Class 9 Mathematics - Introduction to Polynomials - Definition of polynomial Hard Quiz

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व्यंजक \(0x^9+6x^5-4x^2+3\) की डिग्री क्या है?

What is the degree of \(0x^9+6x^5-4x^2+3\)?

Explanation opens after your attempt
Correct Answer

B. (5)

Step 1

Concept

\(0x^9\) is a zero term. The remaining highest power is (5).

Step 2

Why this answer is correct

The correct answer is B. (5). \(0x^9\) is a zero term. The remaining highest power is (5).

Step 3

Exam Tip

\(0x^9\) शून्य पद है। बची हुई सबसे बड़ी घात (5) है।

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व्यंजक ((a+4)x-6+3x-2-8) की डिग्री (6) कब होगी?

When will the degree of ((a+4)x-6+3x-2-8) be (6)?

Explanation opens after your attempt
Correct Answer

C. जब \(a\neq-4\)When \(a\neq-4\)

Step 1

Concept

For degree (6), the coefficient of \(x^6\) must not be zero. So \(a+4\neq0\).

Step 2

Why this answer is correct

The correct answer is C. जब \(a\neq-4\) / When \(a\neq-4\). For degree (6), the coefficient of \(x^6\) must not be zero. So \(a+4\neq0\).

Step 3

Exam Tip

डिग्री (6) के लिए \(x^6\) का गुणांक शून्य नहीं होना चाहिए। इसलिए \(a+4\neq0\) होना चाहिए।

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यदि (k=5), तो ((k-5)x-7+4x-3-x+2) की डिग्री क्या होगी?

If (k=5), what will be the degree of ((k-5)x-7+4x-3-x+2)?

Explanation opens after your attempt
Correct Answer

C. (3)

Step 1

Concept

Putting (k=5) makes the coefficient of \(x^7\) equal to (0). In the remaining polynomial, the highest power is (3).

Step 2

Why this answer is correct

The correct answer is C. (3). Putting (k=5) makes the coefficient of \(x^7\) equal to (0). In the remaining polynomial, the highest power is (3).

Step 3

Exam Tip

(k=5) रखने पर \(x^7\) का गुणांक (0) हो जाता है। शेष बहुपद में सबसे बड़ी घात (3) है।

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किस मान पर ((m+6)x-4-2x+9) रेखीय बहुपद बनेगा?

For which value will ((m+6)x-4-2x+9) become a linear polynomial?

Explanation opens after your attempt
Correct Answer

B. (m=-6)

Step 1

Concept

To become linear, the coefficient of \(x^4\) must be (0). From (m+6=0), we get (m=-6).

Step 2

Why this answer is correct

The correct answer is B. (m=-6). To become linear, the coefficient of \(x^4\) must be (0). From (m+6=0), we get (m=-6).

Step 3

Exam Tip

रेखीय बनने के लिए \(x^4\) का गुणांक (0) होना चाहिए। (m+6=0) से (m=-6) मिलता है।

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व्यंजक \(3x^2+\sqrt{2x-1}\) बहुपद क्यों नहीं है?

Why is \(3x^2+\sqrt{2x-1}\) not a polynomial?

Explanation opens after your attempt
Correct Answer

C. क्योंकि (2x-1) मूल चिह्न के अंदर हैBecause (2x-1) is inside a radical sign

Step 1

Concept

\(\sqrt{2x-1}\) is not a term with valid polynomial powers. Therefore the whole expression is not a polynomial.

Step 2

Why this answer is correct

The correct answer is C. क्योंकि (2x-1) मूल चिह्न के अंदर है / Because (2x-1) is inside a radical sign. \(\sqrt{2x-1}\) is not a term with valid polynomial powers. Therefore the whole expression is not a polynomial.

Step 3

Exam Tip

\(\sqrt{2x-1}\) बहुपद की मान्य घातों वाला पद नहीं है। इसलिए पूरा व्यंजक बहुपद नहीं है।

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यदि (p(x)=5x-5+0x-4-3x+6), तो \(x^4\) का गुणांक क्या है?

If (p(x)=5x-5+0x-4-3x+6), what is the coefficient of \(x^4\)?

Explanation opens after your attempt
Correct Answer

C. (0)

Step 1

Concept

The term containing \(x^4\) is \(0x^4\). Therefore the coefficient of \(x^4\) is (0).

Step 2

Why this answer is correct

The correct answer is C. (0). The term containing \(x^4\) is \(0x^4\). Therefore the coefficient of \(x^4\) is (0).

Step 3

Exam Tip

\(x^4\) वाला पद \(0x^4\) है। इसलिए \(x^4\) का गुणांक (0) है।

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किस विकल्प में (x) में द्विघात बहुपद है?

Which option is a quadratic polynomial in (x)?

Explanation opens after your attempt
Correct Answer

A. \(3x^2-\pi x+\sqrt{7}\)

Step 1

Concept

In the first expression, the highest power is (2), and all powers are valid. So it is a quadratic polynomial.

Step 2

Why this answer is correct

The correct answer is A. \(3x^2-\pi x+\sqrt{7}\). In the first expression, the highest power is (2), and all powers are valid. So it is a quadratic polynomial.

