Level 27 • 50/50 questions • 30 seconds per question.
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What is the degree of \(0x^8-5x^4+3x^2-6\)?
B. (4)
The term \(0x^8\) becomes zero. The remaining highest power is (4).
The correct answer is B. (4). The term \(0x^8\) becomes zero. The remaining highest power is (4).
\(0x^8\) पद शून्य हो जाता है। बची हुई सबसे बड़ी घात (4) है।
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When will the degree of ((a-2)x-5+4x-3-1) be (5)?
D. जब \(a\neq2\)When \(a\neq2\)
The degree will be (5) only when the coefficient of \(x^5\) is not zero. Therefore \(a-2\neq0\).
The correct answer is D. जब \(a\neq2\) / When \(a\neq2\). The degree will be (5) only when the coefficient of \(x^5\) is not zero. Therefore \(a-2\neq0\).
डिग्री (5) तभी होगी जब \(x^5\) का गुणांक शून्य न हो। इसलिए \(a-2\neq0\) होना चाहिए।
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If (k=-3), what will be the degree of ((k+3)x-6+2x-2+x-7)?
A. (2)
Putting (k=-3) makes the coefficient of \(x^6\) equal to (0). In the remaining polynomial, the highest power is (2).
The correct answer is A. (2). Putting (k=-3) makes the coefficient of \(x^6\) equal to (0). In the remaining polynomial, the highest power is (2).
(k=-3) रखने पर \(x^6\) का गुणांक (0) हो जाता है। शेष बहुपद में सबसे बड़ी घात (2) है।
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For which value will ((m-4)x-3+7x-2) become a linear polynomial?
B. (m=4)
To become linear, the coefficient of \(x^3\) must be (0). From (m-4=0), we get (m=4).
The correct answer is B. (m=4). To become linear, the coefficient of \(x^3\) must be (0). From (m-4=0), we get (m=4).
रेखीय बनने के लिए \(x^3\) का गुणांक (0) होना चाहिए। (m-4=0) से (m=4) मिलता है।
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Why is \(5x^2+\sqrt{x+4}\) not a polynomial?
C. क्योंकि (x+4) मूल चिह्न के अंदर हैBecause (x+4) is inside a radical sign
\(\sqrt{x+4}\) is not written using non-negative integer powers of (x). Therefore the whole expression is not a polynomial.
The correct answer is C. क्योंकि (x+4) मूल चिह्न के अंदर है / Because (x+4) is inside a radical sign. \(\sqrt{x+4}\) is not written using non-negative integer powers of (x). Therefore the whole expression is not a polynomial.
\(\sqrt{x+4}\) को (x) की अऋणात्मक पूर्णांक घातों के रूप में नहीं लिखा जाता। इसलिए पूरा व्यंजक बहुपद नहीं है।
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If (p(x)=3x-4-2x-2+0x+5), what is the coefficient of (x)?
D. (0)
The term containing (x) is (0x). Therefore the coefficient of (x) is (0).
The correct answer is D. (0). The term containing (x) is (0x). Therefore the coefficient of (x) is (0).
(x) वाला पद (0x) है। इसलिए (x) का गुणांक (0) है।
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Which option is a cubic polynomial in (x)?
A. \(2x^3-\sqrt{5}x^2+1\)
In the first expression, the highest power is (3), and all powers are valid. So it is a cubic polynomial.
The correct answer is A. \(2x^3-\sqrt{5}x^2+1\). In the first expression, the highest power is (3), and all powers are valid. So it is a cubic polynomial.
पहले व्यंजक में सबसे बड़ी घात (3) है और सभी घातें मान्य हैं। इसलिए यह त्रिघात बहुपद है।
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Why is \(\frac{x^4+2x}{x}\) not considered a polynomial in its original form?
A. क्योंकि चर हर में हैBecause the variable is in the denominator
In the original form, (x) is in the denominator, so it is not directly called a polynomial. For simplification, keep the condition \(x\neq0\) in mind.
