Concept-wise Practice

valid_powers MCQ Questions for Class 9

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Practice Questions

11 questions tagged with valid_powers.

किस व्यंजक में \(\frac{1}{2}\) गुणांक है लेकिन वह बहुपद है?

Which expression has coefficient \(\frac{1}{2}\) but is still a polynomial?

Explanation opens after your attempt
Correct Answer

A. \(\frac{1}{2}x^3+4x-6\)

Step 1

Concept

Fractional coefficients are allowed. In \(\frac{1}{2}x^3+4x-6\), the powers of (x) are (3), (1), and (0).

Step 2

Why this answer is correct

The correct answer is A. \(\frac{1}{2}x^3+4x-6\). Fractional coefficients are allowed. In \(\frac{1}{2}x^3+4x-6\), the powers of (x) are (3), (1), and (0).

Step 3

Exam Tip

भिन्न गुणांक मान्य होते हैं। \(\frac{1}{2}x^3+4x-6\) में (x) की घातें (3), (1) और (0) हैं।

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क्या \(\sqrt{11}x^3-5x+2\) (x) में बहुपद है?

Is \(\sqrt{11}x^3-5x+2\) a polynomial in (x)?

Explanation opens after your attempt
Correct Answer

A. हां, क्योंकि \(\sqrt{11}\) वास्तविक गुणांक हैYes, because \(\sqrt{11}\) is a real coefficient

Step 1

Concept

\(\sqrt{11}\) is only a coefficient and the powers of (x) are (3), (1), and (0). Therefore it is a polynomial.

Step 2

Why this answer is correct

The correct answer is A. हां, क्योंकि \(\sqrt{11}\) वास्तविक गुणांक है / Yes, because \(\sqrt{11}\) is a real coefficient. \(\sqrt{11}\) is only a coefficient and the powers of (x) are (3), (1), and (0). Therefore it is a polynomial.

Step 3

Exam Tip

\(\sqrt{11}\) केवल गुणांक है और (x) की घातें (3), (1), और (0) हैं। इसलिए यह बहुपद है।

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किस विकल्प में सभी गुणांक वास्तविक हैं और (x) की घातें मान्य हैं?

In which option are all coefficients real and powers of (x) valid?

Explanation opens after your attempt
Correct Answer

A. \(2x^3-\pi x^2+\sqrt{13}\)

Step 1

Concept

\(\pi\) and \(\sqrt{13}\) are real coefficients. The powers of (x) are (3), (2), and (0).

Step 2

Why this answer is correct

The correct answer is A. \(2x^3-\pi x^2+\sqrt{13}\). \(\pi\) and \(\sqrt{13}\) are real coefficients. The powers of (x) are (3), (2), and (0).

Step 3

Exam Tip

\(\pi\) और \(\sqrt{13}\) वास्तविक गुणांक हैं। (x) की घातें (3), (2), और (0) हैं।

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किस विकल्प में सभी गुणांक वास्तविक हैं और चर की घातें मान्य हैं?

In which option are all coefficients real and variable powers valid?

Explanation opens after your attempt
Correct Answer

A. \(2x^2-\pi x+\sqrt{11}\)

Step 1

Concept

\(\pi\) and \(\sqrt{11}\) are real coefficients. The powers of (x) are (2), (1), and (0).

Step 2

Why this answer is correct

The correct answer is A. \(2x^2-\pi x+\sqrt{11}\). \(\pi\) and \(\sqrt{11}\) are real coefficients. The powers of (x) are (2), (1), and (0).

Step 3

Exam Tip

\(\pi\) और \(\sqrt{11}\) वास्तविक गुणांक हैं। (x) की घातें (2), (1) और (0) हैं।

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कौन सा व्यंजक (x) में बहुपद है और उसकी डिग्री (3) है?

Which expression is a polynomial in (x) and has degree (3)?

Explanation opens after your attempt
Correct Answer

C. \(-4x^3+\sqrt{5}x+8\)

Step 1

Concept

The third expression is a polynomial because the powers are (3), (1), and (0). The highest power is (3).

Step 2

Why this answer is correct

The correct answer is C. \(-4x^3+\sqrt{5}x+8\). The third expression is a polynomial because the powers are (3), (1), and (0). The highest power is (3).

Step 3

Exam Tip

तीसरा व्यंजक बहुपद है क्योंकि घातें (3), (1) और (0) हैं। सबसे बड़ी घात (3) है।

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कौन-सा विकल्प बहुपद की परिभाषा के अनुसार सही उदाहरण देता है?

Which option gives a correct example according to the definition of polynomial?

