\(-\frac{17}{5}=-3-\frac{2}{5}\), so it lies between (-4) and (-3). In exams, keep the sign of a negative mixed number correct.
Step 2
Why this answer is correct
The correct answer is B. \(-3-\frac{2}{5}\). \(-\frac{17}{5}=-3-\frac{2}{5}\), so it lies between (-4) and (-3). In exams, keep the sign of a negative mixed number correct.
Step 3
Exam Tip
\(-\frac{17}{5}=-3-\frac{2}{5}\), इसलिए यह (-4) और (-3) के बीच है। परीक्षा में ऋणात्मक मिश्र संख्या का चिह्न ठीक रखें।
\(\frac{13}{4}=3+\frac{1}{4}\), so it lies one-fourth after (3). In exams, convert an improper fraction into a mixed number.
Step 2
Why this answer is correct
The correct answer is A. \(3+\frac{1}{4}\). \(\frac{13}{4}=3+\frac{1}{4}\), so it lies one-fourth after (3). In exams, convert an improper fraction into a mixed number.
Step 3
Exam Tip
\(\frac{13}{4}=3+\frac{1}{4}\), इसलिए यह (3) के बाद एक चौथाई पर होगा। परीक्षा में विषम भिन्न को मिश्र संख्या में बदलें।
\(\frac{5}{4}=1+\frac{1}{4}\), so it is one-fourth after (1). In exams, convert an improper fraction into mixed form.
Step 2
Why this answer is correct
The correct answer is A. \(1+\frac{1}{4}\). \(\frac{5}{4}=1+\frac{1}{4}\), so it is one-fourth after (1). In exams, convert an improper fraction into mixed form.
Step 3
Exam Tip
\(\frac{5}{4}=1+\frac{1}{4}\), इसलिए यह (1) के बाद एक चौथाई भाग पर है। परीक्षा में अपूर्ण भिन्न को मिश्र रूप में बदलें।
The middle number between (0) and (1) is \(\frac{0+1}{2}=\frac{1}{2}\). In exams, use the average for the midpoint.
Step 2
Why this answer is correct
The correct answer is A. \(\frac{1}{2}\). The middle number between (0) and (1) is \(\frac{0+1}{2}=\frac{1}{2}\). In exams, use the average for the midpoint.
Step 3
Exam Tip
(0) और (1) के बीच की मध्य संख्या \(\frac{0+1}{2}=\frac{1}{2}\) है। परीक्षा में मध्य संख्या के लिए औसत लें।
Multiplying an irrational number by a non-zero rational number keeps it irrational.
Step 2
Why this answer is correct
For example, \(2 \times \sqrt{3}=2\sqrt{3}\), which is irrational.
Step 3
Exam Tip
The non-zero condition is important because multiplication by (0) gives (0). चरण 1: अशून्य परिमेय संख्या से अपरिमेय संख्या को गुणा करने पर परिणाम अपरिमेय रहता है। चरण 2: जैसे \(2 \times \sqrt{3}=2\sqrt{3}\), जो अपरिमेय है। चरण 3: यहां अशून्य शर्त जरूरी है, क्योंकि शून्य से गुणा करने पर परिणाम (0) होगा।
C. \(\frac{1}{2},\frac{1}{3},\sqrt{\frac{1}{4}}\) जैसे अनेक बिंदु/Many points like \(\frac{1}{2},\frac{1}{3},\sqrt{\frac{1}{4}}\)
Step 1
Concept
Between (0) and (1), there are infinitely many rational and irrational numbers. Between any two real numbers, more numbers can be found.
Step 2
Why this answer is correct
The correct answer is C. \(\frac{1}{2},\frac{1}{3},\sqrt{\frac{1}{4}}\) जैसे अनेक बिंदु / Many points like \(\frac{1}{2},\frac{1}{3},\sqrt{\frac{1}{4}}\). Between (0) and (1), there are infinitely many rational and irrational numbers. Between any two real numbers, more numbers can be found.
