Concept-wise Practice

radical-expression MCQ Questions for Class 10

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Practice Questions

6 questions tagged with radical-expression.

Question 1/6 Medium Mathematics Chapter 1: Real Numbers 5: Irrational numbers Class 10 Level 15

\(\sqrt{242}+\sqrt{98}-\sqrt{32}\) का सरल रूप क्या है?

What is the simplified form of \(\sqrt{242}+\sqrt{98}-\sqrt{32}\)?

Explanation opens after your attempt
Correct Answer

A. \(14\sqrt{2}\)

Step 1

Concept

\(\sqrt{242}=11\sqrt{2}\), \(\sqrt{98}=7\sqrt{2}\), and \(\sqrt{32}=4\sqrt{2}\).

Step 2

Why this answer is correct

\(11\sqrt{2}+7\sqrt{2}-4\sqrt{2}=14\sqrt{2}\).

Step 3

Exam Tip

Convert all radicals into like form before adding or subtracting. चरण 1: \(\sqrt{242}=11\sqrt{2}\), \(\sqrt{98}=7\sqrt{2}\), और \(\sqrt{32}=4\sqrt{2}\)। चरण 2: \(11\sqrt{2}+7\sqrt{2}-4\sqrt{2}=14\sqrt{2}\)। चरण 3: सभी वर्गमूलों को समान रूप में बदलकर ही जोड़-घटाव करें।

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Question 2/6 Medium Mathematics Chapter 1: Real Numbers 5: Irrational numbers Class 10 Level 15

\(\sqrt{245}+\sqrt{180}-\sqrt{80}\) का सरल रूप क्या है?

What is the simplified form of \(\sqrt{245}+\sqrt{180}-\sqrt{80}\)?

Explanation opens after your attempt
Correct Answer

C. \(9\sqrt{5}\)

Step 1

Concept

\(\sqrt{245}=7\sqrt{5}\), \(\sqrt{180}=6\sqrt{5}\), and \(\sqrt{80}=4\sqrt{5}\).

Step 2

Why this answer is correct

\(7\sqrt{5}+6\sqrt{5}-4\sqrt{5}=9\sqrt{5}\).

Step 3

Exam Tip

Before addition or subtraction, write all radicals in like form. चरण 1: \(\sqrt{245}=7\sqrt{5}\), \(\sqrt{180}=6\sqrt{5}\), और \(\sqrt{80}=4\sqrt{5}\)। चरण 2: \(7\sqrt{5}+6\sqrt{5}-4\sqrt{5}=9\sqrt{5}\)। चरण 3: जोड़-घटाव से पहले सभी वर्गमूलों को समान रूप में लिखें।

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Question 3/6 Medium Mathematics Chapter 1: Real Numbers 5: Irrational numbers Class 10 Level 14

\(\sqrt{128}+\sqrt{72}-\sqrt{50}\) का सरल रूप क्या है?

What is the simplified form of \(\sqrt{128}+\sqrt{72}-\sqrt{50}\)?

Explanation opens after your attempt
Correct Answer

A. \(9\sqrt{2}\)

Step 1

Concept

\(\sqrt{128}=8\sqrt{2}\), \(\sqrt{72}=6\sqrt{2}\), and \(\sqrt{50}=5\sqrt{2}\).

Step 2

Why this answer is correct

\(8\sqrt{2}+6\sqrt{2}-5\sqrt{2}=9\sqrt{2}\).

Step 3

Exam Tip

Convert all radicals into like form before adding or subtracting. चरण 1: \(\sqrt{128}=8\sqrt{2}\), \(\sqrt{72}=6\sqrt{2}\), और \(\sqrt{50}=5\sqrt{2}\)। चरण 2: \(8\sqrt{2}+6\sqrt{2}-5\sqrt{2}=9\sqrt{2}\)। चरण 3: सभी वर्गमूलों को समान रूप में बदलकर ही जोड़-घटाव करें।

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Question 4/6 Medium Mathematics Chapter 1: Real Numbers 5: Irrational numbers Class 10 Level 14

\(\sqrt{75}+\sqrt{300}-\sqrt{48}\) का सरल रूप क्या है?

What is the simplified form of \(\sqrt{75}+\sqrt{300}-\sqrt{48}\)?

Explanation opens after your attempt
Correct Answer

B. \(11\sqrt{3}\)

Step 1

Concept

\(\sqrt{75}=5\sqrt{3}\), \(\sqrt{300}=10\sqrt{3}\), and \(\sqrt{48}=4\sqrt{3}\).

Step 2

Why this answer is correct

\(5\sqrt{3}+10\sqrt{3}-4\sqrt{3}=11\sqrt{3}\).

Step 3

Exam Tip

Simplify all radicals before addition and subtraction. चरण 1: \(\sqrt{75}=5\sqrt{3}\), \(\sqrt{300}=10\sqrt{3}\), और \(\sqrt{48}=4\sqrt{3}\)। चरण 2: \(5\sqrt{3}+10\sqrt{3}-4\sqrt{3}=11\sqrt{3}\)। चरण 3: जोड़ और घटाव से पहले सभी वर्गमूलों को सरल करें।

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Question 5/6 Medium Mathematics Chapter 1: Real Numbers 5: Irrational numbers Class 10 Level 13

\(\sqrt{98}+\sqrt{50}-\sqrt{18}\) का सरल रूप क्या है?

What is the simplified form of \(\sqrt{98}+\sqrt{50}-\sqrt{18}\)?

Explanation opens after your attempt
Correct Answer

A. \(9\sqrt{2}\)

Step 1

Concept

\(\sqrt{98}=7\sqrt{2}\), \(\sqrt{50}=5\sqrt{2}\), and \(\sqrt{18}=3\sqrt{2}\).

Step 2

Why this answer is correct

\(7\sqrt{2}+5\sqrt{2}-3\sqrt{2}=9\sqrt{2}\).

Step 3

Exam Tip

Add or subtract only after converting all terms to like radicals. चरण 1: \(\sqrt{98}=7\sqrt{2}\), \(\sqrt{50}=5\sqrt{2}\), और \(\sqrt{18}=3\sqrt{2}\)। चरण 2: \(7\sqrt{2}+5\sqrt{2}-3\sqrt{2}=9\sqrt{2}\)। चरण 3: सभी पदों को समान वर्गमूल में बदलने के बाद ही जोड़-घटाव करें।

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Question 6/6 Medium Mathematics Chapter 1: Real Numbers 5: Irrational numbers Class 10 Level 13

\(\sqrt{45}+\sqrt{80}-\sqrt{20}\) का सरल रूप क्या है?

What is the simplified form of \(\sqrt{45}+\sqrt{80}-\sqrt{20}\)?

Explanation opens after your attempt
Correct Answer

A. \(5\sqrt{5}\)

Step 1

Concept

\(\sqrt{45}=3\sqrt{5}\), \(\sqrt{80}=4\sqrt{5}\), and \(\sqrt{20}=2\sqrt{5}\).

Step 2

Why this answer is correct

\(3\sqrt{5}+4\sqrt{5}-2\sqrt{5}=5\sqrt{5}\).

Step 3

Exam Tip

Convert all radicals to like form before adding or subtracting. चरण 1: \(\sqrt{45}=3\sqrt{5}\), \(\sqrt{80}=4\sqrt{5}\), और \(\sqrt{20}=2\sqrt{5}\)। चरण 2: \(3\sqrt{5}+4\sqrt{5}-2\sqrt{5}=5\sqrt{5}\)। चरण 3: जोड़ और घटाव से पहले सभी वर्गमूलों को समान रूप में बदलें।

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