100 results found for "not zero point graph" in Class 10.
यदि ग्राफ के शून्यक (-12), (5), (14) हैं, तो कौन सा बिंदु ग्राफ पर शून्यक नहीं दिखाता?
If the zeroes of a graph are (-12), (5), (14), which point does not show a zero on the graph?
#zero point
#misconception
#coordinates
A ((-12,0))
B ((5,0))
C ((0,14))
D ((14,0))
Explanation opens after your attempt
Correct Answer
C. ((0,14))
Step 1
Concept
((0,14)) has (y=14), so it is not on the (x)-axis. Tip: a zero point must have second coordinate (0).
Step 2
Why this answer is correct
The correct answer is C. ((0,14)). ((0,14)) has (y=14), so it is not on the (x)-axis. Tip: a zero point must have second coordinate (0).
Step 3
Exam Tip
((0,14)) में (y=14) है, इसलिए यह (x)-अक्ष पर नहीं है। टिप: शून्यक बिंदु में दूसरा निर्देशांक (0) होना चाहिए।
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यदि ग्राफ के शून्यक (-8), (3), (12) हैं, तो कौन सा बिंदु ग्राफ पर शून्यक नहीं दिखाता?
If the zeroes of a graph are (-8), (3), (12), which point does not show a zero on the graph?
#zero point
#misconception
#coordinates
A ((-8,0))
B ((3,0))
C ((0,12))
D ((12,0))
Explanation opens after your attempt
Correct Answer
C. ((0,12))
Step 1
Concept
((0,12)) has (y=12), so it is not on the (x)-axis. Tip: a zero point must have second coordinate (0).
Step 2
Why this answer is correct
The correct answer is C. ((0,12)). ((0,12)) has (y=12), so it is not on the (x)-axis. Tip: a zero point must have second coordinate (0).
Step 3
Exam Tip
((0,12)) में (y=12) है, इसलिए यह (x)-अक्ष पर नहीं है। टिप: शून्यक बिंदु में दूसरा निर्देशांक (0) होना चाहिए।
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यदि (p(x)=x-2 -1) है तो कौन सा बिंदु आलेख पर शून्यक नहीं दिखाता?
If (p(x)=x-2 -1), which point does not show a zero on the graph?
#not zero point graph
A ((-1,0))
B ((1,0))
C ((0,-1))
D दोनों ((-1,0)) और ((1,0)) / Both ((-1,0)) and ((1,0))
Explanation opens after your attempt
Correct Answer
C. ((0,-1))
Step 1
Concept
((0,-1)) has \(y\neq0\), so it does not show a zero. Tip: it is a (y)-axis intercept.
Step 2
Why this answer is correct
The correct answer is C. ((0,-1)). ((0,-1)) has \(y\neq0\), so it does not show a zero. Tip: it is a (y)-axis intercept.
Step 3
Exam Tip
((0,-1)) में \(y\neq0\) है इसलिए यह शून्यक नहीं दिखाता। टिप: यह (y)-अक्ष कटान है।
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यदि किसी ग्राफ में ((4,2)) बिंदु है, तो क्या (4) शून्यक है?
If a graph has the point ((4,2)), is (4) a zero?
#point-test
#not-zero
#graph
#easy
A नहीं / No
B हाँ / Yes
C केवल यदि बहुपद द्विघात हो / Only if the polynomial is quadratic
D केवल यदि ग्राफ रेखा हो / Only if the graph is a line
Explanation opens after your attempt
Correct Answer
A. नहीं / No
Step 1
Concept
In ((4,2)), (y=2), not (0). Therefore (x=4) is not a zero.
Step 2
Why this answer is correct
The correct answer is A. नहीं / No. In ((4,2)), (y=2), not (0). Therefore (x=4) is not a zero.
Step 3
Exam Tip
((4,2)) में (y=2) है, (0) नहीं। इसलिए (x=4) शून्यक नहीं है।
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यदि (x=7) किसी बहुपद का शून्यक है, तो ग्राफ पर कौन सा बिंदु अवश्य होगा?
If (x=7) is a zero of a polynomial, which point must lie on the graph?
#zero to point
#graph
#concept
A ((0,7))
B ((7,7))
C ((7,0))
D ((-7,0))
Explanation opens after your attempt
Correct Answer
C. ((7,0))
Step 1
Concept
A zero (7) means (p(7)=0). Tip: place the zero as the first coordinate.
Step 2
Why this answer is correct
The correct answer is C. ((7,0)). A zero (7) means (p(7)=0). Tip: place the zero as the first coordinate.
Step 3
Exam Tip
शून्यक (7) होने का अर्थ (p(7)=0) है। टिप: शून्यक को पहले निर्देशांक में रखें।
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किस बिंदु पर ग्राफ होने से (x=11) शून्यक सिद्ध होगा?
Which point on the graph proves that (x=11) is a zero?
#point-identification
#zeroes
#x-axis
#graph
A ((11,0))
B ((0,11))
C ((11,1))
D ((-11,0))
Explanation opens after your attempt
Correct Answer
A. ((11,0))
Step 1
Concept
For (x=11) to be a zero, (y=0) is needed. So the point must be ((11,0)).
Step 2
Why this answer is correct
The correct answer is A. ((11,0)). For (x=11) to be a zero, (y=0) is needed. So the point must be ((11,0)).
Step 3
Exam Tip
(x=11) शून्यक होने के लिए (y=0) चाहिए। इसलिए बिंदु ((11,0)) होना चाहिए।
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किस बिंदु पर ग्राफ होने से (x=-2) शून्यक सिद्ध होगा?
Which point on the graph proves that (x=-2) is a zero?
#negative-zero
#point-reading
#x-intercept
#easy
A ((-2,0))
B ((2,0))
C ((0,-2))
D ((-2,2))
Explanation opens after your attempt
Correct Answer
A. ((-2,0))
Step 1
Concept
For (x=-2) to be a zero, (y=0) at that point. Hence the correct point is ((-2,0)).
Step 2
Why this answer is correct
The correct answer is A. ((-2,0)). For (x=-2) to be a zero, (y=0) at that point. Hence the correct point is ((-2,0)).
Step 3
Exam Tip
(x=-2) शून्यक होने के लिए उस बिंदु पर (y=0) होना चाहिए। इसलिए सही बिंदु ((-2,0)) है।
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यदि (p(2)=3) है तो बिंदु ((2,3)) आलेख पर है। क्या (2) शून्यक है?
If (p(2)=3) then the point ((2,3)) is on the graph. Is (2) a zero?
#not a zero value
A नहीं / No
B हाँ / Yes
C केवल द्विघात में हाँ / Yes only in quadratic
D निर्धारित नहीं किया जा सकता / Cannot be decided
Explanation opens after your attempt
Correct Answer
A. नहीं / No
Step 1
Concept
For a zero (p(2)) should be (0). Tip: if (p(a)\neq0) then (a) is not a zero.
Step 2
Why this answer is correct
The correct answer is A. नहीं / No. For a zero (p(2)) should be (0). Tip: if (p(a)\neq0) then (a) is not a zero.
Step 3
Exam Tip
शून्यक के लिए (p(2)) को (0) होना चाहिए था। टिप: (p(a)\neq0) हो तो (a) शून्यक नहीं है।
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किसी बहुपद के ग्राफ पर शून्यक पहचानने के लिए कौन-सा मान शून्य होना चाहिए?
Which value must be zero to identify a zero on the graph of a polynomial?
#polynomials
#zeroes
#graph
#value-test
A बहुपद का मान / Value of the polynomial
B चर का गुणांक / Coefficient of the variable
C घात का मान / Value of the degree
D स्थिर पद / Constant term
Explanation opens after your attempt
Correct Answer
A. बहुपद का मान / Value of the polynomial
Step 1
Concept
At a zero, the polynomial value is (0). While reading a graph, look for points where (y=0).
Step 2
Why this answer is correct
The correct answer is A. बहुपद का मान / Value of the polynomial. At a zero, the polynomial value is (0). While reading a graph, look for points where (y=0).
Step 3
Exam Tip
शून्यक पर बहुपद का मान (0) होता है। ग्राफ पढ़ते समय (y=0) वाले बिंदु देखें।
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यदि ग्राफ (x)-अक्ष को (2.5) पर काटता है तो सही शून्यक कौन सा है?
If a graph cuts the (x)-axis at (2.5), which is the correct zero?
#zero-vs-point
#decimal
#graph
A (2.5)
B ((2.5,0))
C (0)
D ((0,2.5))
Explanation opens after your attempt
Step 1
Concept
A zero is a number not a point. The point is ((2.5,0)) but the zero is (2.5).
Step 2
Why this answer is correct
The correct answer is A. (2.5). A zero is a number not a point. The point is ((2.5,0)) but the zero is (2.5).
Step 3
Exam Tip
शून्यक संख्या होता है बिंदु नहीं। बिंदु ((2.5,0)) है लेकिन शून्यक (2.5) है।
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एक बहुपद का ग्राफ (x)-अक्ष को केवल ((-2,0)) पर छूता है। अलग वास्तविक शून्यक कौन-सा है?
A polynomial graph only touches the (x)-axis at ((-2,0)). What is the distinct real zero?
#touching-point
#distinct-zero
#graph
#easy
A (-2)
B (2)
C (0)
D कोई नहीं / None
Explanation opens after your attempt
Step 1
Concept
A touching point also gives (p(x)=0). Therefore the distinct real zero is (-2).
Step 2
Why this answer is correct
The correct answer is A. (-2). A touching point also gives (p(x)=0). Therefore the distinct real zero is (-2).
Step 3
Exam Tip
छूने वाला बिंदु भी (p(x)=0) देता है। इसलिए अलग वास्तविक शून्यक (-2) है।
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यदि किसी बहुपद के ग्राफ का (x)-अक्ष से केवल एक साझा बिंदु ((6,0)) है, तो अलग वास्तविक शून्यक क्या होगा?
If a polynomial graph has only one common point with the (x)-axis at ((6,0)), what is the distinct real zero?
#distinct-zero
#x-axis
#graph
#easy
A (6)
B (-6)
C (0)
D कोई नहीं / None
Explanation opens after your attempt
Step 1
Concept
The common point ((6,0)) has (x)-coordinate (6). So the distinct real zero is (6).
Step 2
Why this answer is correct
The correct answer is A. (6). The common point ((6,0)) has (x)-coordinate (6). So the distinct real zero is (6).
Step 3
Exam Tip
एक साझा बिंदु ((6,0)) का (x)-निर्देशांक (6) है। इसलिए अलग वास्तविक शून्यक (6) होगा।
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यदि (p(0)=0), तो ग्राफ किस विशेष बिंदु से गुजरेगा?
If (p(0)=0), through which special point will the graph pass?
#origin
#zero
#p-of-zero
#graph
A मूल बिंदु / Origin
B केवल ((1,0)) / Only ((1,0))
C केवल ((0,1)) / Only ((0,1))
D ((-1,0))
Explanation opens after your attempt
Correct Answer
A. मूल बिंदु / Origin
Step 1
Concept
(p(0)=0) means (y=0) at (x=0). So the graph passes through the origin ((0,0)).
Step 2
Why this answer is correct
The correct answer is A. मूल बिंदु / Origin. (p(0)=0) means (y=0) at (x=0). So the graph passes through the origin ((0,0)).
Step 3
Exam Tip
(p(0)=0) का अर्थ है (x=0) पर (y=0)। इसलिए ग्राफ मूल बिंदु ((0,0)) से गुजरेगा।
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ग्राफ पर ((0,4)) बिंदु मिलने से क्या (0) शून्यक होगा?
Does the point ((0,4)) on a graph mean that (0) is a zero?
#common-mistake
#y-intercept
#zeroes
#graph
A नहीं, क्योंकि \(y\neq 0\) है / No, because \(y\neq 0\)
B हाँ, क्योंकि (x=0) है / Yes, because (x=0)
C हाँ, क्योंकि बिंदु (y)-अक्ष पर है / Yes, because the point is on the (y)-axis
D निर्धारित नहीं हो सकता / Cannot be determined
Explanation opens after your attempt
Correct Answer
A. नहीं, क्योंकि \(y\neq 0\) है / No, because \(y\neq 0\)
Step 1
Concept
For a zero, (y=0) is required. In ((0,4)), (y=4), so (0) is not a zero.
Step 2
Why this answer is correct
The correct answer is A. नहीं, क्योंकि \(y\neq 0\) है / No, because \(y\neq 0\). For a zero, (y=0) is required. In ((0,4)), (y=4), so (0) is not a zero.
