व्यंजक \(x^3+\frac{x^2-4}{x-2}\) को \(x\neq2\) पर सरल करने से कौन सा बहुपद मिलता है?

Which polynomial is obtained by simplifying \(x^3+\frac{x^2-4}{x-2}\) for \(x\neq2\)?

Explanation opens after your attempt
Correct Answer

A. \(x^3+x+2\)

Step 1

Concept

\(\frac{x^2-4}{x-2}=x+2\) when \(x\neq2\). Therefore the simplified form is \(x^3+x+2\).

Step 2

Why this answer is correct

The correct answer is A. \(x^3+x+2\). \(\frac{x^2-4}{x-2}=x+2\) when \(x\neq2\). Therefore the simplified form is \(x^3+x+2\).

Step 3

Exam Tip

\(\frac{x^2-4}{x-2}=x+2\) जब \(x\neq2\)। इसलिए सरल रूप \(x^3+x+2\) है।

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व्यंजक \(x^3+\frac{x^2-4}{x-2}\) को \(x\neq2\) पर सरल करने से कौन सा बहुपद मिलता है? / Which polynomial is obtained by simplifying \(x^3+\frac{x^2-4}{x-2}\) for \(x\neq2\)?

Correct Answer: A. \(x^3+x+2\). Explanation: \(\frac{x^2-4}{x-2}=x+2\) जब \(x\neq2\)। इसलिए सरल रूप \(x^3+x+2\) है। / \(\frac{x^2-4}{x-2}=x+2\) when \(x\neq2\). Therefore the simplified form is \(x^3+x+2\).

Which concept should I revise for this Mathematics MCQ?

\(\frac{x^2-4}{x-2}=x+2\) when \(x\neq2\). Therefore the simplified form is \(x^3+x+2\).

What exam hint can help solve this Mathematics question?

\(\frac{x^2-4}{x-2}=x+2\) जब \(x\neq2\)। इसलिए सरल रूप \(x^3+x+2\) है।