व्यंजक \(\frac{x^2-4}{x-2}\) मूल रूप में बहुपद क्यों नहीं माना जाता?
Why is \(\frac{x^2-4}{x-2}\) not considered a polynomial in its original form?
Explanation opens after your attempt
Correct Answer
C. क्योंकि चर हर में हैBecause the variable is in the denominator
Concept
In the original form, the denominator is (x-2), so it is not directly called a polynomial. Even after simplifying, the condition \(x\neq2\) remains.
Why this answer is correct
The correct answer is C. क्योंकि चर हर में है / Because the variable is in the denominator. In the original form, the denominator is (x-2), so it is not directly called a polynomial. Even after simplifying, the condition \(x\neq2\) remains.
Exam Tip
मूल रूप में हर (x-2) है, इसलिए यह सीधे बहुपद नहीं कहलाता। सरल करने पर भी \(x\neq2\) की शर्त रहती है।
Login to save your score, XP, coins and progress.