Step 3
Exam Tip
शून्यक के लिए (y=0) होना चाहिए। ((0,4)) में (y=4) है, इसलिए (0) शून्यक नहीं है।
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किसी बहुपद के आलेख पर बिंदु ((4,0)) है। इससे कौन सा कथन सही है?
The point ((4,0)) lies on the graph of a polynomial. Which statement is correct?
#point zero graph
A (4) बहुपद का शून्यक है / (4) is a zero of the polynomial
B (0) बहुपद का शून्यक है / (0) is a zero of the polynomial
C (4) (y)-अक्ष कटान है / (4) is the (y)-intercept
D बहुपद स्थिर है / The polynomial is constant
Explanation opens after your attempt
Correct Answer
A. (4) बहुपद का शून्यक है / (4) is a zero of the polynomial
Step 1
Concept
The point ((4,0)) means (p(x)=0) at (x=4). Tip: from ((a,0)) the zero is (a).
Step 2
Why this answer is correct
The correct answer is A. (4) बहुपद का शून्यक है / (4) is a zero of the polynomial. The point ((4,0)) means (p(x)=0) at (x=4). Tip: from ((a,0)) the zero is (a).
Step 3
Exam Tip
((4,0)) का अर्थ है (x=4) पर (p(x)=0)। टिप: ((a,0)) से शून्यक (a) मिलता है।
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यदि किसी ग्राफ का (x)-अक्ष से कोई साझा बिंदु नहीं है, तो शून्यकों के बारे में क्या निष्कर्ष है?
If a graph has no common point with the (x)-axis, what is the conclusion about its zeroes?
#no-common-point
#no-real-zero
#graph
#polynomials
A कोई वास्तविक शून्यक नहीं / No real zero
B एक वास्तविक शून्यक / One real zero
C दो वास्तविक शून्यक / Two real zeroes
D अनंत वास्तविक शून्यक / Infinite real zeroes
Explanation opens after your attempt
Correct Answer
A. कोई वास्तविक शून्यक नहीं / No real zero
Step 1
Concept
Real zeroes are obtained from common points of the graph and the (x)-axis. If there is no common point, there is no real zero.
Step 2
Why this answer is correct
The correct answer is A. कोई वास्तविक शून्यक नहीं / No real zero. Real zeroes are obtained from common points of the graph and the (x)-axis. If there is no common point, there is no real zero.
Step 3
Exam Tip
वास्तविक शून्यक ग्राफ और (x)-अक्ष के साझा बिंदुओं से मिलते हैं। साझा बिंदु न हो तो वास्तविक शून्यक नहीं होगा।
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यदि (p(-6)=0), तो कौन-सा बिंदु ग्राफ पर होगा?
If (p(-6)=0), which point will lie on the graph?
#graph-point
#function-value
#negative-zero
#easy
A ((-6,0))
B ((6,0))
C ((0,-6))
D ((0,6))
Explanation opens after your attempt
Correct Answer
A. ((-6,0))
Step 1
Concept
(p(-6)=0) means (y=0) at (x=-6). So the point ((-6,0)) lies on the graph.
Step 2
Why this answer is correct
The correct answer is A. ((-6,0)). (p(-6)=0) means (y=0) at (x=-6). So the point ((-6,0)) lies on the graph.
Step 3
Exam Tip
(p(-6)=0) बताता है कि (x=-6) पर (y=0) है। इसलिए बिंदु ((-6,0)) ग्राफ पर होगा।
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ग्राफ में बिंदु ((-8,0)) दिखने पर बहुपद का कौन-सा मान शून्य होगा?
If the point ((-8,0)) appears on the graph, which value of the polynomial input gives zero?
#negative-zero
#coordinate-reading
#x-intercept
#polynomials
A (x=-8)
B (x=8)
C (x=0)
D (x=-1)
Explanation opens after your attempt
Step 1
Concept
The point ((-8,0)) means (y=0) at (x=-8). So (x=-8) makes the polynomial zero.
Step 2
Why this answer is correct
The correct answer is A. (x=-8). The point ((-8,0)) means (y=0) at (x=-8). So (x=-8) makes the polynomial zero.
Step 3
Exam Tip
((-8,0)) का अर्थ है (x=-8) पर (y=0)। इसलिए (x=-8) बहुपद को शून्य बनाता है।
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कौन सा बहुपद (x=0) को शून्य बनाता है लेकिन शून्य बहुपद नहीं है?
Which polynomial makes (x=0) a zero but is not the zero polynomial?
#zero at zero
#constant term
#polynomial
A \(x^2+9\)
B \(4x^3-7x\)
C (5)
D \(x^4+1\)
Explanation opens after your attempt
Correct Answer
B. \(4x^3-7x\)
Step 1
Concept
Substituting (x=0) in \(4x^3-7x\) gives (0), and it is not the zero polynomial. For (x=0), the constant term must be (0).
Step 2
Why this answer is correct
The correct answer is B. \(4x^3-7x\). Substituting (x=0) in \(4x^3-7x\) gives (0), and it is not the zero polynomial. For (x=0), the constant term must be (0).
Step 3
Exam Tip
\(4x^3-7x\) में (x=0) रखने पर (0) मिलता है और यह शून्य बहुपद नहीं है। (x=0) के लिए अचर पद (0) होना चाहिए।
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यदि किसी ग्राफ में (x)-अक्ष से प्रतिच्छेद (\(-\sqrt{3},0\)) है तो शून्यक क्या है?
If a graph has (x)-axis intersection (\(-\sqrt{3},0\)), what is the zero?
#irrational-zero
#x-intercept
#graph
A \(-\sqrt{3}\)
B \(\sqrt{3}\)
C (0)
D (\(-\sqrt{3},0\))
Explanation opens after your attempt
Correct Answer
A. \(-\sqrt{3}\)
Step 1
Concept
A zero is the (x)-coordinate of the intercept. An irrational number can also be a zero.
Step 2
Why this answer is correct
The correct answer is A. \(-\sqrt{3}\). A zero is the (x)-coordinate of the intercept. An irrational number can also be a zero.
Step 3
Exam Tip
शून्यक प्रतिच्छेद का (x)-निर्देशांक होता है। अपरिमेय संख्या भी शून्यक हो सकती है।
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शून्य बहुपद (p(x)=0) के ग्राफ के बारे में कौन सा कथन सही है?
Which statement is correct about the graph of the zero polynomial (p(x)=0)?
#zero-polynomial
#graph
#conceptual
A पूरा ग्राफ (x)-अक्ष है / The whole graph is the (x)-axis
B ग्राफ (y)-अक्ष है / The graph is the (y)-axis
C कोई बिंदु नहीं है / There is no point
D केवल ((0,0)) है / It is only ((0,0))
Explanation opens after your attempt
Correct Answer
A. पूरा ग्राफ (x)-अक्ष है / The whole graph is the (x)-axis
Step 1
Concept
(p(x)=0) gives (y=0) for every (x). Therefore the whole (x)-axis is the graph.
Step 2
Why this answer is correct
The correct answer is A. पूरा ग्राफ (x)-अक्ष है / The whole graph is the (x)-axis. (p(x)=0) gives (y=0) for every (x). Therefore the whole (x)-axis is the graph.
Step 3
Exam Tip
(p(x)=0) हर (x) के लिए (y=0) देता है। इसलिए पूरा (x)-अक्ष ग्राफ है।
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यदि ग्राफ (x)-अक्ष को ((r,0)) पर काटता है और (r>0) है तो शून्यक के बारे में कौन सा कथन सही है?
If a graph cuts the (x)-axis at ((r,0)) and (r>0), which statement about the zero is correct?
#positive zero graph
A शून्यक ऋणात्मक है / The zero is negative
B शून्यक धनात्मक है / The zero is positive
C शून्यक (0) है / The zero is (0)
D शून्यक नहीं है / There is no zero
Explanation opens after your attempt
Correct Answer
B. शून्यक धनात्मक है / The zero is positive
Step 1
Concept
The first coordinate of the intersection is (r), and (r>0). Tip: read the zero (r) from ((r,0)).
Step 2
Why this answer is correct
The correct answer is B. शून्यक धनात्मक है / The zero is positive. The first coordinate of the intersection is (r), and (r>0). Tip: read the zero (r) from ((r,0)).
Step 3
Exam Tip
कटान का पहला निर्देशांक (r) है और (r>0) है। टिप: ((r,0)) से शून्यक (r) पढ़ें।
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यदि आलेख (x)-अक्ष को ((-6,0)), ((-2,0)), ((4,0)) पर काटता है तो सबसे बड़ा शून्यक कौन सा है?
If a graph cuts the (x)-axis at ((-6,0)), ((-2,0)), ((4,0)), which is the greatest zero?
#greatest zero graph
A (-6)
B (-2)
C (4)
D (0)
Explanation opens after your attempt
Step 1
Concept
The zeroes are (-6), (-2), (4), and (4) is the greatest. Tip: the value to the right on the number line is greater.
Step 2
Why this answer is correct
The correct answer is C. (4). The zeroes are (-6), (-2), (4), and (4) is the greatest. Tip: the value to the right on the number line is greater.
Step 3
Exam Tip
शून्यक (-6), (-2), (4) हैं और (4) सबसे बड़ा है। टिप: संख्या रेखा पर दाईं ओर का मान बड़ा होता है।
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किसी आलेख में (x)-अक्ष कटान ((r,0)) है। यदि (r<0) है तो शून्यक के बारे में क्या कहा जा सकता है?
A graph has an (x)-axis intersection ((r,0)). If (r<0), what can be said about the zero?
#symbolic zero graph
A शून्यक धनात्मक है / The zero is positive
B शून्यक ऋणात्मक है / The zero is negative
C शून्यक (0) है / The zero is (0)
D शून्यक नहीं है / There is no zero
Explanation opens after your attempt
Correct Answer
B. शून्यक ऋणात्मक है / The zero is negative
Step 1
Concept
The first coordinate (r) of the intersection is the zero, and (r<0). Tip: the same rule works in symbolic questions.
Step 2
Why this answer is correct
The correct answer is B. शून्यक ऋणात्मक है / The zero is negative. The first coordinate (r) of the intersection is the zero, and (r<0). Tip: the same rule works in symbolic questions.
Step 3
Exam Tip
कटान का पहला निर्देशांक (r) ही शून्यक है और (r<0) है। टिप: प्रतीकात्मक प्रश्न में भी नियम वही रहता है।
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यदि (p(x)=0) शून्य बहुपद है तो उसके आलेख पर कौन सा कथन सही है?
If (p(x)=0) is the zero polynomial, which statement about its graph is correct?
#zero polynomial graph
A आलेख (x)-अक्ष ही है / The graph is the (x)-axis itself
B आलेख (y)-अक्ष ही है / The graph is the (y)-axis itself
C आलेख (x)-अक्ष के ऊपर है / The graph is above the (x)-axis
D आलेख (x)-अक्ष को नहीं छूता / The graph does not touch the (x)-axis
Explanation opens after your attempt
Correct Answer
A. आलेख (x)-अक्ष ही है / The graph is the (x)-axis itself
Step 1
Concept
For the zero polynomial, (y=0) for every (x). Tip: this is a special case.
Step 2
Why this answer is correct
The correct answer is A. आलेख (x)-अक्ष ही है / The graph is the (x)-axis itself. For the zero polynomial, (y=0) for every (x). Tip: this is a special case.
Step 3
Exam Tip
शून्य बहुपद में हर (x) पर (y=0) होता है। टिप: यह विशेष स्थिति है।
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किसी रैखिक बहुपद का आलेख (y=4x+12) है। इसका शून्यक क्या है?
The graph of a linear polynomial is (y=4x+12). What is its zero?
#linear graph zero
A (-3)
B (3)
C (12)
D (-12)
Explanation opens after your attempt
Step 1
Concept
Solving (4x+12=0) gives (x=-3). Tip: set (y=0) to find the zero.
Step 2
Why this answer is correct
The correct answer is A. (-3). Solving (4x+12=0) gives (x=-3). Tip: set (y=0) to find the zero.
Step 3
Exam Tip
(4x+12=0) से (x=-3) मिलता है। टिप: शून्यक के लिए (y=0) रखें।
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यदि ग्राफ पर ((-2,0)) और ((6,0)) शून्यक बिंदु हैं, तो उनके बीच (x)-अक्ष पर कितनी इकाई की दूरी है?
If ((-2,0)) and ((6,0)) are zero points on a graph, how many units apart are they on the (x)-axis?
#distance
#zero points
#graph
A (4)
B (6)
C (8)
D (-8)
Explanation opens after your attempt
Step 1
Concept
The distance is (6-(-2)=8) units. Tip: distance on the (x)-axis is the absolute difference of (x)-values.
Step 2
Why this answer is correct
The correct answer is C. (8). The distance is (6-(-2)=8) units. Tip: distance on the (x)-axis is the absolute difference of (x)-values.