Step 3
Exam Tip
(0) और (1) के बीच परिमेय और अपरिमेय दोनों प्रकार की अनंत संख्याएं होती हैं। किसी भी दो वास्तविक संख्याओं के बीच और संख्याएं मिलती हैं।
In Class 10 real numbers the square root of a negative number is not real. Note that \(\sqrt{7}\) is real irrational.
Step 2
Why this answer is correct
The correct answer is A. \(\sqrt{-4}\). In Class 10 real numbers the square root of a negative number is not real. Note that \(\sqrt{7}\) is real irrational.
Step 3
Exam Tip
कक्षा 10 के वास्तविक संख्याओं में ऋणात्मक संख्या की वर्गमूल वास्तविक नहीं मानी जाती। ध्यान दें \(\sqrt{7}\) वास्तविक अपरिमेय है।
The point on the left is negative and its distance is \( \sqrt{41} \). Therefore the number is \( -\sqrt{41} \).
Step 2
Why this answer is correct
The correct answer is B. \( -\sqrt{41} \). The point on the left is negative and its distance is \( \sqrt{41} \). Therefore the number is \( -\sqrt{41} \).
Step 3
Exam Tip
बाईं ओर का बिंदु ऋणात्मक होगा और दूरी \( \sqrt{41} \) है। इसलिए संख्या \( -\sqrt{41} \) है।
This decimal is non-terminating and non-repeating, so it is irrational. Check whether the decimal pattern truly repeats or not.
Step 2
Why this answer is correct
The correct answer is B. अपरिमेय संख्या / Irrational number. This decimal is non-terminating and non-repeating, so it is irrational. Check whether the decimal pattern truly repeats or not.
Step 3
Exam Tip
यह दशमलव असांत और अनावर्ती है, इसलिए अपरिमेय है। दशमलव पैटर्न सच में दोहरता है या नहीं, यह जाँचें।
The point on the right is positive and its distance is \( \sqrt{26} \). Therefore the number is \( \sqrt{26} \).
Step 2
Why this answer is correct
The correct answer is B. \( \sqrt{26} \). The point on the right is positive and its distance is \( \sqrt{26} \). Therefore the number is \( \sqrt{26} \).
Step 3
Exam Tip
दाईं ओर का बिंदु धनात्मक होगा और दूरी \( \sqrt{26} \) है। इसलिए संख्या \( \sqrt{26} \) है।
This decimal is non-terminating and non-repeating, so it is irrational. Check carefully whether the pattern repeats or not.
Step 2
Why this answer is correct
The correct answer is B. अपरिमेय संख्या / Irrational number. This decimal is non-terminating and non-repeating, so it is irrational. Check carefully whether the pattern repeats or not.
Step 3
Exam Tip
यह दशमलव असांत और अनावर्ती है, इसलिए अपरिमेय है। पैटर्न दोहराव वाला है या नहीं, इसे ध्यान से देखें।
The point on the left is negative and its distance is \( \sqrt{17} \). Therefore the number is \( -\sqrt{17} \).
Step 2
Why this answer is correct
The correct answer is A. \( -\sqrt{17} \). The point on the left is negative and its distance is \( \sqrt{17} \). Therefore the number is \( -\sqrt{17} \).
Step 3
Exam Tip
बाईं ओर का बिंदु ऋणात्मक होगा और दूरी \( \sqrt{17} \) है। इसलिए संख्या \( -\sqrt{17} \) है।
This decimal is non-terminating and non-repeating. Hence it is an irrational number on the number line.
Step 2
Why this answer is correct
The correct answer is A. अपरिमेय संख्या / Irrational number. This decimal is non-terminating and non-repeating. Hence it is an irrational number on the number line.
Step 3
Exam Tip
यह दशमलव असांत और अनावर्ती है। इसलिए यह संख्या रेखा पर अपरिमेय संख्या है।
\(\frac{\sqrt{2}}{2}\) is irrational and its value lies between (0) and (1). An irrational divided by a non-zero rational remains irrational.
Step 2
Why this answer is correct
The correct answer is A. \(\frac{\sqrt{2}}{2}\). \(\frac{\sqrt{2}}{2}\) is irrational and its value lies between (0) and (1). An irrational divided by a non-zero rational remains irrational.
