व्यंजक \(0x^9+6x^5-4x^2+3\) की डिग्री क्या है?
What is the degree of \(0x^9+6x^5-4x^2+3\)?
#polynomial
#degree
#zero_coefficient
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A (9)
B (5)
C (2)
D (0)
Explanation opens after your attempt
Step 1
Concept
\(0x^9\) is a zero term. The remaining highest power is (5).
Step 2
Why this answer is correct
The correct answer is B. (5). \(0x^9\) is a zero term. The remaining highest power is (5).
Step 3
Exam Tip
\(0x^9\) शून्य पद है। बची हुई सबसे बड़ी घात (5) है।
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व्यंजक ((a+4)x-6 +3x-2 -8) की डिग्री (6) कब होगी?
When will the degree of ((a+4)x-6 +3x-2 -8) be (6)?
#polynomial
#degree
#parameter
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A जब (a=-4) / When (a=-4)
B जब (a=4) / When (a=4)
C जब \(a\neq-4\) / When \(a\neq-4\)
D हर (a) पर / For every (a)
Explanation opens after your attempt
Correct Answer
C. जब \(a\neq-4\) / When \(a\neq-4\)
Step 1
Concept
For degree (6), the coefficient of \(x^6\) must not be zero. So \(a+4\neq0\).
Step 2
Why this answer is correct
The correct answer is C. जब \(a\neq-4\) / When \(a\neq-4\). For degree (6), the coefficient of \(x^6\) must not be zero. So \(a+4\neq0\).
Step 3
Exam Tip
डिग्री (6) के लिए \(x^6\) का गुणांक शून्य नहीं होना चाहिए। इसलिए \(a+4\neq0\) होना चाहिए।
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यदि (k=5), तो ((k-5)x-7 +4x-3 -x+2) की डिग्री क्या होगी?
If (k=5), what will be the degree of ((k-5)x-7 +4x-3 -x+2)?
#polynomial
#parameter_substitution
#degree
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A (7)
B (4)
C (3)
D (1)
Explanation opens after your attempt
Step 1
Concept
Putting (k=5) makes the coefficient of \(x^7\) equal to (0). In the remaining polynomial, the highest power is (3).
Step 2
Why this answer is correct
The correct answer is C. (3). Putting (k=5) makes the coefficient of \(x^7\) equal to (0). In the remaining polynomial, the highest power is (3).
Step 3
Exam Tip
(k=5) रखने पर \(x^7\) का गुणांक (0) हो जाता है। शेष बहुपद में सबसे बड़ी घात (3) है।
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किस मान पर ((m+6)x-4 -2x+9) रेखीय बहुपद बनेगा?
For which value will ((m+6)x-4 -2x+9) become a linear polynomial?
#polynomial
#linear
#parameter
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A (m=6)
B (m=-6)
C (m=0)
D कभी नहीं / Never
Explanation opens after your attempt
Step 1
Concept
To become linear, the coefficient of \(x^4\) must be (0). From (m+6=0), we get (m=-6).
Step 2
Why this answer is correct
The correct answer is B. (m=-6). To become linear, the coefficient of \(x^4\) must be (0). From (m+6=0), we get (m=-6).
Step 3
Exam Tip
रेखीय बनने के लिए \(x^4\) का गुणांक (0) होना चाहिए। (m+6=0) से (m=-6) मिलता है।
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व्यंजक \(3x^2+\sqrt{2x-1}\) बहुपद क्यों नहीं है?
Why is \(3x^2+\sqrt{2x-1}\) not a polynomial?
#polynomial
#radical
#non_polynomial
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A क्योंकि इसमें \(3x^2\) है / Because it has \(3x^2\)
B क्योंकि इसमें दो पद हैं / Because it has two terms
C क्योंकि (2x-1) मूल चिह्न के अंदर है / Because (2x-1) is inside a radical sign
D क्योंकि इसमें (1) है / Because it has (1)
Explanation opens after your attempt
Correct Answer
C. क्योंकि (2x-1) मूल चिह्न के अंदर है / Because (2x-1) is inside a radical sign
Step 1
Concept
\(\sqrt{2x-1}\) is not a term with valid polynomial powers. Therefore the whole expression is not a polynomial.
Step 2
Why this answer is correct
The correct answer is C. क्योंकि (2x-1) मूल चिह्न के अंदर है / Because (2x-1) is inside a radical sign. \(\sqrt{2x-1}\) is not a term with valid polynomial powers. Therefore the whole expression is not a polynomial.
Step 3
Exam Tip
\(\sqrt{2x-1}\) बहुपद की मान्य घातों वाला पद नहीं है। इसलिए पूरा व्यंजक बहुपद नहीं है।
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यदि (p(x)=5x-5 +0x-4 -3x+6), तो \(x^4\) का गुणांक क्या है?
If (p(x)=5x-5 +0x-4 -3x+6), what is the coefficient of \(x^4\)?
#polynomial
#coefficient
#zero_coefficient
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A (5)
B (4)
C (0)
D (-3)
Explanation opens after your attempt
Step 1
Concept
The term containing \(x^4\) is \(0x^4\). Therefore the coefficient of \(x^4\) is (0).
Step 2
Why this answer is correct
The correct answer is C. (0). The term containing \(x^4\) is \(0x^4\). Therefore the coefficient of \(x^4\) is (0).
Step 3
Exam Tip
\(x^4\) वाला पद \(0x^4\) है। इसलिए \(x^4\) का गुणांक (0) है।
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किस विकल्प में (x) में द्विघात बहुपद है?
Which option is a quadratic polynomial in (x)?
#polynomial
#quadratic
#classification
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A \(3x^2-\pi x+\sqrt{7}\)
B \(x^3+2x^2\)
C \(x^{\frac{1}{2}}+x+1\)
D \(\frac{1}{x}+x^2\)
Explanation opens after your attempt
Correct Answer
A. \(3x^2-\pi x+\sqrt{7}\)
Step 1
Concept
In the first expression, the highest power is (2), and all powers are valid. So it is a quadratic polynomial.
Step 2
Why this answer is correct
The correct answer is A. \(3x^2-\pi x+\sqrt{7}\). In the first expression, the highest power is (2), and all powers are valid. So it is a quadratic polynomial.
Step 3
Exam Tip
पहले व्यंजक में सबसे बड़ी घात (2) है और सभी घातें मान्य हैं। इसलिए यह द्विघात बहुपद है।
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व्यंजक \(\frac{x^5+3x^2}{x^2}\) मूल रूप में बहुपद क्यों नहीं माना जाता?