Step 3

Exam Tip

पहले व्यंजक में सबसे बड़ी घात (2) है और सभी घातें मान्य हैं। इसलिए यह द्विघात बहुपद है।

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व्यंजक \(\frac{x^5+3x^2}{x^2}\) मूल रूप में बहुपद क्यों नहीं माना जाता?

Why is \(\frac{x^5+3x^2}{x^2}\) not considered a polynomial in its original form?

Explanation opens after your attempt
Correct Answer

A. क्योंकि चर हर में हैBecause the variable is in the denominator

Step 1

Concept

In the original form, \(x^2\) is in the denominator. While simplifying to polynomial form, the domain condition must also be considered.

Step 2

Why this answer is correct

The correct answer is A. क्योंकि चर हर में है / Because the variable is in the denominator. In the original form, \(x^2\) is in the denominator. While simplifying to polynomial form, the domain condition must also be considered.

Step 3

Exam Tip

मूल रूप में हर में \(x^2\) है। बहुपद रूप के लिए सरल करते समय डोमेन शर्त भी ध्यान रखनी होती है।

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\(\frac{x^5+3x^2}{x^2}\) को \(x\neq0\) पर सरल करने से क्या मिलेगा?

What is obtained by simplifying \(\frac{x^5+3x^2}{x^2}\) for \(x\neq0\)?

Explanation opens after your attempt
Correct Answer

A. \(x^3+3\)

Step 1

Concept

For \(x\neq0\), \(\frac{x^5}{x^2}=x^3\) and \(\frac{3x^2}{x^2}=3\). So the simplified form is \(x^3+3\).

Step 2

Why this answer is correct

The correct answer is A. \(x^3+3\). For \(x\neq0\), \(\frac{x^5}{x^2}=x^3\) and \(\frac{3x^2}{x^2}=3\). So the simplified form is \(x^3+3\).

Step 3

Exam Tip

\(x\neq0\) पर \(\frac{x^5}{x^2}=x^3\) और \(\frac{3x^2}{x^2}=3\) होता है। इसलिए सरल रूप \(x^3+3\) है।

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सरल रूप \(x^3+3\) की डिग्री क्या है?

What is the degree of the simplified form \(x^3+3\)?

Explanation opens after your attempt
Correct Answer

C. (3)

Step 1

Concept

In \(x^3+3\), the highest power is (3). Therefore its degree is (3).

Step 2

Why this answer is correct

The correct answer is C. (3). In \(x^3+3\), the highest power is (3). Therefore its degree is (3).

Step 3

Exam Tip

\(x^3+3\) में सबसे बड़ी घात (3) है। इसलिए इसकी डिग्री (3) है।

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व्यंजक \(4x^2-5|x|+8\) बहुपद है या नहीं?

Is \(4x^2-5|x|+8\) a polynomial or not?

Explanation opens after your attempt
Correct Answer

C. नहीं क्योंकि (|x|) बहुपद पद नहीं हैNo because (|x|) is not a polynomial term

Step 1

Concept

(|x|) is not written as a term with non-negative integer powers of (x). Therefore it is not a polynomial.

Step 2

Why this answer is correct

The correct answer is C. नहीं क्योंकि (|x|) बहुपद पद नहीं है / No because (|x|) is not a polynomial term. (|x|) is not written as a term with non-negative integer powers of (x). Therefore it is not a polynomial.

Step 3

Exam Tip

(|x|) को (x) की अऋणात्मक पूर्णांक घातों वाले पद की तरह नहीं लिखा जाता। इसलिए यह बहुपद नहीं है।

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यदि \(a\neq0\) और (b=0), तो \(ax^8+bx^6-5x+2\) की डिग्री क्या होगी?

If \(a\neq0\) and (b=0), what will be the degree of \(ax^8+bx^6-5x+2\)?

Explanation opens after your attempt
Correct Answer

A. (8)

Step 1

Concept

Since \(a\neq0\), the \(x^8\) term remains present. Therefore the highest power is (8).

Step 2

Why this answer is correct

The correct answer is A. (8). Since \(a\neq0\), the \(x^8\) term remains present. Therefore the highest power is (8).

Step 3

Exam Tip

\(a\neq0\) होने से \(x^8\) पद मौजूद रहेगा। इसलिए सबसे बड़ी घात (8) है।

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यदि (a=0) और \(b\neq0\), तो \(ax^8+bx^6-5x+2\) की डिग्री क्या होगी?

If (a=0) and \(b\neq0\), what will be the degree of \(ax^8+bx^6-5x+2\)?

Explanation opens after your attempt
Correct Answer

B. (6)

Step 1

Concept

When (a=0), the \(x^8\) term disappears. Since \(b\neq0\), the \(x^6\) term remains present.

Step 2

Why this answer is correct

The correct answer is B. (6). When (a=0), the \(x^8\) term disappears. Since \(b\neq0\), the \(x^6\) term remains present.

Step 3

Exam Tip

(a=0) होने से \(x^8\) पद हट जाता है। \(b\neq0\) होने से \(x^6\) पद मौजूद रहता है।

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व्यंजक (\(t^2-9\)x-3+6x+1) रेखीय बहुपद कब बनेगा?

