यदि (p(x)=(k-3)x-2+(2k-6)x+11) की घात (0) हो, तो (k) क्या होगा?
If (p(x)=(k-3)x-2+(2k-6)x+11) has degree (0), what is (k)?
Explanation opens after your attempt
C. (3)
Concept
For degree (0), both variable-term coefficients must be zero. Both (k-3=0) and (2k-6=0) give (k=3).
Why this answer is correct
The correct answer is C. (3). For degree (0), both variable-term coefficients must be zero. Both (k-3=0) and (2k-6=0) give (k=3).
Exam Tip
घात (0) के लिए चर वाले दोनों गुणांक शून्य होने चाहिए। (k-3=0) और (2k-6=0) दोनों से (k=3) मिलता है।
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