Why is \(\frac{x^5+3x^2}{x^2}\) not considered a polynomial in its original form?
#polynomial
#rational_expression
#domain
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A क्योंकि चर हर में है / Because the variable is in the denominator
B क्योंकि इसमें \(x^5\) है / Because it has \(x^5\)
C क्योंकि इसमें \(3x^2\) है / Because it has \(3x^2\)
D क्योंकि इसमें जोड़ है / Because it has addition
Explanation opens after your attempt
Correct Answer
A. क्योंकि चर हर में है / Because the variable is in the denominator
Step 1
Concept
In the original form, \(x^2\) is in the denominator. While simplifying to polynomial form, the domain condition must also be considered.
Step 2
Why this answer is correct
The correct answer is A. क्योंकि चर हर में है / Because the variable is in the denominator. In the original form, \(x^2\) is in the denominator. While simplifying to polynomial form, the domain condition must also be considered.
Step 3
Exam Tip
मूल रूप में हर में \(x^2\) है। बहुपद रूप के लिए सरल करते समय डोमेन शर्त भी ध्यान रखनी होती है।
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\(\frac{x^5+3x^2}{x^2}\) को \(x\neq0\) पर सरल करने से क्या मिलेगा?
What is obtained by simplifying \(\frac{x^5+3x^2}{x^2}\) for \(x\neq0\)?
#polynomial
#simplification
#domain_note
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A \(x^3+3\)
B \(x^5+3\)
C \(x^3+3x^2\)
D \(x^2+3\)
Explanation opens after your attempt
Correct Answer
A. \(x^3+3\)
Step 1
Concept
For \(x\neq0\), \(\frac{x^5}{x^2}=x^3\) and \(\frac{3x^2}{x^2}=3\). So the simplified form is \(x^3+3\).
Step 2
Why this answer is correct
The correct answer is A. \(x^3+3\). For \(x\neq0\), \(\frac{x^5}{x^2}=x^3\) and \(\frac{3x^2}{x^2}=3\). So the simplified form is \(x^3+3\).
Step 3
Exam Tip
\(x\neq0\) पर \(\frac{x^5}{x^2}=x^3\) और \(\frac{3x^2}{x^2}=3\) होता है। इसलिए सरल रूप \(x^3+3\) है।
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सरल रूप \(x^3+3\) की डिग्री क्या है?
What is the degree of the simplified form \(x^3+3\)?
#polynomial
#degree
#simplified_form
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A (0)
B (1)
C (3)
D (5)
Explanation opens after your attempt
Step 1
Concept
In \(x^3+3\), the highest power is (3). Therefore its degree is (3).
Step 2
Why this answer is correct
The correct answer is C. (3). In \(x^3+3\), the highest power is (3). Therefore its degree is (3).
Step 3
Exam Tip
\(x^3+3\) में सबसे बड़ी घात (3) है। इसलिए इसकी डिग्री (3) है।
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व्यंजक \(4x^2-5|x|+8\) बहुपद है या नहीं?
Is \(4x^2-5|x|+8\) a polynomial or not?
#polynomial
#absolute_value
#non_polynomial
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A हां क्योंकि इसमें \(x^2\) है / Yes because it has \(x^2\)
B हां क्योंकि इसमें नियतांक है / Yes because it has a constant
C नहीं क्योंकि (|x|) बहुपद पद नहीं है / No because (|x|) is not a polynomial term
D हां क्योंकि इसमें तीन पद हैं / Yes because it has three terms
Explanation opens after your attempt
Correct Answer
C. नहीं क्योंकि (|x|) बहुपद पद नहीं है / No because (|x|) is not a polynomial term
Step 1
Concept
(|x|) is not written as a term with non-negative integer powers of (x). Therefore it is not a polynomial.
Step 2
Why this answer is correct
The correct answer is C. नहीं क्योंकि (|x|) बहुपद पद नहीं है / No because (|x|) is not a polynomial term. (|x|) is not written as a term with non-negative integer powers of (x). Therefore it is not a polynomial.
Step 3
Exam Tip
(|x|) को (x) की अऋणात्मक पूर्णांक घातों वाले पद की तरह नहीं लिखा जाता। इसलिए यह बहुपद नहीं है।
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यदि \(a\neq0\) और (b=0), तो \(ax^8+bx^6-5x+2\) की डिग्री क्या होगी?
If \(a\neq0\) and (b=0), what will be the degree of \(ax^8+bx^6-5x+2\)?
#polynomial
#degree
#parameters
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A (8)
B (6)
C (1)
D (0)
Explanation opens after your attempt
Step 1
Concept
Since \(a\neq0\), the \(x^8\) term remains present. Therefore the highest power is (8).
Step 2
Why this answer is correct
The correct answer is A. (8). Since \(a\neq0\), the \(x^8\) term remains present. Therefore the highest power is (8).
Step 3
Exam Tip
\(a\neq0\) होने से \(x^8\) पद मौजूद रहेगा। इसलिए सबसे बड़ी घात (8) है।
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यदि (a=0) और \(b\neq0\), तो \(ax^8+bx^6-5x+2\) की डिग्री क्या होगी?
If (a=0) and \(b\neq0\), what will be the degree of \(ax^8+bx^6-5x+2\)?
#polynomial
#degree
#parameter_case
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A (8)
B (6)
C (1)
D (0)
Explanation opens after your attempt
Step 1
Concept
When (a=0), the \(x^8\) term disappears. Since \(b\neq0\), the \(x^6\) term remains present.
Step 2
Why this answer is correct
The correct answer is B. (6). When (a=0), the \(x^8\) term disappears. Since \(b\neq0\), the \(x^6\) term remains present.
Step 3
Exam Tip
(a=0) होने से \(x^8\) पद हट जाता है। \(b\neq0\) होने से \(x^6\) पद मौजूद रहता है।
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व्यंजक (\(t^2-9\)x-3 +6x+1) रेखीय बहुपद कब बनेगा?
When will (\(t^2-9\)x-3 +6x+1) become a linear polynomial?
#polynomial
#linear
#parameter
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A जब (t=3) या (t=-3) / When (t=3) or (t=-3)
B जब (t=0) / When (t=0)
C जब (t=9) / When (t=9)
D कभी नहीं / Never
Explanation opens after your attempt
Correct Answer
A. जब (t=3) या (t=-3) / When (t=3) or (t=-3)
Step 1
Concept
To become linear, the coefficient of \(x^3\) must be (0). From \(t^2-9=0\), we get \(t=\pm3\).
