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5 results found for "number-1176" in Class 10.

Question Hard Mathematics Chapter 1: Real Numbers 3: Prime factorisation Class 10 Level 8

किस संख्या का अभाज्य गुणनखंडन \(2^4\times3\times5\times7^2\) है?

Which number has prime factorisation \(2^4\times3\times5\times7^2\)?

Explanation opens after your attempt
Correct Answer

A. 11760

Step 1

Concept

Calculate \(2^4=16\) and \(7^2=49\).

Step 2

Why this answer is correct

\(16\times3\times5\times49=11760\).

Step 3

Exam Tip

Calculating powers first makes the work easier. चरण 1: \(2^4=16\) और \(7^2=49\) निकालें। चरण 2: \(16\times3\times5\times49=11760\)। चरण 3: घातों का मान पहले निकालने से गणना आसान होती है।

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Question Hard Mathematics Chapter 1: Real Numbers 3: Prime factorisation Class 10 Level 8

संख्या 11760 का अभाज्य गुणनखंडन कौन सा है?

Which is the prime factorisation of 11760?

Explanation opens after your attempt
Correct Answer

A. \(2^4\times3\times5\times7^2\)

Step 1

Concept

Write \(11760=16\times735\).

Step 2

Why this answer is correct

\(16=2^4\) and \(735=3\times5\times7^2\), so \(11760=2^4\times3\times5\times7^2\).

Step 3

Exam Tip

Give 735 its complete prime form. चरण 1: \(11760=16\times735\) लिखें। चरण 2: \(16=2^4\) और \(735=3\times5\times7^2\), इसलिए \(11760=2^4\times3\times5\times7^2\)। चरण 3: 735 को पूरा अभाज्य रूप दें।

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Question Medium Mathematics Chapter 1: Real Numbers 3: Prime factorisation Class 10 Level 7

संख्या 1176 का अभाज्य गुणनखंडन कौन सा है?

Which is the prime factorisation of 1176?

Explanation opens after your attempt
Correct Answer

A. \(2^3\times3\times7^2\)

Step 1

Concept

Write \(1176=24\times49\).

Step 2

Why this answer is correct

\(24=2^3\times3\) and \(49=7^2\), so \(1176=2^3\times3\times7^2\).

Step 3

Exam Tip

Convert 24 and 49 into prime powers. चरण 1: \(1176=24\times49\) लिखें। चरण 2: \(24=2^3\times3\) और \(49=7^2\), इसलिए \(1176=2^3\times3\times7^2\)। चरण 3: 24 और 49 को अभाज्य घातों में बदलें।

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Question Easy Mathematics Chapter 1: Real Numbers 3: Prime factorisation Class 10 Level 9

यदि किसी संख्या का अभाज्य गुणनखंडन \(2^3\times3\times7^2\) है, तो वह संख्या कौन सी है?

If the prime factorisation of a number is \(2^3\times3\times7^2\), which number is it?

Explanation opens after your attempt
Correct Answer

A. 1176

Step 1

Concept

Calculate \(2^3=8\) and \(7^2=49\).

Step 2

Why this answer is correct

\(8\times3\times49=1176\).

Step 3

Exam Tip

Evaluating powers first makes calculation easier. चरण 1: \(2^3=8\) और \(7^2=49\) निकालें। चरण 2: \(8\times3\times49=1176\)। चरण 3: घातों का मान पहले निकालना गणना को आसान बनाता है।

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Question Easy Mathematics Chapter 1: Real Numbers 3: Prime factorisation Class 10 Level 9

संख्या 1176 का सही अभाज्य गुणनखंडन क्या है?

What is the correct prime factorisation of 1176?

Explanation opens after your attempt
Correct Answer

A. \(2^3\times3\times7^2\)

Step 1

Concept

Write \(1176=24\times49\).

Step 2

Why this answer is correct

\(24=2^3\times3\) and \(49=7^2\), so \(1176=2^3\times3\times7^2\).

Step 3

Exam Tip

Write both 24 and 49 in prime form. चरण 1: \(1176=24\times49\) लिखें। चरण 2: \(24=2^3\times3\) और \(49=7^2\), इसलिए \(1176=2^3\times3\times7^2\)। चरण 3: 24 और 49 दोनों को अभाज्य रूप में लिखें।

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