Step 3
Exam Tip
दूरी (6-(-2)=8) इकाई है। टिप: (x)-अक्ष पर दूरी (x)-मानों के अंतर का परिमाण है।
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किस ग्राफ में ठीक एक वास्तविक शून्यक होगा?
Which graph will have exactly one real zero?
#one zero
#graph
#concept
A जो (x)-अक्ष को दो अलग बिंदुओं पर काटे / One that cuts the (x)-axis at two distinct points
B जो (x)-अक्ष को एक ही बिंदु पर स्पर्श करे / One that touches the (x)-axis at only one point
C जो (x)-अक्ष के समांतर ऊपर हो / One that is parallel above the (x)-axis
D जो (y)-अक्ष को दो बार काटे / One that cuts the (y)-axis twice
Explanation opens after your attempt
Correct Answer
B. जो (x)-अक्ष को एक ही बिंदु पर स्पर्श करे / One that touches the (x)-axis at only one point
Step 1
Concept
One touching point gives one real zero. Tip: zeroes depend on meeting the (x)-axis.
Step 2
Why this answer is correct
The correct answer is B. जो (x)-अक्ष को एक ही बिंदु पर स्पर्श करे / One that touches the (x)-axis at only one point. One touching point gives one real zero. Tip: zeroes depend on meeting the (x)-axis.
Step 3
Exam Tip
एक ही स्पर्श बिंदु एक वास्तविक शून्यक देता है। टिप: शून्यक (x)-अक्ष से मिलने पर निर्भर है।
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यदि आलेख (x)-अक्ष को (-2) पर काटता है तो बहुपद का शून्यक क्या है?
If the graph cuts the (x)-axis at (-2) then what is the zero of the polynomial?
#negative zero graph
A (-2)
B (2)
C (0)
D (-1)
Explanation opens after your attempt
Step 1
Concept
The (x)-coordinate of the (x)-axis intersection is the zero. Tip: read the sign carefully.
Step 2
Why this answer is correct
The correct answer is A. (-2). The (x)-coordinate of the (x)-axis intersection is the zero. Tip: read the sign carefully.
Step 3
Exam Tip
(x)-अक्ष कटान का (x)-निर्देशांक ही शून्यक होता है। टिप: चिह्न को ध्यान से पढ़ें।
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यदि बहुपद का आलेख मूल बिंदु ((0,0)) से गुजरता है तो कौन सा शून्यक अवश्य होगा?
If the graph of a polynomial passes through the origin ((0,0)) then which zero is certain?
#origin zero graph
A (0)
B (1)
C (-1)
D (2)
Explanation opens after your attempt
Step 1
Concept
At the origin (x=0) and (p(x)=0). Tip: a graph through the origin has (0) as a zero.
Step 2
Why this answer is correct
The correct answer is A. (0). At the origin (x=0) and (p(x)=0). Tip: a graph through the origin has (0) as a zero.
Step 3
Exam Tip
मूल बिंदु पर (x=0) और (p(x)=0) होता है। टिप: origin पर जाने वाला आलेख (0) को शून्यक बनाता है।
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यदि किसी बहुपद का कोई वास्तविक शून्यक नहीं है, तो उसका ग्राफ (x)-अक्ष के साथ क्या करेगा?
If a polynomial has no real zero, what will its graph do with the (x)-axis?
#no-real-zero
#graph
#x-axis
#concept
A न तो काटेगा न छुएगा / It will neither cut nor touch it
B हमेशा दो बार काटेगा / It will always cut twice
C हमेशा एक बार छुएगा / It will always touch once
D पूरे (x)-अक्ष पर रहेगा / It will lie on the whole (x)-axis
Explanation opens after your attempt
Correct Answer
A. न तो काटेगा न छुएगा / It will neither cut nor touch it
Step 1
Concept
A real zero appears when the graph meets the (x)-axis. With no real zero, the graph will not meet the (x)-axis.
Step 2
Why this answer is correct
The correct answer is A. न तो काटेगा न छुएगा / It will neither cut nor touch it. A real zero appears when the graph meets the (x)-axis. With no real zero, the graph will not meet the (x)-axis.
Step 3
Exam Tip
वास्तविक शून्यक (x)-अक्ष से मिलने पर दिखता है। कोई वास्तविक शून्यक न होने पर ग्राफ (x)-अक्ष से नहीं मिलेगा।
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किसी स्थिर अशून्य बहुपद जैसे (p(x)=5) के ग्राफ से शून्यकों के बारे में क्या पता चलता है?
What does the graph of a non-zero constant polynomial like (p(x)=5) show about its zeroes?
#constant-polynomial
#no-zero
#graph
#easy
A कोई शून्यक नहीं / No zero
B एक शून्यक / One zero
C दो शून्यक / Two zeroes
D अनंत शून्यक / Infinite zeroes
Explanation opens after your attempt
Correct Answer
A. कोई शून्यक नहीं / No zero
Step 1
Concept
The graph of (p(x)=5) is a line parallel to the (x)-axis and does not cut it. Hence it has no zero.
Step 2
Why this answer is correct
The correct answer is A. कोई शून्यक नहीं / No zero. The graph of (p(x)=5) is a line parallel to the (x)-axis and does not cut it. Hence it has no zero.
Step 3
Exam Tip
(p(x)=5) का ग्राफ (x)-अक्ष के समानांतर रेखा है जो (x)-अक्ष को नहीं काटती। इसलिए इसका कोई शून्यक नहीं है।
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यदि किसी बहुपद का ग्राफ (x)-अक्ष को (x=3) पर काटता है, तो उसका शून्यक क्या होगा?
If the graph of a polynomial cuts the (x)-axis at (x=3), what is its zero?
#polynomials
#graph
#zero
#x-intercept
A (3)
B (-3)
C (0)
D (1)
Explanation opens after your attempt
Step 1
Concept
The (x)-value where the graph cuts the (x)-axis is the zero. Hence the zero is (3).
Step 2
Why this answer is correct
The correct answer is A. (3). The (x)-value where the graph cuts the (x)-axis is the zero. Hence the zero is (3).
Step 3
Exam Tip
जहाँ ग्राफ (x)-अक्ष को काटता है वही (x)-मान शून्यक होता है। इसलिए यहाँ शून्यक (3) है।
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यदि (p(a)=0), तो ग्राफ किस बिंदु से अवश्य गुजरेगा?
If (p(a)=0), through which point must the graph pass?
#general-zero
#coordinate
#graph
#polynomials
A ((a,0))
B ((0,a))
C ((a,a))
D ((-a,0))
Explanation opens after your attempt
Correct Answer
A. ((a,0))
Step 1
Concept
(p(a)=0) means (y=0) at (x=a). Therefore the graph passes through ((a,0)).
Step 2
Why this answer is correct
The correct answer is A. ((a,0)). (p(a)=0) means (y=0) at (x=a). Therefore the graph passes through ((a,0)).
Step 3
Exam Tip
(p(a)=0) का अर्थ है (x=a) पर (y=0)। इसलिए ग्राफ ((a,0)) से गुजरेगा।
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आलेख (x)-अक्ष को केवल ((2,0)) पर स्पर्श करता है। शून्यक कौन सा है?
The graph only touches the (x)-axis at ((2,0)). Which is the zero?
#touching point zero
A (2)
B (0)
C दो और शून्य / Two and zero
D कोई नहीं / None
Explanation opens after your attempt
Step 1
Concept
The (x)-coordinate of the touching point is (2) so the zero is (2). Tip: count a touching point too.
Step 2
Why this answer is correct
The correct answer is A. (2). The (x)-coordinate of the touching point is (2) so the zero is (2). Tip: count a touching point too.
Step 3
Exam Tip
स्पर्श बिंदु का (x)-निर्देशांक (2) है इसलिए शून्यक (2) है। टिप: स्पर्श बिंदु को भी गिनें।
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रेखा (5x-6y=30) के लिए कौन-सा बिंदु सही है और ग्राफ बनाने में उपयोगी हो सकता है?
Which point is correct for (5x-6y=30) and can be useful for drawing the graph?
#point on line
#negative intercept
#graph plotting
A बिंदु (\left\(0,-5\right\)) / Point (\left\(0,-5\right\))
B बिंदु (\left\(0,5\right\)) / Point (\left\(0,5\right\))
C बिंदु (\left\(-6,0\right\)) / Point (\left\(-6,0\right\))
D बिंदु (\left\(5,0\right\)) / Point (\left\(5,0\right\))
Explanation opens after your attempt
Correct Answer
A. बिंदु (\left\(0,-5\right\)) / Point (\left\(0,-5\right\))
Step 1
Concept
Substituting (\left\(0,-5\right\)) gives (5\left\(0\right\)-6\left\(-5\right\)=30). A negative (y)-intercept is plotted downward on the graph.
Step 2
Why this answer is correct
The correct answer is A. बिंदु (\left\(0,-5\right\)) / Point (\left\(0,-5\right\)). Substituting (\left\(0,-5\right\)) gives (5\left\(0\right\)-6\left\(-5\right\)=30). A negative (y)-intercept is plotted downward on the graph.
Step 3
Exam Tip
(\left\(0,-5\right\)) रखने पर (5\left\(0\right\)-6\left\(-5\right\)=30)। ऋण (y)-अवरोध ग्राफ में नीचे की ओर लगाया जाता है।
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रेखा (3x-4y=12) के लिए कौन-सा बिंदु सही है और ग्राफ बनाने में उपयोगी हो सकता है?
Which point is correct for (3x-4y=12) and can be useful for drawing the graph?
#point on line
#negative intercept
#graph plotting
A बिंदु (\left\(0,-3\right\)) / Point (\left\(0,-3\right\))
B बिंदु (\left\(0,3\right\)) / Point (\left\(0,3\right\))
C बिंदु (\left\(-4,0\right\)) / Point (\left\(-4,0\right\))
D बिंदु (\left\(3,0\right\)) / Point (\left\(3,0\right\))
Explanation opens after your attempt
Correct Answer
A. बिंदु (\left\(0,-3\right\)) / Point (\left\(0,-3\right\))
Step 1
Concept
Substituting (\left\(0,-3\right\)) gives (3\left\(0\right\)-4\left\(-3\right\)=12). A negative (y)-intercept is plotted downward on the graph.
Step 2
Why this answer is correct
The correct answer is A. बिंदु (\left\(0,-3\right\)) / Point (\left\(0,-3\right\)). Substituting (\left\(0,-3\right\)) gives (3\left\(0\right\)-4\left\(-3\right\)=12). A negative (y)-intercept is plotted downward on the graph.
Step 3
Exam Tip
(\left\(0,-3\right\)) रखने पर (3\left\(0\right\)-4\left\(-3\right\)=12)। ऋण (y)-अवरोध ग्राफ में नीचे की ओर लगाया जाता है।
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यदि (p(x)=x-2 +20x+100) है, तो ग्राफ (x)-अक्ष को किस बिंदु पर स्पर्श करेगा?
If (p(x)=x-2 +20x+100), at which point will the graph touch the (x)-axis?
#perfect square
#touching point
#graph
A ((-10,0))
B ((10,0))
C ((20,0))
D ((0,100))
Explanation opens after your attempt
Correct Answer
A. ((-10,0))
Step 1
Concept
(x-2 +20x+100=(x+10)2 ), so the touching point is ((-10,0)). Tip: change the sign in a perfect square to get the zero.
Step 2
Why this answer is correct
The correct answer is A. ((-10,0)). (x-2 +20x+100=(x+10)2 ), so the touching point is ((-10,0)). Tip: change the sign in a perfect square to get the zero.
Step 3
Exam Tip
(x-2 +20x+100=(x+10)2 ) है, इसलिए स्पर्श बिंदु ((-10,0)) है। टिप: पूर्ण वर्ग में चिह्न बदलकर शून्यक मिलता है।
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यदि (p(x)=x-2 -18x+81) है, तो ग्राफ (x)-अक्ष को किस बिंदु पर स्पर्श करेगा?
If (p(x)=x-2 -18x+81), at which point will the graph touch the (x)-axis?
#perfect square
#touching point
#graph
A ((9,0))
B ((-9,0))
C ((18,0))
D ((0,81))
Explanation opens after your attempt
Correct Answer
A. ((9,0))
Step 1
Concept
(x-2 -18x+81=(x-9)2 ), so the touching point is ((9,0)). Tip: change the sign in a perfect square to get the zero.
Step 2
Why this answer is correct
The correct answer is A. ((9,0)). (x-2 -18x+81=(x-9)2 ), so the touching point is ((9,0)). Tip: change the sign in a perfect square to get the zero.
