व्यंजक ((r+4)x-2+(r-1)x+10) नियतांक बहुपद कब बनेगा?

When will ((r+4)x-2+(r-1)x+10) become a constant polynomial?

Explanation opens after your attempt
Correct Answer

D. कभी नहींNever

Step 1

Concept

To become constant, both (r+4=0) and (r-1=0) are required. One value of (r) cannot satisfy both conditions.

Step 2

Why this answer is correct

The correct answer is D. कभी नहीं / Never. To become constant, both (r+4=0) and (r-1=0) are required. One value of (r) cannot satisfy both conditions.

Step 3

Exam Tip

नियतांक बनने के लिए (r+4=0) और (r-1=0) दोनों चाहिए। एक ही (r) दोनों शर्तें पूरी नहीं कर सकता।

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Mathematics Answer, Explanation and Revision Hints

व्यंजक ((r+4)x-2+(r-1)x+10) नियतांक बहुपद कब बनेगा? / When will ((r+4)x-2+(r-1)x+10) become a constant polynomial?

Correct Answer: D. कभी नहीं / Never. Explanation: नियतांक बनने के लिए (r+4=0) और (r-1=0) दोनों चाहिए। एक ही (r) दोनों शर्तें पूरी नहीं कर सकता। / To become constant, both (r+4=0) and (r-1=0) are required. One value of (r) cannot satisfy both conditions.

Which concept should I revise for this Mathematics MCQ?

To become constant, both (r+4=0) and (r-1=0) are required. One value of (r) cannot satisfy both conditions.

What exam hint can help solve this Mathematics question?

नियतांक बनने के लिए (r+4=0) और (r-1=0) दोनों चाहिए। एक ही (r) दोनों शर्तें पूरी नहीं कर सकता।