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If (p(x)=(m+1)x^3+(m-2)x^2+5) has degree (2), what is the value of (m)?यदि (p(x)=(m+1)x^3+(m-2)x^2+5) की घात (2) है, तो (m) का मान क्या होगा?
Answer and explanationउत्तर और व्याख्या
Correct answer:सही उत्तर: (m=-1)(m=-1)
For degree (2), the coefficient of (x^3) must be (0) and the coefficient of (x^2) non-zero. This happens at (m=-1).घात (2) के लिए (x^3) का गुणांक (0) और (x^2) का गुणांक अशून्य होना चाहिए। (m=-1) पर ऐसा होता है।
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