Step 2
Why this answer is correct
The correct answer is A. जब (t=3) या (t=-3) / When (t=3) or (t=-3). To become linear, the coefficient of \(x^3\) must be (0). From \(t^2-9=0\), we get \(t=\pm3\).
Step 3
Exam Tip
रेखीय बनने के लिए \(x^3\) का गुणांक (0) होना चाहिए। \(t^2-9=0\) से \(t=\pm3\) मिलता है।
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व्यंजक ((r+4)x-2 +(r-1)x+10) नियतांक बहुपद कब बनेगा?
When will ((r+4)x-2 +(r-1)x+10) become a constant polynomial?
#polynomial
#constant_polynomial
#parameter
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A जब (r=-4) / When (r=-4)
B जब (r=1) / When (r=1)
C जब (r=-4) और (r=1) साथ-साथ / When (r=-4) and (r=1) together
D कभी नहीं / Never
Explanation opens after your attempt
Correct Answer
D. कभी नहीं / Never
Step 1
Concept
To become constant, both (r+4=0) and (r-1=0) are required. One value of (r) cannot satisfy both conditions.
Step 2
Why this answer is correct
The correct answer is D. कभी नहीं / Never. To become constant, both (r+4=0) and (r-1=0) are required. One value of (r) cannot satisfy both conditions.
Step 3
Exam Tip
नियतांक बनने के लिए (r+4=0) और (r-1=0) दोनों चाहिए। एक ही (r) दोनों शर्तें पूरी नहीं कर सकता।
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कौन सा व्यंजक (x) में बहुपद है जबकि (y) गुणांक की तरह माना गया है?
Which expression is a polynomial in (x) while (y) is treated as a coefficient?
#polynomial
#in_x
#parameter_coefficient
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A \(y^2x^3-2yx+5\)
B \(\frac{y}{x}+3\)
C \(\sqrt{x}+y\)
D \(x^{-2}+y\)
Explanation opens after your attempt
Correct Answer
A. \(y^2x^3-2yx+5\)
Step 1
Concept
With respect to (x), \(y^2\) and (-2y) are coefficients. The powers of (x) are (3), (1), and (0).
Step 2
Why this answer is correct
The correct answer is A. \(y^2x^3-2yx+5\). With respect to (x), \(y^2\) and (-2y) are coefficients. The powers of (x) are (3), (1), and (0).
Step 3
Exam Tip
(x) के संदर्भ में \(y^2\) और (-2y) गुणांक हैं। (x) की घातें (3), (1), और (0) हैं।
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बहुपद \(9x^7-2x^5+4\) में \(x^6\), \(x^4\), और (x) के गुणांक क्या हैं?
In \(9x^7-2x^5+4\), what are the coefficients of \(x^6\), \(x^4\), and (x)?
#polynomial
#missing_terms
#coefficients
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A (9), (-2), और (4) / (9), (-2), and (4)
B (0), (0), और (0) / (0), (0), and (0)
C (7), (5), और (1) / (7), (5), and (1)
D (-2), (0), और (4) / (-2), (0), and (4)
Explanation opens after your attempt
Correct Answer
B. (0), (0), और (0) / (0), (0), and (0)
Step 1
Concept
The terms with these three powers are absent. Therefore their coefficients are (0), (0), and (0).
Step 2
Why this answer is correct
The correct answer is B. (0), (0), और (0) / (0), (0), and (0). The terms with these three powers are absent. Therefore their coefficients are (0), (0), and (0).
Step 3
Exam Tip
इन तीनों घातों वाले पद अनुपस्थित हैं। इसलिए इनके गुणांक (0), (0), और (0) हैं।
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यदि (n=-2), तो (\(n^2-4\)x-6 +(n+5)x-3 -7) की डिग्री क्या होगी?
If (n=-2), what will be the degree of (\(n^2-4\)x-6 +(n+5)x-3 -7)?
#polynomial
#degree
#parameter_substitution
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A (6)
B (3)
C (1)
D (0)
Explanation opens after your attempt
Step 1
Concept
Putting (n=-2), the coefficient of \(x^6\) is (0) and the coefficient of \(x^3\) is (3). Therefore the degree is (3).
Step 2
Why this answer is correct
The correct answer is B. (3). Putting (n=-2), the coefficient of \(x^6\) is (0) and the coefficient of \(x^3\) is (3). Therefore the degree is (3).
Step 3
Exam Tip
(n=-2) रखने पर \(x^6\) का गुणांक (0) और \(x^3\) का गुणांक (3) होता है। इसलिए डिग्री (3) है।
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किस विकल्प में डिग्री (5) है और अग्रणी गुणांक ऋणात्मक है?
Which option has degree (5) and a negative leading coefficient?
#polynomial
#degree
#leading_coefficient
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A \(2x^5-3x+1\)
B \(-7x^5+x^2-4\)
C \(-3x^4+2x-1\)
D (9x-5)
Explanation opens after your attempt
Correct Answer
B. \(-7x^5+x^2-4\)
Step 1
Concept
\(-7x^5+x^2-4\) has degree (5) and leading coefficient (-7). Therefore it is the correct option.
Step 2
Why this answer is correct
The correct answer is B. \(-7x^5+x^2-4\). \(-7x^5+x^2-4\) has degree (5) and leading coefficient (-7). Therefore it is the correct option.
Step 3
Exam Tip
\(-7x^5+x^2-4\) की डिग्री (5) है और अग्रणी गुणांक (-7) है। इसलिए यह सही विकल्प है।
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व्यंजक (x-2 \(x^3-4\)-x-5 +7x-2 ) को सरल करने पर क्या मिलेगा?
What is obtained by simplifying (x-2 \(x^3-4\)-x-5 +7x-2 )?
#polynomial
#simplification
#cancellation
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A \(2x^5+3x^2\)
B \(3x^2\)
C \(x^5+3x^2\)
D \(7x^2\)
Explanation opens after your attempt
Correct Answer
B. \(3x^2\)
Step 1
Concept
(x-2 \(x^3-4\)=x-5 -4x-2 ), then \(-x^5\) cancels \(x^5\). The simplified form is \(3x^2\).
