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Which point lies on \(2x+5y=27\) but not on \(x+y=9\)?
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Answer and explanation
Correct answer: Point \(\left(1,5\right)\)
At \(\left(1,5\right)\), \(2\left(1\right)+5\left(5\right)=27\), but \(1+5=6\). To be a common solution, both equations must be true.
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What is the correct answer to this question?
Point \(\left(1,5\right)\)
Why is this the correct answer?
At \(\left(1,5\right)\), \(2\left(1\right)+5\left(5\right)=27\), but \(1+5=6\). To be a common solution, both equations must be true.
Which subject and chapter does this question cover?
This is a Class 10 Mathematics question. Chapter: Pair of Linear Equations in Two Variables. Topic: Graphical method of finding solutions..
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