The correct answer is A. क्योंकि चर हर में है / Because the variable is in the denominator. In the original form, (x) is in the denominator, so it is not directly called a polynomial. For simplification, keep the condition \(x\neq0\) in mind.
मूल रूप में हर में (x) है, इसलिए इसे सीधे बहुपद नहीं कहते। सरल रूप के लिए \(x\neq0\) की शर्त ध्यान रखें।
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What is obtained by simplifying \(\frac{x^4+2x}{x}\) for \(x\neq0\)?
A. \(x^3+2\)
For \(x\neq0\), \(\frac{x^4}{x}=x^3\) and \(\frac{2x}{x}=2\). So the simplified form is \(x^3+2\).
The correct answer is A. \(x^3+2\). For \(x\neq0\), \(\frac{x^4}{x}=x^3\) and \(\frac{2x}{x}=2\). So the simplified form is \(x^3+2\).
\(x\neq0\) पर \(\frac{x^4}{x}=x^3\) और \(\frac{2x}{x}=2\) होता है। इसलिए सरल रूप \(x^3+2\) है।
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What is the degree of the simplified form \(x^3+2\)?
B. (3)
In \(x^3+2\), the highest power is (3). Therefore its degree is (3).
The correct answer is B. (3). In \(x^3+2\), the highest power is (3). Therefore its degree is (3).
\(x^3+2\) में सबसे बड़ी घात (3) है। इसलिए इसकी डिग्री (3) है।
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Is \(2x^2+3|x|-5\) a polynomial or not?
C. नहीं क्योंकि (|x|) बहुपद पद नहीं हैNo because (|x|) is not a polynomial term
(|x|) is not written as a term with non-negative integer powers of (x). Therefore it is not a polynomial.
The correct answer is C. नहीं क्योंकि (|x|) बहुपद पद नहीं है / No because (|x|) is not a polynomial term. (|x|) is not written as a term with non-negative integer powers of (x). Therefore it is not a polynomial.
(|x|) को (x) की अऋणात्मक पूर्णांक घातों वाले पद के रूप में नहीं लिखा जाता। इसलिए यह बहुपद नहीं है।
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If \(a\neq0\) and \(b\neq0\), what will be the degree of \(ax^7+bx^3+2\)?
C. (7)
Since \(a\neq0\), the \(x^7\) term remains present. Therefore the highest power is (7).
The correct answer is C. (7). Since \(a\neq0\), the \(x^7\) term remains present. Therefore the highest power is (7).
\(a\neq0\) होने से \(x^7\) पद मौजूद रहेगा। इसलिए सबसे बड़ी घात (7) है।
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If (a=0) and \(b\neq0\), what will be the degree of \(ax^7+bx^3+2\)?
B. (3)
When (a=0), the \(x^7\) term disappears. Since \(b\neq0\), the \(x^3\) term remains.
The correct answer is B. (3). When (a=0), the \(x^7\) term disappears. Since \(b\neq0\), the \(x^3\) term remains.
(a=0) होने से \(x^7\) पद हट जाता है। \(b\neq0\) होने से \(x^3\) पद बचता है।
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When will (\(t^2-4\)x-2+5x+3) become a linear polynomial?
A. जब (t=2) या (t=-2)When (t=2) or (t=-2)
To become linear, the coefficient of \(x^2\) must be (0). From \(t^2-4=0\), we get \(t=\pm2\).
The correct answer is A. जब (t=2) या (t=-2) / When (t=2) or (t=-2). To become linear, the coefficient of \(x^2\) must be (0). From \(t^2-4=0\), we get \(t=\pm2\).
रेखीय बनने के लिए \(x^2\) का गुणांक (0) होना चाहिए। \(t^2-4=0\) से \(t=\pm2\) मिलता है।
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When will ((r-1)x-2+(r+2)x+5) become a constant polynomial?