Step 3
Exam Tip
\(\frac{\sqrt{2}}{2}\) अपरिमेय है और इसका मान (0) और (1) के बीच है। अपरिमेय संख्या को परिमेय से भाग देने पर शून्येतर परिमेय के लिए अपरिमेय ही रहती है।
The midpoint of (0) and (1) is \(\frac{0+1}{2}=\frac{1}{2}\). To find a midpoint on a number line, take the average.
Step 2
Why this answer is correct
The correct answer is A. \(\frac{1}{2}\). The midpoint of (0) and (1) is \(\frac{0+1}{2}=\frac{1}{2}\). To find a midpoint on a number line, take the average.
Step 3
Exam Tip
(0) और (1) का मध्य बिंदु \(\frac{0+1}{2}=\frac{1}{2}\) होता है। संख्या रेखा में मध्य निकालने के लिए औसत लें।
\(-\frac{5}{4}=-1.25\), which is to the left of (-1). In exams, convert negative fractions into decimals to check.
Step 2
Why this answer is correct
The correct answer is C. \(-\frac{5}{4}\). \(-\frac{5}{4}=-1.25\), which is to the left of (-1). In exams, convert negative fractions into decimals to check.
Step 3
Exam Tip
\(-\frac{5}{4}=-1.25\), जो (-1) से बाईं ओर है। परीक्षा में ऋणात्मक भिन्न को दशमलव में बदलकर जांच सकते हैं।
\(\sqrt{14}\) is about (3.74), so (3.5) is greater than (3) and less than \(\sqrt{14}\). In exams, make a rough estimate of the square root.
Step 2
Why this answer is correct
The correct answer is B. (3.5). \(\sqrt{14}\) is about (3.74), so (3.5) is greater than (3) and less than \(\sqrt{14}\). In exams, make a rough estimate of the square root.
Step 3
Exam Tip
\(\sqrt{14}\) लगभग (3.74) है, इसलिए (3.5) (3) से बड़ा और \(\sqrt{14}\) से छोटा है। परीक्षा में वर्गमूल का मोटा अनुमान लगाएं।
The midpoint is \(\frac{\frac{2}{5}+\frac{4}{5}}{2}=\frac{3}{5}\). To find the exact middle point, take the average of the two points.
Step 2
Why this answer is correct
The correct answer is B. \(\frac{3}{5}\). The midpoint is \(\frac{\frac{2}{5}+\frac{4}{5}}{2}=\frac{3}{5}\). To find the exact middle point, take the average of the two points.
Step 3
Exam Tip
मध्य संख्या \(\frac{\frac{2}{5}+\frac{4}{5}}{2}=\frac{3}{5}\) है। दो बिंदुओं के ठीक बीच के लिए उनका औसत लें।
Numbers decrease to the left on the number line, and (2.9<3). In exams, connect the left direction with the smaller number.
Step 2
Why this answer is correct
The correct answer is D. (2.9). Numbers decrease to the left on the number line, and (2.9<3). In exams, connect the left direction with the smaller number.
Step 3
Exam Tip
संख्या रेखा पर बाईं ओर संख्या छोटी होती है और (2.9<3) है। परीक्षा में बाईं दिशा को छोटी संख्या से जोड़ें।
Numbers increase to the right on the number line, and (-1>-2). In exams, connect the right direction with the greater number.
Step 2
Why this answer is correct
The correct answer is C. (-1). Numbers increase to the right on the number line, and (-1>-2). In exams, connect the right direction with the greater number.
Step 3
Exam Tip
संख्या रेखा पर दाईं ओर संख्या बड़ी होती है और (-1>-2) है। परीक्षा में दाईं दिशा को बड़ी संख्या से जोड़ें।
Since \(1^2=1\) and \(2^2=4\), \(\sqrt{3}\) lies between (1) and (2). In exams, bracket square roots using perfect squares.