When will (\(t^2-9\)x-3+6x+1) become a linear polynomial?

Explanation opens after your attempt
Correct Answer

A. जब (t=3) या (t=-3)When (t=3) or (t=-3)

Step 1

Concept

To become linear, the coefficient of \(x^3\) must be (0). From \(t^2-9=0\), we get \(t=\pm3\).

Step 2

Why this answer is correct

The correct answer is A. जब (t=3) या (t=-3) / When (t=3) or (t=-3). To become linear, the coefficient of \(x^3\) must be (0). From \(t^2-9=0\), we get \(t=\pm3\).

Step 3

Exam Tip

रेखीय बनने के लिए \(x^3\) का गुणांक (0) होना चाहिए। \(t^2-9=0\) से \(t=\pm3\) मिलता है।

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व्यंजक ((r+4)x-2+(r-1)x+10) नियतांक बहुपद कब बनेगा?

When will ((r+4)x-2+(r-1)x+10) become a constant polynomial?

Explanation opens after your attempt
Correct Answer

D. कभी नहींNever

Step 1

Concept

To become constant, both (r+4=0) and (r-1=0) are required. One value of (r) cannot satisfy both conditions.

Step 2

Why this answer is correct

The correct answer is D. कभी नहीं / Never. To become constant, both (r+4=0) and (r-1=0) are required. One value of (r) cannot satisfy both conditions.

Step 3

Exam Tip

नियतांक बनने के लिए (r+4=0) और (r-1=0) दोनों चाहिए। एक ही (r) दोनों शर्तें पूरी नहीं कर सकता।

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कौन सा व्यंजक (x) में बहुपद है जबकि (y) गुणांक की तरह माना गया है?

Which expression is a polynomial in (x) while (y) is treated as a coefficient?

Explanation opens after your attempt
Correct Answer

A. \(y^2x^3-2yx+5\)

Step 1

Concept

With respect to (x), \(y^2\) and (-2y) are coefficients. The powers of (x) are (3), (1), and (0).

Step 2

Why this answer is correct

The correct answer is A. \(y^2x^3-2yx+5\). With respect to (x), \(y^2\) and (-2y) are coefficients. The powers of (x) are (3), (1), and (0).

Step 3

Exam Tip

(x) के संदर्भ में \(y^2\) और (-2y) गुणांक हैं। (x) की घातें (3), (1), और (0) हैं।

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बहुपद \(9x^7-2x^5+4\) में \(x^6\), \(x^4\), और (x) के गुणांक क्या हैं?

In \(9x^7-2x^5+4\), what are the coefficients of \(x^6\), \(x^4\), and (x)?

Explanation opens after your attempt
Correct Answer

B. (0), (0), और (0)(0), (0), and (0)

Step 1

Concept

The terms with these three powers are absent. Therefore their coefficients are (0), (0), and (0).

Step 2

Why this answer is correct

The correct answer is B. (0), (0), और (0) / (0), (0), and (0). The terms with these three powers are absent. Therefore their coefficients are (0), (0), and (0).

Step 3

Exam Tip

इन तीनों घातों वाले पद अनुपस्थित हैं। इसलिए इनके गुणांक (0), (0), और (0) हैं।

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यदि (n=-2), तो (\(n^2-4\)x-6+(n+5)x-3-7) की डिग्री क्या होगी?

If (n=-2), what will be the degree of (\(n^2-4\)x-6+(n+5)x-3-7)?

Explanation opens after your attempt
Correct Answer

B. (3)

Step 1

Concept

Putting (n=-2), the coefficient of \(x^6\) is (0) and the coefficient of \(x^3\) is (3). Therefore the degree is (3).

Step 2

Why this answer is correct

The correct answer is B. (3). Putting (n=-2), the coefficient of \(x^6\) is (0) and the coefficient of \(x^3\) is (3). Therefore the degree is (3).

Step 3

Exam Tip

(n=-2) रखने पर \(x^6\) का गुणांक (0) और \(x^3\) का गुणांक (3) होता है। इसलिए डिग्री (3) है।

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किस विकल्प में डिग्री (5) है और अग्रणी गुणांक ऋणात्मक है?

Which option has degree (5) and a negative leading coefficient?

Explanation opens after your attempt
Correct Answer

B. \(-7x^5+x^2-4\)

Step 1

Concept

\(-7x^5+x^2-4\) has degree (5) and leading coefficient (-7). Therefore it is the correct option.

Step 2

Why this answer is correct

The correct answer is B. \(-7x^5+x^2-4\). \(-7x^5+x^2-4\) has degree (5) and leading coefficient (-7). Therefore it is the correct option.

Step 3

Exam Tip

\(-7x^5+x^2-4\) की डिग्री (5) है और अग्रणी गुणांक (-7) है। इसलिए यह सही विकल्प है।

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व्यंजक (x-2\(x^3-4\)-x-5+7x-2) को सरल करने पर क्या मिलेगा?

What is obtained by simplifying (x-2\(x^3-4\)-x-5+7x-2)?

Explanation opens after your attempt
Correct Answer

B. \(3x^2\)

Step 1

Concept

(x-2\(x^3-4\)=x-5-4x-2), then \(-x^5\) cancels \(x^5\). The simplified form is \(3x^2\).

