यदि (q(x)=(a+2)x-6+(a-4)x-5+3) की घात ठीक (5) हो, तो (a) का मान क्या होगा?
If (q(x)=(a+2)x-6+(a-4)x-5+3) has degree exactly (5), what is the value of (a)?
Explanation opens after your attempt
B. (-2)
Concept
For degree (5), the \(x^6\) coefficient must be zero and the \(x^5\) coefficient must be non-zero. At (a=-2), (a-4=-6) remains non-zero.
Why this answer is correct
The correct answer is B. (-2). For degree (5), the \(x^6\) coefficient must be zero and the \(x^5\) coefficient must be non-zero. At (a=-2), (a-4=-6) remains non-zero.
Exam Tip
घात (5) के लिए \(x^6\) का गुणांक शून्य और \(x^5\) का गुणांक अशून्य होना चाहिए। (a=-2) पर (a-4=-6) अशून्य रहता है।
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