यदि (p(x)=kx-3+(k-2)x-2+1) की घात (2) हो, तो (k) क्या होगा?
If (p(x)=kx-3+(k-2)x-2+1) has degree (2), what is (k)?
Explanation opens after your attempt
A. (0)
Concept
For degree (2), the \(x^3\) coefficient must be zero and the \(x^2\) coefficient must be non-zero. At (k=0), (k-2=-2) is non-zero.
Why this answer is correct
The correct answer is A. (0). For degree (2), the \(x^3\) coefficient must be zero and the \(x^2\) coefficient must be non-zero. At (k=0), (k-2=-2) is non-zero.
Exam Tip
घात (2) के लिए \(x^3\) का गुणांक शून्य चाहिए और \(x^2\) का गुणांक अशून्य चाहिए। (k=0) पर (k-2=-2) अशून्य है।
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