यदि (q(x)=x-6+x^{\frac{3}{2}}+2), तो (q(x)) बहुपद क्यों नहीं है?
If (q(x)=x-6+x^{\frac{3}{2}}+2), why is (q(x)) not a polynomial?
Explanation opens after your attempt
Correct Answer
C. क्योंकि \(x^{\frac{3}{2}}\) की घात भिन्न हैBecause \(x^{\frac{3}{2}}\) has a fractional power
Concept
In \(x^{\frac{3}{2}}\), the variable has a fractional power. Fractional powers are not valid in a polynomial.
Why this answer is correct
The correct answer is C. क्योंकि \(x^{\frac{3}{2}}\) की घात भिन्न है / Because \(x^{\frac{3}{2}}\) has a fractional power. In \(x^{\frac{3}{2}}\), the variable has a fractional power. Fractional powers are not valid in a polynomial.
Exam Tip
\(x^{\frac{3}{2}}\) में चर की घात भिन्न है। बहुपद में भिन्न घात मान्य नहीं होती।
Login to save your score, XP, coins and progress.