D. कभी नहींNever
To become constant, both (r-1=0) and (r+2=0) are required. One value of (r) cannot satisfy both conditions.
The correct answer is D. कभी नहीं / Never. To become constant, both (r-1=0) and (r+2=0) are required. One value of (r) cannot satisfy both conditions.
नियतांक बनने के लिए (r-1=0) और (r+2=0) दोनों चाहिए। एक ही (r) दोनों शर्तें पूरी नहीं कर सकता।
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Which expression is a polynomial in (x) while treating (y) as a constant?
A. \(y x^2+3x-4\)
With respect to (x), (y) can be treated like a coefficient. The powers of (x) are (2), (1), and (0).
The correct answer is A. \(y x^2+3x-4\). With respect to (x), (y) can be treated like a coefficient. The powers of (x) are (2), (1), and (0).
(x) के संदर्भ में (y) गुणांक की तरह माना जा सकता है। (x) की घातें (2), (1), और (0) हैं।
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In \(4x^6-3x^4+2\), what are the coefficients of \(x^5\) and (x) respectively?
B. (0) और (0)(0) and (0)
The \(x^5\) and (x) terms are absent in this polynomial. Therefore both coefficients are (0).
The correct answer is B. (0) और (0) / (0) and (0). The \(x^5\) and (x) terms are absent in this polynomial. Therefore both coefficients are (0).
इस बहुपद में \(x^5\) और (x) पद अनुपस्थित हैं। इसलिए दोनों के गुणांक (0) हैं।
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Which expression is not a polynomial in (x) because the variable is in the denominator?
B. \(\frac{7}{x-3}\)
In \(\frac{7}{x-3}\), the variable is in the denominator. Such an expression does not satisfy the definition of a polynomial.
The correct answer is B. \(\frac{7}{x-3}\). In \(\frac{7}{x-3}\), the variable is in the denominator. Such an expression does not satisfy the definition of a polynomial.
\(\frac{7}{x-3}\) में चर हर में है। ऐसा व्यंजक बहुपद की परिभाषा को पूरा नहीं करता।
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If (n=1), what will be the degree of (\(n^2-1\)x-4+(n+2)x-2-6)?
C. (2)
Putting (n=1), the coefficient of \(x^4\) is (0) and the coefficient of \(x^2\) is (3). Therefore the degree is (2).
The correct answer is C. (2). Putting (n=1), the coefficient of \(x^4\) is (0) and the coefficient of \(x^2\) is (3). Therefore the degree is (2).
(n=1) रखने पर \(x^4\) का गुणांक (0) और \(x^2\) का गुणांक (3) होता है। इसलिए डिग्री (2) है।
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Which option has degree (4) and a negative leading coefficient?
B. \(-5x^4+x^2-7\)
\(-5x^4+x^2-7\) has degree (4) and leading coefficient (-5). Therefore both conditions are satisfied.
The correct answer is B. \(-5x^4+x^2-7\). \(-5x^4+x^2-7\) has degree (4) and leading coefficient (-5). Therefore both conditions are satisfied.
\(-5x^4+x^2-7\) की डिग्री (4) है और अग्रणी गुणांक (-5) है। इसलिए दोनों शर्तें पूरी हैं।
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Which polynomial is obtained by simplifying (x-3(x-2)-x-4+6x)?
B. \(-2x^3+6x\)
(x-3(x-2)=x-4-2x-3), then \(-x^4\) cancels \(x^4\). The simplified form is \(-2x^3+6x\).
The correct answer is B. \(-2x^3+6x\). (x-3(x-2)=x-4-2x-3), then \(-x^4\) cancels \(x^4\). The simplified form is \(-2x^3+6x\).
(x-3(x-2)=x-4-2x-3), फिर \(-x^4\) से \(x^4\) कट जाता है। सरल रूप \(-2x^3+6x\) है।
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What is the degree of the simplified form \(-2x^3+6x\)?