Step 3
Exam Tip
(x-2 -18x+81=(x-9)2 ) है, इसलिए स्पर्श बिंदु ((9,0)) है। टिप: पूर्ण वर्ग में चिह्न बदलकर शून्यक मिलता है।
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यदि (p(x)=x-2 +14x+49) है तो ग्राफ (x)-अक्ष को किस बिंदु पर स्पर्श करेगा?
If (p(x)=x-2 +14x+49), at which point will the graph touch the (x)-axis?
#perfect square
#touching point
#graph
A ((-7,0))
B ((7,0))
C ((14,0))
D ((0,49))
Explanation opens after your attempt
Correct Answer
A. ((-7,0))
Step 1
Concept
(x-2 +14x+49=(x+7)2 ), so the touching point is ((-7,0)). Tip: in a perfect square, change the sign to get the zero.
Step 2
Why this answer is correct
The correct answer is A. ((-7,0)). (x-2 +14x+49=(x+7)2 ), so the touching point is ((-7,0)). Tip: in a perfect square, change the sign to get the zero.
Step 3
Exam Tip
(x-2 +14x+49=(x+7)2 ) है इसलिए स्पर्श बिंदु ((-7,0)) है। टिप: पूर्ण वर्ग में चिह्न बदलकर शून्यक मिलता है।
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यदि (p(x)=x-2 -12x+36) है, तो ग्राफ (x)-अक्ष को किस बिंदु पर स्पर्श करेगा?
If (p(x)=x-2 -12x+36), at which point will the graph touch the (x)-axis?
#perfect square
#touching point
#graph
A ((6,0))
B ((-6,0))
C ((12,0))
D ((0,36))
Explanation opens after your attempt
Correct Answer
A. ((6,0))
Step 1
Concept
(x-2 -12x+36=(x-6)2 ), so the touching point is ((6,0)). Tip: in a perfect square, change the sign to get the zero.
Step 2
Why this answer is correct
The correct answer is A. ((6,0)). (x-2 -12x+36=(x-6)2 ), so the touching point is ((6,0)). Tip: in a perfect square, change the sign to get the zero.
Step 3
Exam Tip
(x-2 -12x+36=(x-6)2 ) है, इसलिए स्पर्श बिंदु ((6,0)) है। टिप: पूर्ण वर्ग में चिह्न बदलकर शून्यक मिलता है।
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यदि (p(x)=x-2 +8x+16) है, तो ग्राफ (x)-अक्ष को किस बिंदु पर स्पर्श करेगा?
If (p(x)=x-2 +8x+16), at which point will the graph touch the (x)-axis?
#perfect square
#touching point
#graph
A ((-4,0))
B ((4,0))
C ((-8,0))
D ((0,16))
Explanation opens after your attempt
Correct Answer
A. ((-4,0))
Step 1
Concept
(x-2 +8x+16=(x+4)2 ), so the touching point is ((-4,0)). Tip: in a perfect square the sign changes to get the zero.
Step 2
Why this answer is correct
The correct answer is A. ((-4,0)). (x-2 +8x+16=(x+4)2 ), so the touching point is ((-4,0)). Tip: in a perfect square the sign changes to get the zero.
Step 3
Exam Tip
(x-2 +8x+16=(x+4)2 ), इसलिए स्पर्श बिंदु ((-4,0)) है। टिप: पूर्ण वर्ग में चिह्न बदलकर शून्यक मिलता है।
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यदि (p(9)=0), तो ग्राफ किस बिंदु से गुजरेगा?
If (p(9)=0), through which point will the graph pass?
#function-value
#graph-point
#zeroes
#class-10
A ((9,0))
B ((0,9))
C ((-9,0))
D ((9,9))
Explanation opens after your attempt
Correct Answer
A. ((9,0))
Step 1
Concept
(p(9)=0) means (y=0) when (x=9). Therefore the graph passes through ((9,0)).
Step 2
Why this answer is correct
The correct answer is A. ((9,0)). (p(9)=0) means (y=0) when (x=9). Therefore the graph passes through ((9,0)).
Step 3
Exam Tip
(p(9)=0) का अर्थ है (x=9) पर (y=0)। इसलिए ग्राफ ((9,0)) से गुजरेगा।
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यदि (p(-1)=0), तो ग्राफ किस बिंदु से गुजरेगा?
If (p(-1)=0), through which point will the graph pass?
#function-value
#graph-point
#zeroes
#polynomials
A ((-1,0))
B ((1,0))
C ((0,-1))
D ((0,1))
Explanation opens after your attempt
Correct Answer
A. ((-1,0))
Step 1
Concept
(p(-1)=0) means (y=0) at (x=-1). So the graph passes through ((-1,0)).
Step 2
Why this answer is correct
The correct answer is A. ((-1,0)). (p(-1)=0) means (y=0) at (x=-1). So the graph passes through ((-1,0)).
Step 3
Exam Tip
(p(-1)=0) का अर्थ है (x=-1) पर (y=0)। इसलिए ग्राफ ((-1,0)) से गुजरेगा।
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ग्राफ पर ((3,0)) बिंदु बहुपद के लिए क्या दर्शाता है?
What does the point ((3,0)) on a polynomial graph represent?
#coordinate-point
#x-axis
#zeroes
#graph
A (3) बहुपद का शून्यक है / (3) is a zero of the polynomial
B (0) बहुपद का शून्यक है / (0) is a zero of the polynomial
C (3) बहुपद का गुणांक है / (3) is a coefficient of the polynomial
D ग्राफ का अधिकतम मान है / It is the maximum value of the graph
Explanation opens after your attempt
Correct Answer
A. (3) बहुपद का शून्यक है / (3) is a zero of the polynomial
Step 1
Concept
In ((3,0)), (y=0) and (x=3). Therefore (3) is the zero.
Step 2
Why this answer is correct
The correct answer is A. (3) बहुपद का शून्यक है / (3) is a zero of the polynomial. In ((3,0)), (y=0) and (x=3). Therefore (3) is the zero.
Step 3
Exam Tip
((3,0)) में (y=0) है और (x=3) है। इसलिए (3) शून्यक होगा।
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एक ग्राफ (x)-अक्ष को (x=1) पर पार करता है और (x=4) पर पार करता है। यदि (x=2) पर (p(x)>0), तो (x=2) शून्यक क्यों नहीं है?
A graph crosses the (x)-axis at (x=1) and (x=4). If (p(x)>0) at (x=2), why is (x=2) not a zero?
#misconception
#between zeroes
#graph
A क्योंकि (2) दोनों शून्यकों के बीच है / Because (2) lies between the two zeroes
B क्योंकि (p(2)\neq0) है / Because (p(2)\neq0)
C क्योंकि (2) धनात्मक है / Because (2) is positive
D क्योंकि ग्राफ पर बिंदु नहीं हो सकता / Because it cannot be a point on the graph
Explanation opens after your attempt
Correct Answer
B. क्योंकि (p(2)\neq0) है / Because (p(2)\neq0)
Step 1
Concept
For a zero, the function value must be (0). Tip: being between zeroes does not guarantee being a zero.
Step 2
Why this answer is correct
The correct answer is B. क्योंकि (p(2)\neq0) है / Because (p(2)\neq0). For a zero, the function value must be (0). Tip: being between zeroes does not guarantee being a zero.
Step 3
Exam Tip
शून्यक के लिए फलन मान (0) होना चाहिए। टिप: बीच में होना शून्यक होने की गारंटी नहीं देता।
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एक बिंदु परिप्रेक्ष्य में यदि रेखाएं लुप्त बिंदु से न मिलें तो क्या समस्या होगी?
If lines do not meet the vanishing point in one-point perspective what problem will occur?
#one point perspective
#vanishing point
#depth
A गहराई असंगत लगेगी / Depth will look inconsistent
B रंग चमकीला होगा / Colour will become bright
C बनावट मुलायम होगी / Texture will become soft
D कागज बदल जाएगा / Paper will change
Explanation opens after your attempt
Correct Answer
A. गहराई असंगत लगेगी / Depth will look inconsistent
Step 1
Concept
Perspective lines make depth logical by relating to vanishing point. Exam tip: check vanishing point direction.
Step 2
Why this answer is correct
The correct answer is A. गहराई असंगत लगेगी / Depth will look inconsistent. Perspective lines make depth logical by relating to vanishing point. Exam tip: check vanishing point direction.
Step 3
Exam Tip
परिप्रेक्ष्य रेखाएं लुप्त बिंदु से जुड़कर गहराई को तार्किक बनाती हैं। परीक्षा में vanishing point की दिशा जांचें।
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यदि कोई ग्राफ (x)-अक्ष को केवल छूता है, तो क्या वह बिंदु शून्यक देगा?
If a graph only touches the (x)-axis, will that point give a zero?
#touching-x-axis
#zeroes
#concept
#easy
A हाँ / Yes
B नहीं / No
C केवल रेखा में / Only for a line
D केवल तब जब (y=1) हो / Only when (y=1)
Explanation opens after your attempt
Correct Answer
A. हाँ / Yes
Step 1
Concept
Even when the graph touches, the point lies on the (x)-axis and (y=0). Therefore that point gives a zero.
Step 2
Why this answer is correct
The correct answer is A. हाँ / Yes. Even when the graph touches, the point lies on the (x)-axis and (y=0). Therefore that point gives a zero.
Step 3
Exam Tip
छूने पर भी बिंदु (x)-अक्ष पर होता है और (y=0) होता है। इसलिए वह बिंदु शून्यक देता है।
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किसी स्थिर अशून्य बहुपद (p(x)=-3) का ग्राफ (x)-अक्ष को क्यों नहीं काटता?
Why does the graph of the non-zero constant polynomial (p(x)=-3) not cut the (x)-axis?
#constant-polynomial
#no-zero
#x-axis
#easy
A क्योंकि (y) हमेशा (-3) रहता है / Because (y) always remains (-3)
B क्योंकि (x) हमेशा (-3) रहता है / Because (x) always remains (-3)
C क्योंकि ग्राफ पर कोई बिंदु नहीं होता / Because the graph has no point
D क्योंकि यह परवलय है / Because it is a parabola
Explanation opens after your attempt
Correct Answer
A. क्योंकि (y) हमेशा (-3) रहता है / Because (y) always remains (-3)
Step 1
Concept
For (p(x)=-3), the (y)-value is never (0). So the graph does not cut the (x)-axis and has no zero.
Step 2
Why this answer is correct
The correct answer is A. क्योंकि (y) हमेशा (-3) रहता है / Because (y) always remains (-3). For (p(x)=-3), the (y)-value is never (0). So the graph does not cut the (x)-axis and has no zero.
Step 3
Exam Tip
(p(x)=-3) का (y)-मान कभी (0) नहीं होता। इसलिए ग्राफ (x)-अक्ष को नहीं काटता और कोई शून्यक नहीं है।
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किसी बहुपद का ग्राफ (x)-अक्ष को दो बार काटता है और एक बार उसी बिंदु पर स्पर्श नहीं करता। इसका अर्थ क्या है?
A polynomial graph cuts the (x)-axis twice and does not touch at the same point. What does this mean?
#two crossings graph
A दो अलग वास्तविक शून्यक हैं / There are two distinct real zeroes
B एक ही दोहराया शून्यक है / There is one repeated zero
C कोई वास्तविक शून्यक नहीं है / There is no real zero
D हर बिंदु शून्यक है / Every point is a zero
Explanation opens after your attempt
Correct Answer
A. दो अलग वास्तविक शून्यक हैं / There are two distinct real zeroes
Step 1
Concept
Two distinct crossings give two distinct zeroes. Tip: distinct points show distinct (x)-values.
Step 2
Why this answer is correct
The correct answer is A. दो अलग वास्तविक शून्यक हैं / There are two distinct real zeroes. Two distinct crossings give two distinct zeroes. Tip: distinct points show distinct (x)-values.
Step 3
Exam Tip
दो अलग कटान दो अलग शून्यक देते हैं। टिप: अलग बिंदु अलग (x)-मान बताते हैं।
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ग्राफ में (2x-5y=10) की (y)-अवरोध वाली बिंदु कौन सी है?
Which point is the (y)-intercept point of (2x-5y=10) on the graph?
#linear equations
#graphical method
#y-intercept
#plotting
A ((0,-2))
B ((-2,0))
C ((0,2))
D ((5,0))
Explanation opens after your attempt
Correct Answer
A. ((0,-2))
Step 1
Concept
For the (y)-intercept, put (x=0), then (-5y=10) and (y=-2). For intercepts, set the correct variable to zero.
Step 2
Why this answer is correct
The correct answer is A. ((0,-2)). For the (y)-intercept, put (x=0), then (-5y=10) and (y=-2). For intercepts, set the correct variable to zero.