Step 2
Why this answer is correct
The correct answer is B. \(3x^2\). (x-2 \(x^3-4\)=x-5 -4x-2 ), then \(-x^5\) cancels \(x^5\). The simplified form is \(3x^2\).
Step 3
Exam Tip
(x-2 \(x^3-4\)=x-5 -4x-2 ), फिर \(-x^5\) से \(x^5\) कट जाता है। सरल रूप \(3x^2\) है।
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सरल रूप \(3x^2\) किस प्रकार का बहुपद है?
What type of polynomial is the simplified form \(3x^2\)?
#polynomial
#quadratic
#monomial
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A रेखीय बहुपद / Linear polynomial
B द्विघात एकपदी बहुपद / Quadratic monomial polynomial
C त्रिघात बहुपद / Cubic polynomial
D नियतांक बहुपद / Constant polynomial
Explanation opens after your attempt
Correct Answer
B. द्विघात एकपदी बहुपद / Quadratic monomial polynomial
Step 1
Concept
\(3x^2\) has one term and the highest power is (2). So it is a quadratic monomial polynomial.
Step 2
Why this answer is correct
The correct answer is B. द्विघात एकपदी बहुपद / Quadratic monomial polynomial. \(3x^2\) has one term and the highest power is (2). So it is a quadratic monomial polynomial.
Step 3
Exam Tip
\(3x^2\) में एक पद है और सबसे बड़ी घात (2) है। इसलिए यह द्विघात एकपदी बहुपद है।
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कौन सा निष्कर्ष \(x^0-\sqrt{5}x^4+\frac{3x}{8}\) के लिए सही है?
Which conclusion is correct for \(x^0-\sqrt{5}x^4+\frac{3x}{8}\)?
#polynomial
#real_coefficients
#degree
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A यह बहुपद नहीं है क्योंकि इसमें \(\sqrt{5}\) है / It is not a polynomial because it has \(\sqrt{5}\)
B यह बहुपद है और डिग्री (4) है / It is a polynomial and degree is (4)
C यह शून्य बहुपद है / It is the zero polynomial
D यह बहुपद नहीं है क्योंकि इसमें भिन्न गुणांक है / It is not a polynomial because it has a fractional coefficient
Explanation opens after your attempt
Correct Answer
B. यह बहुपद है और डिग्री (4) है / It is a polynomial and degree is (4)
Step 1
Concept
\(-\sqrt{5}\) and \(\frac{3}{8}\) are real coefficients. The powers of (x) are (0), (4), and (1).
Step 2
Why this answer is correct
The correct answer is B. यह बहुपद है और डिग्री (4) है / It is a polynomial and degree is (4). \(-\sqrt{5}\) and \(\frac{3}{8}\) are real coefficients. The powers of (x) are (0), (4), and (1).
Step 3
Exam Tip
\(-\sqrt{5}\) और \(\frac{3}{8}\) वास्तविक गुणांक हैं। (x) की घातें (0), (4), और (1) हैं।
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यदि (c=0), तो (cx-8 +(c+2)x-5 -4x+1) की डिग्री क्या होगी?
If (c=0), what will be the degree of (cx-8 +(c+2)x-5 -4x+1)?
#polynomial
#degree
#parameter
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A (8)
B (5)
C (1)
D (0)
Explanation opens after your attempt
Step 1
Concept
For (c=0), the \(x^8\) term disappears and the coefficient of \(x^5\) remains (2). Therefore the degree is (5).
Step 2
Why this answer is correct
The correct answer is B. (5). For (c=0), the \(x^8\) term disappears and the coefficient of \(x^5\) remains (2). Therefore the degree is (5).
Step 3
Exam Tip
(c=0) पर \(x^8\) पद हट जाता है और \(x^5\) का गुणांक (2) रहता है। इसलिए डिग्री (5) है।
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व्यंजक \(x^3+\frac{x^2-9}{x-3}\) को \(x\neq3\) पर सरल करने से क्या मिलेगा?
What is obtained by simplifying \(x^3+\frac{x^2-9}{x-3}\) for \(x\neq3\)?
#polynomial
#rational_simplification
#domain
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A \(x^3+x-3\)
B \(x^3+x+3\)
C \(x^2+x+3\)
D \(x^3+3\)
Explanation opens after your attempt
Correct Answer
B. \(x^3+x+3\)
Step 1
Concept
\(\frac{x^2-9}{x-3}=x+3\) when \(x\neq3\). Therefore the simplified form is \(x^3+x+3\).
Step 2
Why this answer is correct
The correct answer is B. \(x^3+x+3\). \(\frac{x^2-9}{x-3}=x+3\) when \(x\neq3\). Therefore the simplified form is \(x^3+x+3\).
Step 3
Exam Tip
\(\frac{x^2-9}{x-3}=x+3\) जब \(x\neq3\)। इसलिए सरल रूप \(x^3+x+3\) है।
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सरल रूप \(x^3+x+3\) किस प्रकार का बहुपद है?
What type of polynomial is the simplified form \(x^3+x+3\)?
#polynomial
#cubic
#simplified_form
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A रेखीय बहुपद / Linear polynomial
B द्विघात बहुपद / Quadratic polynomial
C त्रिघात बहुपद / Cubic polynomial
D नियतांक बहुपद / Constant polynomial
Explanation opens after your attempt
Correct Answer
C. त्रिघात बहुपद / Cubic polynomial
Step 1
Concept
In \(x^3+x+3\), the highest power is (3). Therefore it is a cubic polynomial.
Step 2
Why this answer is correct
The correct answer is C. त्रिघात बहुपद / Cubic polynomial. In \(x^3+x+3\), the highest power is (3). Therefore it is a cubic polynomial.
Step 3
Exam Tip
\(x^3+x+3\) में सबसे बड़ी घात (3) है। इसलिए यह त्रिघात बहुपद है।
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व्यंजक \(x^6+x^4+x^0\) की डिग्री क्या है?
What is the degree of \(x^6+x^4+x^0\)?
#polynomial
#zero_power
#degree
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A (0)
B (4)
C (6)
D (10)
Explanation opens after your attempt
Step 1
Concept
\(x^0=1\), and the highest power is (6). Therefore the degree is (6).
Step 2
Why this answer is correct
The correct answer is C. (6). \(x^0=1\), and the highest power is (6). Therefore the degree is (6).
Step 3
Exam Tip
\(x^0=1\) होता है और सबसे बड़ी घात (6) है। इसलिए डिग्री (6) है।
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यदि (a=0), \(b\neq0\), तो \(ax^6+bx^4+x-1\) की डिग्री क्या होगी?