Step 2

Why this answer is correct

The correct answer is B. \(3x^2\). (x-2\(x^3-4\)=x-5-4x-2), then \(-x^5\) cancels \(x^5\). The simplified form is \(3x^2\).

Step 3

Exam Tip

(x-2\(x^3-4\)=x-5-4x-2), फिर \(-x^5\) से \(x^5\) कट जाता है। सरल रूप \(3x^2\) है।

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सरल रूप \(3x^2\) किस प्रकार का बहुपद है?

What type of polynomial is the simplified form \(3x^2\)?

Explanation opens after your attempt
Correct Answer

B. द्विघात एकपदी बहुपदQuadratic monomial polynomial

Step 1

Concept

\(3x^2\) has one term and the highest power is (2). So it is a quadratic monomial polynomial.

Step 2

Why this answer is correct

The correct answer is B. द्विघात एकपदी बहुपद / Quadratic monomial polynomial. \(3x^2\) has one term and the highest power is (2). So it is a quadratic monomial polynomial.

Step 3

Exam Tip

\(3x^2\) में एक पद है और सबसे बड़ी घात (2) है। इसलिए यह द्विघात एकपदी बहुपद है।

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कौन सा निष्कर्ष \(x^0-\sqrt{5}x^4+\frac{3x}{8}\) के लिए सही है?

Which conclusion is correct for \(x^0-\sqrt{5}x^4+\frac{3x}{8}\)?

Explanation opens after your attempt
Correct Answer

B. यह बहुपद है और डिग्री (4) हैIt is a polynomial and degree is (4)

Step 1

Concept

\(-\sqrt{5}\) and \(\frac{3}{8}\) are real coefficients. The powers of (x) are (0), (4), and (1).

Step 2

Why this answer is correct

The correct answer is B. यह बहुपद है और डिग्री (4) है / It is a polynomial and degree is (4). \(-\sqrt{5}\) and \(\frac{3}{8}\) are real coefficients. The powers of (x) are (0), (4), and (1).

Step 3

Exam Tip

\(-\sqrt{5}\) और \(\frac{3}{8}\) वास्तविक गुणांक हैं। (x) की घातें (0), (4), और (1) हैं।

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यदि (c=0), तो (cx-8+(c+2)x-5-4x+1) की डिग्री क्या होगी?

If (c=0), what will be the degree of (cx-8+(c+2)x-5-4x+1)?

Explanation opens after your attempt
Correct Answer

B. (5)

Step 1

Concept

For (c=0), the \(x^8\) term disappears and the coefficient of \(x^5\) remains (2). Therefore the degree is (5).

Step 2

Why this answer is correct

The correct answer is B. (5). For (c=0), the \(x^8\) term disappears and the coefficient of \(x^5\) remains (2). Therefore the degree is (5).

Step 3

Exam Tip

(c=0) पर \(x^8\) पद हट जाता है और \(x^5\) का गुणांक (2) रहता है। इसलिए डिग्री (5) है।

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व्यंजक \(x^3+\frac{x^2-9}{x-3}\) को \(x\neq3\) पर सरल करने से क्या मिलेगा?

What is obtained by simplifying \(x^3+\frac{x^2-9}{x-3}\) for \(x\neq3\)?

Explanation opens after your attempt
Correct Answer

B. \(x^3+x+3\)

Step 1

Concept

\(\frac{x^2-9}{x-3}=x+3\) when \(x\neq3\). Therefore the simplified form is \(x^3+x+3\).

Step 2

Why this answer is correct

The correct answer is B. \(x^3+x+3\). \(\frac{x^2-9}{x-3}=x+3\) when \(x\neq3\). Therefore the simplified form is \(x^3+x+3\).

Step 3

Exam Tip

\(\frac{x^2-9}{x-3}=x+3\) जब \(x\neq3\)। इसलिए सरल रूप \(x^3+x+3\) है।

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सरल रूप \(x^3+x+3\) किस प्रकार का बहुपद है?

What type of polynomial is the simplified form \(x^3+x+3\)?

Explanation opens after your attempt
Correct Answer

C. त्रिघात बहुपदCubic polynomial

Step 1

Concept

In \(x^3+x+3\), the highest power is (3). Therefore it is a cubic polynomial.

Step 2

Why this answer is correct

The correct answer is C. त्रिघात बहुपद / Cubic polynomial. In \(x^3+x+3\), the highest power is (3). Therefore it is a cubic polynomial.

Step 3

Exam Tip

\(x^3+x+3\) में सबसे बड़ी घात (3) है। इसलिए यह त्रिघात बहुपद है।

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व्यंजक \(x^6+x^4+x^0\) की डिग्री क्या है?

What is the degree of \(x^6+x^4+x^0\)?

Explanation opens after your attempt
Correct Answer

C. (6)

Step 1

Concept

\(x^0=1\), and the highest power is (6). Therefore the degree is (6).

Step 2

Why this answer is correct

The correct answer is C. (6). \(x^0=1\), and the highest power is (6). Therefore the degree is (6).

