\(\frac{x^4+x^2+x}{x}\) को \(x\neq0\) पर सरल करने के बाद कौन-सा बहुपद मिलेगा?

After simplifying \(\frac{x^4+x^2+x}{x}\) for \(x\neq0\), which polynomial is obtained?

Explanation opens after your attempt
Correct Answer

A. \(x^3+x+1\)

Step 1

Concept

Dividing each term by (x) gives \(x^3+x+1\). All its powers are non-negative integers.

Step 2

Why this answer is correct

The correct answer is A. \(x^3+x+1\). Dividing each term by (x) gives \(x^3+x+1\). All its powers are non-negative integers.

Step 3

Exam Tip

हर पद को (x) से भाग देने पर \(x^3+x+1\) मिलता है। इसमें सभी घातें शून्य या धनात्मक पूर्णांक हैं।

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Mathematics Answer, Explanation and Revision Hints

\(\frac{x^4+x^2+x}{x}\) को \(x\neq0\) पर सरल करने के बाद कौन-सा बहुपद मिलेगा? / After simplifying \(\frac{x^4+x^2+x}{x}\) for \(x\neq0\), which polynomial is obtained?

Correct Answer: A. \(x^3+x+1\). Explanation: हर पद को (x) से भाग देने पर \(x^3+x+1\) मिलता है। इसमें सभी घातें शून्य या धनात्मक पूर्णांक हैं। / Dividing each term by (x) gives \(x^3+x+1\). All its powers are non-negative integers.

Which concept should I revise for this Mathematics MCQ?

Dividing each term by (x) gives \(x^3+x+1\). All its powers are non-negative integers.

What exam hint can help solve this Mathematics question?

हर पद को (x) से भाग देने पर \(x^3+x+1\) मिलता है। इसमें सभी घातें शून्य या धनात्मक पूर्णांक हैं।