Concept-wise Practice

degree-condition MCQ Questions for Class 9

degree-condition se related questions ko ek jagah revise karein. Har question me bilingual content, answer feedback aur explanation available hai.

Practice Questions

5 questions tagged with degree-condition.

किस (k) पर ((k-1)x-4+(k+2)x-3+7x-4) की घात (3) होगी?

For which (k) will ((k-1)x-4+(k+2)x-3+7x-4) have degree (3)?

Explanation opens after your attempt
Correct Answer

A. (k=1)

Step 1

Concept

For degree (3), the \(x^4\) coefficient must be zero and the \(x^3\) coefficient must be non-zero. At (k=1), (k+2=3) is also non-zero.

Step 2

Why this answer is correct

The correct answer is A. (k=1). For degree (3), the \(x^4\) coefficient must be zero and the \(x^3\) coefficient must be non-zero. At (k=1), (k+2=3) is also non-zero.

Step 3

Exam Tip

घात (3) के लिए \(x^4\) का गुणांक शून्य और \(x^3\) का गुणांक अशून्य होना चाहिए। (k=1) पर (k+2=3) भी अशून्य है।

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किस स्थिति में ((k+2)x-3+(5-k)x-2+7) की घात (2) होगी?

Under which condition will ((k+2)x-3+(5-k)x-2+7) have degree (2)?

Explanation opens after your attempt
Correct Answer

D. (k=-2)

Step 1

Concept

For degree (2), the coefficient of \(x^3\) must be zero and the coefficient of \(x^2\) must remain non-zero. From (k+2=0), (k=-2).

Step 2

Why this answer is correct

The correct answer is D. (k=-2). For degree (2), the coefficient of \(x^3\) must be zero and the coefficient of \(x^2\) must remain non-zero. From (k+2=0), (k=-2).

Step 3

Exam Tip

घात (2) के लिए \(x^3\) का गुणांक शून्य होना चाहिए और \(x^2\) का गुणांक अशून्य रहना चाहिए। (k+2=0) से (k=-2) मिलता है।

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यदि (p(x)=(k+2)x-5+(k-1)x-3+9) की घात (3) है, तो (k) क्या होगा?

If (p(x)=(k+2)x-5+(k-1)x-3+9) has degree (3), what is (k)?

Explanation opens after your attempt
Correct Answer

A. (k=-2)

Step 1

Concept

For degree (3), the coefficient of \(x^5\) must be (0). From (k+2=0), (k=-2), and the \(x^3\) coefficient remains non-zero.

Step 2

Why this answer is correct

The correct answer is A. (k=-2). For degree (3), the coefficient of \(x^5\) must be (0). From (k+2=0), (k=-2), and the \(x^3\) coefficient remains non-zero.

Step 3

Exam Tip

घात (3) के लिए \(x^5\) का गुणांक (0) होना चाहिए। (k+2=0) से (k=-2), और \(x^3\) का गुणांक अशून्य रहता है।

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यदि (p(x)=(m+1)x-3+(m-2)x-2+5) की घात (2) है, तो (m) का मान क्या होगा?

If (p(x)=(m+1)x-3+(m-2)x-2+5) has degree (2), what is the value of (m)?

Explanation opens after your attempt
Correct Answer

A. (m=-1)

Step 1

Concept

For degree (2), the coefficient of \(x^3\) must be (0) and the coefficient of \(x^2\) non-zero. This happens at (m=-1).

Step 2

Why this answer is correct

The correct answer is A. (m=-1). For degree (2), the coefficient of \(x^3\) must be (0) and the coefficient of \(x^2\) non-zero. This happens at (m=-1).

Step 3

Exam Tip

घात (2) के लिए \(x^3\) का गुणांक (0) और \(x^2\) का गुणांक अशून्य होना चाहिए। (m=-1) पर ऐसा होता है।

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यदि (r(x)=kx-3+2x-2+1) की घात (2) है, तो (k) के बारे में क्या सही है?

If the degree of (r(x)=kx-3+2x-2+1) is (2), what is correct about (k)?

Explanation opens after your attempt
Correct Answer

C. (k=0)

Step 1

Concept

For the degree to be (2), the \(x^3\) term must disappear. Therefore, (k=0) is required.

Step 2

Why this answer is correct

The correct answer is C. (k=0). For the degree to be (2), the \(x^3\) term must disappear. Therefore, (k=0) is required.

Step 3

Exam Tip

घात (2) होने के लिए \(x^3\) वाला पद हटना चाहिए। इसलिए (k=0) होना जरूरी है।

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