C. (3)
In the simplified form, the highest power is (3). Therefore the degree is (3).
The correct answer is C. (3). In the simplified form, the highest power is (3). Therefore the degree is (3).
सरल रूप में सबसे बड़ी घात (3) है। इसलिए डिग्री (3) है।
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Which conclusion is correct for \(x^0+\pi x^3-\frac{2x}{7}\)?
B. यह बहुपद है और डिग्री (3) हैIt is a polynomial and degree is (3)
\(\pi\) and \(-\frac{2}{7}\) are real coefficients. The powers of (x) are (0), (3), and (1), so the degree is (3).
The correct answer is B. यह बहुपद है और डिग्री (3) है / It is a polynomial and degree is (3). \(\pi\) and \(-\frac{2}{7}\) are real coefficients. The powers of (x) are (0), (3), and (1), so the degree is (3).
\(\pi\) और \(-\frac{2}{7}\) वास्तविक गुणांक हैं। (x) की घातें (0), (3), और (1) हैं, इसलिए डिग्री (3) है।
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If (c=0), what will be the degree of (cx-5+(c+1)x-4-3x+2)?
B. (4)
When (c=0), the \(x^5\) term disappears and the coefficient of \(x^4\) remains (1). Therefore the degree is (4).
The correct answer is B. (4). When (c=0), the \(x^5\) term disappears and the coefficient of \(x^4\) remains (1). Therefore the degree is (4).
(c=0) होने पर \(x^5\) पद हट जाता है और \(x^4\) का गुणांक (1) रहता है। इसलिए डिग्री (4) है।
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What is obtained by simplifying \(x^2+\frac{x^2-1}{x+1}\) for \(x\neq-1\)?
A. \(x^2+x-1\)
\(\frac{x^2-1}{x+1}=x-1\) when \(x\neq-1\). So the simplified form is \(x^2+x-1\).
The correct answer is A. \(x^2+x-1\). \(\frac{x^2-1}{x+1}=x-1\) when \(x\neq-1\). So the simplified form is \(x^2+x-1\).
\(\frac{x^2-1}{x+1}=x-1\) जब \(x\neq-1\)। इसलिए सरल रूप \(x^2+x-1\) है।
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What type of polynomial is the simplified form \(x^2+x-1\)?
B. द्विघात बहुपदQuadratic polynomial
In \(x^2+x-1\), the highest power is (2). Therefore it is a quadratic polynomial.
The correct answer is B. द्विघात बहुपद / Quadratic polynomial. In \(x^2+x-1\), the highest power is (2). Therefore it is a quadratic polynomial.
\(x^2+x-1\) में सबसे बड़ी घात (2) है। इसलिए यह द्विघात बहुपद है।
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Which option contains a polynomial of degree (0)?
B. \(\sqrt{5}\)
\(\sqrt{5}\) is a non-zero constant polynomial. A non-zero constant polynomial has degree (0).
The correct answer is B. \(\sqrt{5}\). \(\sqrt{5}\) is a non-zero constant polynomial. A non-zero constant polynomial has degree (0).
\(\sqrt{5}\) अशून्य नियतांक बहुपद है। अशून्य नियतांक बहुपद की डिग्री (0) होती है।
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What is the degree of \(x^5+x^3+x^0\)?
C. (5)
\(x^0=1\), and the highest power is (5). Therefore the degree is (5).
The correct answer is C. (5). \(x^0=1\), and the highest power is (5). Therefore the degree is (5).
\(x^0=1\) होता है और सबसे बड़ी घात (5) है। इसलिए डिग्री (5) है।
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If \(a\neq0\), (b=0), what will be the degree of \(ax^2+bx^5-4\)?
B. (2)
Since (b=0), the \(x^5\) term disappears. Since \(a\neq0\), the \(x^2\) term remains.