Step 3
Exam Tip
(y)-अवरोध के लिए (x=0) रखें, तब (-5y=10) और (y=-2)। अवरोध निकालते समय सही चर को शून्य रखें।
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कौन-सा बिंदु (3x+4y=26) पर है लेकिन (x+y=7) पर नहीं है?
Which point lies on (3x+4y=26) but not on (x+y=7)?
#point verification
#not common point
#graph
A बिंदु (\left\(2,5\right\)) / Point (\left\(2,5\right\))
B बिंदु (\left\(4,\frac{7}{2}\right\)) / Point (\left\(4,\frac{7}{2}\right\))
C बिंदु (\left\(6,2\right\)) / Point (\left\(6,2\right\))
D बिंदु (\left\(5,2\right\)) / Point (\left\(5,2\right\))
Explanation opens after your attempt
Correct Answer
A. बिंदु (\left\(2,5\right\)) / Point (\left\(2,5\right\))
Step 1
Concept
At (\left\(2,5\right\)), (3\left\(2\right\)+4\left\(5\right\)=26), but (2+5=7) also, so check fully. The correct non-common point is (\left\(4,\frac{7}{2}\right\)).
Step 2
Why this answer is correct
The correct answer is A. बिंदु (\left\(2,5\right\)) / Point (\left\(2,5\right\)). At (\left\(2,5\right\)), (3\left\(2\right\)+4\left\(5\right\)=26), but (2+5=7) also, so check fully. The correct non-common point is (\left\(4,\frac{7}{2}\right\)).
Step 3
Exam Tip
(\left\(2,5\right\)) पर (3\left\(2\right\)+4\left\(5\right\)=26), लेकिन (2+5=7) भी है, इसलिए जाँच पूरी करें। सही अलग बिंदु (\left\(4,\frac{7}{2}\right\)) है।
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कौन-सा बिंदु (2x+5y=27) पर है लेकिन (x+y=9) पर नहीं है?
Which point lies on (2x+5y=27) but not on (x+y=9)?
#point verification
#not common point
#graph
A बिंदु (\left\(1,5\right\)) / Point (\left\(1,5\right\))
B बिंदु (\left\(6,3\right\)) / Point (\left\(6,3\right\))
C बिंदु (\left\(9,0\right\)) / Point (\left\(9,0\right\))
D बिंदु (\left\(4,5\right\)) / Point (\left\(4,5\right\))
Explanation opens after your attempt
Correct Answer
A. बिंदु (\left\(1,5\right\)) / Point (\left\(1,5\right\))
Step 1
Concept
At (\left\(1,5\right\)), (2\left\(1\right\)+5\left\(5\right\)=27), but (1+5=6). To be a common solution, both equations must be true.
Step 2
Why this answer is correct
The correct answer is A. बिंदु (\left\(1,5\right\)) / Point (\left\(1,5\right\)). At (\left\(1,5\right\)), (2\left\(1\right\)+5\left\(5\right\)=27), but (1+5=6). To be a common solution, both equations must be true.
Step 3
Exam Tip
(\left\(1,5\right\)) पर (2\left\(1\right\)+5\left\(5\right\)=27), लेकिन (1+5=6)। सामान्य हल बनने के लिए दोनों समीकरण सत्य होने चाहिए।
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कौन-सा बिंदु (2x+3y=24) पर है लेकिन (x+y=10) पर नहीं है?
Which point lies on (2x+3y=24) but not on (x+y=10)?
#point verification
#not common point
#graph
A बिंदु (\left\(6,4\right\)) / Point (\left\(6,4\right\))
B बिंदु (\left\(3,6\right\)) / Point (\left\(3,6\right\))
C बिंदु (\left\(9,2\right\)) / Point (\left\(9,2\right\))
D बिंदु (\left\(0,8\right\)) / Point (\left\(0,8\right\))
Explanation opens after your attempt
Correct Answer
B. बिंदु (\left\(3,6\right\)) / Point (\left\(3,6\right\))
Step 1
Concept
At (\left\(3,6\right\)), (2\left\(3\right\)+3\left\(6\right\)=24), but (3+6=9). For a common solution, both equations must be true.
Step 2
Why this answer is correct
The correct answer is B. बिंदु (\left\(3,6\right\)) / Point (\left\(3,6\right\)). At (\left\(3,6\right\)), (2\left\(3\right\)+3\left\(6\right\)=24), but (3+6=9). For a common solution, both equations must be true.
Step 3
Exam Tip
(\left\(3,6\right\)) पर (2\left\(3\right\)+3\left\(6\right\)=24), लेकिन (3+6=9)। सामान्य हल के लिए दोनों समीकरण सत्य होने चाहिए।
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कौन-सा बिंदु (4x+y=18) पर है लेकिन (x+y=9) पर नहीं है?
Which point lies on (4x+y=18) but not on (x+y=9)?
#point verification
#not common point
#graph
A ( (4,2) )
B ( (3,6) )
C ( (2,10) )
D ( (5,-2) )
Explanation opens after your attempt
Correct Answer
A. ( (4,2) )
Step 1
Concept
At ( (4,2) ), (4(4)+2=18), but (4+2=6). For a common solution, the point must satisfy both equations.
Step 2
Why this answer is correct
The correct answer is A. ( (4,2) ). At ( (4,2) ), (4(4)+2=18), but (4+2=6). For a common solution, the point must satisfy both equations.
Step 3
Exam Tip
( (4,2) ) पर (4(4)+2=18), लेकिन (4+2=6)। सामान्य हल के लिए बिंदु को दोनों समीकरण संतुष्ट करने चाहिए।
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कौन-सा बिंदु (3x+2y=16) पर है लेकिन (x+y=7) पर नहीं है?
Which point lies on (3x+2y=16) but not on (x+y=7)?
#point verification
#not common point
#graph
A ( (2,5) )
B ( (4,2) )
C ( (6,-1) )
D ( (3,4) )
Explanation opens after your attempt
Correct Answer
B. ( (4,2) )
Step 1
Concept
At ( (4,2) ), (3(4)+2(2)=16), but (4+2=6). To be a solution of both lines, both equations must be true.
Step 2
Why this answer is correct
The correct answer is B. ( (4,2) ). At ( (4,2) ), (3(4)+2(2)=16), but (4+2=6). To be a solution of both lines, both equations must be true.
Step 3
Exam Tip
( (4,2) ) पर (3(4)+2(2)=16), लेकिन (4+2=6)। दोनों रेखाओं का हल बनने के लिए दोनों समीकरण सत्य होने चाहिए।
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कौन-सा बिंदु रेखा (2x+3y=19) पर है लेकिन रेखा (x+y=8) पर नहीं है?
Which point lies on the line (2x+3y=19) but not on the line (x+y=8)?
#point verification
#not common point
#graph
A ( (5,3) )
B ( (2,5) )
C ( (4,3) )
D ( (1,6) )
Explanation opens after your attempt
Correct Answer
B. ( (2,5) )
Step 1
Concept
At ( (2,5) ), (2(2)+3(5)=19), but (2+5=7). To be a solution of both lines, both equations must be true.
Step 2
Why this answer is correct
The correct answer is B. ( (2,5) ). At ( (2,5) ), (2(2)+3(5)=19), but (2+5=7). To be a solution of both lines, both equations must be true.
Step 3
Exam Tip
( (2,5) ) पर (2(2)+3(5)=19), लेकिन (2+5=7) है। दोनों रेखाओं का हल बनने के लिए दोनों समीकरण सत्य होने चाहिए।
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कौन सा बिंदु (x=9) को शून्यक साबित करता है?
Which point proves that (x=9) is a zero?
#zero point proof
A ((9,0))
B ((0,9))
C ((9,9))
D ((-9,0))
Explanation opens after your attempt
Correct Answer
A. ((9,0))
Step 1
Concept
A zero (x=9) means (p(9)=0). Tip: place the zero as the first coordinate.
Step 2
Why this answer is correct
The correct answer is A. ((9,0)). A zero (x=9) means (p(9)=0). Tip: place the zero as the first coordinate.
Step 3
Exam Tip
(x=9) शून्यक होने का अर्थ (p(9)=0) है। टिप: शून्यक को पहले निर्देशांक में रखें।
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कौन सा बिंदु किसी बहुपद के शून्यक को सीधे दिखाता है?
Which point directly shows a zero of a polynomial?
#identify zero point
A ((9,0))
B ((0,9))
C ((9,9))
D ((0,-9))
Explanation opens after your attempt
Correct Answer
A. ((9,0))
Step 1
Concept
A point showing a zero has (y)-coordinate (0). Tip: choose points lying on the (x)-axis.
Step 2
Why this answer is correct
The correct answer is A. ((9,0)). A point showing a zero has (y)-coordinate (0). Tip: choose points lying on the (x)-axis.
Step 3
Exam Tip
शून्यक वाले बिंदु का (y)-निर्देशांक (0) होता है। टिप: (x)-अक्ष पर पड़े बिंदु चुनें।
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किसी बहुपद के ग्राफ पर ((2,0)), ((3,4)), ((4,0)) और ((5,-1)) बिंदु हैं। (p(3)) और (p(5)) को शून्यक क्यों नहीं कहा जाएगा?
The points ((2,0)), ((3,4)), ((4,0)) and ((5,-1)) lie on a polynomial graph. Why will (3) and (5) not be called zeroes?
#function value
#not zero
#graph
A क्योंकि उनके (x)-मान धनात्मक हैं / Because their (x)-values are positive
B क्योंकि उनके (y)-मान (0) नहीं हैं / Because their (y)-values are not (0)
C क्योंकि वे (y)-अक्ष पर हैं / Because they are on the (y)-axis
D क्योंकि बहुपद का ग्राफ नहीं बनता / Because a polynomial graph is not formed
Explanation opens after your attempt
Correct Answer
B. क्योंकि उनके (y)-मान (0) नहीं हैं / Because their (y)-values are not (0)
Step 1
Concept
At (3) and (5), (p(x)) is (4) and (-1). Tip: for a zero, the function value must be exactly (0).
Step 2
Why this answer is correct
The correct answer is B. क्योंकि उनके (y)-मान (0) नहीं हैं / Because their (y)-values are not (0). At (3) and (5), (p(x)) is (4) and (-1). Tip: for a zero, the function value must be exactly (0).
Step 3
Exam Tip
(3) और (5) पर (p(x)) क्रमशः (4) और (-1) है। टिप: शून्यक के लिए फलन मान बिल्कुल (0) होना चाहिए।
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यदि ग्राफ केवल (x= -6) पर (x)-अक्ष को काटता है और बाकी जगह अक्ष से दूर रहता है तो शून्यक क्या है?
If a graph cuts the (x)-axis only at (x=-6) and stays away from the axis elsewhere, what is the zero?
#single-zero
#graph-reading
#linear
A (-6)
B (6)
C (0)
D कोई नहीं / None
Explanation opens after your attempt
Step 1
Concept
Only at (x=-6) the value of (y) is (0). Hence the zero is (-6).
Step 2
Why this answer is correct
The correct answer is A. (-6). Only at (x=-6) the value of (y) is (0). Hence the zero is (-6).
Step 3
Exam Tip
केवल (x=-6) पर (y=0) है। इसलिए शून्यक (-6) है।
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किसी बहुपद का ग्राफ (x)-अक्ष को ((-9,0)), ((-1,0)) और ((4,0)) पर काटता है। सबसे बड़ा शून्यक कौन सा है?
A polynomial graph cuts the (x)-axis at ((-9,0)), ((-1,0)) and ((4,0)). Which is the greatest zero?
#compare zeroes graph
A (-9)
B (-1)
C (4)
D (0)
Explanation opens after your attempt
Step 1
Concept
The zeroes are (-9), (-1), (4) and the greatest is (4). Tip: the value to the right on the number line is greater.
Step 2
Why this answer is correct
The correct answer is C. (4). The zeroes are (-9), (-1), (4) and the greatest is (4). Tip: the value to the right on the number line is greater.
Step 3
Exam Tip
शून्यक (-9), (-1), (4) हैं और सबसे बड़ा (4) है। टिप: संख्या रेखा पर दाईं ओर वाला मान बड़ा होता है।
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यदि ग्राफ (x)-अक्ष को ((-3,0)), ((2,0)), ((8,0)) पर काटता है, तो सबसे छोटा शून्यक कौन सा है?
If a graph cuts the (x)-axis at ((-3,0)), ((2,0)), ((8,0)), which is the smallest zero?
#compare zeroes
#three intercepts
#graph
A (-3)
B (2)
C (8)
D (0)
Explanation opens after your attempt
Step 1
Concept
The zeroes are (-3), (2), (8), and the smallest is (-3). Tip: a negative number is smaller than a positive number.