Step 3

Exam Tip

\(x^0=1\) होता है और सबसे बड़ी घात (6) है। इसलिए डिग्री (6) है।

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यदि (a=0), \(b\neq0\), तो \(ax^6+bx^4+x-1\) की डिग्री क्या होगी?

If (a=0), \(b\neq0\), what will be the degree of \(ax^6+bx^4+x-1\)?

Explanation opens after your attempt
Correct Answer

B. (4)

Step 1

Concept

Since (a=0), the \(x^6\) term disappears, and since \(b\neq0\), the \(x^4\) term remains. So the degree is (4).

Step 2

Why this answer is correct

The correct answer is B. (4). Since (a=0), the \(x^6\) term disappears, and since \(b\neq0\), the \(x^4\) term remains. So the degree is (4).

Step 3

Exam Tip

(a=0) होने से \(x^6\) पद हटता है और \(b\neq0\) होने से \(x^4\) पद बचता है। इसलिए डिग्री (4) है।

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बहुपद \(8x^5+0x^4-3x^2+0x+6\) में कुल कितने अशून्य पद हैं?

How many non-zero terms are there in \(8x^5+0x^4-3x^2+0x+6\)?

Explanation opens after your attempt
Correct Answer

B. (3)

Step 1

Concept

\(0x^4\) and (0x) are zero terms. The remaining \(8x^5\), \(-3x^2\), and (6) are three non-zero terms.

Step 2

Why this answer is correct

The correct answer is B. (3). \(0x^4\) and (0x) are zero terms. The remaining \(8x^5\), \(-3x^2\), and (6) are three non-zero terms.

Step 3

Exam Tip

\(0x^4\) और (0x) शून्य पद हैं। बाकी \(8x^5\), \(-3x^2\), और (6) तीन अशून्य पद हैं।

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कौन सा कथन \(\frac{x^4}{3}-\sqrt{10}x^2+7\) के लिए सही है?

Which statement is correct for \(\frac{x^4}{3}-\sqrt{10}x^2+7\)?

Explanation opens after your attempt
Correct Answer

B. यह बहुपद है और डिग्री (4) हैIt is a polynomial and degree is (4)

Step 1

Concept

Fractional and irrational real coefficients are valid in a polynomial. The highest power is (4).

Step 2

Why this answer is correct

The correct answer is B. यह बहुपद है और डिग्री (4) है / It is a polynomial and degree is (4). Fractional and irrational real coefficients are valid in a polynomial. The highest power is (4).

Step 3

Exam Tip

भिन्न और अपरिमेय वास्तविक गुणांक बहुपद में मान्य होते हैं। सबसे बड़ी घात (4) है।

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यदि (q(x)=x-6+x^{\frac{3}{2}}+2), तो (q(x)) बहुपद क्यों नहीं है?

If (q(x)=x-6+x^{\frac{3}{2}}+2), why is (q(x)) not a polynomial?

Explanation opens after your attempt
Correct Answer

C. क्योंकि \(x^{\frac{3}{2}}\) की घात भिन्न हैBecause \(x^{\frac{3}{2}}\) has a fractional power

Step 1

Concept

In \(x^{\frac{3}{2}}\), the variable has a fractional power. Fractional powers are not valid in a polynomial.

Step 2

Why this answer is correct

The correct answer is C. क्योंकि \(x^{\frac{3}{2}}\) की घात भिन्न है / Because \(x^{\frac{3}{2}}\) has a fractional power. In \(x^{\frac{3}{2}}\), the variable has a fractional power. Fractional powers are not valid in a polynomial.

Step 3

Exam Tip

\(x^{\frac{3}{2}}\) में चर की घात भिन्न है। बहुपद में भिन्न घात मान्य नहीं होती।

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व्यंजक ((u+2)x-4+(u+2)x+15) नियतांक बहुपद कब बनेगा?

When will ((u+2)x-4+(u+2)x+15) become a constant polynomial?

Explanation opens after your attempt
Correct Answer

B. जब (u=-2)When (u=-2)

Step 1

Concept

To become constant, the coefficients of both \(x^4\) and (x) must be (0). From (u+2=0), both terms disappear.

Step 2

Why this answer is correct

The correct answer is B. जब (u=-2) / When (u=-2). To become constant, the coefficients of both \(x^4\) and (x) must be (0). From (u+2=0), both terms disappear.

Step 3

Exam Tip

नियतांक बनने के लिए \(x^4\) और (x) दोनों के गुणांक (0) चाहिए। (u+2=0) से दोनों पद हट जाते हैं।

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कौन सा व्यंजक बहुपद है जिसकी डिग्री (3) से अधिक है?

Which expression is a polynomial whose degree is greater than (3)?

Explanation opens after your attempt
Correct Answer

C. \(x^6-2x^2+9\)

Step 1

Concept

\(x^6-2x^2+9\) is a polynomial and its degree is (6). (6) is greater than (3).

Step 2

Why this answer is correct

The correct answer is C. \(x^6-2x^2+9\). \(x^6-2x^2+9\) is a polynomial and its degree is (6). (6) is greater than (3).

