If (p(x)=kx^3+(k-2)x^2+1) has degree (2), what is (k)?यदि (p(x)=kx^3+(k-2)x^2+1) की घात (2) हो, तो (k) क्या होगा?
Answer and explanationउत्तर और व्याख्या
Correct answer:सही उत्तर: (0)(0)
For degree (2), the (x^3) coefficient must be zero and the (x^2) coefficient must be non-zero. At (k=0), (k-2=-2) is non-zero.घात (2) के लिए (x^3) का गुणांक शून्य चाहिए और (x^2) का गुणांक अशून्य चाहिए। (k=0) पर (k-2=-2) अशून्य है।
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