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If (p(x)=(k+2)x^5+(k-1)x^3+9) has degree (3), what is (k)?यदि (p(x)=(k+2)x^5+(k-1)x^3+9) की घात (3) है, तो (k) क्या होगा?
Answer and explanationउत्तर और व्याख्या
Correct answer:सही उत्तर: (k=-2)(k=-2)
For degree (3), the coefficient of (x^5) must be (0). From (k+2=0), (k=-2), and the (x^3) coefficient remains non-zero.घात (3) के लिए (x^5) का गुणांक (0) होना चाहिए। (k+2=0) से (k=-2), और (x^3) का गुणांक अशून्य रहता है।
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