Step 2
Why this answer is correct
The correct answer is A. (-3). The zeroes are (-3), (2), (8), and the smallest is (-3). Tip: a negative number is smaller than a positive number.
Step 3
Exam Tip
शून्यक (-3), (2), (8) हैं और सबसे छोटा (-3) है। टिप: ऋणात्मक संख्या धनात्मक से छोटी होती है।
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यदि रेखा (y=5-x) का आलेख दिया हो तो शून्यक क्या होगा?
If the graph of the line (y=5-x) is given then what is the zero?
#linear equation graph
A (5)
B (-5)
C (0)
D (1)
Explanation opens after your attempt
Step 1
Concept
From (5-x=0) we get (x=5). Tip: take (y) as (0) for the zero.
Step 2
Why this answer is correct
The correct answer is A. (5). From (5-x=0) we get (x=5). Tip: take (y) as (0) for the zero.
Step 3
Exam Tip
(5-x=0) से (x=5) मिलता है। टिप: शून्यक के लिए (y) को (0) मानें।
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अशून्य स्थिर बहुपद (p(x)=5) के आलेख का (x)-अक्ष से संबंध क्या है?
What is the relation of the graph of the non-zero constant polynomial (p(x)=5) with the (x)-axis?
#constant polynomial graph
A यह (x)-अक्ष के समांतर है और उसे नहीं काटता / It is parallel to the (x)-axis and does not cut it
B यह (x)-अक्ष को दो बार काटता है / It cuts the (x)-axis twice
C यह मूल बिंदु से गुजरता है / It passes through the origin
D यह (y)-अक्ष के समांतर है / It is parallel to the (y)-axis
Explanation opens after your attempt
Correct Answer
A. यह (x)-अक्ष के समांतर है और उसे नहीं काटता / It is parallel to the (x)-axis and does not cut it
Step 1
Concept
The value (p(x)=5) is never (0) so it has no zero. Tip: a non-zero constant polynomial has no zero.
Step 2
Why this answer is correct
The correct answer is A. यह (x)-अक्ष के समांतर है और उसे नहीं काटता / It is parallel to the (x)-axis and does not cut it. The value (p(x)=5) is never (0) so it has no zero. Tip: a non-zero constant polynomial has no zero.
Step 3
Exam Tip
(p(x)=5) कभी (0) नहीं होता इसलिए शून्यक नहीं है। टिप: अशून्य स्थिर बहुपद का शून्यक नहीं होता।
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किसी बहुपद (p(x)) का शून्यक आलेख में किससे दर्शाया जाता है?
What represents a zero of a polynomial (p(x)) on its graph?
#polynomials zeroes graph
A जहाँ आलेख (x)-अक्ष को काटता है / Where the graph cuts the (x)-axis
B जहाँ आलेख (y)-अक्ष को काटता है / Where the graph cuts the (y)-axis
C आलेख का सबसे ऊँचा बिंदु / The highest point of the graph
D आलेख का कोई भी बिंदु / Any point on the graph
Explanation opens after your attempt
Correct Answer
A. जहाँ आलेख (x)-अक्ष को काटता है / Where the graph cuts the (x)-axis
Step 1
Concept
At a zero (p(x)=0) so the point lies on the (x)-axis. Tip: on the (x)-axis (y=0).
Step 2
Why this answer is correct
The correct answer is A. जहाँ आलेख (x)-अक्ष को काटता है / Where the graph cuts the (x)-axis. At a zero (p(x)=0) so the point lies on the (x)-axis. Tip: on the (x)-axis (y=0).
Step 3
Exam Tip
शून्यक पर (p(x)=0) होता है इसलिए बिंदु (x)-अक्ष पर होता है। टिप: (x)-अक्ष पर (y=0) होता है।
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यदि (p(x)) का ग्राफ मूल बिंदु से गुजरता है, तो कौन-सा मान शून्यक है?
If the graph of (p(x)) passes through the origin, which value is a zero?
#origin
#zeroes
#graph
#polynomials
A (0)
B (1
C (-1)
D निर्धारित नहीं / Cannot be determined
Explanation opens after your attempt
Step 1
Concept
The origin is ((0,0)), so (p(x)=0) at (x=0). Hence (0) is a zero.
Step 2
Why this answer is correct
The correct answer is A. (0). The origin is ((0,0)), so (p(x)=0) at (x=0). Hence (0) is a zero.
Step 3
Exam Tip
मूल बिंदु ((0,0)) है, इसलिए (x=0) पर (p(x)=0)। अतः (0) शून्यक है।
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यदि ग्राफ ((0,7)) से गुजरता है, तो क्या इससे (0) शून्यक सिद्ध होता है?
If a graph passes through ((0,7)), does it prove that (0) is a zero?
#common-mistake
#y-intercept
#zeroes
#graph
A नहीं, क्योंकि (y=7) है / No, because (y=7)
B हाँ, क्योंकि (x=0) है / Yes, because (x=0)
C हाँ, क्योंकि यह (y)-अक्ष पर है / Yes, because it is on the (y)-axis
D निर्धारित नहीं / Cannot be determined
Explanation opens after your attempt
Correct Answer
A. नहीं, क्योंकि (y=7) है / No, because (y=7)
Step 1
Concept
For a zero, (y=0) is needed. In ((0,7)), (y=7), so (0) is not a zero.
Step 2
Why this answer is correct
The correct answer is A. नहीं, क्योंकि (y=7) है / No, because (y=7). For a zero, (y=0) is needed. In ((0,7)), (y=7), so (0) is not a zero.
Step 3
Exam Tip
शून्यक के लिए (y=0) चाहिए। ((0,7)) में (y=7) है, इसलिए (0) शून्यक नहीं है।
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यदि ग्राफ (x)-अक्ष को ((-4,0)) पर काटता है, तो कौन-सा मान बहुपद को शून्य बनाता है?
If a graph cuts the (x)-axis at ((-4,0)), which value makes the polynomial zero?
#negative-x-intercept
#zeroes
#graph
#easy
A (-4)
B (4)
C (0)
D (1)
Explanation opens after your attempt
Step 1
Concept
The (x)-coordinate of the intersection point is (-4). Therefore the polynomial value is (0) at (x=-4).
Step 2
Why this answer is correct
The correct answer is A. (-4). The (x)-coordinate of the intersection point is (-4). Therefore the polynomial value is (0) at (x=-4).
Step 3
Exam Tip
कटाव बिंदु का (x)-निर्देशांक (-4) है। इसलिए (x=-4) पर बहुपद का मान (0) होगा।
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बहुपद (p(x)) के ग्राफ में (y=p(x)) होता है। शून्यक पर (y) का मान क्या होगा?
In the graph of polynomial (p(x)), (y=p(x)). What is the value of (y) at a zero?
#definition
#y-value
#zeroes
#graph
A (0)
B (1)
C (-1)
D निर्धारित नहीं / Cannot be determined
Explanation opens after your attempt
Step 1
Concept
At a zero, the value of the polynomial is (0). Therefore the (y)-value at that point on the graph is (0).
Step 2
Why this answer is correct
The correct answer is A. (0). At a zero, the value of the polynomial is (0). Therefore the (y)-value at that point on the graph is (0).
Step 3
Exam Tip
शून्यक पर बहुपद का मान (0) होता है। इसलिए ग्राफ पर उस बिंदु का (y)-मान (0) होगा।
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यदि (p(a)=0) और (p(b)=0), जहाँ \(a\neq b\), तो आलेख (x)-अक्ष को किन बिंदुओं पर काटेगा?
If (p(a)=0) and (p(b)=0), where \(a\neq b\), at which points will the graph cut the (x)-axis?
#function value
#zero point
#graph
A ((0,a)) और ((0,b)) / ((0,a)) and ((0,b))
B ((a,b)) और ((b,a)) / ((a,b)) and ((b,a))
C ((a,0)) और ((b,0)) / ((a,0)) and ((b,0))
D ((a,a)) और ((b,b)) / ((a,a)) and ((b,b))
Explanation opens after your attempt
Correct Answer
C. ((a,0)) और ((b,0)) / ((a,0)) and ((b,0))
Step 1
Concept
The value (p(a)=0) gives the point ((a,0)). Tip: (p(x)) is the (y)-coordinate on the graph.
Step 2
Why this answer is correct
The correct answer is C. ((a,0)) और ((b,0)) / ((a,0)) and ((b,0)). The value (p(a)=0) gives the point ((a,0)). Tip: (p(x)) is the (y)-coordinate on the graph.
Step 3
Exam Tip
(p(a)=0) का बिंदु ((a,0)) होता है। टिप: (p(x)) ग्राफ में (y)-निर्देशांक होता है।
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यदि किसी ग्राफ के लिए (p(-3)<0), (p(1)=0), और (p(4)>0) है तो निश्चित शून्यक कौन सा है?
If for a graph (p(-3)<0), (p(1)=0), and (p(4)>0), which zero is certain?
#function-values
#zero-identification
#reasoning
A (1)
B (-3)
C (4)
D (-3) और (4) / (-3) and (4)
Explanation opens after your attempt
Step 1
Concept
Only (p(1)=0) directly gives a zero. Positive or negative values are not zeroes.
Step 2
Why this answer is correct
The correct answer is A. (1). Only (p(1)=0) directly gives a zero. Positive or negative values are not zeroes.
Step 3
Exam Tip
केवल (p(1)=0) सीधे शून्यक बताता है। धनात्मक या ऋणात्मक मान शून्यक नहीं होते।
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एक छात्र कहता है कि यदि ग्राफ (y)-अक्ष को ((0,0)) पर काटता है, तो (0) शून्यक नहीं हो सकता क्योंकि यह (y)-अक्ष पर है। सही निर्णय क्या है?
A student says that if a graph cuts the (y)-axis at ((0,0)), then (0) cannot be a zero because it is on the (y)-axis. What is the correct decision?
#origin
#misconception
#zero
A कथन सही है / The statement is correct
B कथन गलत है क्योंकि ((0,0)) (x)-अक्ष पर भी है / The statement is wrong because ((0,0)) is also on the (x)-axis
C कथन सही है क्योंकि (y)-अक्ष पर कोई शून्यक नहीं होता / The statement is correct because no zero lies on the (y)-axis
D निर्धारित नहीं / Cannot be determined
Explanation opens after your attempt
Correct Answer
B. कथन गलत है क्योंकि ((0,0)) (x)-अक्ष पर भी है / The statement is wrong because ((0,0)) is also on the (x)-axis
Step 1
Concept
The origin lies on both axes, so (p(0)=0). Tip: treat ((0,0)) as a special point.
Step 2
Why this answer is correct
The correct answer is B. कथन गलत है क्योंकि ((0,0)) (x)-अक्ष पर भी है / The statement is wrong because ((0,0)) is also on the (x)-axis. The origin lies on both axes, so (p(0)=0). Tip: treat ((0,0)) as a special point.
Step 3
Exam Tip
मूल बिंदु दोनों अक्षों पर होता है, इसलिए (p(0)=0) है। टिप: ((0,0)) को विशेष बिंदु समझें।
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यदि किसी ग्राफ पर ((2,3)) और ((5,0)) हैं तो कौन सा (x)-मान निश्चित शून्यक है?
If ((2,3)) and ((5,0)) lie on a graph, which (x)-value is definitely a zero?
#identify certain zero
A (2)
B (3)
C (5)
D (0)
Explanation opens after your attempt
Step 1
Concept
In ((5,0)), (y=0), so (5) is a zero. Tip: ((2,3)) does not show a zero.
Step 2
Why this answer is correct
The correct answer is C. (5). In ((5,0)), (y=0), so (5) is a zero. Tip: ((2,3)) does not show a zero.
Step 3
Exam Tip
((5,0)) में (y=0) है इसलिए (5) शून्यक है। टिप: ((2,3)) शून्यक नहीं दिखाता।
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यदि ग्राफ (x)-अक्ष को ((-12,0)) और ((-4,0)) पर काटता है तो बड़ा शून्यक कौन सा है?
If a graph cuts the (x)-axis at ((-12,0)) and ((-4,0)), which zero is greater?
#negative zero comparison
A (-12)
B (-4)
C (0)
D (12)
Explanation opens after your attempt
Step 1
Concept
The number (-4) lies to the right of (-12) on the number line. Tip: the less negative number is greater.
Step 2
Why this answer is correct
The correct answer is B. (-4). The number (-4) lies to the right of (-12) on the number line. Tip: the less negative number is greater.
Step 3
Exam Tip
(-4) संख्या रेखा पर (-12) से दाईं ओर है। टिप: कम ऋणात्मक संख्या बड़ी होती है।
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यदि किसी ग्राफ का केवल एक (x)-अक्ष कटान ((-5,0)) है और वह वहाँ पार करता है, तो वास्तविक शून्यक कौन सा है?
