\(\frac{x^5+x^2}{x^2}\) को सरल करने पर किस कारण बहुपद नहीं मिलेगा?

Why will \(\frac{x^5+x^2}{x^2}\) give a polynomial after simplification or not?

Explanation opens after your attempt
Correct Answer

A. यह \(x^3+1\) बनता है, इसलिए बहुपद हैIt becomes \(x^3+1\), so it is a polynomial

Step 1

Concept

\(\frac{x^5+x^2}{x^2}=x^3+1\). Its powers are (3) and (0), so it is a polynomial.

Step 2

Why this answer is correct

The correct answer is A. यह \(x^3+1\) बनता है, इसलिए बहुपद है / It becomes \(x^3+1\), so it is a polynomial. \(\frac{x^5+x^2}{x^2}=x^3+1\). Its powers are (3) and (0), so it is a polynomial.

Step 3

Exam Tip

\(\frac{x^5+x^2}{x^2}=x^3+1\) है। इसमें घातें (3) और (0) हैं, इसलिए यह बहुपद है।

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Mathematics Answer, Explanation and Revision Hints

\(\frac{x^5+x^2}{x^2}\) को सरल करने पर किस कारण बहुपद नहीं मिलेगा? / Why will \(\frac{x^5+x^2}{x^2}\) give a polynomial after simplification or not?

Correct Answer: A. यह \(x^3+1\) बनता है, इसलिए बहुपद है / It becomes \(x^3+1\), so it is a polynomial. Explanation: \(\frac{x^5+x^2}{x^2}=x^3+1\) है। इसमें घातें (3) और (0) हैं, इसलिए यह बहुपद है। / \(\frac{x^5+x^2}{x^2}=x^3+1\). Its powers are (3) and (0), so it is a polynomial.

Which concept should I revise for this Mathematics MCQ?

\(\frac{x^5+x^2}{x^2}=x^3+1\). Its powers are (3) and (0), so it is a polynomial.

What exam hint can help solve this Mathematics question?

\(\frac{x^5+x^2}{x^2}=x^3+1\) है। इसमें घातें (3) और (0) हैं, इसलिए यह बहुपद है।