If (p(x)=(a-2)x^2+(a-2)x+7) has degree (0), what is (a)?यदि (p(x)=(a-2)x^2+(a-2)x+7) की घात (0) हो, तो (a) क्या होगा?
Answer and explanationउत्तर और व्याख्या
Correct answer:सही उत्तर: (2)(2)
For degree (0), the coefficients of both (x^2) and (x) must be zero. From (a-2=0), (a=2), and (7) remains.घात (0) के लिए (x^2) और (x) दोनों के गुणांक शून्य होने चाहिए। (a-2=0) से (a=2) है और (7) बचता है।
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