If (a=0), \(b\neq0\), what will be the degree of \(ax^6+bx^4+x-1\)?
#polynomial
#degree
#parameters
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A (6)
B (4)
C (1)
D (0)
Explanation opens after your attempt
Step 1
Concept
Since (a=0), the \(x^6\) term disappears, and since \(b\neq0\), the \(x^4\) term remains. So the degree is (4).
Step 2
Why this answer is correct
The correct answer is B. (4). Since (a=0), the \(x^6\) term disappears, and since \(b\neq0\), the \(x^4\) term remains. So the degree is (4).
Step 3
Exam Tip
(a=0) होने से \(x^6\) पद हटता है और \(b\neq0\) होने से \(x^4\) पद बचता है। इसलिए डिग्री (4) है।
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बहुपद \(8x^5+0x^4-3x^2+0x+6\) में कुल कितने अशून्य पद हैं?
How many non-zero terms are there in \(8x^5+0x^4-3x^2+0x+6\)?
#polynomial
#terms
#nonzero_terms
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A (2)
B (3)
C (4)
D (5)
Explanation opens after your attempt
Step 1
Concept
\(0x^4\) and (0x) are zero terms. The remaining \(8x^5\), \(-3x^2\), and (6) are three non-zero terms.
Step 2
Why this answer is correct
The correct answer is B. (3). \(0x^4\) and (0x) are zero terms. The remaining \(8x^5\), \(-3x^2\), and (6) are three non-zero terms.
Step 3
Exam Tip
\(0x^4\) और (0x) शून्य पद हैं। बाकी \(8x^5\), \(-3x^2\), और (6) तीन अशून्य पद हैं।
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कौन सा कथन \(\frac{x^4}{3}-\sqrt{10}x^2+7\) के लिए सही है?
Which statement is correct for \(\frac{x^4}{3}-\sqrt{10}x^2+7\)?
#polynomial
#real_coefficients
#degree
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A यह बहुपद नहीं है क्योंकि गुणांक भिन्न है / It is not a polynomial because a coefficient is fractional
B यह बहुपद है और डिग्री (4) है / It is a polynomial and degree is (4)
C यह शून्य बहुपद है / It is the zero polynomial
D यह बहुपद नहीं है क्योंकि इसमें \(\sqrt{10}\) है / It is not a polynomial because it has \(\sqrt{10}\)
Explanation opens after your attempt
Correct Answer
B. यह बहुपद है और डिग्री (4) है / It is a polynomial and degree is (4)
Step 1
Concept
Fractional and irrational real coefficients are valid in a polynomial. The highest power is (4).
Step 2
Why this answer is correct
The correct answer is B. यह बहुपद है और डिग्री (4) है / It is a polynomial and degree is (4). Fractional and irrational real coefficients are valid in a polynomial. The highest power is (4).
Step 3
Exam Tip
भिन्न और अपरिमेय वास्तविक गुणांक बहुपद में मान्य होते हैं। सबसे बड़ी घात (4) है।
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यदि (q(x)=x-6 +x^{\frac{3}{2}}+2), तो (q(x)) बहुपद क्यों नहीं है?
If (q(x)=x-6 +x^{\frac{3}{2}}+2), why is (q(x)) not a polynomial?
#polynomial
#fractional_power
#non_polynomial
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A क्योंकि इसमें \(x^6\) है / Because it has \(x^6\)
B क्योंकि इसमें (2) है / Because it has (2)
C क्योंकि \(x^{\frac{3}{2}}\) की घात भिन्न है / Because \(x^{\frac{3}{2}}\) has a fractional power
D क्योंकि इसमें तीन पद हैं / Because it has three terms
Explanation opens after your attempt
Correct Answer
C. क्योंकि \(x^{\frac{3}{2}}\) की घात भिन्न है / Because \(x^{\frac{3}{2}}\) has a fractional power
Step 1
Concept
In \(x^{\frac{3}{2}}\), the variable has a fractional power. Fractional powers are not valid in a polynomial.
Step 2
Why this answer is correct
The correct answer is C. क्योंकि \(x^{\frac{3}{2}}\) की घात भिन्न है / Because \(x^{\frac{3}{2}}\) has a fractional power. In \(x^{\frac{3}{2}}\), the variable has a fractional power. Fractional powers are not valid in a polynomial.
Step 3
Exam Tip
\(x^{\frac{3}{2}}\) में चर की घात भिन्न है। बहुपद में भिन्न घात मान्य नहीं होती।
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व्यंजक ((u+2)x-4 +(u+2)x+15) नियतांक बहुपद कब बनेगा?
When will ((u+2)x-4 +(u+2)x+15) become a constant polynomial?
#polynomial
#constant_polynomial
#parameter
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A जब (u=2) / When (u=2)
B जब (u=-2) / When (u=-2)
C जब (u=0) / When (u=0)
D कभी नहीं / Never
Explanation opens after your attempt
Correct Answer
B. जब (u=-2) / When (u=-2)
Step 1
Concept
To become constant, the coefficients of both \(x^4\) and (x) must be (0). From (u+2=0), both terms disappear.
Step 2
Why this answer is correct
The correct answer is B. जब (u=-2) / When (u=-2). To become constant, the coefficients of both \(x^4\) and (x) must be (0). From (u+2=0), both terms disappear.
Step 3
Exam Tip
नियतांक बनने के लिए \(x^4\) और (x) दोनों के गुणांक (0) चाहिए। (u+2=0) से दोनों पद हट जाते हैं।
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कौन सा व्यंजक बहुपद है जिसकी डिग्री (3) से अधिक है?
Which expression is a polynomial whose degree is greater than (3)?
#polynomial
#degree
#classification
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A \(2x^3+1\)
B (5x-4)
C \(x^6-2x^2+9\)
D \(\frac{1}{x}+6\)
Explanation opens after your attempt
Correct Answer
C. \(x^6-2x^2+9\)
Step 1
Concept
\(x^6-2x^2+9\) is a polynomial and its degree is (6). (6) is greater than (3).
Step 2
Why this answer is correct
The correct answer is C. \(x^6-2x^2+9\). \(x^6-2x^2+9\) is a polynomial and its degree is (6). (6) is greater than (3).
