यदि (p(x)=(k+2)x-5+(k-1)x-3+9) की घात (3) है, तो (k) क्या होगा?

If (p(x)=(k+2)x-5+(k-1)x-3+9) has degree (3), what is (k)?

Explanation opens after your attempt
Correct Answer

A. (k=-2)

Step 1

Concept

For degree (3), the coefficient of \(x^5\) must be (0). From (k+2=0), (k=-2), and the \(x^3\) coefficient remains non-zero.

Step 2

Why this answer is correct

The correct answer is A. (k=-2). For degree (3), the coefficient of \(x^5\) must be (0). From (k+2=0), (k=-2), and the \(x^3\) coefficient remains non-zero.

Step 3

Exam Tip

घात (3) के लिए \(x^5\) का गुणांक (0) होना चाहिए। (k+2=0) से (k=-2), और \(x^3\) का गुणांक अशून्य रहता है।

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Mathematics Answer, Explanation and Revision Hints

यदि (p(x)=(k+2)x-5+(k-1)x-3+9) की घात (3) है, तो (k) क्या होगा? / If (p(x)=(k+2)x-5+(k-1)x-3+9) has degree (3), what is (k)?

Correct Answer: A. (k=-2). Explanation: घात (3) के लिए \(x^5\) का गुणांक (0) होना चाहिए। (k+2=0) से (k=-2), और \(x^3\) का गुणांक अशून्य रहता है। / For degree (3), the coefficient of \(x^5\) must be (0). From (k+2=0), (k=-2), and the \(x^3\) coefficient remains non-zero.

Which concept should I revise for this Mathematics MCQ?

For degree (3), the coefficient of \(x^5\) must be (0). From (k+2=0), (k=-2), and the \(x^3\) coefficient remains non-zero.

What exam hint can help solve this Mathematics question?

घात (3) के लिए \(x^5\) का गुणांक (0) होना चाहिए। (k+2=0) से (k=-2), और \(x^3\) का गुणांक अशून्य रहता है।