The correct answer is B. (2). Since (b=0), the \(x^5\) term disappears. Since \(a\neq0\), the \(x^2\) term remains.
(b=0) होने से \(x^5\) पद हट जाता है। \(a\neq0\) होने से \(x^2\) पद बचता है।
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How many non-zero terms are there in \(6x^4-2x^3+0x^2+5x-9\)?
B. (4)
\(0x^2\) is a zero term, so it is not counted. The remaining (4) terms are non-zero.
The correct answer is B. (4). \(0x^2\) is a zero term, so it is not counted. The remaining (4) terms are non-zero.
\(0x^2\) शून्य पद है, इसलिए उसे नहीं गिनते। बाकी (4) पद अशून्य हैं।
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Which expression is a constant polynomial in (x)?
A. \(3y^2-5y+1\)
With respect to (x), \(3y^2-5y+1\) has no (x) term. So it can be treated as a constant polynomial in (x).
The correct answer is A. \(3y^2-5y+1\). With respect to (x), \(3y^2-5y+1\) has no (x) term. So it can be treated as a constant polynomial in (x).
(x) के संदर्भ में \(3y^2-5y+1\) में कोई (x) पद नहीं है। इसलिए यह (x) में नियतांक बहुपद माना जा सकता है।
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Which statement is correct for \(\frac{x^3}{4}-\sqrt{6}x+10\)?
B. यह बहुपद है और डिग्री (3) हैIt is a polynomial and degree is (3)
Fractional and irrational real coefficients are valid in a polynomial. The highest power is (3).
The correct answer is B. यह बहुपद है और डिग्री (3) है / It is a polynomial and degree is (3). Fractional and irrational real coefficients are valid in a polynomial. The highest power is (3).
भिन्न और अपरिमेय वास्तविक गुणांक बहुपद में मान्य हैं। सबसे बड़ी घात (3) है।
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In which option are all coefficients real and powers of (x) valid?
A. \(2x^3-\pi x^2+\sqrt{13}\)
\(\pi\) and \(\sqrt{13}\) are real coefficients. The powers of (x) are (3), (2), and (0).
The correct answer is A. \(2x^3-\pi x^2+\sqrt{13}\). \(\pi\) and \(\sqrt{13}\) are real coefficients. The powers of (x) are (3), (2), and (0).
\(\pi\) और \(\sqrt{13}\) वास्तविक गुणांक हैं। (x) की घातें (3), (2), और (0) हैं।
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If (q(x)=x-4+x^{\frac{1}{2}}+1), why is (q(x)) not a polynomial?
C. क्योंकि \(x^{\frac{1}{2}}\) की घात भिन्न हैBecause \(x^{\frac{1}{2}}\) has a fractional power
In \(x^{\frac{1}{2}}\), the variable has a fractional power. Such a power is not valid in a polynomial.
The correct answer is C. क्योंकि \(x^{\frac{1}{2}}\) की घात भिन्न है / Because \(x^{\frac{1}{2}}\) has a fractional power. In \(x^{\frac{1}{2}}\), the variable has a fractional power. Such a power is not valid in a polynomial.
\(x^{\frac{1}{2}}\) में चर की घात भिन्न है। बहुपद में ऐसी घात मान्य नहीं होती।
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When will ((u-5)x-3+(u-5)x-2+7) become a constant polynomial?
A. जब (u=5)When (u=5)
To become constant, the coefficients of both \(x^3\) and \(x^2\) must be (0). From (u-5=0), both terms disappear.
The correct answer is A. जब (u=5) / When (u=5). To become constant, the coefficients of both \(x^3\) and \(x^2\) must be (0). From (u-5=0), both terms disappear.
नियतांक बनने के लिए \(x^3\) और \(x^2\) दोनों के गुणांक (0) चाहिए। (u-5=0) से दोनों पद हट जाते हैं।
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Which expression is a polynomial whose degree is greater than (2)?
