यदि (p(x)=(m+1)x-3+(m-2)x-2+5) की घात (2) है, तो (m) का मान क्या होगा?
If (p(x)=(m+1)x-3+(m-2)x-2+5) has degree (2), what is the value of (m)?
Explanation opens after your attempt
A. (m=-1)
Concept
For degree (2), the coefficient of \(x^3\) must be (0) and the coefficient of \(x^2\) non-zero. This happens at (m=-1).
Why this answer is correct
The correct answer is A. (m=-1). For degree (2), the coefficient of \(x^3\) must be (0) and the coefficient of \(x^2\) non-zero. This happens at (m=-1).
Exam Tip
घात (2) के लिए \(x^3\) का गुणांक (0) और \(x^2\) का गुणांक अशून्य होना चाहिए। (m=-1) पर ऐसा होता है।
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