Concept-wise Practice

position MCQ Questions for Class 10

position se related questions ko ek jagah revise karein. Har question me bilingual content, answer feedback aur explanation available hai.

Practice Questions

5 questions tagged with position.

Question 1/5 Medium Mathematics Polynomials Representing real numbers on the number line Class 10 Level 51

संख्या रेखा पर \(\frac{13}{4}\) को (3) और (4) के बीच कहां रखा जाएगा?

Where will \(\frac{13}{4}\) be placed between (3) and (4) on the number line?

Explanation opens after your attempt
Correct Answer

A. (3) के बाद पहला चौथाई बिंदुFirst quarter point after (3)

Step 1

Concept

\(\frac{13}{4}=3+\frac{1}{4}\), so it is the first quarter point after (3). Think of improper fractions as mixed numbers.

Step 2

Why this answer is correct

The correct answer is A. (3) के बाद पहला चौथाई बिंदु / First quarter point after (3). \(\frac{13}{4}=3+\frac{1}{4}\), so it is the first quarter point after (3). Think of improper fractions as mixed numbers.

Step 3

Exam Tip

\(\frac{13}{4}=3+\frac{1}{4}\), इसलिए यह (3) के बाद पहले चौथाई बिंदु पर होगा। अशुद्ध भिन्न को मिश्रित रूप में सोचें।

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Question 2/5 Medium Mathematics Polynomials Representing real numbers on the number line Class 10 Level 51

पिछले प्रश्न जैसी रेखा में (2) से चौथा बराबर बिंदु कौन सा होगा जब प्रत्येक भाग \(\frac{1}{2}\) हो?

In a similar segment, what is the fourth equal point from (2) when each part is \(\frac{1}{2}\)?

Explanation opens after your attempt
Correct Answer

C. (4)

Step 1

Concept

The fourth point is \(2+4\times\frac{1}{2}=4\). Add the total step length to the starting point.

Step 2

Why this answer is correct

The correct answer is C. (4). The fourth point is \(2+4\times\frac{1}{2}=4\). Add the total step length to the starting point.

Step 3

Exam Tip

चौथा बिंदु \(2+4\times\frac{1}{2}=4\) है। बराबर भागों में आरंभिक बिंदु में कुल कदम जोड़ें।

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Question 3/5 Medium Mathematics Polynomials Representing real numbers on the number line Class 10 Level 51

संख्या रेखा पर \(\sqrt{0.49}\) का सही स्थान कौन सा है?

What is the correct position of \(\sqrt{0.49}\) on the number line?

Explanation opens after your attempt
Correct Answer

B. (0.7)

Step 1

Concept

Since \(0.7^2=0.49\), \(\sqrt{0.49}=0.7\). Be careful with place value in decimal squares.

Step 2

Why this answer is correct

The correct answer is B. (0.7). Since \(0.7^2=0.49\), \(\sqrt{0.49}=0.7\). Be careful with place value in decimal squares.

Step 3

Exam Tip

\(0.7^2=0.49\), इसलिए \(\sqrt{0.49}=0.7\) है। दशमलव वर्गों में स्थान मान सावधानी से देखें।

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Question 4/5 Medium Mathematics Polynomials Representing real numbers on the number line Class 10 Level 49

संख्या रेखा पर \(\frac{11}{5}\) को रखने के लिए वह किस दो पूर्णांकों के बीच आएगा?

To place \(\frac{11}{5}\) on the number line, between which two integers will it lie?

Explanation opens after your attempt
Correct Answer

B. (2) और (3)(2) and (3)

Step 1

Concept

\(\frac{11}{5}=2.2\), so it lies between (2) and (3). Convert an improper fraction to decimal or mixed form.

Step 2

Why this answer is correct

The correct answer is B. (2) और (3) / (2) and (3). \(\frac{11}{5}=2.2\), so it lies between (2) and (3). Convert an improper fraction to decimal or mixed form.

Step 3

Exam Tip

\(\frac{11}{5}=2.2\), इसलिए यह (2) और (3) के बीच है। अशुद्ध भिन्न को दशमलव या मिश्रित रूप में बदलें।

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Question 5/5 Medium Mathematics Polynomials Representing real numbers on the number line Class 10 Level 49

संख्या रेखा पर (1.375) को (1) और (2) के बीच रखने के लिए (1) से कितना आगे जाना होगा?

To place (1.375) between (1) and (2) on the number line, how far should we move from (1)?

Explanation opens after your attempt
Correct Answer

C. (0.375)

Step 1

Concept

Since (1.375=1+0.375), move (0.375) unit from (1). Separate the integer part when locating decimals.

Step 2

Why this answer is correct

The correct answer is C. (0.375). Since (1.375=1+0.375), move (0.375) unit from (1). Separate the integer part when locating decimals.

Step 3

Exam Tip

क्योंकि (1.375=1+0.375), इसलिए (1) से (0.375) इकाई आगे जाना होगा। दशमलव स्थान में पूर्णांक भाग अलग करें।

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