यदि \(a\neq0\), (b=0), तो \(ax^2+bx^5-4\) की डिग्री क्या होगी?

If \(a\neq0\), (b=0), what will be the degree of \(ax^2+bx^5-4\)?

Explanation opens after your attempt
Correct Answer

B. (2)

Step 1

Concept

Since (b=0), the \(x^5\) term disappears. Since \(a\neq0\), the \(x^2\) term remains.

Step 2

Why this answer is correct

The correct answer is B. (2). Since (b=0), the \(x^5\) term disappears. Since \(a\neq0\), the \(x^2\) term remains.

Step 3

Exam Tip

(b=0) होने से \(x^5\) पद हट जाता है। \(a\neq0\) होने से \(x^2\) पद बचता है।

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FAQs

Mathematics Answer, Explanation and Revision Hints

यदि \(a\neq0\), (b=0), तो \(ax^2+bx^5-4\) की डिग्री क्या होगी? / If \(a\neq0\), (b=0), what will be the degree of \(ax^2+bx^5-4\)?

Correct Answer: B. (2). Explanation: (b=0) होने से \(x^5\) पद हट जाता है। \(a\neq0\) होने से \(x^2\) पद बचता है। / Since (b=0), the \(x^5\) term disappears. Since \(a\neq0\), the \(x^2\) term remains.

Which concept should I revise for this Mathematics MCQ?

Since (b=0), the \(x^5\) term disappears. Since \(a\neq0\), the \(x^2\) term remains.

What exam hint can help solve this Mathematics question?

(b=0) होने से \(x^5\) पद हट जाता है। \(a\neq0\) होने से \(x^2\) पद बचता है।