यदि (n=-2), तो (\(n^2-4\)x-6+(n+5)x-3-7) की डिग्री क्या होगी?
If (n=-2), what will be the degree of (\(n^2-4\)x-6+(n+5)x-3-7)?
Explanation opens after your attempt
B. (3)
Concept
Putting (n=-2), the coefficient of \(x^6\) is (0) and the coefficient of \(x^3\) is (3). Therefore the degree is (3).
Why this answer is correct
The correct answer is B. (3). Putting (n=-2), the coefficient of \(x^6\) is (0) and the coefficient of \(x^3\) is (3). Therefore the degree is (3).
Exam Tip
(n=-2) रखने पर \(x^6\) का गुणांक (0) और \(x^3\) का गुणांक (3) होता है। इसलिए डिग्री (3) है।
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