Step 3
Exam Tip
\(x^6-2x^2+9\) बहुपद है और इसकी डिग्री (6) है। (6), (3) से अधिक है।
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बहुपद \(6x^8-5x^6+3\) में \(x^7\), \(x^5\), और (x) के गुणांक क्या हैं?
In \(6x^8-5x^6+3\), what are the coefficients of \(x^7\), \(x^5\), and (x)?
#polynomial
#missing_terms
#coefficients
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A (6), (-5), और (3) / (6), (-5), and (3)
B (0), (0), और (0) / (0), (0), and (0)
C (8), (6), और (1) / (8), (6), and (1)
D (-5), (0), और (3) / (-5), (0), and (3)
Explanation opens after your attempt
Correct Answer
B. (0), (0), और (0) / (0), (0), and (0)
Step 1
Concept
The terms with these powers are not present in the polynomial. Therefore all three coefficients are (0).
Step 2
Why this answer is correct
The correct answer is B. (0), (0), और (0) / (0), (0), and (0). The terms with these powers are not present in the polynomial. Therefore all three coefficients are (0).
Step 3
Exam Tip
इन घातों वाले पद बहुपद में नहीं हैं। इसलिए तीनों गुणांक (0) हैं।
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यदि (r=3), तो (\(r^2-9\)x-7 +(r-1)x-4 +x-2 ) की डिग्री क्या होगी?
If (r=3), what will be the degree of (\(r^2-9\)x-7 +(r-1)x-4 +x-2 )?
#polynomial
#degree
#parameter_substitution
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A (7)
B (4)
C (2)
D (0)
Explanation opens after your attempt
Step 1
Concept
For (r=3), the coefficient of \(x^7\) is (0) and the coefficient of \(x^4\) is (2). Therefore the degree is (4).
Step 2
Why this answer is correct
The correct answer is B. (4). For (r=3), the coefficient of \(x^7\) is (0) and the coefficient of \(x^4\) is (2). Therefore the degree is (4).
Step 3
Exam Tip
(r=3) पर \(x^7\) का गुणांक (0) और \(x^4\) का गुणांक (2) होता है। इसलिए डिग्री (4) है।
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व्यंजक (x-3 \(x^2-5\)-x-5 +9x-3 ) को सरल करने पर क्या मिलेगा?
What is obtained by simplifying (x-3 \(x^2-5\)-x-5 +9x-3 )?
#polynomial
#simplification
#cancellation
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A \(2x^5+4x^3\)
B \(4x^3\)
C \(x^5+4x^3\)
D \(9x^3\)
Explanation opens after your attempt
Correct Answer
B. \(4x^3\)
Step 1
Concept
(x-3 \(x^2-5\)=x-5 -5x-3 ), then \(-x^5\) cancels \(x^5\). The simplified form is \(4x^3\).
Step 2
Why this answer is correct
The correct answer is B. \(4x^3\). (x-3 \(x^2-5\)=x-5 -5x-3 ), then \(-x^5\) cancels \(x^5\). The simplified form is \(4x^3\).
Step 3
Exam Tip
(x-3 \(x^2-5\)=x-5 -5x-3 ), फिर \(-x^5\) से \(x^5\) कटता है। सरल रूप \(4x^3\) है।
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सरल रूप \(4x^3\) किस प्रकार का बहुपद है?
What type of polynomial is the simplified form \(4x^3\)?
#polynomial
#cubic
#monomial
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A रेखीय एकपदी बहुपद / Linear monomial polynomial
B द्विघात बहुपद / Quadratic polynomial
C त्रिघात एकपदी बहुपद / Cubic monomial polynomial
D नियतांक बहुपद / Constant polynomial
Explanation opens after your attempt
Correct Answer
C. त्रिघात एकपदी बहुपद / Cubic monomial polynomial
Step 1
Concept
\(4x^3\) has one term and the highest power is (3). So it is a cubic monomial polynomial.
Step 2
Why this answer is correct
The correct answer is C. त्रिघात एकपदी बहुपद / Cubic monomial polynomial. \(4x^3\) has one term and the highest power is (3). So it is a cubic monomial polynomial.
Step 3
Exam Tip
\(4x^3\) में एक पद है और सबसे बड़ी घात (3) है। इसलिए यह त्रिघात एकपदी बहुपद है।
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कौन सा निष्कर्ष \(x^0+\sqrt{2}x^5-\frac{4x^2}{9}\) के लिए सही है?
Which conclusion is correct for \(x^0+\sqrt{2}x^5-\frac{4x^2}{9}\)?
#polynomial
#real_coefficients
#degree
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A यह बहुपद नहीं है क्योंकि इसमें \(\sqrt{2}\) है / It is not a polynomial because it has \(\sqrt{2}\)
B यह बहुपद है और डिग्री (5) है / It is a polynomial and degree is (5)
C यह शून्य बहुपद है / It is the zero polynomial
D यह बहुपद नहीं है क्योंकि इसमें भिन्न गुणांक है / It is not a polynomial because it has a fractional coefficient
Explanation opens after your attempt
Correct Answer
B. यह बहुपद है और डिग्री (5) है / It is a polynomial and degree is (5)
Step 1
Concept
\(\sqrt{2}\) and \(-\frac{4}{9}\) are real coefficients. The powers of (x) are (0), (5), and (2).
Step 2
Why this answer is correct
The correct answer is B. यह बहुपद है और डिग्री (5) है / It is a polynomial and degree is (5). \(\sqrt{2}\) and \(-\frac{4}{9}\) are real coefficients. The powers of (x) are (0), (5), and (2).
Step 3
Exam Tip
\(\sqrt{2}\) और \(-\frac{4}{9}\) वास्तविक गुणांक हैं। (x) की घातें (0), (5), और (2) हैं।
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यदि (d=-1), तो ((d+1)x-5 +(2d+3)x-2 +7) की डिग्री क्या होगी?
If (d=-1), what will be the degree of ((d+1)x-5 +(2d+3)x-2 +7)?
#polynomial
#degree
#parameter_substitution
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A (5)
B (2)
C (1)
D (0)
Explanation opens after your attempt
Step 1
Concept
Putting (d=-1) makes the coefficient of \(x^5\) equal to (0) and the coefficient of \(x^2\) equal to (1). So the highest power is (2).
Step 2
Why this answer is correct
The correct answer is B. (2). Putting (d=-1) makes the coefficient of \(x^5\) equal to (0) and the coefficient of \(x^2\) equal to (1). So the highest power is (2).