Step 3

Exam Tip

\(x^6-2x^2+9\) बहुपद है और इसकी डिग्री (6) है। (6), (3) से अधिक है।

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बहुपद \(6x^8-5x^6+3\) में \(x^7\), \(x^5\), और (x) के गुणांक क्या हैं?

In \(6x^8-5x^6+3\), what are the coefficients of \(x^7\), \(x^5\), and (x)?

Explanation opens after your attempt
Correct Answer

B. (0), (0), और (0)(0), (0), and (0)

Step 1

Concept

The terms with these powers are not present in the polynomial. Therefore all three coefficients are (0).

Step 2

Why this answer is correct

The correct answer is B. (0), (0), और (0) / (0), (0), and (0). The terms with these powers are not present in the polynomial. Therefore all three coefficients are (0).

Step 3

Exam Tip

इन घातों वाले पद बहुपद में नहीं हैं। इसलिए तीनों गुणांक (0) हैं।

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यदि (r=3), तो (\(r^2-9\)x-7+(r-1)x-4+x-2) की डिग्री क्या होगी?

If (r=3), what will be the degree of (\(r^2-9\)x-7+(r-1)x-4+x-2)?

Explanation opens after your attempt
Correct Answer

B. (4)

Step 1

Concept

For (r=3), the coefficient of \(x^7\) is (0) and the coefficient of \(x^4\) is (2). Therefore the degree is (4).

Step 2

Why this answer is correct

The correct answer is B. (4). For (r=3), the coefficient of \(x^7\) is (0) and the coefficient of \(x^4\) is (2). Therefore the degree is (4).

Step 3

Exam Tip

(r=3) पर \(x^7\) का गुणांक (0) और \(x^4\) का गुणांक (2) होता है। इसलिए डिग्री (4) है।

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व्यंजक (x-3\(x^2-5\)-x-5+9x-3) को सरल करने पर क्या मिलेगा?

What is obtained by simplifying (x-3\(x^2-5\)-x-5+9x-3)?

Explanation opens after your attempt
Correct Answer

B. \(4x^3\)

Step 1

Concept

(x-3\(x^2-5\)=x-5-5x-3), then \(-x^5\) cancels \(x^5\). The simplified form is \(4x^3\).

Step 2

Why this answer is correct

The correct answer is B. \(4x^3\). (x-3\(x^2-5\)=x-5-5x-3), then \(-x^5\) cancels \(x^5\). The simplified form is \(4x^3\).

Step 3

Exam Tip

(x-3\(x^2-5\)=x-5-5x-3), फिर \(-x^5\) से \(x^5\) कटता है। सरल रूप \(4x^3\) है।

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सरल रूप \(4x^3\) किस प्रकार का बहुपद है?

What type of polynomial is the simplified form \(4x^3\)?

Explanation opens after your attempt
Correct Answer

C. त्रिघात एकपदी बहुपदCubic monomial polynomial

Step 1

Concept

\(4x^3\) has one term and the highest power is (3). So it is a cubic monomial polynomial.

Step 2

Why this answer is correct

The correct answer is C. त्रिघात एकपदी बहुपद / Cubic monomial polynomial. \(4x^3\) has one term and the highest power is (3). So it is a cubic monomial polynomial.

Step 3

Exam Tip

\(4x^3\) में एक पद है और सबसे बड़ी घात (3) है। इसलिए यह त्रिघात एकपदी बहुपद है।

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कौन सा निष्कर्ष \(x^0+\sqrt{2}x^5-\frac{4x^2}{9}\) के लिए सही है?

Which conclusion is correct for \(x^0+\sqrt{2}x^5-\frac{4x^2}{9}\)?

Explanation opens after your attempt
Correct Answer

B. यह बहुपद है और डिग्री (5) हैIt is a polynomial and degree is (5)

Step 1

Concept

\(\sqrt{2}\) and \(-\frac{4}{9}\) are real coefficients. The powers of (x) are (0), (5), and (2).

Step 2

Why this answer is correct

The correct answer is B. यह बहुपद है और डिग्री (5) है / It is a polynomial and degree is (5). \(\sqrt{2}\) and \(-\frac{4}{9}\) are real coefficients. The powers of (x) are (0), (5), and (2).

Step 3

Exam Tip

\(\sqrt{2}\) और \(-\frac{4}{9}\) वास्तविक गुणांक हैं। (x) की घातें (0), (5), और (2) हैं।

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यदि (d=-1), तो ((d+1)x-5+(2d+3)x-2+7) की डिग्री क्या होगी?

If (d=-1), what will be the degree of ((d+1)x-5+(2d+3)x-2+7)?

Explanation opens after your attempt
Correct Answer

B. (2)

Step 1

Concept

Putting (d=-1) makes the coefficient of \(x^5\) equal to (0) and the coefficient of \(x^2\) equal to (1). So the highest power is (2).

Step 2

Why this answer is correct

The correct answer is B. (2). Putting (d=-1) makes the coefficient of \(x^5\) equal to (0) and the coefficient of \(x^2\) equal to (1). So the highest power is (2).

Step 3

Exam Tip

(d=-1) रखने पर \(x^5\) का गुणांक (0) और \(x^2\) का गुणांक (1) होता है। इसलिए सबसे बड़ी घात (2) है।

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किस मान पर ((2a-8)x-6+(a+1)x-3+4) की डिग्री (3) होगी?

