Concept-wise Practice

radical MCQ Questions for Class 10

radical se related questions ko ek jagah revise karein. Har question me bilingual content, answer feedback aur explanation available hai.

Practice Questions

2 questions tagged with radical.

कौन-सा विकल्प सामान्य रूप में द्विघात समीकरण नहीं है?

Which option is not a quadratic equation in the usual form?

Explanation opens after your attempt
Correct Answer

C. \(\sqrt{x}+x=4\)

Step 1

Concept

The term \(\sqrt{x}\) has a fractional power of the variable, so it is not in usual quadratic form. Quadratic form has only \(x^2\), (x), and constant terms.

Step 2

Why this answer is correct

The correct answer is C. \(\sqrt{x}+x=4\). The term \(\sqrt{x}\) has a fractional power of the variable, so it is not in usual quadratic form. Quadratic form has only \(x^2\), (x), and constant terms.

Step 3

Exam Tip

\(\sqrt{x}\) में चर की भिन्न घात है, इसलिए यह सामान्य द्विघात रूप नहीं है। द्विघात रूप में केवल \(x^2\), (x) और स्थिर पद होते हैं।

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समीकरण \(\sqrt{x}+x^2=0\) को सामान्य रूप में द्विघात क्यों नहीं माना जाता?

Why is \(\sqrt{x}+x^2=0\) not considered a quadratic equation in the usual form?

Explanation opens after your attempt
Correct Answer

D. क्योंकि इसमें \(\sqrt{x}\) पद हैBecause it has a \(\sqrt{x}\) term

Step 1

Concept

The term \(\sqrt{x}\) shows a fractional power of the variable, so it is not in usual quadratic form. A quadratic equation has only \(x^2\), (x), and constant terms.

Step 2

Why this answer is correct

The correct answer is D. क्योंकि इसमें \(\sqrt{x}\) पद है / Because it has a \(\sqrt{x}\) term. The term \(\sqrt{x}\) shows a fractional power of the variable, so it is not in usual quadratic form. A quadratic equation has only \(x^2\), (x), and constant terms.

Step 3

Exam Tip

\(\sqrt{x}\) चर की भिन्न घात दिखाता है इसलिए यह सामान्य द्विघात रूप में नहीं है। द्विघात में केवल \(x^2\), (x) और स्थिर पद होते हैं।

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