If a graph has only one (x)-axis intersection ((-5,0)) and it crosses there, what is the real zero?
#single intercept zero
A (5)
B (-5)
C (0)
D कोई नहीं / None
Explanation opens after your attempt
Step 1
Concept
The (x)-value (-5) of the intersection point is the zero. Tip: do not change the negative sign.
Step 2
Why this answer is correct
The correct answer is B. (-5). The (x)-value (-5) of the intersection point is the zero. Tip: do not change the negative sign.
Step 3
Exam Tip
कटान बिंदु का (x)-मान (-5) शून्यक है। टिप: ऋण चिह्न को न बदलें।
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बहुपद (p(x)=2x-6) का शून्यक आलेख में किस (x)-मान पर दिखेगा?
At which (x)-value will the zero of (p(x)=2x-6) appear on the graph?
#linear zero value
A (3)
B (-3)
C (6)
D (2)
Explanation opens after your attempt
Step 1
Concept
Solving (2x-6=0) gives (x=3). Tip: first put (p(x)=0).
Step 2
Why this answer is correct
The correct answer is A. (3). Solving (2x-6=0) gives (x=3). Tip: first put (p(x)=0).
Step 3
Exam Tip
(2x-6=0) से (x=3) होता है। टिप: पहले (p(x)=0) रखें।
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यदि किसी परवलय का एक ही वास्तविक शून्यक है, तो ग्राफ (x)-अक्ष से कैसे मिलेगा?
If a parabola has exactly one real zero, how will its graph meet the (x)-axis?
#one-real-zero
#parabola
#tangent-case
#easy
A एक बिंदु पर छुएगा / It will touch at one point
B दो बिंदुओं पर काटेगा / It will cut at two points
C कहीं नहीं मिलेगा / It will not meet
D चार बिंदुओं पर काटेगा / It will cut at four points
Explanation opens after your attempt
Correct Answer
A. एक बिंदु पर छुएगा / It will touch at one point
Step 1
Concept
One real zero means the graph meets the (x)-axis at only one point. For a parabola, this is usually the touching case.
Step 2
Why this answer is correct
The correct answer is A. एक बिंदु पर छुएगा / It will touch at one point. One real zero means the graph meets the (x)-axis at only one point. For a parabola, this is usually the touching case.
Step 3
Exam Tip
एक वास्तविक शून्यक का अर्थ है ग्राफ (x)-अक्ष से केवल एक बिंदु पर मिलता है। परवलय में यह सामान्यतः छूने की स्थिति होती है।
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यदि (p(x)=x), तो ग्राफ का शून्यक क्या है?
If (p(x)=x), what is the zero of the graph?
#linear-polynomial
#origin
#zero
#easy
A (0)
B (1)
C (-1)
D कोई नहीं / None
Explanation opens after your attempt
Step 1
Concept
For the zero, (x=0) because (p(x)=x). The graph passes through the origin.
Step 2
Why this answer is correct
The correct answer is A. (0). For the zero, (x=0) because (p(x)=x). The graph passes through the origin.
Step 3
Exam Tip
शून्यक के लिए (x=0) होना चाहिए क्योंकि (p(x)=x)। ग्राफ मूल बिंदु से गुजरता है।
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यदि रेखा (y=x+7) का ग्राफ (x)-अक्ष को काटता है, तो शून्यक क्या होगा?
If the graph of the line (y=x+7) cuts the (x)-axis, what is the zero?
#linear-polynomial
#zero
#x-intercept
#easy
A (7)
B (-7)
C (0)
D (1)
Explanation opens after your attempt
Step 1
Concept
On the (x)-axis, (y=0), so (x+7=0) gives (x=-7). Watch the negative sign carefully.
Step 2
Why this answer is correct
The correct answer is B. (-7). On the (x)-axis, (y=0), so (x+7=0) gives (x=-7). Watch the negative sign carefully.
Step 3
Exam Tip
(x)-अक्ष पर (y=0), इसलिए (x+7=0) से (x=-7) मिलता है। ऋण चिह्न को ध्यान से देखें।
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यदि (p(x)=x+2) का ग्राफ (x)-अक्ष को काटता है, तो शून्यक कौन-सा है?
If the graph of (p(x)=x+2) cuts the (x)-axis, which is the zero?
#linear-polynomial
#negative-zero
#x-intercept
#easy
A (2)
B (-2)
C (0)
D (1)
Explanation opens after your attempt
Step 1
Concept
For the zero, (x+2=0), so (x=-2). The graph cuts the (x)-axis at (x=-2).
Step 2
Why this answer is correct
The correct answer is B. (-2). For the zero, (x+2=0), so (x=-2). The graph cuts the (x)-axis at (x=-2).
Step 3
Exam Tip
शून्यक के लिए (x+2=0), इसलिए (x=-2)। ग्राफ (x)-अक्ष को (x=-2) पर काटेगा।
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यदि (p(x)=x-4) का ग्राफ (x)-अक्ष को काटता है, तो शून्यक क्या होगा?
If the graph of (p(x)=x-4) cuts the (x)-axis, what is the zero?
#linear-polynomial
#zero
#graphical-meaning
#class-10
A (4)
B (-4)
C (0)
D (1)
Explanation opens after your attempt
Step 1
Concept
For the zero, (x-4=0), so (x=4). The graph also cuts the (x)-axis at (x=4).
Step 2
Why this answer is correct
The correct answer is A. (4). For the zero, (x-4=0), so (x=4). The graph also cuts the (x)-axis at (x=4).
Step 3
Exam Tip
शून्यक के लिए (x-4=0), इसलिए (x=4)। ग्राफ भी (x)-अक्ष को (x=4) पर काटेगा।
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यदि ग्राफ (x)-अक्ष को ((0,0)) पर काटता है, तो बहुपद का एक शून्यक क्या होगा?
If a graph cuts the (x)-axis at ((0,0)), what is one zero of the polynomial?
#origin
#zero-of-polynomial
#x-intercept
#easy
A (0)
B (1)
C (-1)
D निर्धारित नहीं / Cannot be determined
Explanation opens after your attempt
Step 1
Concept
The (x)-coordinate of ((0,0)) is (0). Therefore (0) is one zero of the polynomial.
Step 2
Why this answer is correct
The correct answer is A. (0). The (x)-coordinate of ((0,0)) is (0). Therefore (0) is one zero of the polynomial.
Step 3
Exam Tip
बिंदु ((0,0)) का (x)-निर्देशांक (0) है। इसलिए (0) बहुपद का एक शून्यक होगा।
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ग्राफ में यदि दो रेखाएं केवल एक बिंदु पर कटें तो हल-प्रकार क्या है?
If two lines intersect at exactly one point in a graph then what is the solution type?
#linear equations
#graph
#one solution
A कोई हल नहीं / No solution
B एक अद्वितीय हल / One unique solution
C अनंत हल / Infinitely many solutions
D असंगत / Inconsistent
Explanation opens after your attempt
Correct Answer
B. एक अद्वितीय हल / One unique solution
Step 1
Concept
One intersection point is the common solution of both equations. Therefore exactly one unique solution is obtained.
Step 2
Why this answer is correct
The correct answer is B. एक अद्वितीय हल / One unique solution. One intersection point is the common solution of both equations. Therefore exactly one unique solution is obtained.
Step 3
Exam Tip
कटने का एक बिंदु दोनों समीकरणों का सामान्य हल होता है। इसलिए केवल एक अद्वितीय हल मिलता है।
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ग्राफ में यदि दो रेखाएं केवल एक बिंदु पर मिलें तो युग्म कैसा है?
If two lines meet only at one point in a graph then what type of pair is it?
#linear equations
#consistent independent
#graph
A संगत और स्वतंत्र / Consistent and independent
B असंगत / Inconsistent
C संगत और आश्रित / Consistent and dependent
D संपाती / Coincident
Explanation opens after your attempt
Correct Answer
A. संगत और स्वतंत्र / Consistent and independent
Step 1
Concept
One common point gives one unique solution. Therefore it is a consistent and independent pair.
Step 2
Why this answer is correct
The correct answer is A. संगत और स्वतंत्र / Consistent and independent. One common point gives one unique solution. Therefore it is a consistent and independent pair.
Step 3
Exam Tip
एक सामान्य बिंदु होने से एक अद्वितीय हल मिलता है। इसलिए यह संगत और स्वतंत्र युग्म है।
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यदि ग्राफ पर प्रतिच्छेद बिंदु (\left\(-\frac{7}{3},\frac{2}{3}\right\)) है, तो (x-y) का मान क्या होगा?
If the intersection point on the graph is (\left\(-\frac{7}{3},\frac{2}{3}\right\)), what will be the value of (x-y)?
#graph reading
#fraction coordinates
#application
A (-3)
B (3)
C \(-\frac{5}{3}\)
D \(-\frac{9}{6}\)
Explanation opens after your attempt
Step 1
Concept
Here \(x-y=-\frac{7}{3}-\frac{2}{3}=-3\). Values of (x) and (y) are read directly from the intersection point.
Step 2
Why this answer is correct
The correct answer is A. (-3). Here \(x-y=-\frac{7}{3}-\frac{2}{3}=-3\). Values of (x) and (y) are read directly from the intersection point.
Step 3
Exam Tip
यहाँ \(x-y=-\frac{7}{3}-\frac{2}{3}=-3\)। प्रतिच्छेद बिंदु से (x) और (y) के मान सीधे पढ़े जाते हैं।
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यदि ग्राफ में प्रतिच्छेद बिंदु (\left\(3.75,-2.5\right\)) पढ़ा गया है, तो भिन्न रूप क्या होगा?
If the intersection point is read as (\left\(3.75,-2.5\right\)) on a graph, what is its fraction form?
#decimal coordinates
#fraction form
#graph reading
A (\left\(\frac{15}{4},-\frac{5}{2}\right\))
B (\left\(\frac{5}{2},-\frac{15}{4}\right\))
C (\left\(\frac{375}{10},-\frac{25}{10}\right\))
D (\left\(-\frac{15}{4},\frac{5}{2}\right\))
Explanation opens after your attempt
Correct Answer
A. (\left\(\frac{15}{4},-\frac{5}{2}\right\))
Step 1
Concept
\(3.75=\frac{15}{4}\) and \(-2.5=-\frac{5}{2}\). It is better to convert decimal coordinates into simplified fractions.
Step 2
Why this answer is correct
The correct answer is A. (\left\(\frac{15}{4},-\frac{5}{2}\right\)). \(3.75=\frac{15}{4}\) and \(-2.5=-\frac{5}{2}\). It is better to convert decimal coordinates into simplified fractions.
Step 3
Exam Tip
\(3.75=\frac{15}{4}\) और \(-2.5=-\frac{5}{2}\)। दशमलव निर्देशांक को सरल भिन्न में बदलना बेहतर रहता है।
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यदि ग्राफ पर प्रतिच्छेद बिंदु (\left\(-\frac{5}{2},3\right\)) है, तो सही हल क्या है?
If the intersection point on the graph is (\left\(-\frac{5}{2},3\right\)), what is the correct solution?
#graph reading
#negative fraction
#coordinates
A \(x=3,\ y=-\frac{5}{2}\)
B \(x=-\frac{5}{2},\ y=3\)
C \(x=\frac{5}{2},\ y=-3\)
D \(x=-3,\ y=\frac{5}{2}\)
Explanation opens after your attempt
Correct Answer
B. \(x=-\frac{5}{2},\ y=3\)
Step 1
Concept
The first coordinate of a point is (x) and the second is (y). Do not change order while reading negative fraction coordinates.
Step 2
Why this answer is correct
The correct answer is B. \(x=-\frac{5}{2},\ y=3\). The first coordinate of a point is (x) and the second is (y). Do not change order while reading negative fraction coordinates.
Step 3
Exam Tip
बिंदु में पहला निर्देशांक (x) और दूसरा (y) होता है। ऋण भिन्न निर्देशांक पढ़ते समय क्रम न बदलें।
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यदि ग्राफ में प्रतिच्छेद बिंदु (\left\(2.25,-1.5\right\)) पढ़ा गया है, तो भिन्न रूप क्या होगा?
If the intersection point is read as (\left\(2.25,-1.5\right\)) on a graph, what is its fraction form?
