व्यंजक \(x^2+\frac{x^2-1}{x+1}\) को \(x\neq-1\) पर सरल करने से क्या मिलेगा?
What is obtained by simplifying \(x^2+\frac{x^2-1}{x+1}\) for \(x\neq-1\)?
Explanation opens after your attempt
Correct Answer
A. \(x^2+x-1\)
Concept
\(\frac{x^2-1}{x+1}=x-1\) when \(x\neq-1\). So the simplified form is \(x^2+x-1\).
Why this answer is correct
The correct answer is A. \(x^2+x-1\). \(\frac{x^2-1}{x+1}=x-1\) when \(x\neq-1\). So the simplified form is \(x^2+x-1\).
Exam Tip
\(\frac{x^2-1}{x+1}=x-1\) जब \(x\neq-1\)। इसलिए सरल रूप \(x^2+x-1\) है।
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