शून्य होना चाहिए। \(k^2-1=0\) से \(k=\pm1\) और \(2x^4\) अशून्य रहता है।
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