0 reads0 ratings0 helpful
If (p(x)=(k-3)x^2+(2k-6)x+11) has degree (0), what is (k)?यदि (p(x)=(k-3)x^2+(2k-6)x+11) की घात (0) हो, तो (k) क्या होगा?
Answer and explanationउत्तर और व्याख्या
Correct answer:सही उत्तर: (3)(3)
For degree (0), both variable-term coefficients must be zero. Both (k-3=0) and (2k-6=0) give (k=3).घात (0) के लिए चर वाले दोनों गुणांक शून्य होने चाहिए। (k-3=0) और (2k-6=0) दोनों से (k=3) मिलता है।
Student feedback
Was this question useful?
Was this question useful?
👍 0 Helpful 👎 0 Not helpful
Difficulty
Easy0%
Medium0%
Hard0%
Was the explanation clear?
Yes 0% No 0%
0 responsesStudent Reviews
No published reviews yet.
