यदि (q(x)=x-4+x^{\frac{1}{2}}+1), तो (q(x)) बहुपद क्यों नहीं है?
If (q(x)=x-4+x^{\frac{1}{2}}+1), why is (q(x)) not a polynomial?
Explanation opens after your attempt
Correct Answer
C. क्योंकि \(x^{\frac{1}{2}}\) की घात भिन्न हैBecause \(x^{\frac{1}{2}}\) has a fractional power
Concept
In \(x^{\frac{1}{2}}\), the variable has a fractional power. Such a power is not valid in a polynomial.
Why this answer is correct
The correct answer is C. क्योंकि \(x^{\frac{1}{2}}\) की घात भिन्न है / Because \(x^{\frac{1}{2}}\) has a fractional power. In \(x^{\frac{1}{2}}\), the variable has a fractional power. Such a power is not valid in a polynomial.
Exam Tip
\(x^{\frac{1}{2}}\) में चर की घात भिन्न है। बहुपद में ऐसी घात मान्य नहीं होती।
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