Step 3
Exam Tip
(d=-1) रखने पर \(x^5\) का गुणांक (0) और \(x^2\) का गुणांक (1) होता है। इसलिए सबसे बड़ी घात (2) है।
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किस मान पर ((2a-8)x-6 +(a+1)x-3 +4) की डिग्री (3) होगी?
For which value will the degree of ((2a-8)x-6 +(a+1)x-3 +4) be (3)?
#polynomial
#degree
#parameter_value
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A (a=-1)
B (a=0)
C (a=4)
D (a=8)
Explanation opens after your attempt
Step 1
Concept
For degree (3), the coefficient of \(x^6\) must be (0) and the coefficient of \(x^3\) must remain non-zero. From (2a-8=0), (a=4).
Step 2
Why this answer is correct
The correct answer is C. (a=4). For degree (3), the coefficient of \(x^6\) must be (0) and the coefficient of \(x^3\) must remain non-zero. From (2a-8=0), (a=4).
Step 3
Exam Tip
डिग्री (3) के लिए \(x^6\) का गुणांक (0) होना चाहिए और \(x^3\) का गुणांक अशून्य रहना चाहिए। (2a-8=0) से (a=4) मिलता है।
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व्यंजक \(\frac{x^2-4}{x-2}\) मूल रूप में बहुपद क्यों नहीं माना जाता?
Why is \(\frac{x^2-4}{x-2}\) not considered a polynomial in its original form?
#polynomial
#rational_expression
#domain
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A क्योंकि इसमें \(x^2\) है / Because it has \(x^2\)
B क्योंकि इसमें घटाव है / Because it has subtraction
C क्योंकि चर हर में है / Because the variable is in the denominator
D क्योंकि अंश में दो पद हैं / Because the numerator has two terms
Explanation opens after your attempt
Correct Answer
C. क्योंकि चर हर में है / Because the variable is in the denominator
Step 1
Concept
In the original form, the denominator is (x-2), so it is not directly called a polynomial. Even after simplifying, the condition \(x\neq2\) remains.
Step 2
Why this answer is correct
The correct answer is C. क्योंकि चर हर में है / Because the variable is in the denominator. In the original form, the denominator is (x-2), so it is not directly called a polynomial. Even after simplifying, the condition \(x\neq2\) remains.
Step 3
Exam Tip
मूल रूप में हर (x-2) है, इसलिए यह सीधे बहुपद नहीं कहलाता। सरल करने पर भी \(x\neq2\) की शर्त रहती है।
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\(\frac{x^2-4}{x-2}\) को \(x\neq2\) पर सरल करने से क्या मिलेगा?
What is obtained by simplifying \(\frac{x^2-4}{x-2}\) for \(x\neq2\)?
#polynomial
#simplification
#difference_of_squares
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A (x-2)
B (x+2)
C \(x^2+2\)
D (2x)
Explanation opens after your attempt
Step 1
Concept
(\frac{x-2 -4}{x-2}=\frac{(x-2)(x+2)}{x-2}=x+2) when \(x\neq2\). Factor first.
Step 2
Why this answer is correct
The correct answer is B. (x+2). (\frac{x-2 -4}{x-2}=\frac{(x-2)(x+2)}{x-2}=x+2) when \(x\neq2\). Factor first.
Step 3
Exam Tip
(\frac{x-2 -4}{x-2}=\frac{(x-2)(x+2)}{x-2}=x+2) जब \(x\neq2\)। पहले गुणनखंड बनाएं।
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सरल रूप (x+2) किस प्रकार का बहुपद है?
What type of polynomial is the simplified form (x+2)?
#polynomial
#linear
#simplified_form
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A नियतांक बहुपद / Constant polynomial
B द्विघात बहुपद / Quadratic polynomial
C त्रिघात बहुपद / Cubic polynomial
D रेखीय बहुपद / Linear polynomial
Explanation opens after your attempt
Correct Answer
D. रेखीय बहुपद / Linear polynomial
Step 1
Concept
In (x+2), the highest power is (1). Therefore it is a linear polynomial.
Step 2
Why this answer is correct
The correct answer is D. रेखीय बहुपद / Linear polynomial. In (x+2), the highest power is (1). Therefore it is a linear polynomial.
Step 3
Exam Tip
(x+2) में सबसे बड़ी घात (1) है। इसलिए यह रेखीय बहुपद है।
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कौन सा व्यंजक (x) में बहुपद है लेकिन \(x^3\) का गुणांक (0) है?
Which expression is a polynomial in (x) but has coefficient of \(x^3\) equal to (0)?
#polynomial
#coefficient
#missing_term
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A \(2x^4-5x^2+1\)
B \(2x^4+x^3+1\)
C \(\frac{1}{x^3}+2\)
D \(x^{\frac{3}{2}}+1\)
Explanation opens after your attempt
Correct Answer
A. \(2x^4-5x^2+1\)
Step 1
Concept
\(2x^4-5x^2+1\) is a polynomial and the \(x^3\) term is absent. So the coefficient of \(x^3\) is (0).
Step 2
Why this answer is correct
The correct answer is A. \(2x^4-5x^2+1\). \(2x^4-5x^2+1\) is a polynomial and the \(x^3\) term is absent. So the coefficient of \(x^3\) is (0).
Step 3
Exam Tip
\(2x^4-5x^2+1\) बहुपद है और इसमें \(x^3\) पद अनुपस्थित है। इसलिए \(x^3\) का गुणांक (0) है।
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किस विकल्प में बहुपद है और उसके सभी अशून्य पदों की घातें सम हैं?
Which option is a polynomial and all its non-zero variable terms have even powers?
#polynomial
#even_powers
#classification
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A \(x^5+x^2+1\)
B \(3x^4-2x^2+9\)
C \(x^3+x+1\)
D \(\sqrt{x}+x^2\)
Explanation opens after your attempt
Correct Answer
B. \(3x^4-2x^2+9\)
Step 1
Concept
In \(3x^4-2x^2+9\), the non-zero variable term powers are (4) and (2). Both are even and valid powers.
Step 2
Why this answer is correct
The correct answer is B. \(3x^4-2x^2+9\). In \(3x^4-2x^2+9\), the non-zero variable term powers are (4) and (2). Both are even and valid powers.
Step 3
Exam Tip
\(3x^4-2x^2+9\) में चर वाले अशून्य पदों की घातें (4) और (2) हैं। दोनों सम और मान्य घातें हैं।
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व्यंजक (\(w^2-1\)x-4 +(w-1)x-2 +6) नियतांक बहुपद कब बनेगा?