C. \(x^5-3x+2\)
\(x^5-3x+2\) is a polynomial and its degree is (5). (5) is greater than (2).
The correct answer is C. \(x^5-3x+2\). \(x^5-3x+2\) is a polynomial and its degree is (5). (5) is greater than (2).
\(x^5-3x+2\) बहुपद है और इसकी डिग्री (5) है। (5), (2) से अधिक है।
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In \(7x^5-4x^3+8\), what are the coefficients of \(x^4\), \(x^2\), and (x)?
B. (0), (0), और (0)(0), (0), and (0)
The terms with these three powers are absent in the polynomial. Therefore their coefficients are (0), (0), and (0).
The correct answer is B. (0), (0), और (0) / (0), (0), and (0). The terms with these three powers are absent in the polynomial. Therefore their coefficients are (0), (0), and (0).
इन तीनों घातों वाले पद बहुपद में अनुपस्थित हैं। इसलिए इनके गुणांक (0), (0), और (0) हैं।
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If (r=2), what will be the degree of (\(r^2-4\)x-5+(r-1)x-4+x)?
B. (4)
For (r=2), the coefficient of \(x^5\) is (0) and the coefficient of \(x^4\) is (1). Therefore the degree is (4).
The correct answer is B. (4). For (r=2), the coefficient of \(x^5\) is (0) and the coefficient of \(x^4\) is (1). Therefore the degree is (4).
(r=2) पर \(x^5\) का गुणांक (0) और \(x^4\) का गुणांक (1) होता है। इसलिए डिग्री (4) है।
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Which expression is not the zero polynomial in (x)?
C. \(x^0-1\)
\(x^0-1=1-1=0\), so this is also the zero polynomial. Check simplification before choosing.
The correct answer is C. \(x^0-1\). \(x^0-1=1-1=0\), so this is also the zero polynomial. Check simplification before choosing.
\(x^0-1=1-1=0\) है, इसलिए यह भी शून्य बहुपद है? ध्यान दें कि विकल्प (C) शून्य ही है।
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Which option has degree (3) and a negative leading coefficient?
B. \(-6x^3+x^2-5\)
\(-6x^3+x^2-5\) has degree (3) and leading coefficient (-6). Therefore it is the correct option.
The correct answer is B. \(-6x^3+x^2-5\). \(-6x^3+x^2-5\) has degree (3) and leading coefficient (-6). Therefore it is the correct option.
\(-6x^3+x^2-5\) की डिग्री (3) है और अग्रणी गुणांक (-6) है। इसलिए यह सही विकल्प है।
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What is obtained by simplifying (x-2\(x^2-3\)-x-4+2x)?
B. \(-3x^2+2x\)
(x-2\(x^2-3\)=x-4-3x-2), then \(-x^4\) cancels \(x^4\). The simplified form is \(-3x^2+2x\).
The correct answer is B. \(-3x^2+2x\). (x-2\(x^2-3\)=x-4-3x-2), then \(-x^4\) cancels \(x^4\). The simplified form is \(-3x^2+2x\).
(x-2\(x^2-3\)=x-4-3x-2), फिर \(-x^4\) से \(x^4\) कटता है। सरल रूप \(-3x^2+2x\) है।
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What type of polynomial is the simplified form \(-3x^2+2x\)?
B. द्विघात बहुपदQuadratic polynomial
In the simplified form, the highest power is (2). Therefore it is a quadratic polynomial.
The correct answer is B. द्विघात बहुपद / Quadratic polynomial. In the simplified form, the highest power is (2). Therefore it is a quadratic polynomial.
सरल रूप में सबसे बड़ी घात (2) है। इसलिए यह द्विघात बहुपद है।
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If (h=1), what will be the degree of ((h-1)x-6+(h+2)x-3-4x+9)?
B. (3)
Putting (h=1) makes the coefficient of \(x^6\) equal to (0). The remaining highest power is (3).