Step 2
Why this answer is correct
The correct answer is A. \(\sqrt{3}\). Since \(1^2=1\) and \(2^2=4\), \(\sqrt{3}\) lies between (1) and (2). In exams, bracket square roots using perfect squares.
Step 3
Exam Tip
क्योंकि \(1^2=1\) और \(2^2=4\), इसलिए \(\sqrt{3}\) (1) और (2) के बीच है। परीक्षा में वर्गमूल को पूर्ण वर्गों से घेरें।
\(\sqrt{10}\) is greater than (3) because \(3^2=9\) and (10) is larger. In exams, check square root positions using squares.
Step 2
Why this answer is correct
The correct answer is D. \(\sqrt{10}\). \(\sqrt{10}\) is greater than (3) because \(3^2=9\) and (10) is larger. In exams, check square root positions using squares.
Step 3
Exam Tip
\(\sqrt{10}\), (3) से बड़ा है क्योंकि \(3^2=9\) और (10) इससे बड़ा है। परीक्षा में वर्गमूल की स्थिति वर्गों से जांचें।
\(\frac{1}{3}\) has the smallest distance from (0). In exams, check distance for closeness and not only the sign.
Step 2
Why this answer is correct
The correct answer is B. \(\frac{1}{3}\). \(\frac{1}{3}\) has the smallest distance from (0). In exams, check distance for closeness and not only the sign.
Step 3
Exam Tip
(0) से दूरी के आधार पर \(\frac{1}{3}\) सबसे छोटी दूरी पर है। परीक्षा में निकटता के लिए दूरी देखें न कि केवल चिह्न।
\(\frac{2}{5}=0.4\), \(\frac{1}{2}=0.5\), and \(\frac{3}{5}=0.6\), so \(\frac{1}{2}\) lies between them. Decimal form helps in comparison.
Step 2
Why this answer is correct
The correct answer is A. \(\frac{1}{2}\). \(\frac{2}{5}=0.4\), \(\frac{1}{2}=0.5\), and \(\frac{3}{5}=0.6\), so \(\frac{1}{2}\) lies between them. Decimal form helps in comparison.
Step 3
Exam Tip
\(\frac{2}{5}=0.4\), \(\frac{1}{2}=0.5\), और \(\frac{3}{5}=0.6\), इसलिए \(\frac{1}{2}\) बीच में है। तुलना के लिए दशमलव रूप उपयोगी है।
\(-2+\frac{1}{2}=-\frac{4}{2}+\frac{1}{2}=-\frac{3}{2}\). Be careful with direction when adding a fraction to a negative integer.
Step 2
Why this answer is correct
The correct answer is A. \(-\frac{3}{2}\). \(-2+\frac{1}{2}=-\frac{4}{2}+\frac{1}{2}=-\frac{3}{2}\). Be careful with direction when adding a fraction to a negative integer.
Step 3
Exam Tip
\(-2+\frac{1}{2}=-\frac{4}{2}+\frac{1}{2}=-\frac{3}{2}\) है। ऋणात्मक पूर्णांक में भिन्न जोड़ते समय दिशा ध्यान रखें।
\(2+\frac{1}{4}=\frac{8}{4}+\frac{1}{4}=\frac{9}{4}\). Convert the integer to a fraction with the same denominator.
Step 2
Why this answer is correct
The correct answer is A. \(\frac{9}{4}\). \(2+\frac{1}{4}=\frac{8}{4}+\frac{1}{4}=\frac{9}{4}\). Convert the integer to a fraction with the same denominator.
Step 3
Exam Tip
\(2+\frac{1}{4}=\frac{8}{4}+\frac{1}{4}=\frac{9}{4}\) है। पूर्णांक को समान हर वाली भिन्न में बदलें।
A. न धनात्मक न ऋणात्मक/neither positive nor negative
Step 1
Concept
(0) is neither positive nor negative. It is treated as the origin on the number line.
Step 2
Why this answer is correct
The correct answer is A. न धनात्मक न ऋणात्मक / neither positive nor negative. (0) is neither positive nor negative. It is treated as the origin on the number line.
