यदि (p(x)=(a-2)x-2+(a-2)x+7) की घात (0) हो, तो (a) क्या होगा?
If (p(x)=(a-2)x-2+(a-2)x+7) has degree (0), what is (a)?
Explanation opens after your attempt
A. (2)
Concept
For degree (0), the coefficients of both \(x^2\) and (x) must be zero. From (a-2=0), (a=2), and (7) remains.
Why this answer is correct
The correct answer is A. (2). For degree (0), the coefficients of both \(x^2\) and (x) must be zero. From (a-2=0), (a=2), and (7) remains.
Exam Tip
घात (0) के लिए \(x^2\) और (x) दोनों के गुणांक शून्य होने चाहिए। (a-2=0) से (a=2) है और (7) बचता है।
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