यदि (p(x)=(k+2)x-5+(k-1)x-3+9) की घात (3) है, तो (k) क्या होगा?
If (p(x)=(k+2)x-5+(k-1)x-3+9) has degree (3), what is (k)?
Explanation opens after your attempt
A. (k=-2)
Concept
For degree (3), the coefficient of \(x^5\) must be (0). From (k+2=0), (k=-2), and the \(x^3\) coefficient remains non-zero.
Why this answer is correct
The correct answer is A. (k=-2). For degree (3), the coefficient of \(x^5\) must be (0). From (k+2=0), (k=-2), and the \(x^3\) coefficient remains non-zero.
Exam Tip
घात (3) के लिए \(x^5\) का गुणांक (0) होना चाहिए। (k+2=0) से (k=-2), और \(x^3\) का गुणांक अशून्य रहता है।
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