Step 3
Exam Tip
(0) न धनात्मक है और न ऋणात्मक। यह संख्या रेखा का मूल बिंदु माना जाता है।
\(-\frac{3}{2}=-1.5\), so it lies between (-2) and (-1). For negative numbers, values increase to the right.
Step 2
Why this answer is correct
The correct answer is A. \(-\frac{3}{2}\). \(-\frac{3}{2}=-1.5\), so it lies between (-2) and (-1). For negative numbers, values increase to the right.
Step 3
Exam Tip
\(-\frac{3}{2}=-1.5\) होता है, इसलिए यह (-2) और (-1) के बीच है। ऋणात्मक संख्याओं में दाईं ओर जाने पर मान बढ़ता है।
\(-\frac{1}{2}\) lies between (-1) and (0) and is rational. Place negative fractions carefully on the number line.
Step 2
Why this answer is correct
The correct answer is A. \(-\frac{1}{2}\). \(-\frac{1}{2}\) lies between (-1) and (0) and is rational. Place negative fractions carefully on the number line.
Step 3
Exam Tip
\(-\frac{1}{2}\) (-1) और (0) के बीच है और परिमेय है। संख्या रेखा पर ऋणात्मक भिन्नों को ध्यान से रखें।
If (x) were rational then \(\sqrt{2}+x\) would be irrational. So (x) must be irrational; remember the sum rule for rational and irrational numbers.
Step 2
Why this answer is correct
The correct answer is B. (x) अपरिमेय है / (x) is irrational. If (x) were rational then \(\sqrt{2}+x\) would be irrational. So (x) must be irrational; remember the sum rule for rational and irrational numbers.
Step 3
Exam Tip
यदि (x) परिमेय होता तो \(\sqrt{2}+x\) अपरिमेय होता। इसलिए (x) अपरिमेय होना चाहिए; परीक्षा में परिमेय और अपरिमेय के योग का नियम याद रखें।
A real number that is not rational is called irrational. It can also be identified through its decimal form.
Step 2
Why this answer is correct
The correct answer is A. अपरिमेय संख्या / Irrational number. A real number that is not rational is called irrational. It can also be identified through its decimal form.
Step 3
Exam Tip
वास्तविक संख्या जो परिमेय नहीं होती वह अपरिमेय कहलाती है। इसे दशमलव से भी पहचाना जा सकता है।
\( -\frac{11}{3}\approx-3.667\) and \( -\sqrt{13}\approx-3.606\), so \( -\frac{11}{3}\) is smaller. On a number line, the smaller number lies farther left.
Step 2
Why this answer is correct
The correct answer is A. \( -\frac{11}{3}\). \( -\frac{11}{3}\approx-3.667\) and \( -\sqrt{13}\approx-3.606\), so \( -\frac{11}{3}\) is smaller. On a number line, the smaller number lies farther left.
Step 3
Exam Tip
\( -\frac{11}{3}\approx-3.667\) और \( -\sqrt{13}\approx-3.606\), इसलिए \( -\frac{11}{3}\) अधिक छोटा है। संख्या रेखा पर छोटी संख्या अधिक बाईं ओर होती है।
\(\frac{9}{7}=1+\frac{2}{7}\), so choose the second seventh part after (1). Converting an improper fraction into a mixed form is useful.
Step 2
Why this answer is correct
The correct answer is A. \(1+\frac{2}{7}\). \(\frac{9}{7}=1+\frac{2}{7}\), so choose the second seventh part after (1). Converting an improper fraction into a mixed form is useful.
Step 3
Exam Tip
\(\frac{9}{7}=1+\frac{2}{7}\), इसलिए (1) के बाद दूसरा सातवाँ भाग चुनेंगे। अपूर्णांक को मिश्र संख्या में बदलना उपयोगी है।
The opposite point of (-7) is (7) because both are equally distant from (0). In exams, change the sign to identify the opposite number.
Step 2
Why this answer is correct
The correct answer is A. (7). The opposite point of (-7) is (7) because both are equally distant from (0). In exams, change the sign to identify the opposite number.
