\(\sqrt{245}+\sqrt{180}-\sqrt{80}\) का सरल रूप क्या है?

What is the simplified form of \(\sqrt{245}+\sqrt{180}-\sqrt{80}\)?

Explanation opens after your attempt
Correct Answer

C. \(9\sqrt{5}\)

Step 1

Concept

\(\sqrt{245}=7\sqrt{5}\), \(\sqrt{180}=6\sqrt{5}\), and \(\sqrt{80}=4\sqrt{5}\).

Step 2

Why this answer is correct

\(7\sqrt{5}+6\sqrt{5}-4\sqrt{5}=9\sqrt{5}\).

Step 3

Exam Tip

Before addition or subtraction, write all radicals in like form. चरण 1: \(\sqrt{245}=7\sqrt{5}\), \(\sqrt{180}=6\sqrt{5}\), और \(\sqrt{80}=4\sqrt{5}\)। चरण 2: \(7\sqrt{5}+6\sqrt{5}-4\sqrt{5}=9\sqrt{5}\)। चरण 3: जोड़-घटाव से पहले सभी वर्गमूलों को समान रूप में लिखें।

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Mathematics Answer, Explanation and Revision Hints

\(\sqrt{245}+\sqrt{180}-\sqrt{80}\) का सरल रूप क्या है? / What is the simplified form of \(\sqrt{245}+\sqrt{180}-\sqrt{80}\)?

Correct Answer: C. \(9\sqrt{5}\). Explanation: चरण 1: \(\sqrt{245}=7\sqrt{5}\), \(\sqrt{180}=6\sqrt{5}\), और \(\sqrt{80}=4\sqrt{5}\)। चरण 2: \(7\sqrt{5}+6\sqrt{5}-4\sqrt{5}=9\sqrt{5}\)। चरण 3: जोड़-घटाव से पहले सभी वर्गमूलों को समान रूप में लिखें। / Step 1: \(\sqrt{245}=7\sqrt{5}\), \(\sqrt{180}=6\sqrt{5}\), and \(\sqrt{80}=4\sqrt{5}\). Step 2: \(7\sqrt{5}+6\sqrt{5}-4\sqrt{5}=9\sqrt{5}\). Step 3: Before addition or subtraction, write all radicals in like form.

Which concept should I revise for this Mathematics MCQ?

\(\sqrt{245}=7\sqrt{5}\), \(\sqrt{180}=6\sqrt{5}\), and \(\sqrt{80}=4\sqrt{5}\).

What exam hint can help solve this Mathematics question?

Before addition or subtraction, write all radicals in like form. चरण 1: \(\sqrt{245}=7\sqrt{5}\), \(\sqrt{180}=6\sqrt{5}\), और \(\sqrt{80}=4\sqrt{5}\)। चरण 2: \(7\sqrt{5}+6\sqrt{5}-4\sqrt{5}=9\sqrt{5}\)। चरण 3: जोड़-घटाव से पहले सभी वर्गमूलों को समान रूप में लिखें।