For which value will the degree of ((2a-8)x-6+(a+1)x-3+4) be (3)?

Explanation opens after your attempt
Correct Answer

C. (a=4)

Step 1

Concept

For degree (3), the coefficient of \(x^6\) must be (0) and the coefficient of \(x^3\) must remain non-zero. From (2a-8=0), (a=4).

Step 2

Why this answer is correct

The correct answer is C. (a=4). For degree (3), the coefficient of \(x^6\) must be (0) and the coefficient of \(x^3\) must remain non-zero. From (2a-8=0), (a=4).

Step 3

Exam Tip

डिग्री (3) के लिए \(x^6\) का गुणांक (0) होना चाहिए और \(x^3\) का गुणांक अशून्य रहना चाहिए। (2a-8=0) से (a=4) मिलता है।

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व्यंजक \(\frac{x^2-4}{x-2}\) मूल रूप में बहुपद क्यों नहीं माना जाता?

Why is \(\frac{x^2-4}{x-2}\) not considered a polynomial in its original form?

Explanation opens after your attempt
Correct Answer

C. क्योंकि चर हर में हैBecause the variable is in the denominator

Step 1

Concept

In the original form, the denominator is (x-2), so it is not directly called a polynomial. Even after simplifying, the condition \(x\neq2\) remains.

Step 2

Why this answer is correct

The correct answer is C. क्योंकि चर हर में है / Because the variable is in the denominator. In the original form, the denominator is (x-2), so it is not directly called a polynomial. Even after simplifying, the condition \(x\neq2\) remains.

Step 3

Exam Tip

मूल रूप में हर (x-2) है, इसलिए यह सीधे बहुपद नहीं कहलाता। सरल करने पर भी \(x\neq2\) की शर्त रहती है।

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\(\frac{x^2-4}{x-2}\) को \(x\neq2\) पर सरल करने से क्या मिलेगा?

What is obtained by simplifying \(\frac{x^2-4}{x-2}\) for \(x\neq2\)?

Explanation opens after your attempt
Correct Answer

B. (x+2)

Step 1

Concept

(\frac{x-2-4}{x-2}=\frac{(x-2)(x+2)}{x-2}=x+2) when \(x\neq2\). Factor first.

Step 2

Why this answer is correct

The correct answer is B. (x+2). (\frac{x-2-4}{x-2}=\frac{(x-2)(x+2)}{x-2}=x+2) when \(x\neq2\). Factor first.

Step 3

Exam Tip

(\frac{x-2-4}{x-2}=\frac{(x-2)(x+2)}{x-2}=x+2) जब \(x\neq2\)। पहले गुणनखंड बनाएं।

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सरल रूप (x+2) किस प्रकार का बहुपद है?

What type of polynomial is the simplified form (x+2)?

Explanation opens after your attempt
Correct Answer

D. रेखीय बहुपदLinear polynomial

Step 1

Concept

In (x+2), the highest power is (1). Therefore it is a linear polynomial.

Step 2

Why this answer is correct

The correct answer is D. रेखीय बहुपद / Linear polynomial. In (x+2), the highest power is (1). Therefore it is a linear polynomial.

Step 3

Exam Tip

(x+2) में सबसे बड़ी घात (1) है। इसलिए यह रेखीय बहुपद है।

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कौन सा व्यंजक (x) में बहुपद है लेकिन \(x^3\) का गुणांक (0) है?

Which expression is a polynomial in (x) but has coefficient of \(x^3\) equal to (0)?

Explanation opens after your attempt
Correct Answer

A. \(2x^4-5x^2+1\)

Step 1

Concept

\(2x^4-5x^2+1\) is a polynomial and the \(x^3\) term is absent. So the coefficient of \(x^3\) is (0).

Step 2

Why this answer is correct

The correct answer is A. \(2x^4-5x^2+1\). \(2x^4-5x^2+1\) is a polynomial and the \(x^3\) term is absent. So the coefficient of \(x^3\) is (0).

Step 3

Exam Tip

\(2x^4-5x^2+1\) बहुपद है और इसमें \(x^3\) पद अनुपस्थित है। इसलिए \(x^3\) का गुणांक (0) है।

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किस विकल्प में बहुपद है और उसके सभी अशून्य पदों की घातें सम हैं?

Which option is a polynomial and all its non-zero variable terms have even powers?

Explanation opens after your attempt
Correct Answer

B. \(3x^4-2x^2+9\)

Step 1

Concept

In \(3x^4-2x^2+9\), the non-zero variable term powers are (4) and (2). Both are even and valid powers.

Step 2

Why this answer is correct

The correct answer is B. \(3x^4-2x^2+9\). In \(3x^4-2x^2+9\), the non-zero variable term powers are (4) and (2). Both are even and valid powers.

Step 3

Exam Tip

\(3x^4-2x^2+9\) में चर वाले अशून्य पदों की घातें (4) और (2) हैं। दोनों सम और मान्य घातें हैं।

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व्यंजक (\(w^2-1\)x-4+(w-1)x-2+6) नियतांक बहुपद कब बनेगा?