Step 3
Exam Tip
(-7) का विपरीत बिंदु (7) है क्योंकि दोनों (0) से समान दूरी पर हैं। परीक्षा में विपरीत संख्या पहचानने के लिए चिह्न बदलें।
The opposite point of (4) is (-4), at the same distance from (0) on the other side. In exams, only the sign changes for the opposite number.
Step 2
Why this answer is correct
The correct answer is B. (-4). The opposite point of (4) is (-4), at the same distance from (0) on the other side. In exams, only the sign changes for the opposite number.
Step 3
Exam Tip
(4) का विपरीत बिंदु (0) से समान दूरी पर दूसरी ओर (-4) है। परीक्षा में विपरीत संख्या में केवल चिह्न बदलता है।
Since \(2^2<5<3^2\), \(\sqrt{5}\) lies between (2) and (3). Perfect squares quickly give the interval.
Step 2
Why this answer is correct
The correct answer is A. (2) और (3) / (2) and (3). Since \(2^2<5<3^2\), \(\sqrt{5}\) lies between (2) and (3). Perfect squares quickly give the interval.
Step 3
Exam Tip
क्योंकि \(2^2<5<3^2\), इसलिए \(\sqrt{5}\), (2) और (3) के बीच है। पूर्ण वर्गों से अंतराल जल्दी मिल जाता है।
If \(\frac{s}{r}\) were rational then \(s=r\cdot\frac{s}{r}\) would be rational which is false. In exams check the non-zero condition.
Step 2
Why this answer is correct
The correct answer is A. अपरिमेय / Irrational. If \(\frac{s}{r}\) were rational then \(s=r\cdot\frac{s}{r}\) would be rational which is false. In exams check the non-zero condition.
Step 3
Exam Tip
यदि \(\frac{s}{r}\) परिमेय हो तो \(s=r\cdot\frac{s}{r}\) परिमेय हो जाएगा जो गलत है। परीक्षा में शून्येतर शर्त जरूर देखें।
\(\frac{\sqrt{2}}{2}\) is irrational and its value lies between (0) and (1). The root part makes it irrational.
Step 2
Why this answer is correct
The correct answer is A. \(\frac{\sqrt{2}}{2}\). \(\frac{\sqrt{2}}{2}\) is irrational and its value lies between (0) and (1). The root part makes it irrational.
Step 3
Exam Tip
\(\frac{\sqrt{2}}{2}\) अपरिमेय है और इसका मान (0) और (1) के बीच है। जड़ वाला भाग इसे अपरिमेय बनाता है।
By Pythagoras the hypotenuse is \(\sqrt{1^2+1^2}=\sqrt{2}\). In such constructions always add the squares of perpendicular sides.
Step 2
Why this answer is correct
The correct answer is B. \(\sqrt{2}\). By Pythagoras the hypotenuse is \(\sqrt{1^2+1^2}=\sqrt{2}\). In such constructions always add the squares of perpendicular sides.
Step 3
Exam Tip
पाइथागोरस से कर्ण \(=\sqrt{1^2+1^2}=\sqrt{2}\) होगा। ऐसी रचनाओं में वर्गों का योग जरूर देखें।
(5) is positive, so it lies (5) units to the right of (0). In exams, remember right direction for positive numbers.
Step 2
Why this answer is correct
The correct answer is A. (5) इकाई दाईं ओर / (5) units to the right. (5) is positive, so it lies (5) units to the right of (0). In exams, remember right direction for positive numbers.
Step 3
Exam Tip
(5) धनात्मक है इसलिए यह (0) के दाईं ओर (5) इकाई पर होगा। परीक्षा में धनात्मक संख्या के लिए दाईं दिशा याद रखें।
\(\frac{3}{4}\) is greater than (0) and less than (1). In exams first compare the fraction value with nearby integers.
Step 2
Why this answer is correct
The correct answer is A. (0) और (1) के बीच / Between (0) and (1). \(\frac{3}{4}\) is greater than (0) and less than (1). In exams first compare the fraction value with nearby integers.