#decimal coordinates
#fraction form
#graph reading
A (\left\(\frac{9}{4},-\frac{3}{2}\right\))
B (\left\(\frac{3}{2},-\frac{9}{4}\right\))
C (\left\(\frac{225}{10},-\frac{15}{10}\right\))
D (\left\(-\frac{9}{4},\frac{3}{2}\right\))
Explanation opens after your attempt
Correct Answer
A. (\left\(\frac{9}{4},-\frac{3}{2}\right\))
Step 1
Concept
\(2.25=\frac{9}{4}\) and \(-1.5=-\frac{3}{2}\). It is better to convert decimal coordinates into simplified fractions.
Step 2
Why this answer is correct
The correct answer is A. (\left\(\frac{9}{4},-\frac{3}{2}\right\)). \(2.25=\frac{9}{4}\) and \(-1.5=-\frac{3}{2}\). It is better to convert decimal coordinates into simplified fractions.
Step 3
Exam Tip
\(2.25=\frac{9}{4}\) और \(-1.5=-\frac{3}{2}\)। दशमलव निर्देशांक को सरल भिन्न में बदलना बेहतर रहता है।
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यदि ग्राफ पर प्रतिच्छेद बिंदु (\left\(-\frac{3}{2},4\right\)) है, तो सही हल क्या है?
If the intersection point on the graph is (\left\(-\frac{3}{2},4\right\)), what is the correct solution?
#graph reading
#negative fraction
#coordinates
A \(x=4,\ y=-\frac{3}{2}\)
B \(x=-\frac{3}{2},\ y=4\)
C \(x=\frac{3}{2},\ y=-4\)
D \(x=-4,\ y=\frac{3}{2}\)
Explanation opens after your attempt
Correct Answer
B. \(x=-\frac{3}{2},\ y=4\)
Step 1
Concept
The first coordinate of a point is (x) and the second is (y). Do not change order while reading negative fraction coordinates.
Step 2
Why this answer is correct
The correct answer is B. \(x=-\frac{3}{2},\ y=4\). The first coordinate of a point is (x) and the second is (y). Do not change order while reading negative fraction coordinates.
Step 3
Exam Tip
बिंदु में पहला निर्देशांक (x) और दूसरा (y) होता है। ऋण भिन्न निर्देशांक पढ़ते समय क्रम न बदलें।
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यदि ग्राफ पर प्रतिच्छेद बिंदु (\left\(\frac{7}{2},\frac{5}{2}\right\)) है, तो दशमलव रूप क्या होगा?
If the intersection point on the graph is (\left\(\frac{7}{2},\frac{5}{2}\right\)), what is its decimal form?
#fraction coordinates
#decimal form
#graph reading
A बिंदु (\left\(3.5,2.5\right\)) / Point (\left\(3.5,2.5\right\))
B बिंदु (\left\(2.5,3.5\right\)) / Point (\left\(2.5,3.5\right\))
C बिंदु (\left\(7.2,5.2\right\)) / Point (\left\(7.2,5.2\right\))
D बिंदु (\left\(0.7,0.5\right\)) / Point (\left\(0.7,0.5\right\))
Explanation opens after your attempt
Correct Answer
A. बिंदु (\left\(3.5,2.5\right\)) / Point (\left\(3.5,2.5\right\))
Step 1
Concept
\(\frac{7}{2}=3.5\) and \(\frac{5}{2}=2.5\). While reading a graph, understand the relation between fraction and decimal forms.
Step 2
Why this answer is correct
The correct answer is A. बिंदु (\left\(3.5,2.5\right\)) / Point (\left\(3.5,2.5\right\)). \(\frac{7}{2}=3.5\) and \(\frac{5}{2}=2.5\). While reading a graph, understand the relation between fraction and decimal forms.
Step 3
Exam Tip
\(\frac{7}{2}=3.5\) और \(\frac{5}{2}=2.5\)। ग्राफ पढ़ते समय भिन्न और दशमलव रूप का संबंध समझें।
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यदि ग्राफ में प्रतिच्छेद बिंदु (\left\(4.5,1.5\right\)) पढ़ा गया है, तो इसे भिन्न में कैसे लिखेंगे?
If the intersection point is read as (\left\(4.5,1.5\right\)) on a graph, how will it be written in fractions?
#decimal coordinates
#fraction
#graph reading
A (\left\(\frac{9}{2},\frac{3}{2}\right\))
B (\left\(\frac{3}{2},\frac{9}{2}\right\))
C (\left\(\frac{45}{100},\frac{15}{100}\right\))
D (\left\(\frac{4}{5},\frac{1}{5}\right\))
Explanation opens after your attempt
Correct Answer
A. (\left\(\frac{9}{2},\frac{3}{2}\right\))
Step 1
Concept
\(4.5=\frac{9}{2}\) and \(1.5=\frac{3}{2}\). Write decimal coordinates read from a graph as simplified fractions.
Step 2
Why this answer is correct
The correct answer is A. (\left\(\frac{9}{2},\frac{3}{2}\right\)). \(4.5=\frac{9}{2}\) and \(1.5=\frac{3}{2}\). Write decimal coordinates read from a graph as simplified fractions.
Step 3
Exam Tip
\(4.5=\frac{9}{2}\) और \(1.5=\frac{3}{2}\)। ग्राफ से मिले दशमलव निर्देशांक को सरल भिन्न में लिखें।
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यदि ग्राफ पर प्रतिच्छेद बिंदु (\left\(-4,3\right\)) है, तो सही हल क्या है?
If the intersection point on the graph is (\left\(-4,3\right\)), what is the correct solution?
#negative coordinates
#graph reading
#solution
A (x=-4,\ y=3)
B (x=3,\ y=-4)
C (x=4,\ y=-3)
D (x=-3,\ y=4)
Explanation opens after your attempt
Correct Answer
A. (x=-4,\ y=3)
Step 1
Concept
In the point (\left\(-4,3\right\)), the first coordinate is (x) and the second is (y). Do not change order with negative coordinates.
Step 2
Why this answer is correct
The correct answer is A. (x=-4,\ y=3). In the point (\left\(-4,3\right\)), the first coordinate is (x) and the second is (y). Do not change order with negative coordinates.
Step 3
Exam Tip
बिंदु (\left\(-4,3\right\)) में पहला निर्देशांक (x) और दूसरा (y) होता है। ऋण निर्देशांक में क्रम न बदलें।
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यदि ग्राफ में प्रतिच्छेद बिंदु ( \left\(3.5,2.5\right\) ) पढ़ा गया है, तो इसे भिन्न में कैसे लिखेंगे?
If the intersection point is read as ( \left\(3.5,2.5\right\) ) on a graph, how will it be written in fractions?
#decimal coordinates
#fraction
#graph reading
A ( \left\(\frac{7}{2},\frac{5}{2}\right\) )
B ( \left\(\frac{5}{2},\frac{7}{2}\right\) )
C ( \left\(\frac{35}{100},\frac{25}{100}\right\) )
D ( \left\(\frac{3}{5},\frac{2}{5}\right\) )
Explanation opens after your attempt
Correct Answer
A. ( \left\(\frac{7}{2},\frac{5}{2}\right\) )
Step 1
Concept
\(3.5=\frac{7}{2}\) and \(2.5=\frac{5}{2}\). Write decimal coordinates read from a graph as simplified fractions.
Step 2
Why this answer is correct
The correct answer is A. ( \left\(\frac{7}{2},\frac{5}{2}\right\) ). \(3.5=\frac{7}{2}\) and \(2.5=\frac{5}{2}\). Write decimal coordinates read from a graph as simplified fractions.
Step 3
Exam Tip
\(3.5=\frac{7}{2}\) और \(2.5=\frac{5}{2}\)। ग्राफ से मिले दशमलव निर्देशांक को सरल भिन्न में लिखें।
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यदि ग्राफ में प्रतिच्छेद बिंदु ( \left\(2.5,1.5\right\) ) पढ़ा गया है, तो हल को भिन्न में कैसे लिखेंगे?
If the intersection point is read as ( \left\(2.5,1.5\right\) ) on a graph, how will the solution be written in fractions?
#decimal coordinates
#fraction
#graph reading
A ( \left\(\frac{5}{2},\frac{3}{2}\right\) )
B ( \left\(\frac{3}{2},\frac{5}{2}\right\) )
C ( \left\(\frac{25}{10},\frac{15}{100}\right\) )
D ( \left\(\frac{2}{5},\frac{1}{5}\right\) )
Explanation opens after your attempt
Correct Answer
A. ( \left\(\frac{5}{2},\frac{3}{2}\right\) )
Step 1
Concept
\(2.5=\frac{5}{2}\) and \(1.5=\frac{3}{2}\). When reading decimals from a graph, write them as simplified fractions.
Step 2
Why this answer is correct
The correct answer is A. ( \left\(\frac{5}{2},\frac{3}{2}\right\) ). \(2.5=\frac{5}{2}\) and \(1.5=\frac{3}{2}\). When reading decimals from a graph, write them as simplified fractions.
Step 3
Exam Tip
\(2.5=\frac{5}{2}\) और \(1.5=\frac{3}{2}\)। ग्राफ से दशमलव बिंदु पढ़ने पर सरल भिन्न में लिखें।
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यदि ग्राफ पर प्रतिच्छेद बिंदु ( (15,2) ) है, तो (x) का मान क्या है?
If the intersection point on the graph is ( (15,2) ), what is the value of (x)?
#coordinates
#graphical solution
#graph reading
A (2)
B (13)
C (17)
D (15)
Explanation opens after your attempt
Step 1
Concept
In the point ( (15,2) ), the first coordinate is (x). Therefore, (x=15).
Step 2
Why this answer is correct
The correct answer is D. (15). In the point ( (15,2) ), the first coordinate is (x). Therefore, (x=15).
Step 3
Exam Tip
बिंदु ( (15,2) ) में पहला निर्देशांक (x) होता है। इसलिए (x=15) है।
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यदि ग्राफ पर प्रतिच्छेद बिंदु ( (7,13) ) है, तो (y) का मान क्या है?
If the intersection point on the graph is ( (7,13) ), what is the value of (y)?
#coordinates
#graph reading
#solution
A (7)
B (20)
C (13)
D (6)
Explanation opens after your attempt
Step 1
Concept
In the point ( (7,13) ), the second coordinate is (y). Therefore, (y=13).
Step 2
Why this answer is correct
The correct answer is C. (13). In the point ( (7,13) ), the second coordinate is (y). Therefore, (y=13).
Step 3
Exam Tip
बिंदु ( (7,13) ) में दूसरा निर्देशांक (y) होता है। इसलिए (y=13) है।
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ग्राफ पर दो रेखाएँ एक ही बिंदु पर कटें, तो युग्म कैसा कहलाता है?
If two lines cut at exactly one point on a graph, what is the pair called?
#consistent independent
#unique solution
#graph
A असंगत / Inconsistent
B संगत और आश्रित / Consistent and dependent
C संगत और स्वतंत्र / Consistent and independent
D संपाती / Coincident
Explanation opens after your attempt
Correct Answer
C. संगत और स्वतंत्र / Consistent and independent
Step 1
Concept
One intersection point gives a unique solution. Hence, the pair is consistent and independent.
Step 2
Why this answer is correct
The correct answer is C. संगत और स्वतंत्र / Consistent and independent. One intersection point gives a unique solution. Hence, the pair is consistent and independent.
Step 3
Exam Tip
एक प्रतिच्छेद बिंदु एक अद्वितीय हल देता है। इसलिए युग्म संगत और स्वतंत्र होता है।
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यदि ग्राफ पर प्रतिच्छेद बिंदु ( (12,1) ) है, तो (x) का मान क्या है?
If the intersection point on the graph is ( (12,1) ), what is the value of (x)?
#coordinates
#graphical solution
#graph reading
A (1)
B (11)
C (13)
D (12)
Explanation opens after your attempt
Step 1
Concept
In the point ( (12,1) ), the first coordinate is (x). Therefore, (x=12).
Step 2
Why this answer is correct
The correct answer is D. (12). In the point ( (12,1) ), the first coordinate is (x). Therefore, (x=12).
Step 3
Exam Tip
बिंदु ( (12,1) ) में पहला निर्देशांक (x) होता है। इसलिए (x=12) है।
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यदि ग्राफ पर प्रतिच्छेद बिंदु ( (3,10) ) है, तो (y) का मान क्या है?
If the intersection point on the graph is ( (3,10) ), what is the value of (y)?
#coordinates
#graph reading
#solution
A (3)
B (13)
C (10)
D (7)
Explanation opens after your attempt
Step 1
Concept
In the point ( (3,10) ), the second coordinate is (y). Therefore, (y=10).
Step 2
Why this answer is correct
The correct answer is C. (10). In the point ( (3,10) ), the second coordinate is (y). Therefore, (y=10).
Step 3
Exam Tip
बिंदु ( (3,10) ) में दूसरा निर्देशांक (y) होता है। इसलिए (y=10) है।
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