When will (\(w^2-1\)x-4+(w-1)x-2+6) become a constant polynomial?

Explanation opens after your attempt
Correct Answer

A. जब (w=1)When (w=1)

Step 1

Concept

To become constant, both \(w^2-1=0\) and (w-1=0) are needed. Both conditions are satisfied together at (w=1).

Step 2

Why this answer is correct

The correct answer is A. जब (w=1) / When (w=1). To become constant, both \(w^2-1=0\) and (w-1=0) are needed. Both conditions are satisfied together at (w=1).

Step 3

Exam Tip

नियतांक बनने के लिए \(w^2-1=0\) और (w-1=0) दोनों चाहिए। दोनों शर्तें साथ में (w=1) पर पूरी होती हैं।

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यदि (z=-2), तो ((z+2)x-5+\(z^2-4\)x-3+9x-1) की डिग्री क्या होगी?

If (z=-2), what will be the degree of ((z+2)x-5+\(z^2-4\)x-3+9x-1)?

Explanation opens after your attempt
Correct Answer

C. (1)

Step 1

Concept

For (z=-2), the coefficients of both \(x^5\) and \(x^3\) become (0). The remaining highest power is (1).

Step 2

Why this answer is correct

The correct answer is C. (1). For (z=-2), the coefficients of both \(x^5\) and \(x^3\) become (0). The remaining highest power is (1).

Step 3

Exam Tip

(z=-2) पर \(x^5\) और \(x^3\) दोनों के गुणांक (0) हो जाते हैं। बची हुई सबसे बड़ी घात (1) है।

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कौन सा व्यंजक बहुपद नहीं है क्योंकि उसमें चर घात के रूप में है?

Which expression is not a polynomial because the variable appears as an exponent?

Explanation opens after your attempt
Correct Answer

A. \(2^x+3\)

Step 1

Concept

In \(2^x\), the variable is in the exponent. In a polynomial, the variable is the base with a non-negative integer power.

Step 2

Why this answer is correct

The correct answer is A. \(2^x+3\). In \(2^x\), the variable is in the exponent. In a polynomial, the variable is the base with a non-negative integer power.

Step 3

Exam Tip

\(2^x\) में चर घात के स्थान पर है। बहुपद में चर आधार में होता है और उसकी घात अऋणात्मक पूर्णांक होती है।

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कौन सा व्यंजक (x) में बहुपद है और उसकी डिग्री (0) है?

Which expression is a polynomial in (x) and has degree (0)?

Explanation opens after your attempt
Correct Answer

B. (6y-4)

Step 1

Concept

With respect to (x), (6y-4) is a non-zero constant. Therefore it is a polynomial in (x) of degree (0).

Step 2

Why this answer is correct

The correct answer is B. (6y-4). With respect to (x), (6y-4) is a non-zero constant. Therefore it is a polynomial in (x) of degree (0).

Step 3

Exam Tip

(x) के संदर्भ में (6y-4) अशून्य नियतांक है। इसलिए यह (x) में डिग्री (0) का बहुपद है।

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व्यंजक \(x^4-4x^2+4\) में \(x^3\) और (x) के गुणांक क्रमशः क्या हैं?

In \(x^4-4x^2+4\), what are the coefficients of \(x^3\) and (x) respectively?

Explanation opens after your attempt
Correct Answer

B. (0) और (0)(0) and (0)

Step 1

Concept

The \(x^3\) and (x) terms are not present in this polynomial. Therefore both coefficients are (0).

Step 2

Why this answer is correct

The correct answer is B. (0) और (0) / (0) and (0). The \(x^3\) and (x) terms are not present in this polynomial. Therefore both coefficients are (0).

Step 3

Exam Tip

इस बहुपद में \(x^3\) और (x) पद नहीं हैं। इसलिए दोनों गुणांक (0) हैं।

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कौन सा विकल्प बहुपद और अपूर्ण बहुपद दोनों की सही पहचान करता है?

Which option correctly identifies a polynomial with missing powers?

Explanation opens after your attempt
Correct Answer

A. \(x^5+x^2+1\) में \(x^4\) और \(x^3\) के गुणांक (0) हैंIn \(x^5+x^2+1\), coefficients of \(x^4\) and \(x^3\) are (0)

Step 1

Concept

Coefficients of absent terms are taken as (0). Here the \(x^4\) and \(x^3\) terms are absent.

Step 2

Why this answer is correct

The correct answer is A. \(x^5+x^2+1\) में \(x^4\) और \(x^3\) के गुणांक (0) हैं / In \(x^5+x^2+1\), coefficients of \(x^4\) and \(x^3\) are (0). Coefficients of absent terms are taken as (0). Here the \(x^4\) and \(x^3\) terms are absent.

Step 3

Exam Tip

अनुपस्थित पदों के गुणांक (0) माने जाते हैं। यहां \(x^4\) और \(x^3\) पद नहीं हैं।

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FAQs

Class 9 Mathematics Quiz FAQs

How many questions are in this quiz?

This level is designed for 50 active questions. Currently 50 questions are available for the selected class and difficulty.

Is there a timer in this quiz?

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Can I open each question separately?

Yes, every question has its own SEO-friendly page with answer, explanation and related practice links.