Explanation opens after your attempt
Correct Answer

A. \(x^2+4x+4\) क्योंकि घातें (2), (1), (0) हैं\(x^2+4x+4\) because powers are (2), (1), (0)

Step 1

Concept

In \(x^2+4x+4\), all powers are non-negative integers. So it is a correct polynomial example.

Step 2

Why this answer is correct

The correct answer is A. \(x^2+4x+4\) क्योंकि घातें (2), (1), (0) हैं / \(x^2+4x+4\) because powers are (2), (1), (0). In \(x^2+4x+4\), all powers are non-negative integers. So it is a correct polynomial example.

Step 3

Exam Tip

\(x^2+4x+4\) में सभी घातें शून्य या धनात्मक पूर्णांक हैं। इसलिए यह सही बहुपद उदाहरण है।

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कौन-सा व्यंजक (m) में बहुपद है?

Which expression is a polynomial in (m)?

Explanation opens after your attempt
Correct Answer

C. \(2m^5-3m+1\)

Step 1

Concept

In \(2m^5-3m+1\), the powers of (m) are (5), (1), and (0). All are valid.

Step 2

Why this answer is correct

The correct answer is C. \(2m^5-3m+1\). In \(2m^5-3m+1\), the powers of (m) are (5), (1), and (0). All are valid.

Step 3

Exam Tip

\(2m^5-3m+1\) में (m) की घातें (5), (1) और (0) हैं। ये सभी मान्य हैं।

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कौन सा व्यंजक (x) में बहुपद है?

Which expression is a polynomial in (x)?

Explanation opens after your attempt
Correct Answer

C. \(3x^4+\frac{x}{5}-6\)

Step 1

Concept

In \(3x^4+\frac{x}{5}-6\), the powers of (x) are (4), (1), and (0). A fractional coefficient is valid.

Step 2

Why this answer is correct

The correct answer is C. \(3x^4+\frac{x}{5}-6\). In \(3x^4+\frac{x}{5}-6\), the powers of (x) are (4), (1), and (0). A fractional coefficient is valid.

Step 3

Exam Tip

\(3x^4+\frac{x}{5}-6\) में (x) की घातें (4), (1), और (0) हैं। भिन्न गुणांक मान्य होता है।

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कौन-सा विकल्प बहुपद की सही उदाहरण-व्याख्या देता है?

Which option gives a correct example-explanation of a polynomial?

Explanation opens after your attempt
Correct Answer

A. \(x^2+1\) क्योंकि घातें (2) और (0) हैं\(x^2+1\) because powers are (2) and (0)

Step 1

Concept

In \(x^2+1\), the powers are (2) and (0), which are valid. The other options contain invalid powers.

Step 2

Why this answer is correct

The correct answer is A. \(x^2+1\) क्योंकि घातें (2) और (0) हैं / \(x^2+1\) because powers are (2) and (0). In \(x^2+1\), the powers are (2) and (0), which are valid. The other options contain invalid powers.

Step 3

Exam Tip

\(x^2+1\) में घातें (2) और (0) हैं जो मान्य हैं। बाकी विकल्पों में अमान्य घातें हैं।

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किस विकल्प में (x) की सभी घातें बहुपद के लिए मान्य हैं?

In which option are all powers of (x) valid for a polynomial?

Explanation opens after your attempt
Correct Answer

C. \(x^6+x^3+x^0\)

Step 1

Concept

(6), (3), and (0) are all non-negative integers. Therefore these powers are valid for a polynomial.

Step 2

Why this answer is correct

The correct answer is C. \(x^6+x^3+x^0\). (6), (3), and (0) are all non-negative integers. Therefore these powers are valid for a polynomial.

Step 3

Exam Tip

(6), (3), और (0) सभी अशून्य या शून्य पूर्णांक हैं। इसलिए ये घातें बहुपद के लिए मान्य हैं।

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किस विकल्प में बहुपद के सभी पदों में चर की घात मान्य है?

In which option do all terms have valid powers of the variable for a polynomial?

Explanation opens after your attempt
Correct Answer

A. \(x^2+x+1\)

Step 1

Concept

In \(x^2+x+1\), the powers are (2), (1), and (0). These are valid powers for a polynomial.

Step 2

Why this answer is correct

The correct answer is A. \(x^2+x+1\). In \(x^2+x+1\), the powers are (2), (1), and (0). These are valid powers for a polynomial.

Step 3

Exam Tip

\(x^2+x+1\) में घातें (2), (1), और (0) हैं। ये बहुपद के लिए मान्य घातें हैं।

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