\(x^2+\sqrt{x^2+4}\) के बारे में सही कथन कौन-सा है?
Which statement is correct about \(x^2+\sqrt{x^2+4}\)?
Explanation opens after your attempt
B. यह बहुपद नहीं है क्योंकि चर मूल के अंदर हैIt is not a polynomial because the variable is inside a root
Concept
\(\sqrt{x^2+4}\) has the variable inside a root. In the class (9) definition, such a term is not treated as a polynomial term.
Why this answer is correct
The correct answer is B. यह बहुपद नहीं है क्योंकि चर मूल के अंदर है / It is not a polynomial because the variable is inside a root. \(\sqrt{x^2+4}\) has the variable inside a root. In the class (9) definition, such a term is not treated as a polynomial term.
Exam Tip
\(\sqrt{x^2+4}\) में चर मूल के अंदर है। कक्षा (9) की परिभाषा में ऐसा पद बहुपद पद नहीं माना जाता।
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