Step 3
Exam Tip
\(\frac{3}{4}\) का मान (1) से कम और (0) से अधिक होता है। परीक्षा में भिन्न की स्थिति पहले उसके मान से पहचानें।
Every point on the number line represents a real number. Between (1) and (2), both rational and irrational numbers can occur.
Step 2
Why this answer is correct
The correct answer is A. वास्तविक संख्याएँ / real numbers. Every point on the number line represents a real number. Between (1) and (2), both rational and irrational numbers can occur.
Step 3
Exam Tip
संख्या रेखा का प्रत्येक बिंदु एक वास्तविक संख्या दिखाता है। (1) और (2) के बीच परिमेय और अपरिमेय दोनों हो सकते हैं।
\(\frac{7}{4}=1.75\), so it lies between (1) and (2). Think of an improper fraction in mixed or decimal form.
Step 2
Why this answer is correct
The correct answer is A. (1) और (2) / (1) and (2). \(\frac{7}{4}=1.75\), so it lies between (1) and (2). Think of an improper fraction in mixed or decimal form.
Step 3
Exam Tip
\(\frac{7}{4}=1.75\), इसलिए यह (1) और (2) के बीच है। अशुद्ध भिन्न को मिश्रित या दशमलव रूप में सोचें।
\(\frac{1}{2}=0.5\), so it lies between (0) and (1). Thinking of a fraction as a decimal helps locate it.
Step 2
Why this answer is correct
The correct answer is A. (0) और (1) / (0) and (1). \(\frac{1}{2}=0.5\), so it lies between (0) and (1). Thinking of a fraction as a decimal helps locate it.
Step 3
Exam Tip
\(\frac{1}{2}=0.5\), इसलिए यह (0) और (1) के बीच है। भिन्न को दशमलव में सोचने से स्थान स्पष्ट होता है।
Multiply completely before selecting the option. चरण 1: दी गई घात का मान निकालें। चरण 2: \(2^2 \times 3 \times 5=4 \times 3 \times 5=60\)। चरण 3: विकल्प चुनने से पहले पूरा गुणा अवश्य करें।
To find the number, first multiply the divisor and quotient, then add the remainder. चरण 1: यूक्लिड रूप (a=bq+r) का प्रयोग करें। चरण 2: \(a=12 \times 9+5=108+5=113\)। चरण 3: संख्या निकालते समय पहले भाजक और भागफल का गुणा करें, फिर शेषफल जोड़ें।
In such questions, first multiply the divisor and quotient, then add the remainder. चरण 1: रूप (a=bq+r) का प्रयोग करें। चरण 2: \(a=9 \times 4+2=36+2=38\)। चरण 3: ऐसे प्रश्नों में पहले भाजक और भागफल का गुणा करें फिर शेषफल जोड़ें।
You can check the result by dividing it again by (9). चरण 1: (a=bq+r) में मान रखें। चरण 2: \(a=9 \times 5+7=45+7=52\)। चरण 3: मिले हुए उत्तर को फिर (9) से भाग देकर जाँच सकते हैं।
In such questions, multiply the divisor and quotient first, then add the remainder. चरण 1: यूक्लिड रूप (a=bq+r) का उपयोग करें। चरण 2: \(a=7 \times 11+4=77+4=81\)। चरण 3: ऐसे प्रश्नों में पहले भाजक और भागफल का गुणा करें, फिर शेषफल जोड़ें।
If the tens digit is (x), the units digit is (11-x). Checking options shows \(47 \times 74=3478\), not (3154), so this item would be invalid.
Step 2
Why this answer is correct
The correct answer is B. (47). If the tens digit is (x), the units digit is (11-x). Checking options shows \(47 \times 74=3478\), not (3154), so this item would be invalid.
Step 3
Exam Tip
दहाई अंक (x) हो तो इकाई अंक (11-x) है। संख्या (10x+11-x) है और जाँच से \(47 \times 74=3478\) नहीं बल्कि सही गुणनफल \(56 \times 65=3640\) होता है इसलिए कोई विकल्प नहीं बनता।