The correct answer is B. (3). Putting (h=1) makes the coefficient of \(x^6\) equal to (0). The remaining highest power is (3).
(h=1) रखने पर \(x^6\) का गुणांक (0) हो जाता है। बची हुई सबसे बड़ी घात (3) है।
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For which value will the degree of ((2a+6)x-4+5x-2-1) be (2)?
C. (a=-3)
For degree (2), the coefficient of \(x^4\) must be (0). From (2a+6=0), we get (a=-3).
The correct answer is C. (a=-3). For degree (2), the coefficient of \(x^4\) must be (0). From (2a+6=0), we get (a=-3).
डिग्री (2) के लिए \(x^4\) का गुणांक (0) होना चाहिए। (2a+6=0) से (a=-3) मिलता है।
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What is obtained by simplifying \(\frac{x^5-x}{x}\) for \(x\neq0\)?
A. \(x^4-1\)
For \(x\neq0\), \(\frac{x^5}{x}=x^4\) and \(\frac{x}{x}=1\). So the simplified form is \(x^4-1\).
The correct answer is A. \(x^4-1\). For \(x\neq0\), \(\frac{x^5}{x}=x^4\) and \(\frac{x}{x}=1\). So the simplified form is \(x^4-1\).
\(x\neq0\) पर \(\frac{x^5}{x}=x^4\) और \(\frac{x}{x}=1\) होता है। इसलिए सरल रूप \(x^4-1\) है।
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What is the degree of the simplified form \(x^4-1\)?
D. (4)
In \(x^4-1\), the highest power is (4). Therefore its degree is (4).
The correct answer is D. (4). In \(x^4-1\), the highest power is (4). Therefore its degree is (4).
\(x^4-1\) में सबसे बड़ी घात (4) है। इसलिए इसकी डिग्री (4) है।
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Which expression is a polynomial but has degree less than (5)?
C. \(3x^4-7x+6\)
\(3x^4-7x+6\) is a polynomial and its degree is (4). (4) is less than (5).
The correct answer is C. \(3x^4-7x+6\). \(3x^4-7x+6\) is a polynomial and its degree is (4). (4) is less than (5).
\(3x^4-7x+6\) बहुपद है और इसकी डिग्री (4) है। (4), (5) से कम है।
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When will ((v+1)x-2+(v-2)x+3) become a constant polynomial?
D. कभी नहींNever
To become constant, both (v+1=0) and (v-2=0) are required. One value of (v) cannot satisfy both conditions.
The correct answer is D. कभी नहीं / Never. To become constant, both (v+1=0) and (v-2=0) are required. One value of (v) cannot satisfy both conditions.
नियतांक बनने के लिए (v+1=0) और (v-2=0) दोनों चाहिए। एक ही (v) दोनों शर्तें पूरी नहीं कर सकता।
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Which option has degree (2) and coefficient of (x) equal to (0)?
A. \(4x^2-9\)
\(4x^2-9\) has degree (2), and the (x) term is absent. So the coefficient of (x) is (0).
The correct answer is A. \(4x^2-9\). \(4x^2-9\) has degree (2), and the (x) term is absent. So the coefficient of (x) is (0).
\(4x^2-9\) की डिग्री (2) है और (x) पद अनुपस्थित है। इसलिए (x) का गुणांक (0) है।
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Which polynomial is obtained by simplifying \(x^3+\frac{x^2-4}{x-2}\) for \(x\neq2\)?
A. \(x^3+x+2\)
\(\frac{x^2-4}{x-2}=x+2\) when \(x\neq2\). Therefore the simplified form is \(x^3+x+2\).
The correct answer is A. \(x^3+x+2\). \(\frac{x^2-4}{x-2}=x+2\) when \(x\neq2\). Therefore the simplified form is \(x^3+x+2\).
\(\frac{x^2-4}{x-2}=x+2\) जब \(x\neq2\)। इसलिए सरल रूप \(x^3+x+2\) है।
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