When will (\(w^2-1\)x-4 +(w-1)x-2 +6) become a constant polynomial?
#polynomial
#constant_polynomial
#parameter
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A जब (w=1) / When (w=1)
B जब (w=-1) / When (w=-1)
C जब (w=0) / When (w=0)
D कभी नहीं / Never
Explanation opens after your attempt
Correct Answer
A. जब (w=1) / When (w=1)
Step 1
Concept
To become constant, both \(w^2-1=0\) and (w-1=0) are needed. Both conditions are satisfied together at (w=1).
Step 2
Why this answer is correct
The correct answer is A. जब (w=1) / When (w=1). To become constant, both \(w^2-1=0\) and (w-1=0) are needed. Both conditions are satisfied together at (w=1).
Step 3
Exam Tip
नियतांक बनने के लिए \(w^2-1=0\) और (w-1=0) दोनों चाहिए। दोनों शर्तें साथ में (w=1) पर पूरी होती हैं।
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यदि (z=-2), तो ((z+2)x-5 +\(z^2-4\)x-3 +9x-1) की डिग्री क्या होगी?
If (z=-2), what will be the degree of ((z+2)x-5 +\(z^2-4\)x-3 +9x-1)?
#polynomial
#degree
#parameter_substitution
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A (5)
B (3)
C (1)
D (0)
Explanation opens after your attempt
Step 1
Concept
For (z=-2), the coefficients of both \(x^5\) and \(x^3\) become (0). The remaining highest power is (1).
Step 2
Why this answer is correct
The correct answer is C. (1). For (z=-2), the coefficients of both \(x^5\) and \(x^3\) become (0). The remaining highest power is (1).
Step 3
Exam Tip
(z=-2) पर \(x^5\) और \(x^3\) दोनों के गुणांक (0) हो जाते हैं। बची हुई सबसे बड़ी घात (1) है।
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कौन सा व्यंजक बहुपद नहीं है क्योंकि उसमें चर घात के रूप में है?
Which expression is not a polynomial because the variable appears as an exponent?
#polynomial
#variable_exponent
#non_polynomial
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A \(2^x+3\)
B \(2x^3+3\)
C \(\sqrt{2}x+3\)
D \(x^0+3x\)
Explanation opens after your attempt
Correct Answer
A. \(2^x+3\)
Step 1
Concept
In \(2^x\), the variable is in the exponent. In a polynomial, the variable is the base with a non-negative integer power.
Step 2
Why this answer is correct
The correct answer is A. \(2^x+3\). In \(2^x\), the variable is in the exponent. In a polynomial, the variable is the base with a non-negative integer power.
Step 3
Exam Tip
\(2^x\) में चर घात के स्थान पर है। बहुपद में चर आधार में होता है और उसकी घात अऋणात्मक पूर्णांक होती है।
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कौन सा व्यंजक (x) में बहुपद है और उसकी डिग्री (0) है?
Which expression is a polynomial in (x) and has degree (0)?
#polynomial
#in_x
#degree_zero
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A (0)
B (6y-4)
C (x+6)
D \(\frac{1}{x}+6\)
Explanation opens after your attempt
Step 1
Concept
With respect to (x), (6y-4) is a non-zero constant. Therefore it is a polynomial in (x) of degree (0).
Step 2
Why this answer is correct
The correct answer is B. (6y-4). With respect to (x), (6y-4) is a non-zero constant. Therefore it is a polynomial in (x) of degree (0).
Step 3
Exam Tip
(x) के संदर्भ में (6y-4) अशून्य नियतांक है। इसलिए यह (x) में डिग्री (0) का बहुपद है।
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व्यंजक \(x^4-4x^2+4\) में \(x^3\) और (x) के गुणांक क्रमशः क्या हैं?
In \(x^4-4x^2+4\), what are the coefficients of \(x^3\) and (x) respectively?
#polynomial
#missing_terms
#coefficients
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A (1) और (-4) / (1) and (-4)
B (0) और (0) / (0) and (0)
C (4) और (1) / (4) and (1)
D (-4) और (4) / (-4) and (4)
Explanation opens after your attempt
Correct Answer
B. (0) और (0) / (0) and (0)
Step 1
Concept
The \(x^3\) and (x) terms are not present in this polynomial. Therefore both coefficients are (0).
Step 2
Why this answer is correct
The correct answer is B. (0) और (0) / (0) and (0). The \(x^3\) and (x) terms are not present in this polynomial. Therefore both coefficients are (0).
Step 3
Exam Tip
इस बहुपद में \(x^3\) और (x) पद नहीं हैं। इसलिए दोनों गुणांक (0) हैं।
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कौन सा विकल्प बहुपद और अपूर्ण बहुपद दोनों की सही पहचान करता है?
Which option correctly identifies a polynomial with missing powers?
#polynomial
#missing_powers
#coefficient_zero
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A \(x^5+x^2+1\) में \(x^4\) और \(x^3\) के गुणांक (0) हैं / In \(x^5+x^2+1\), coefficients of \(x^4\) and \(x^3\) are (0)
B \(x^5+x^2+1\) में \(x^4\) का गुणांक (5) है / In \(x^5+x^2+1\), coefficient of \(x^4\) is (5)
C \(x^5+x^2+1\) बहुपद नहीं है / \(x^5+x^2+1\) is not a polynomial
D \(x^5+x^2+1\) की डिग्री (2) है / Degree of \(x^5+x^2+1\) is (2)
Explanation opens after your attempt
Correct Answer
A. \(x^5+x^2+1\) में \(x^4\) और \(x^3\) के गुणांक (0) हैं / In \(x^5+x^2+1\), coefficients of \(x^4\) and \(x^3\) are (0)
Step 1
Concept
Coefficients of absent terms are taken as (0). Here the \(x^4\) and \(x^3\) terms are absent.
Step 2
Why this answer is correct
The correct answer is A. \(x^5+x^2+1\) में \(x^4\) और \(x^3\) के गुणांक (0) हैं / In \(x^5+x^2+1\), coefficients of \(x^4\) and \(x^3\) are (0). Coefficients of absent terms are taken as (0). Here the \(x^4\) and \(x^3\) terms are absent.
Step 3
Exam Tip
अनुपस्थित पदों के गुणांक (0) माने जाते हैं। यहां \(x^4\) और \(x^3\) पद नहीं हैं।
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